ng-model as link inside input text - javascript

I would like to convert my ng-model to a link.
I have an input binding a value. This value is a link.
Basically, I want to when you click on the text in the input (on not when you click on the textbox), it opens a link.
Here what I am trying to do:
html :
<input name="mytext"type="text" ng-model="field.savedValue" />
js:
field.savedValue = "<a href="" + $scope.baseUrl + "?etn=" + field.Values[0] + "&pagetype=entityrecord&id=" + field.lookupGuid + "">" + field.value + "<⁄a>";
but in this case, it just display me the whole content as a string (can't click on it...).
Thanks for your help !

Related

Input text value in url after clicking button

I would like to know how to input text value from a text field and adding it into an url after click Search button. So far I am not able to make that the value from input shows in the url. So what I have is this:
<input type="text" id="myText" value="Mickey">
<button onclick="myFunction()">Search</button>
and the javascript:
function myFunction() {
var x = document.getElementById("myText").value;
}
var sourceCode = '' + '<img src="' + imageBase + image + '" width="'+sizes[0]+'" height="'+sizes[1]+'"/>'
How can I get x value to be showing the value from the input text field?
Thanks in advance.
x does get the value of the input field, but your string build of sourceCode is riddled with errors (x is inside the double-quotes, image is undefined, etc). It also lies outside myFunction() so x is undefined too, and in any case will be executed before you click. If you comment out that line and add alert(x) inside myFunction() you can see that you do indeed capture the input, but the script fails and stops running.
try this:
function myFunction() {
var x = document.getElementById("myText").value;
var sourceCode = '' + '<img src="' + imageBase + image + '" width="'+sizes[0]+'" height="'+sizes[1]+'"/>';
}

Radio Input gets unchecked after jQuery html operation

I'm getting an extremely weird error. My radio button gets unchecked after doing the following operations:
var $page = $('[data-shortcode-page="' + shortcode + '"]', $webrock).html();
//CHECKED
console.log($('[data-shortcode-page="' + shortcode + '"] :checked', $webrock).length)
$('.webrock-page-content', $addPage).replaceWith($page);
//UNCHECKED
console.log($('[data-shortcode-page="' + shortcode + '"] :checked', $webrock).length)
Does anyone know why this is happening? Here's a jsFiddle: http://jsfiddle.net/mVB2q/1/
Thank you very much!
You are cloning a radio group with the same name. You need to update the name of the cloned radio group. Here is a simple solution where I am hardcoding in "test1" for the new group name, but you may want to modify it to fit your needs:
var shortcode = 'object';
var $page = $('[data-shortcode-page="' + shortcode + '"]');
console.log($('[data-shortcode-page="' + shortcode + '"] :checked').length);
//after cloning the radio buttons, find radio buttons and update the name attribute.
$('.webrock-page-content').html($page.clone().find("input[type='radio']").attr("name", "test1").end().html());
console.log($('[data-shortcode-page="' + shortcode + '"] :checked').length);
Updated fiddle.

Want value from javascript in Jquery, this is php?

I am following this example - http://jqueryui.com/selectable/#serialize and would like to be able to set the value of a hidden input field based on the user selection. So rather than the value being displayed as per the example, that value instead would be consecutively added to the hidden input field value. How can I achieve this?
<input type="hidden" />
If you want the selected value to be placed in your hidden field, add a class or id to your hidden input, and then change the following lines from the source example page:
your hidden input
<input type="hidden" id="hiddenInput" />
from the example, change
var result = $( "#select-result" ).empty();
to your hidden input
var result = $('#hiddenInput').empty();
then change
result.append( " #" + ( index + 1 ) );
to
result.val('#' + (index + 1));
to add the values rather than replace them, change the line to
result.val(result.val() + "#" + ( index + 1 ) );
here is a working example - http://jsfiddle.net/DBuVf/1

how to delete a value between <input> tags?

I'm creating checkboxes using JQuery as following:
$('<input type="checkbox" ' + 'id=' + (i+1) + '>' + (i+1) + '</input><br/>')
Then later it is removed whenever the user checks the box in:
if (this.checked) {
$(this).remove();
}
However, The input box is deleted, but the number (id) stays on the page, along the <br/> Tag, so I can see the #i there on the HTML Page.
I would like to remove them as well.
So, to in order to make my question as complete as possible, here is how the HTML is laid:
<input id="1" type="checkbox">
1
<br>
Could someone please give me a clue how to remove #i and <br/> from the page?
Thanks
as stated by other answers - input don't have closing tags
You will still need to remove all id and <br />. You can find those with .next() function in jquery. You should put your id in <label> or <span>.
Then. for example:
$(this).next('label').remove();
$(this).next('br').remove();
$(this).remove();
Code can be written shorter but it's for you to see how it works.
The text in <input> text boxes is not set with a textnode (like for textareas), but with the value attribute. (Sorry for the confusion)
Yet, you want to have a checkbox. Best, create a <label> for it, instead of a text node plus a <br /> (which is not handleable with jQuery):
<div class="inputcell">
<input type="checkbox" id="check5">
<label for="check5">5</label>
</div>
With this DOM, you can easily remove the whole box by $("#check5").parent().remove(). Note that single numbers are no valid element ids.
that's because input tags don't have closing tags and remove ignores everything after the >, change this:
$('<input type="checkbox" ' + 'id=' + (i+1) + '>' + (i+1) + '</input><br/>')
to:
$('<input type="checkbox" ' + 'id=' + (i+1) + 'value="' + (i+1) +'"><label>'+ (i+1) +'</label>')
$(this).next('label').andSelf().remove();
input tags don't have closing tag, to create a checkbox you just need the following:
$('<input type="checkbox" ' + 'id=' + (i+1) + '>');
and if you want also to use a label for that checkbox, create appropriate label or any other element, because you can't put closign tag for input and a text between them

Calendar Control on Dynamically created forms

I’m trying to accomplish a small task where I have one single Form ITERATED with a Date textinput which gets its Value by a Javascript DatePicker control.
My problem is, the datepicker on all these dynamically created forms only prints value on the first textbox element in the first form, how do I give it Dynamic reference to forms[x] text box element.
My form names are being generated Dynamically as form1, form2, form3, form[x], how do I reference the inner element of that particular form whose DatePicker is being clicked.
you can download the Zip file which has the datepicker & the HTML page for the Dynamic forms from here enter link description here
function addElement() {
intTextBox = intTextBox + 1;
intTextArea = intTextArea + 1;
var contentID = document.getElementById("new-field-back");
var newTBDiv = document.createElement("div");
newTBDiv.onclick=function(){ current=this; }
newTBDiv.setAttribute("id","strText"+intTextBox);
newTBDiv.innerHTML = "<br/><br/><form method='post' name='form" + intTextBox + "'><input
id='date_of_event' name='date_of_event" + intTextBox + "' class='date-pick' value=''><div
class='date-text'><a href='#' onclick=displayDatePicker('date_of_event" + intTextBox +
"');>Calendar</a></div></div><input type='submit' value='Update'><input type='button'
onclick='removeElement()' value='Remove'></form><br/><br/>";
contentID.appendChild(newTBDiv);
}
this is the correct function
if you are sending all data using one click of a button then you need to add a hidden field on the html form containing the total number of dates to be sent.
$num=$_POST['no_of_dates'];
$i;
for ($i=1;$i<=$num;$i++)
{
$_field_name="date_of_event".$i;
$_date_get=$_POST[$_field_name];
//now you can insert the $_date_get variable into the database by running a query.
}

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