i am newbie to jquery.I called a ajax when submit the form.But form submits before ajax complete the request.How to fix this issue? Below is my code
$("#formSearch").submit(
function() {
if (checkUserNumber($("#UserNumber").val())) {
$.ajax({
type : 'post',
url : 'CheckDetails.do',
data : {
userNumber:$("#UserNumber").val()
},
success : function(data) {
if (data == 'EI') {
$("#ErrMsg").text(
'User Number does not exist');
return false;
} else {
return true;
}
}
});
} else {
return false;
}
});
Any help will be greatly appreciated!!!
use event.preventDefault(); to prevent the form submission.
$("#formSearch").submit(
function(event) {
event.preventDefault();
...
...
....
});
You can apply trick to achieve your requirement, add a data attribute to target form as follows
<form id="formSearch" data-prevent-default="1">
set default value to data-prevent-attribute=1 than you can rewrite your jquery submit function as follows:
$("#formSearch").submit(function (e) {
if ($(this).data("prevent-default") === 1) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'CheckDetails.do',
data: {
userNumber: $("#UserNumber").val()
},
success: function (data) {
//on success change the value of data attribute to 0
$("#formSearch").data("prevent-default", "0");
$("#formSearch").submit(); //than call form submit again
}
}).fail(function () {
});
}
//otherwise it will submitted by default
});
Related
I am new to Ajax. I am currently submitting a form into my database using jQuery AJAX but it sends the same data multiple times in my database.
Here's my Ajax code :
$(document).ready(function () {
var id_js;
$(document).on('click', '.btn-success', function () {
id_js = $('#ID_TXT').val();
$('form').submit(function (e) {
e.preventDefault();
e.stopImmediatePropagation();
$.ajax({
type: "POST",
url: 'server.php',
data: {
'Mark': 1,
'id': id_js,
},
success: function (response) {
$('#result').html(response);
}
});
return false;
});
});
});
Also I have tried .one() and .stopImmediatePropogation() but still no results
I see both form submit and Ajax call are doing the same work. If you are going to post the data only with AJAX call then form submit is not required.
I hope this works well for you.
$(document).ready(function () {
function postDataToServer() {
var id_js = $('#ID_TXT').val();
$.ajax({
type: "POST",
url: 'server.php',
data: {
'Mark': 1,
'id': id_js,
},
success: function (response) {
$('#result').html(response);
}
});
}
$(document).on('click', '.btn-success', postDataToServer);
});
The submit handler shouldn't be inside the click handler. Every time you click on the button, it adds another submit handler. So when you finally submit the form, it will submit it as many times as you clicked on the button.
If you want to ensure that the form isn't submitted until you've clicked on the button, add a test in the submit handler.
$(document).ready(function() {
var id_js;
$(document).on('click', '.btn-success', function() {
id_js = $('#ID_TXT').val();
});
$('form').submit(function(e) {
if (id_js !== undefined) {
$.ajax({
type: "POST",
url: 'server.php',
data: {
'Mark': 1,
'id': id_js,
},
success: function(response) {
$('#result').html(response);
}
});
} else {
alert("You need to click on the success button first");
}
return false;
});
});
I have a form in an Asp.net MVC 5 project which has a Submit button. When the Submit button is clicked, I want to do the following:
Perform client=side validation using jQuery on various fields (required fields have been filled, email format is valid, etc...). That part is working fine.
Make an Ajax call that will perform some server side validation by calling an action from the controller and return a JSON response. The response contains a Success property and Errors property which contains a list of errors.
The Success property will return true if no error are found and the Errors property will be null. If errors are found the Success property is returns false and the Errors property contains a list of relevant errors.
I'm calling '\ApplicationForm\Validate' action from my ApplicationForm controller and this part is working fine.
When no errors are found in part 2, I want my form to be submitted as normal and call the '\ApplicationForm\Index' action so that my data can then be added to my database. I cannot get this part to work!!
The Submit button is defined as follows:
<div class="form-group">
<div>
<input type="button" id="btnApply" value="Apply" class="btn btn-primary" />
</div>
</div>
My JavaScript code is defined as follows:
$('#AppllicationForm').submit(function () {
if (!$(this).attr('validated')) {
if ($(this).valid()) {
$.ajax({
type: "POST",
data: $(this).serialize(),
url: "/ApplicationForm/ValidateForm",
dataType: 'json',
success: function (response) {
$('validationSummary').show();
if (response != null && response.success) {
console.log('No Validation errors detected');
$('#ApplicationForm').attr('validated', true);
$('#ApplicationForm').attr('action', '/ApplicationForm/Index')
.submit();
return true;
}
else if (response != null && !response.success) {
console.log('Validation errors detected');
var errors = response['errors'];
displayValidationErrors(errors);
window.scrollTo(0, 0);
}
return false;
},
error: function (response) {
$('validationSummary').hide();
console.log(response);
return false;
}
});
}
}
return false;
});
The above is using a regular button but I've also tried to define its type as Submit but to no avail.
I know similar questions have been posted in the past but I cannot find one that has actually helped me out to find a resolution to my problem, so please bear with me and do not mark this question as a duplicate unless there is an actual question/answer with an actual resolution to my problem. Much appreciated!
The closest scenario I found to what I'm trying to achieve is can be found from this article on SO: Submit a form from inside an ajax success function that checks the values
I've been trying so many different things at this stage but nothing is working out. I either don't get the Index action to be called after the ValidateForm action, or either one or the other action is called or the only Index action is called or my model gets messed up, and the list goes on.
I'm clearly not doing this correctly or missing something but I'm at a complete stand still for now. I'm hoping that it will be something silly that I've missed and hopefully someone will clarify this for me.
Any help would be greatly appreciated.
Try it out :
$('#btnApply').click(function (e) {
alert('submit');
e.preventDefault();
var form = $('form'); // change selector your form
if (!form.attr('validated')) {
if (form.valid()) {
$.ajax({
type: "POST",
data: form.serialize(),
url: "/ApplicationForm/ValidateForm",
dataType: 'json',
success: function (response) {
console.log('response received.');
if (response != null && response.success) {
console.log('No validation errors detected.');
form.attr('validated', true);
form.attr('action', '/ApplicationForm/Index')
.submit();
} else if (response != null && !response.success) {
console.log('Validation errors detected.');
var errors = response['errors'];
displayValidationErrors(errors);
window.scrollTo(0, 0);
}
},
error: function (response) {
console.log(response);
$('validationSummary').hide();
}
});
}
}
});
Please try it out:
$('#btnApply').on('click', function (e) {
e.preventDefault();
var form = $( "#AppllicationForm" );
if (!form.attr('validated')) {
if (form.valid()) {
$.ajax({
type: "POST",
data: $(this).serialize(),
url: "/ApplicationForm/ValidateForm",
dataType: 'json',
success: function (response) {
$('validationSummary').show();
if (response != null && response.success) {
console.log('No Validation errors detected');
form.attr('validated', true);
form.submit();
return true;
}
else if (response != null && !response.success) {
console.log('Validation errors detected');
var errors = response['errors'];
displayValidationErrors(errors);
window.scrollTo(0, 0);
}
return false;
},
error: function (response) {
$('validationSummary').hide();
console.log(response);
return false;
}
});
}
}
return false;
});
Your form action attribute will be '/ApplicationForm/Index'. When you click on the button, you make the validation and if everything is OK, then submit the form.
Please check below solution :
$('#btnApply').on('click', function (event) {
if ($('form').valid()) {
event.preventDefault();
$.ajax({
type: "POST",
data: $(this).serialize(),
url: "/ApplicationForm/ValidateForm",
dataType: 'json',
success: function (response) {
$('validationSummary').show();
if (response != null && response.success) {
console.log('No Validation errors detected');
$('#ApplicationForm').attr('validated', true);
$('form').submit(); // Here form will be submmited to Index action.
return true;
}
else if (response != null && !response.success) {
console.log('Validation errors detected');
var errors = response['errors'];
displayValidationErrors(errors);
window.scrollTo(0, 0);
}
return false;
},
error: function (response) {
$('validationSummary').hide();
console.log(response);
return false;
}
});
});
And decorate your ValidateForm method with [HttpPost] attribute.
I thought I'd share my solution as I ended up hiring a freelancer to have a look at it as I was under time constraint and could not afford to spend any more time on this.
How did it fix it? He added a second ajax call from within the first one. The annoying (and costly!) part is that I did try this but I had one important missing line i.e. var formValidated = $('#AppllicationForm').serialize();.
After these changes were made, I just had to rejig some of my logic regarding which div should be displayed and/or hidden but bar that it was pretty standard stuff.
Here's the final code that worked as expected:
$('#AppllicationForm').submit(function () {
if ($(this).valid()) {
$.ajax({
type: "POST",
data: $(this).serialize(),
url: "/ApplicationForm/ValidateForm",
dataType: 'json',
success: function (response) {
if (response != null && response.success) {
var formValidated = $('#AppllicationForm').serialize();
$.ajax({
url: '/ApplicationForm/Index',
data: formValidated,
type: 'POST',
success: function (result) {
$('#mainDiv').hide();
$('#Congrats').show();
}
});
return true;
}
else if (response != null && !response.success) {
var errors = response['errors'];
displayValidationErrors(errors);
window.scrollTo(0, 0);
}
return false;
},
error: function (response) {
$('validationSummary').hide();
return false;
}
});
}
return false;
});
Hope this helps others.
I am running an ajax request, then once I get the result back I choose if it should be continued or if the form should not submit. I am checking if the email exists.
Issue is I moved the return false out of the success: as it was not working there and now in a seperate function it is not working either. I get the alert("FALSE"); but the form still submits which is no good as I want an error pop up to happen.
$.ajax({
type: "POST",
url: "/ajax/checkdata.php",
data: "email="+email,
success: function(data){
var returned = true;
if (data == "Email Exists") {
returned = false;
} else {
}
emailModal(returned);
}
})
function emailModal(result){
if (result) {
alert("TRUE");
} else {
alert("FALSE");
return false;
}
}
You'd have to always prevent the form from submitting, and then in the check for the email figure out wether to show an error or submit the form using the native submit handler
$('form').on('submit', function(e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "/ajax/checkdata.php",
data: {email : email},
context: this
}).done(function(data) {
if (data == "Email Exists") {
alert(data);
} else {
this.submit();
}
});
});
I would like to merge two JavaScripts. The first one is using ajax to send message and the second one to alert user about required field in the contact form.
I want to merge this two, maybe with an IF statement, so first to check all fields and then to send message.
1 with ajax JavaScript:
$('document').ready(function () {
$('form#contact-form').submit(function () {
var form = $(this);
var post_data = form.serialize(); //Serialized the form data for process.php
$('#loader').html('<img src="../spinner.gif" /> Please Wait...');
form.fadeOut(500, function () {
form.html("<h3>Thank you.").fadeIn();
$('#loader').html('');
});
// Normally would use this
$.ajax({
type: 'POST',
url: 'process.php', // Your form script
data: post_data,
success: function(msg) {
form.fadeOut(500, function(){
form.html(msg).fadeIn();
});
}
});
return false;
});
});
2 alert JavaScript:
$('document').ready(function () {
$('form#contact-form').submit(function(e) {
var ref = $(this).find("[required]");
$(ref).each(function(){
if ( $(this).val() == '' )
{
alert("Required field should not be blank.");
$(this).focus();
e.preventDefault();
return false;
}
}); return true;
});
});
From the answer below i have create the following code.
I made this link if someone wants to help. The alert works fine but the code not stop. It continue to load the rest code.
https://jsfiddle.net/L8huq1t1/
You can do this by the following code.
function checkValidation() {
var ref = $(this).find("[required]");
$(ref).each(function(){
if ( $(this).val() == '' )
{
alert("Required field should not be blank.");
$(this).focus();
//e.preventDefault();
return false;
}
});
return true;
}
$('document').ready(function () {
$('form#contact-form').submit(function () {
if(!checkValidation()) {
return false;
}
var form = $(this);
var post_data = form.serialize(); //Serialized the form data for process.php
$('#loader').html('<img src="../spinner.gif" /> Please Wait...');
form.fadeOut(500, function () {
form.html("<h3>Thank you.").fadeIn();
$('#loader').html('');
});
// Normally would use this
$.ajax({
type: 'POST',
url: 'process.php', // Your form script
data: post_data,
success: function(msg) {
form.fadeOut(500, function(){
form.html(msg).fadeIn();
});
}
});
return false;
});
});
But I give you a suggestion to use jquery.validate plugin which is better option. But if you still want to do like this, go ahead this is also works fine.
You can use jQuery Validation plugin that has a form submit handler where you can put your AJAX. Link to the plugin.
Your code should look something like this:
$('#contact-form').validate({
rules: {
your_input_name: {
required: true
}
},
messages: {
your_input_name: {
required: 'Field is required'
}
},
submitHandler: function() {
var form = $(this);
var post_data = form.serialize(); //Serialized the form data for process.php
$('#loader').html('<img src="../spinner.gif" /> Please Wait...');
form.fadeOut(500, function() {
form.html("<h3>Thank you.").fadeIn();
$('#loader').html('');
});
// Normally would use this
$.ajax({
type: 'POST',
url: 'process.php', // Your form script
data: post_data,
success: function(msg) {
form.fadeOut(500, function() {
form.html(msg).fadeIn();
});
}
});
return false;
}
});
HTML5 validation isn't working in Safari so I'm using Happy.js.
My form is still submitting via ajax in Safari though with the code below (here is JSFiddle).
How can I validate #email-input before sending the form with ajax?
The code below is checking if ($(this).hasClass('unhappy')) then don't submit form, if it doesn't have class unhappy then submit form. But I guess the problem is that it doesn't have class unhappy from the beginning.
used from this reference: isHappy.js allowing ajax call when not valid
$(document).ready(function() {
function ajaxEmailForm() {
$(".sendingEmailLink, .sentEmailLink").hide();
$('#email-form').submit(function(event) {
event.preventDefault();
var formserialize = $(this).serialize();
var submitButton = $('#submitEmailForm');
$.ajax({
type: 'POST',
url: 'https://formkeep.com/f/MYID',
accept: {
javascript: 'application/javascript'
},
data: formserialize,
beforeSend: function() {
$(".sendEmailLink").hide();
$('.sendingEmailLink').show();
},
complete: function() {
$(".sendingEmailLink").hide();
},
success: function(d) {
$('.sentEmailLink').show();
},
error: function() {
$('.notification-e--phone').slideDown("medium", function() {});
},
}).done(function(data) {
submitButton.prop('disabled', 'disabled');
});
});
};
$('#email-form').isHappy({
fields: {
'#email-input': {
required: true,
test: happy.email,
message: 'Please enter your full email address.',
errorTarget: '.email-input-error'
}
}
});
var is_unhappy = false;
$('#email-form div :input').each(function(i) {
if ($(this).hasClass('unhappy')) {
is_unhappy = true;
return false;
}
});
if (!is_unhappy) {
ajaxEmailForm();
};
});