I am trying to upload a image to Database using Javascript on client and PHP on server.
first image is selected from the gallery.
after zooming and cropping the image is passed to database
The Problem is when iam trying to submit the cropped image value is not passed to the php the actual uploaded input "File" Value is Being Passed, but i need the cropped areas value to be passed to PHP.
For testing purpose if all the js are required i can provide it.
Js: This Crops the image
$(function() {
$('.image-editor').cropit({
exportZoom: 1.25,
imageBackground: true,
imageBackgroundBorderWidth: 40,
});
$('.export').click(function() {
var imageData = $('.image-editor').cropit('export');
window.open(imageData);
});
});
HTML:
<form id="uploadForm" class="image-editor">
<input type="file" class="cropit-image-input">
<!-- .cropit-image-preview-container is needed for background image to work -->
<div class="cropit-image-preview-container">
<div class="cropit-image-preview"></div>
</div>
<div class="image-size-label">
Resize image
</div>
<input type="range" class="cropit-image-zoom-input">
<input type="submit" class="export">Export</input >
</form>
Ajax: ajax sends the data to php
$(document).ready(function (e) {
$("#uploadForm").on('submit', (function (e) {
e.preventDefault();
$.ajax({
url: "upload.php",
type: "POST",
data: new FormData(this),
contentType: false,
cache: false,
processData: false,
success: function (data) {
$("#targetLayer1").html(data);
},
error: function () {}
});
});
});
PHP:
if(count($_FILES) > 0) {
if(is_uploaded_file($_FILES['userImage']['tmp_name'])) {
$mysl = mysqli_connect("localhost", "root", "root","test");
$imgData =addslashes(file_get_contents($_FILES['userImage']['tmp_name']));
$imageProperties = getimageSize($_FILES['userImage']['tmp_name']);
$sql = "UPDATE output_images SET imageType ='{$imageProperties['mime']}',imageData= '{$imgData}' WHERE imageId='16'";
$current_id = mysqli_query($mysl,
$sql) or die("<b>Error:</b> Problem on Image Insert<br/>" . mysqli_error());;
if(isset($current_id)) {
echo "done";
}
}
}
First, take a look at this: Can I pass image form data to a PHP function for upload?
I think the issue is here: var imageData = $('.image-editor').cropit('export');. Since this new image is never a part of the form, there is no way to pass it via AJAX.
In your JS/JQuery, I would advise:
var imageData = '';
$(function() {
$('.image-editor').cropit({
exportZoom: 1.25,
imageBackground: true,
imageBackgroundBorderWidth: 40,
});
$('.export').click(function() {
imageData = $('.image-editor').cropit('export');
window.open(imageData);
});
});
$(document).ready(function (e) {
$("#uploadForm").on('submit', (function (e) {
e.preventDefault();
var fd = new FormData(this);
fd.append( imageData, file );
$.ajax({
url: "upload.php",
type: "POST",
data: fd,
contentType: false,
cache: false,
processData: false,
success: function (data) {
$("#targetLayer1").html(data);
},
error: function () {}
});
});
});
EDIT
In your example, you never defined a name or id attribute for your input, so there would be no way for PHP to index the $_FILES global. Could try $_FILES[0]. I would advise assigning that in your form or when you post it.
You can adjust the myFormData.append(name, file, filename);. So it would be:
fd.append('crop-image', imageData, 'crop-image.jpg');
Then in PHP, you call it using $_FILES['crop-image']. If you want to pass the file name from the form:
$(document).ready(function (e) {
$("#uploadForm").on('submit', (function (e) {
e.preventDefault();
var fd = new FormData(this);
var origFileName = $("input[type='file']").val();
var startIndex = (origFileName.indexOf('\\') >= 0 ? origFileName.lastIndexOf('\\') : origFileName.lastIndexOf('/'));
var filename = origFileName.substring(startIndex);
if (filename.indexOf('\\') === 0 || filename.indexOf('/') === 0){
filename = filename.substring(1);
}
var cropFileName = "crop-" + filename;
fd.append('crop-image' imageData, cropFileName );
$.ajax({
url: "upload.php",
type: "POST",
data: fd,
contentType: false,
cache: false,
processData: false,
success: function (data) {
$("#targetLayer1").html(data);
},
error: function () {}
});
});
Related
I'm using jQuery and Ajax for my forms to submit data and files but I'm not sure how to send both data and files in one form?
I currently do almost the same with both methods but the way in which the data is gathered into an array is different, the data uses .serialize(); but the files use = new FormData($(this)[0]);
Is it possible to combine both methods to be able to upload files and data in one form through Ajax?
Data jQuery, Ajax and html
$("form#data").submit(function(){
var formData = $(this).serialize();
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="data" method="post">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<button>Submit</button>
</form>
Files jQuery, Ajax and html
$("form#files").submit(function(){
var formData = new FormData($(this)[0]);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
<form id="files" method="post" enctype="multipart/form-data">
<input name="image" type="file" />
<button>Submit</button>
</form>
How can I combine the above so that I can send data and files in one form via Ajax?
My aim is to be able to send all of this form in one post with Ajax, is it possible?
<form id="datafiles" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>
The problem I had was using the wrong jQuery identifier.
You can upload data and files with one form using ajax.
PHP + HTML
<?php
print_r($_POST);
print_r($_FILES);
?>
<form id="data" method="post" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button>Submit</button>
</form>
jQuery + Ajax
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
url: window.location.pathname,
type: 'POST',
data: formData,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
});
Short Version
$("form#data").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function(data) {
alert(data);
});
});
another option is to use an iframe and set the form's target to it.
you may try this (it uses jQuery):
function ajax_form($form, on_complete)
{
var iframe;
if (!$form.attr('target'))
{
//create a unique iframe for the form
iframe = $("<iframe></iframe>").attr('name', 'ajax_form_' + Math.floor(Math.random() * 999999)).hide().appendTo($('body'));
$form.attr('target', iframe.attr('name'));
}
if (on_complete)
{
iframe = iframe || $('iframe[name="' + $form.attr('target') + '"]');
iframe.load(function ()
{
//get the server response
var response = iframe.contents().find('body').text();
on_complete(response);
});
}
}
it works well with all browsers, you don't need to serialize or prepare the data.
one down side is that you can't monitor the progress.
also, at least for chrome, the request will not appear in the "xhr" tab of the developer tools but under "doc"
I was having this same issue in ASP.Net MVC with HttpPostedFilebase and instead of using form on Submit I needed to use button on click where I needed to do some stuff and then if all OK the submit form so here is how I got it working
$(".submitbtn").on("click", function(e) {
var form = $("#Form");
// you can't pass Jquery form it has to be javascript form object
var formData = new FormData(form[0]);
//if you only need to upload files then
//Grab the File upload control and append each file manually to FormData
//var files = form.find("#fileupload")[0].files;
//$.each(files, function() {
// var file = $(this);
// formData.append(file[0].name, file[0]);
//});
if ($(form).valid()) {
$.ajax({
type: "POST",
url: $(form).prop("action"),
//dataType: 'json', //not sure but works for me without this
data: formData,
contentType: false, //this is requireded please see answers above
processData: false, //this is requireded please see answers above
//cache: false, //not sure but works for me without this
error : ErrorHandler,
success : successHandler
});
}
});
this will than correctly populate your MVC model, please make sure in your Model, The Property for HttpPostedFileBase[] has the same name as the Name of the input control in html i.e.
<input id="fileupload" type="file" name="UploadedFiles" multiple>
public class MyViewModel
{
public HttpPostedFileBase[] UploadedFiles { get; set; }
}
Or shorter:
$("form#data").submit(function() {
var formData = new FormData(this);
$.post($(this).attr("action"), formData, function() {
// success
});
return false;
});
EDIT: with the new version of JQuery (3.6), you could also try using contentType function argument instead of enctype. Try contentType: multipart/form-data.
For me, it didn't work without enctype: 'multipart/form-data' field in the Ajax request. I hope it helps someone who is stuck in a similar problem.
Even though the enctype was already set in the form attribute, for some reason, the Ajax request didn't automatically identify the enctype without explicit declaration (jQuery 3.3.1).
// Tested, this works for me (jQuery 3.3.1)
fileUploadForm.submit(function (e) {
e.preventDefault();
$.ajax({
type: 'POST',
url: $(this).attr('action'),
enctype: 'multipart/form-data',
data: new FormData(this),
processData: false,
contentType: false,
success: function (data) {
console.log('Thank God it worked!');
}
}
);
});
// enctype field was set in the form but Ajax request didn't set it by default.
<form action="process/file-upload" enctype="multipart/form-data" method="post" >
<input type="file" name="input-file" accept="text/plain" required>
...
</form>
As others mentioned above, please also pay special attention to the contentType and processData fields.
A Simple but more effective way:
new FormData() is itself like a container (or a bag). You can put everything attr or file in itself.
The only thing you'll need to append the attribute, file, fileName eg:
let formData = new FormData()
formData.append('input', input.files[0], input.files[0].name)
and just pass it in AJAX request. Eg:
let formData = new FormData()
var d = $('#fileid')[0].files[0]
formData.append('fileid', d);
formData.append('inputname', value);
$.ajax({
url: '/yourroute',
method: 'POST',
contentType: false,
processData: false,
data: formData,
success: function(res){
console.log('successfully')
},
error: function(){
console.log('error')
}
})
You can append n number of files or data with FormData.
and if you're making AJAX Request from Script.js file to Route file in Node.js beware of using
req.body to access data (ie text)
req.files to access file (ie image, video etc)
The code below works for me
$(function () {
debugger;
document.getElementById("FormId").addEventListener("submit", function (e) {
debugger;
if (ValidDateFrom()) { // Check Validation
var form = e.target;
if (form.getAttribute("enctype") === "multipart/form-data") {
debugger;
if (form.dataset.ajax) {
e.preventDefault();
e.stopImmediatePropagation();
var xhr = new XMLHttpRequest();
xhr.open(form.method, form.action);
xhr.onreadystatechange = function (result) {
debugger;
if (xhr.readyState == 4 && xhr.status == 200) {
debugger;
var responseData = JSON.parse(xhr.responseText);
SuccessMethod(responseData); // Redirect to your Success method
}
};
xhr.send(new FormData(form));
}
}
}
}, true);
});
In your Action Post Method, pass parameter as HttpPostedFileBase UploadFile and make sure your file input has same as mentioned in your parameter of the Action Method.
It should work with AJAX Begin form as well.
Remember over here that your AJAX BEGIN Form will not work over here since you make your post call defined in the code mentioned above and you can reference your method in the code as per the Requirement
I know I am answering late but this is what worked for me
Just to remind, in 2022 you don't need to use jquery. Try js standard Fetch API
var formData = new FormData(this);
fetch(url, {
method: 'POST',
body: formData
})
.then(response => {
if(response.ok) {
//success
alert(response);
} else {
throw Error('Server error');
}
})
.catch(error => {
console.log('fail', error);
});
This is a solution that I implemented
var formData = new FormData();
var files = $('input[type=file]');
for (var i = 0; i < files.length; i++) {
if (files[i].value == "" || files[i].value == null) {
return false;
}
else {
formData.append(files[i].name, files[i].files[0]);
}
}
var formSerializeArray = $("#Form").serializeArray();
for (var i = 0; i < formSerializeArray.length; i++) {
formData.append(formSerializeArray[i].name, formSerializeArray[i].value)
}
$.ajax({
type: 'POST',
data: formData,
contentType: false,
processData: false,
cache: false,
url: '/Controller/Action',
success: function (response) {
if (response.Success == true) {
return true;
}
else {
return false;
}
},
error: function () {
return false;
},
failure: function () {
return false;
}
});
---Solution for DOT NET CORE MVC Implementation---
While looking at this question I though I should right .NET CORE implementation for this because the question is not specific to any backend language.
So guys here is the standalone implementation example.
Objective :- To submit form fields including files and how we can get data in a single model at backend
HTML Code / View Code - Views/Home/Index.cshtml
#{
ViewData["Title"] = "Home Page";
}
<input type="file" id="FileUpload1" multiple />
<div>
<label>Enter First Name :</label>
<input type="text" id="nameText" maxlength="50" />
</div>
<input type="button" id="btnUpload" value="Submit Form with Files" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
$(document).ready(function () {
$('#btnUpload').click(function () {
// Checking whether FormData is available in browser
if (window.FormData !== undefined) {
var fileUpload = $("#FileUpload1").get(0);
var files = fileUpload.files;
// Create FormData object
var fileData = new FormData();
// Looping over all files and add it to FormData object
for (var i = 0; i < files.length; i++) {
fileData.append("files", files[i]);
}
// Adding one more key to FormData object
fileData.append('FirstName', $("#nameText").val());
$.ajax({
url: '/Home/UploadFiles',
type: "POST",
contentType: false, // Not to set any content header
processData: false, // Not to process data
data: fileData,
success: function (result) {
alert(result);
},
error: function (err) {
alert(err.statusText);
}
});
} else {
alert("FormData is not supported.");
}
});
});
</script>
Backend Code / Controller action method Controllers/HomeController.cs
public class HomeController : Controller
{
private readonly ILogger<HomeController> _logger;
private readonly IWebHostEnvironment _environment;
public HomeController(ILogger<HomeController> logger, IWebHostEnvironment environment)
{
_logger = logger;
_environment = environment;
}
public IActionResult Index()
{
return View();
}
public IActionResult Privacy()
{
return View();
}
[HttpPost]
public async Task<IActionResult> UploadFiles(MyForm myForm)
{
var files = myForm.Files;
// First Name
string name = myForm.FirstName;
// check All files
foreach (IFormFile source in files)
{
string filename = ContentDispositionHeaderValue.Parse(source.ContentDisposition).FileName.Trim('"');
filename = this.EnsureCorrectFilename(filename);
string fileWithPath = this.GetPathAndFilename(filename);
// Create directory if not exist
Directory.CreateDirectory(Path.GetDirectoryName(fileWithPath));
using (FileStream output = System.IO.File.Create(fileWithPath))
await source.CopyToAsync(output);
}
return Ok("Success");
}
[ResponseCache(Duration = 0, Location = ResponseCacheLocation.None, NoStore = true)]
public IActionResult Error()
{
return View(new ErrorViewModel { RequestId = Activity.Current?.Id ?? HttpContext.TraceIdentifier });
}
public class MyForm
{
public string FirstName { get; set; }
public IList<IFormFile> Files { get; set; }
}
private string EnsureCorrectFilename(string filename)
{
if (filename.Contains("\\"))
filename = filename.Substring(filename.LastIndexOf("\\") + 1);
return filename;
}
private string GetPathAndFilename(string filename)
{
return Path.Combine(_environment.ContentRootPath, "uploadedFiles", filename);
}
}
Full Source Code Repo: https://github.com/rj-learning/DotNetCoreFileUpload
In my case I had to make a POST request, which had information sent through the header, and also a file sent using a FormData object.
I made it work using a combination of some of the answers here, so basically what ended up working was having this five lines in my Ajax request:
contentType: "application/octet-stream",
enctype: 'multipart/form-data',
contentType: false,
processData: false,
data: formData,
Where formData was a variable created like this:
var file = document.getElementById('uploadedFile').files[0];
var form = $('form')[0];
var formData = new FormData(form);
formData.append("File", file);
you can just append them on your formdata, add your files and datas in it.you can read this..
https://developer.mozilla.org/en-US/docs/Web/API/FormData/append
for better understanding. you can separately retrieve them $_FILES for your files and $_POST for your data.
<form id="form" method="post" action="otherpage.php" enctype="multipart/form-data">
<input type="text" name="first" value="Bob" />
<input type="text" name="middle" value="James" />
<input type="text" name="last" value="Smith" />
<input name="image" type="file" />
<button type='button' id='submit_btn'>Submit</button>
</form>
<script>
$(document).on("click", "#submit_btn", function (e) {
//Prevent Instant Click
e.preventDefault();
// Create an FormData object
var formData = $("#form").submit(function (e) {
return;
});
//formData[0] contain form data only
// You can directly make object via using form id but it require all ajax operation inside $("form").submit(<!-- Ajax Here -->)
var formData = new FormData(formData[0]);
$.ajax({
url: $('#form').attr('action'),
type: 'POST',
data: formData,
success: function (response) {
console.log(response);
},
contentType: false,
processData: false,
cache: false
});
return false;
});
</script>
///// otherpage.php
<?php
print_r($_FILES);
?>
My onImageUpload in summer note jquery plugin is not working.
for upload image in some folder different place then summernote default location
how can i handle this ?!
index.php
<textarea id="summernote" name="contents"></textarea>
<script>
$('#summernote').summernote({
tabsize: 2,
height: 200,
focus: true,
callbacks: {
onChange: function(contents, $editable) {
console.log('onChange:', contents, $editable);
}
}
});
$('#summernote').on('summernote.image.upload', function(we, contents, $editable) {
data = new FormData ();
data.append("file",file);
$.ajax({
url: "summernote_upload.php",
type: "POST",
data: data,
cache: false,
contentType: false,
processData: false,
});
$summernote.summernote('insertNode', imgNode);
});
</script>
summernote_upload.php
require_once ('./../../lib/curl_setup.php'); // curl json&token
$data_array = array(
"request" => array(
"image" => "this upload file/base64"
),
);
$make_call = callAPI('POST', '/api/v2/admin/products/images', json_encode($data_array));
$response = json_decode($make_call, true);
//$errors = $response['response']['errors'];
//$data = $response['response']['data'][0];
print_r($response);exit;
However, summernote_upload.php works well.
The response is:
{
"image": {
"shop_no": 1,
"path": "/web/upload/NNEditor/20180408/b69c819e36b4abc3f393b731829ab747.gif"
}
}
I need to solve the index.php.
first you must catch the upload image event
and dont allow to summernote add it automatically
callbacks: {
onImageUpload: function(files, editor, $editable) {
console.log('onImageUpload');
sendFile(files[0],editor,$editable);
}},
then you must handle image upload with json yourself.
there is a function for this:
function sendFile(file,editor,welEditable) {
data = new FormData();
data.append("file", file);
$.ajax({
url: "uploader.php",
data: data,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
// alert(data);
$('#summernote10').summernote("insertImage", data, 'filename');
},
error: function(jqXHR, textStatus, errorThrown) {
console.log(textStatus+" "+errorThrown);
}
});
}
and in server side you can save the file
$allowed = array('png', 'jpg', 'gif','jpeg');
if(isset($_FILES['file']) && $_FILES['file']['error'] == 0){
$extension = pathinfo($_FILES['file']['name'], PATHINFO_EXTENSION);
if(!in_array(strtolower($extension), $allowed)){
echo '{"status":"error"}';
exit;
}
$newFileAddress = '../files/-'.rand(1000).'.'.$extension;
if(move_uploaded_file($_FILES['file']['tmp_name'],$newFileAddress)){
echo $newFileAddress;
exit;
}
}
by return the file path on server you can insert it on summer note easily
I am using codeigniter 3.1 . I want to post upload data using ajax.
Ajax upload file not working. But when i post the simple form without ajax, it working fine.
I don't know why but no error in console.
HTML
<?php echo form_open_multipart(site_url("upload/post"), ['id' => 'uploader']) ?>
<input type="file" name="userfile" value="">
<input type="submit" value="Submit" />
<?php echo form_close() ?>
JAVASCRIPT
$('#uploader').submit(function (event) {
event.preventDefault();
$.ajax({
url: window.location.href + '/post',
type: "POST",
dataType: 'json',
data: new FormData(this)
});
});
CONTROLLERS
public function post()
{
$this->load->helper('url');
$this->load->helper('form');
$this->load->library("upload");
$file = $this->common->nohtml($this->input->post("userfile"));
$this->upload->initialize(array(
"upload_path" => 'upload',
"overwrite" => FALSE,
"max_filename" => 300,
"encrypt_name" => TRUE
));
$this->upload->do_upload('userfile');
$data = $this->upload->data();
$image_file = $data['file_name'];
}
Another approach to this would be passing to PHP the file encoded in base64:
get the selected file from #userfile field using $('#userfile').prop('files')[0];
transform the contents of that file into a base64 encoded string using FileReader.readAsDataURL(). We're going to call this content; Here's a similar question showing how to do and expanding the answer & possibilities;
send the AJAX passing both the filename and content strings;
now on CI, fetch the POST data;
base64_decode() the content;
fwrite() the result into a file using the filename.
That way also you could avoid POSTing all form fields.
try this..
Post data using FormData() formdata post file also.
To get all your form inputs, including the type="file" you need to use FormData object.
$('#post').on('click', function (e) {
var file_data = $("#userfile").prop("files")[0];
var form_data = new FormData();
form_data.append("userfile", file_data)
$.ajax({
url: window.location.href+'/post',
type: 'POST',
data: form_data,
async: false,
success: function (data) {
alert(data)
},
cache: false,
contentType: false,
processData: false
});
return false;
});
For more...https://abandon.ie/notebook/simple-file-uploads-using-jquery-ajax
One of the issues is that file uploading uses a different mechanism than the other form <input> types. That is why $this->input->post("userfile") isn't getting the job done for you. Other answers have suggested using javascript's FormData and this one does too.
HTML
A very simple form for picking a file and submitting it. Note the change from a simple button to <input type="submit".... Doing so makes it a lot easier for the javascript to use the FormData object.
FormData documentation
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<script src="https://code.jquery.com/jquery-2.2.2.js"></script>
<title>Upload Test</title>
</head>
<body>
<?= form_open_multipart("upload/post", ['id' => 'uploader']); ?>
<input type="file" name="userfile">
<p>
<input type="submit" value="Upload">
</p>
<?php echo form_close() ?>
<div id="message"></div>
<script>
$('#uploader').submit(function (event) {
event.preventDefault();
$.ajax({
url: window.location.href + '/post',
type: "POST",
dataType: 'json',
data: new FormData(this),
processData: false,
contentType: false,
success: function (data) {
console.log(data);
if (data.result === true) {
$("#message").html("<p>File Upload Succeeded</p>");
} else {
$("#message").html("<p>File Upload Failed!</p>");
}
$("#message").append(data.message);
}
});
});
</script>
</body>
</html>
JAVASCRIPT
Use FormData to capture the fields.
Note that instead of handling the button click we handle the submit event.
$('#uploader').submit(function (event) {
event.preventDefault();
$.ajax({
url: window.location.href + '/post',
type: "POST",
dataType: 'json',
data: new FormData(this),
processData: false,
contentType: false,
success: function (data) {
//uncomment the next line to log the returned data in the javascript console
// console.log(data);
if (data.result === true) {
$("#message").html("<p>File Upload Succeeded</p>");
} else {
$("#message").html("<p>File Upload Failed!</p>");
}
$("#message").append(data.message);
}
});
});
CONTROLLER
I've added some code that "reports" results to ajax and will display it on the upload page.
class Upload extends CI_Controller
{
public function __construct()
{
parent::__construct();
$this->load->helper(['form', 'url']);
}
public function index()
{
$this->load->view('upload_v');
}
public function post()
{
$this->load->library("upload");
$this->upload->initialize(array(
"upload_path" => './uploads/',
'allowed_types' => 'gif|jpg|png|doc|txt',
"overwrite" => FALSE,
"max_filename" => 300,
"encrypt_name" => TRUE,
));
$successful = $this->upload->do_upload('userfile');
if($successful)
{
$data = $this->upload->data();
$image_file = $data['file_name'];
$msg = "<p>File: {$image_file}</p>";
$this->data_models->update($this->data->INFO, array("image" => $image_file));
} else {
$msg = $this->upload->display_errors();
}
echo json_encode(['result' => $successful, 'message' => $msg]);
}
}
This will upload your file. Your work probably isn't done because I suspect that your are not saving all the file info you need to the db. That, and I suspect you are going to be surprised by the name of the uploaded file.
I suggest you study up on how PHP handles file uploads and examine some of the similar codeigniter related questions on file uploads here on SO.
Controller
public function upload()
{
$this->load->library('upload');
if (isset($_FILES['myfile']) && !empty($_FILES['myfile']))
{
if ($_FILES['myfile']['error'] != 4)
{
// Image file configurations
$config['upload_path'] = './upload/';
$config['allowed_types'] = 'jpg|jpeg|png';
$this->upload->initialize($config);
$this->upload->do_upload('myfile');
}
}
}
View
<form id="myform" action="<?php base_url('controller/method'); ?>" method="post">
<input type="file" name="myfile">
("#myform").submit(function(evt){
evt.preventDefault();
var url = $(this).attr('action');
var formData = new FormData($(this)[0]);
$.ajax({
url: url,
type: 'POST',
data: formData,
processData: false,
contentType: false,
success: function (res) {
console.log(res);
},
error: function (error) {
console.log(error);
}
}); // End: $.ajax()
}); // End: submit()
Let me know if any query
you need to submit the form not on click but on submit ... give the form an id and then on submit put ajax
HTML
<?php $attributes = array('id' => 'post'); ?>
<?php echo form_open_multipart(site_url("upload/post",$attributes), ?>
<input type="file" id="userfile" name="userfile" value="">
<button id="post">Submit</button>
<?php echo form_close() ?>
JAVASCRIPT
$('#post').on('submit', function () {
var formData = new FormData();
formData.append("userfile",$("#userfile")[0].files[0]);
$.ajax({
url: window.location.href+'/post',
type: "POST",
data: formData
});
CONTROLLERS
public function post()
{
$this->load->library("upload");
$file = $this->common->nohtml($this->input->post("userfile"));
$this->upload->initialize(array(
"upload_path" => 'upload',
"overwrite" => FALSE,
"max_filename" => 300,
"encrypt_name" => TRUE,
));
$data = $this->upload->data();
$image_file = $data['file_name'];
$this->data_models->update($this->data->INFO, array(
"image" => $image_file
)
);
}
The file upload function working on the Upload button click.The function
$("#fuPDFAdd").change(function () {})
file upload change is working two time when click the 'btnUploadAdd' button.
How can avoid this
<div id="divUploadFileAdd">
<form enctype="multipart/form-data" id="frmUplaodFileAdd">
#Html.AntiForgeryToken()
<input id="fuPDFAdd" name="file" type="file" style = "display:none;"/>
<button class="" id="btnUploadAdd" type="button" onclick="test()">Upload</button>
<label id="txtuploadedMsgAdd"> </label>
</form>
</div>
$(document).ready(function () {
$("#fuPDFAdd").change(function () {
console.log("tst1");
var file = this.files[0];
fileName = file.name;
size = file.size;
type = file.type;
if (type.toLowerCase() == "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet") { //I just want pdf files and only want to show
var formData = new FormData($('#frmUplaodFileAdd')[0]);
$.ajax({
url: "UploadFile", //Server script to process data
type: 'POST',
async: false,
xhr: function () { // Custom XMLHttpRequest
var myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) { // Check if upload property exists
myXhr.upload.addEventListener('progress',
progressHandlingFunction, false); // For handling the progress of the upload
}
return myXhr;
},
data: formData,
//Options to tell jQuery not to process data or worry about content-type.
cache: false,
contentType: false,
processData: false,
success: function (data) {
grdStaffAddition.PerformCallback({ transStatus: "New" });
ShowClientToastr('False', 'False', 'toast-bottom-right', 'True', 'success', 'Template migration completed' + data.result, 'CAM - Contract Staff');
}
});
}
else {
ShowClientToastr('False', 'False', 'toast-bottom-right', 'True', 'error', 'Please select xls/xlsx file.', 'CAM - Contract Staff');
}
});
});
function test() {
$("#fuPDFAdd").click();
}
Something like this will work, I did wrap the file upload code to a separate function there, and make it to call this new function from your event listeners.
function uploadTheFile() {
console.log("tst1");
var file = this.files[0];
fileName = file.name;
size = file.size;
type = file.type;
if (type.toLowerCase() == "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet") { //I just want pdf files and only want to show
var formData = new FormData($('#frmUplaodFileAdd')[0]);
$.ajax({
url: "UploadFile", //Server script to process data
type: 'POST',
async: false,
xhr: function() { // Custom XMLHttpRequest
var myXhr = $.ajaxSettings.xhr();
if (myXhr.upload) { // Check if upload property exists
myXhr.upload.addEventListener('progress',
progressHandlingFunction, false); // For handling the progress of the upload
}
return myXhr;
},
data: formData,
//Options to tell jQuery not to process data or worry about content-type.
cache: false,
contentType: false,
processData: false,
success: function(data) {
grdStaffAddition.PerformCallback({
transStatus: "New"
});
ShowClientToastr('False', 'False', 'toast-bottom-right', 'True', 'success', 'Template migration completed' + data.result, 'CAM - Contract Staff');
}
});
} else {
ShowClientToastr('False', 'False', 'toast-bottom-right', 'True', 'error', 'Please select xls/xlsx file.', 'CAM - Contract Staff');
}
}
$("#fuPDFAdd").change(function() {
uploadTheFile();
});
function test() {
uploadTheFile();
}
I'm developing a small function for an image-upload. This image-upload resizes selected pictures on the client and upload the resized image.
This works, but the browser will hang a lot between "resizes-functionality".
This is my code:
function manageImage(file) {
if (!file) return;
var mime = file.type;
var src = URL.createObjectURL(file);
loadImage.parseMetaData(file, function (data) {
var options = { maxWidth: 1920, maxHeight: 1920, canvas: true };
if (data.exif) {
options.orientation = data.exif.get('Orientation');
}
loadImage(file,
function (img, test) {
loaded++;
var formData = new FormData();
formData.append("image", dataURI);
$.ajax({
url: "/URL",
data: formData,
cache: false,
contentType: false,
processData: false,
async: false,
type: "POST",
success: function (resp) {
}
}).error(function () {
}).done(function () {
if (loaded < checkedFiles.length) {
manageImage(files[loaded]);
} else {
//FINISHED
}
});
},
options);
});
}
manageImage(files[0]);
This funcition is recursive, because i had some problems with the iteration (browser-hang, memory and cpu-usage).
Additionally, i'm using this library for EXIF-Data and correct orientation on mobile phones:
https://github.com/blueimp/JavaScript-Load-Image
With one or two selected pictures (e.g. 7MB) it works perfect, but i want to upload maybe 50 pictures.
It would be great if someone can give me a clue?!