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Form with two buttons

I am trying to create multiple forms which have two buttons, each will submit the form to different script, one via ajax and second one will just submit the form.
<?php foreach($objects as $object) : ?>
<div class="card-body">
<form id="edit-form" action="#" method="POST">
<input name="subject" value="<?=$object['subject']?>" type="text" id="title" class="input-xxlarge">
<textarea id="content" name="content" rows="25"><?=$object['content']?></textarea>
<button type="button" id="send-button" class="btn btn-primary">Send</button>
<input type="submit" id="submit-button" value="Submit"/>
</form>
</div>
<?php endforeach; ?>
First I am trying to get the current form, but I have problem with that. console.log shows something only on the first form, if I click on the buttons from other forms then It will do nothing.
$('#send-button').on('click', function(e) {
e.defaultPrevented;
$form = $(this);
$url = $form.attr('action');
$data = $form.serialize(); console.log($form);
console.log($url);
});
Is it because my button has same ID for every form ?

You shouln't use ID's multiple times on the same page. Try to use a class for that case. Also as stated in the comments use e.preventDefault(); to stop the event.
$(this) will result in the #send-button beeing targeted. To access the form you need to find the closest form element like this:
$form = $(this).closest('form');

html:
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
<form method="POST" action="#">
<input type="text">
<button type="button">send</button>
<input type="submit" value="submit" />
</form>
js:
$("form").each(function() {
var form = this;
$(form).find('button').on('click', function(e) {
e.preventDefault();
console.log(form);
console.log(this);
})
});
this will add events on every form you have on your page, button will submit form via script and submit will just submit it. also here's a fiddle to play with

Multi form submit with one selector use jquery ajax

I have a problem with jquery ajax multi form.
every execution is always part of the form at the top, to form the other does not work.
can help me.
this Source Code
<form id="form_action" action="http://www.dom.dom/act/">
<input type="text" name="nama" value="" />
<button type="submit" >Save</buton>
</form>
<form id="form_action" action="http://www.dom.dom/act/">
<input type="text" name="nama" value="" />
<button type="submit" >Save</buton>
</form>
<form id="form_action" action="http://www.dom.dom/act/">
<input type="text" name="nama" value="" />
<button type="submit" >Save</buton>
</form>
<form id="form_action" action="http://www.dom.dom/act/">
<input type="text" name="nama" value="" />
<button type="submit" >Save</buton>
</form>
jquery ajax nya :
$("‪#‎form_action‬").on('submit', function(e){
e.preventDefault();
var link = $(this).attr("action");
var data = $(this).serialize();
$.ajajx({
url:link,
data:data,
type:"POST",
typeData:'html',
cache:false,
success: function(data){
//// bla bla //
}
});
return false;
});
How to use this jquery for multi form..?

When you use an id selector ($('#some-id')) you get only the first element that matches your selector, not an array as you get with other selectors.
Also, it seems that they're all the same form.. What are you trying to achieve? Maybe you can use the same form and just change action attribute or some input in the form.
Another thing, as #dave mentioned in the comments, there's no $.ajajx function in jQuery :-)

javascript function call for single form

I have multiple forms in my php file for different buttons. So, if I click on Back button, ramesh.php script should be called and so on. This is the code.
<form action="ramesh.php">
<input type="submit" value="Back" />
</form>
<form action="process.php" method="post">
<input name="rep_skyline" type="text" />
<input type="submit" />
</form>
<form action="update.php" method="post" >
<button type="submit">Update</button>
</form>
However, I need to pass some data to server from my client side on form submit just for the update button. I have a javascript function to send the data to server side as below.
<script type="text/javascript">
$(document).ready(function() {
$('form').submit(function(e) {
var mydata = 3;
if ($(this).is(':not([data-submit="true"])'))
{
$('form').append('<input type="hidden" name="foo" value="'+mydata+'">');
$('form').data('submit', 'true').submit();
e.preventDefault();
return false;
}
})
})
</script>
If I click on the update button, the javascript function is working fine. However, if I click on Back or Submit button, I should not be calling the javascript function. Is there someway to do this?

Give your form an id:
<form action="update.php" method="post" id="update-form">
Then use a more specific selector:
$("#update-form").submit(function() {
// Code
});
I'm not quite sure why you need JavaScript to dynamically add data to your form, however. You should just use an <input type="hidden" /> directly.

type=submit will always load the form's action. Try to specify wich form to submit.
<form name="backForm" id="backForm" action="ramesh.php">
<input type="submit" value="Back" />
</form>
<form name="form2" id="form2" action="process.php" method="post">
<input name="rep_skyline" type="text" />
<input type="submit" />
</form>
Now you can access the form via document.backForm or document.getElementById("backForm") and than use submit(); like document.getElementById("backForm").submit();

submit a form inside another form

I have a form with POST method and an action of another page.
Within the form i have another form that I need to make submit with a different action but its submitting with the main form action.
this is my second form:
<script>
function formSubmit()
{
document.getElementById("invoices_form").submit();
}
</script>
<form action="resend_multiple_invoices.php" name="invoices_form" method="post">
<input type="button" onclick="formSubmit()" value="Send Invoices" />
</form>
how can i get it to submit the second form and not the main one?

You cannot (universally) submit a nested form separately from its parent form. Nested forms are invalid HTML as outlined in the W3C prohibitions.
To solve your problem, I suggest you use two separate forms as follows:
<script>
function invoicesFormSubmit()
{
document.getElementById("invoices_form").submit();
}
function otherFormSubmit()
{
document.getElementById("other_form").submit();
}
</script>
<form action="resend_multiple_invoices.php" name="invoices_form" method="post">
//
// Input fields go here
//
<input type="button" onclick="invoicesFormSubmit()" value="Send Invoices" />
</form>
<form action="other_method.php" name="other_form" method="post">
//
// Input fields go here
//
<input type="button" onclick="otherFormSubmit()" value="Other Method" />
</form>

You can use the 'form'-attribute in your input-fields and then mix all your inputs.
By submitting they refer to the correct form.
<form action="" method="post" id="form1"></form>
<form action="" method="post" id="form2"></form>
<input name="firstname" form="form1">
<input name="firstname" form="form2">
<button type="submit" name="submit" form="form1">Save form 1</button>
<button type="submit" name="submit" form="form2">Save form 2</button>
See also https://www.w3schools.com/tags/att_input_form.asp

JQuery.ajax and html for validating an "inner form" through ajax, then submitting the entire form. I use ajax in both cases to show the purpose of a controller.php file and a submission id. You could also have an inner form which consists of several segregated sections by using classes instead of ids as Jquery selectors.
<form>
<input />
<textarea />
<select /> <!-- etc. -->
<section id="verify">
<input />
<textarea />
<select /> <!-- etc -->
<button type="button">submit</button>
<!-- eg. sub-submission verifies data in section -->
</section>
<select />
<input />
<input type="submit" value="submit" />
</form>
<script>
$(document).ready(function() {
$("#verify button").on ('click', verify);
$('form').submit (formSend);
function verify (){
// get input data within section only (ie. within inner form)
var postData = $('#verify').filter(':input' ).serializeArray();
postData.push ({name:"submitId", value:'verify'});
var request = $.ajax ({
type: "POST",
url: "controller.php",
data: postData,
error: function (xhr, status, message){
alert (status);
}
});
}
function formSend (){
// get input data within entire form
var postData = $(this).serializeArray();
postData.push ({name:"submitId", value:'send'});
var request = $.ajax ({
type: "POST",
url: "controller.php",
data: postData,
error: function (xhr, status, message){
alert (status);
}
});
}
});
</script>

Submitting Ajax Form With SimpleModal (jQuery)

I have a form within a SimpleModal modal, but when I try to use serialize with jQuery, the form data is always blank. The form serialize works outside of the modal, so theres something preventing the serialize from grabbing the form data. This is the code I am using:
<div id="address_form" style="display:none">
<div id="contact-area">
<form id="address_form" action="submit" method="POST">
<label for="Street">Street:</label>
<input type="text" name="Street" id="street" />
<input type="submit" name="submit" class="submit-button" />
</form>
</div>
</div>
$("#address_form").submit(function(){
var data = $(this).serialize();
alert(data)
return false;
});

You have two elements with the id of address_form. Change the id on the DIV with that id and it will work.