I'm trying to create a GUI to let the user edit any row that is displayed in my table. I've manage to create a form that pops up when the user clicks an image which symbolize an edit icon. Now I like to use Jquery (if possible) to fill this form with data from my DB. The error code is down bellow and I can't seem to get any results at all
Script
<script type="text/javascript">
$(document).ready(function(){
$('#edit').click(function() {
$.ajax({
url: 'edit.php?itemid=$itemid',
success: function(response) {
$('#itemid').val($itemid);
......
$('#status').val($status);
}
});
});
});
</script>
Edit.php
<?php
$DB = new mysqli("localhost", "root", "", "book1");
$result2 = mysqli_query($DB, "SELECT * FROM booking WHERE itemID='$itemid'");
while($row = mysqli_fetch_array($result2)){
$itemid = $row['itemID'];
......
$status = $row['status'];
}
echo (array($itemid, $userid, $description, $manufacturer, $model, $caldate, $duedate, $shelf, $status);
?>
Form
<div id="light1" class="white_content">
<form id="editform" name="myForm" action="checkout.php" method="POST">
<h2>Edit Instrument</h2>
<label>ItemID:</label>
<input type="text" id="itemid"/>
<br>
......
<a>Status: </a>
<input type="text" id="status"/>
<br>
<input type="submit" value="Accept">
<input href = "javascript:void(1)" onclick = "document.getElementById('light1').style.display='none';document.getElementById('fade').style.display='none'" type="reset" value="Close">
<br>
</form>
</div>
Error
ReferenceError: $itemid is not defined
$('#itemid').val($itemid);
change
$('#itemid').val($itemid);
to
$('#itemid').val('<?php echo $itemid; ?>');
Related
I want to stop page refresh after the user submits the form. The problem is that it doesn't seem to work.
PHP:
<?php
function displayimage() {
$con = mysqli_connect("localhost", "root", "", "cookbook");
$result = mysqli_query($con, "SELECT * FROM product");
while ($row = mysqli_fetch_array($result)) {
echo "<img src='uploads/".$row['image']."' class='imageaaa'>";
}
mysqli_close($con);
}
function addrecipe() {
$con = mysqli_connect("localhost", "root", "", "cookbook");
if (isset($_POST["Add"])) {
if (!empty($_POST["Name"])
){
$name = $_POST["Name"];
$type = $_POST["Type"];
$image = $_FILES['Image']['name'];
$date = date("d.m.Y, G:i");
$sql = "
INSERT INTO
product(`name`, `type`, `image`, `date`)
VALUES('$name', '$type', '$image', '$date');
// More Insert Into queries
";
$target = "uploads/".basename($image);
if (move_uploaded_file($_FILES['Image']['tmp_name'], $target)) {
$msg = "Image uploaded successfully";
} else {
$msg = "Failed to upload image";
}
$var = mysqli_multi_query($con,$sql);
if($var){
echo "good";
} else {
echo "bad";
}
} else {
echo "Fill in the form";
}
}
mysqli_close($con);
}
?>
HTML:
<?php
addrecipe();
displayimage();
?>
<form method="POST" id="form" enctype='multipart/form-data'>
Name:
<input type="text" name="Name" value="<?php echo isset($_POST['Name'])?htmlspecialchars($_POST['Name'], ENT_QUOTES):'';?>"><br>
Type:
<select name="Type" required>
<option value="dishes" disabled selected hidden required>Wybierz typ</option>
<option value="dishes">Dania</option>
<option value="desserts">Desery</option>
<option value="snacks">Przekąski</option>
</select><be>
Image (jpg, png):
<input type="button" id="loadFileXml" value="loadXml" onclick="document.getElementById('upload_image').click();" />
<input type="file" style="display:none;" id="upload_image" name="Image">
<br><be>
<!-- More text inputs -->
<button name="Add" id="add">sdfsdfsd</button>
<script>
$("#add").submit(function(e) {
e.preventDefault();
});
</script>
</form>
I've tried a few things, but nothing seems to work. Everything works ok, data is sent to the database, but I can't get rid of this page reload. Did I do something wrong? If there is a better solution I'd love to know it. Also, I have this js code:
<script>
if (window.history.replaceState){
window.history.replaceState(null, null, window.location.href);
}
</script>
After my HTML tag, deleting it changes nothing. It disables the resubmit form pop-up before you refresh the page.
Is there any way I can disable page refresh after form submission?
The <script> tag should be outside of the <form> tag and should contain #form instead of #add
...
</form>
<script>
$("#form").submit(function(e) {
e.preventDefault();
});
</script>
The .submit() method is applied on the form element.
You can also achieve the same by simply returning false from the handler as mentioned in the spec.
...
</form>
<script>
$("#form").submit(() => false);
</script>
I have an problem, I have multiple button generate with while, with different names (button[$nostation]).
Now, I want to update MySQL database (table: smt, column: no) with the same id ($nostation).
How I can generate AJAX function for that?
This is my code:
<?php
$query1 = mysqli_query($connect,"SELECT * FROM smt WHERE no <= 15");
while ( $data=mysqli_fetch_array($query1)){
$nostation = $data['no'];
$namastation = $data['name'];
echo "
<div class='col-xs-2-2'>
<form action='coba.php' method='post'>
<button name='button[$nostation]' value='2' style='background-color:#02780d; width:140px; height:75px; margin : 2px; border-radius:10%;'>
<center>
<b style='font-size:15px; color: #fff; font-family:Calibri;'>$namastation</b>
</center>
</button>
</form>
</div>
";}?>
And this is my code for update database with PHP:
<?php
include 'connect.php';
$array=$_POST['button'];
foreach ($array as $nostation => $value) {
$updch=mysqli_query($connect,"UPDATE smt SET status='$value' WHERE no='$nostation'");
}?>
How I can update with AJAX without refreshing the page?
View Part :-
<?php
$query1 = mysqli_query($connect,"SELECT * FROM smt WHERE no <= 15");
while ( $data=mysqli_fetch_array($query1)){
$nostation = $data['no'];
$namastation = $data['name'];
?>
<div class='col-xs-2-2'>
<form method='post'>
<input type="hidden" value="<?php echo $nostation;?>" id="name_<?=$nostation;?>" name="name">
<button type="submit" id="button_<?=$nostation;?>" data-id="<?=$nostation;?>">SAVE</button>
<center>
<b style='font-size:15px; color: #fff; font-family:Calibri;'>$namastation</b>
</center>
</button>
</form>
</div>
<?php } ?>
jQuery / AJAX Part:-
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script>
$(document).ready(function(){ //when DOM is Ready.
$("[id^=button_]").click(function () { //when Button is Clicked.
var id = $(this).data('id'); // Get the ID of the button that was clicked on.
var name = $("#name_"+id).val(); // value from `input` which is connected the clicked button.
// console.log(id+"---"+name);
$.ajax({ // AJAX request
url: 'update.php', // send request to server.
method: 'POST', // method is POST.
data: { //data which is sent to server.
id: id,name: name
},
success: function (data) { //success function called.
alert(data); // alert success data.
}
});
});
});
</script>
update.php:-
And in the php-side We catch it by:-
echo $id = $_POST['id'];
echo $name = $_POST['name'];
//use update query.
Note:- For more info regarding click()
https://api.jquery.com/click
I have a div which contains a button(Book it).When I press the button I want to add to the current url the id of the item I clicked on.Then get that id to pop up a box with clicked item data without refreshing the page, because I need to pop up in the current page.
Here it gets the treatments Id
<div class="treatments">
<ul>
<?php
global $treatments;
foreach($treatments as $treatment){
echo ' <li>'.$treatment['name'].'</li>';
};
?>
</ul>
<div class="line"></div>
</div>
<div class="treatment-items">
<?php
global $iController;
$items;
if(isset($_GET['treatmentID'])){
$items = $iController->getItemByTreatmentId($_GET['treatmentID']);
}else{
$items = $iController->getItemByTreatmentId(4);
}
foreach($items as $item){
echo '
<div class="col-30 items">
<div>
<p>'.$item['id'].'</p>
<img src="'.$item['img_url'].'" alt="'.$item['name'].'" />
<h3>'.$item['name'].'</h3>
<p>'.$item['time'].' min</p>
<p>'.$item['price'].'$</p>
<input type="hidden" id="hidden_input" name="id_item" value="'.$item['id'].'">
<a class="bookBtn" id="btn"><button>BOOK IT</button></a> // when I press this button I want that box to pop up
</div>
</div>
';
}
?>
</div>
Pop up box
<div class="bookDetails">
<div class="details">
<?php
global $iController;
$itemm;
if(isset($_GET['id_item'])){
$itemm = $iController->getItemById($_GET['id_item']);
}
echo'
<h1>Book your treatment</h1>
<p>Treatment Name : '.$itemm['name'].'</p>
<p>Treatment Time :'.$itemm['time'].' </p>
<p>Treatment Price : '.$itemm['price'].'</p>
';
?>
<form action="" method="POST">
<label for="date">Choose your date:</label>
<input type="date" for="date" name="date"><br>
<input type="submit" value="Cancel" id="cancel">
<input type="submit" value="Book Now">
</form>
Jquery code
$(".bookBtn").click(function(){
$(".bookDetails").show();
})
getItemById function
public function getItemById($id){
$sql="SELECT * FROM treatments_item WHERE id=$id";
echo $id;
$items = mysqli_query($this->connection,$sql);
$returnArray = array();
if($items){
while($row = mysqli_fetch_assoc($items)){
array_push($returnArray, $row);
}
return $returnArray[0];
}else{
echo'It doesn't work';
}
}
You can use ajax or mix php and javascript like this:
<script>
$(document).ready(function() {
<?php session_start(); ?>//Remove session_start
if (!<?php $_GET(['id'])?'true':'false'; ?>) {
alert something
} else {
something ..
}
});
</script>
hope this was helpful. :)
<div class="treatment-items">
<?php
global $iController;
$items;
if(isset($_GET['treatmentID'])){
$items = $iController->getItemByTreatmentId($_GET['treatmentID']);
}else{
$items = $iController->getItemByTreatmentId(4);
}
foreach($items as $item){
echo '
<div class="col-30 items">
<div>
<p>'.$item['id'].'</p>
<img src="'.$item['img_url'].'" alt="'.$item['name'].'" />
<h3>'.$item['name'].'</h3>
<p>'.$item['time'].' min</p>
<p>'.$item['price'].'$</p>
<input type="hidden" class="id_item" value="'.$item['id'].'">
<div class="bookBtn"><button>BOOK IT</button></div> // when I press this button I want that box to pop up
</div>
</div>
';
}
?>
Note: Never use id same name in one Page i.e., id="hidden_input" // In for loop same name will be generated. It will create bug down the line. Same goes for Input name, instead use class.
$(document).ready(function(){
$('body').on('click','.bookBtn',function(){
var treatmentID = $(this).siblings('.id_item').val();
// $(this) --> it will read the data of the property you have clicked
// .siblings --> adjacent class with name ('.id_item')
$.ajax({
url: 'treatments.php',
type: "get", //send it through get method
data: {
treatmentID: treatmentID
},
success: function(response) {
//operation to show the data in div
//e.g., $('#divId').html(data.name);
$(".bookDetails").show();
}
});
})
})
So i am haveing this page where it is displaying articles andunderneet each article it will have a textarea asking allowing the user to insert a comment.I did the AJAX and it works fine.Some of the validation works fine aswell(Meaning that if the textarea is left empty it will not submit the comment and display an error).The way i am doing this validation is with the ID.So i have multi forms with the same ID.For the commets to be submited it works fine but the validtion doesnt work when i go on a second form for exmaple it only works for the first form
AJAX code
$(document).ready(function(){
$(document).on('click','.submitComment',function(e) {
e.preventDefault();
//send ajax request
var form = $(this).closest('form');
var comment = $('#comment');
if (comment.val().length > 1)
{
$.ajax({
url: 'ajax_comment.php',
type: 'POST',
cache: false,
dataType: 'json',
data: $(form).serialize(), //form serialize data
beforeSend: function(){
//Changeing submit button value text and disableing it
$(this).val('Submiting ....').attr('disabled', 'disabled');
},
success: function(data)
{
var item = $(data.html).hide().fadeIn(800);
$('.comment-block_' + data.id).append(item);
// reset form and button
$(form).trigger('reset');
$(this).val('Submit').removeAttr('disabled');
},
error: function(e)
{
alert(e);
}
});
}
else
{
alert("Hello");
}
});
});
index.php
<?php
require_once("menu.php");
?>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" type="text/javascript"></script>
<script src="comments.js" type="text/javascript" ></script>
<?php
$connection = connectToMySQL();
$selectPostQuery = "SELECT * FROM (SELECT * FROM `tblposts` ORDER BY id DESC LIMIT 3) t ORDER BY id DESC";
$result = mysqli_query($connection,$selectPostQuery)
or die("Error in the query: ". mysqli_error($connection));
while ($row = mysqli_fetch_assoc($result))
{
$postid = $row['ID'];
?>
<div class="wrapper">
<div class="titlecontainer">
<h1><?php echo $row['Title']?></h1>
</div>
<div class="textcontainer">
<?php echo $row['Content']?>
</div>
<?php
if (!empty($row['ImagePath'])) #This will check if there is an path in the textfield
{
?>
<div class="imagecontainer">
<img src="images/<?php echo "$row[ImagePath]"; ?>" alt="Article Image">
</div>
<?php
}
?>
<div class="timestampcontainer">
<b>Date posted :</b><?php echo $row['TimeStamp']?>
<b>Author :</b> Admin
</div>
<?php
#Selecting comments corresponding to the post
$selectCommentQuery = "SELECT * FROM `tblcomments` LEFT JOIN `tblusers` ON tblcomments.userID = tblusers.ID WHERE tblcomments.PostID ='$postid'";
$commentResult = mysqli_query($connection,$selectCommentQuery)
or die ("Error in the query: ". mysqli_error($connection));
#renderinf the comments
echo '<div class="comment-block_' . $postid .'">';
while ($commentRow = mysqli_fetch_assoc($commentResult))
{
?>
<div class="commentcontainer">
<div class="commentusername"><h1>Username :<?php echo $commentRow['Username']?></h1></div>
<div class="commentcontent"><?php echo $commentRow['Content']?></div>
<div class="commenttimestamp"><?php echo $commentRow['Timestamp']?></div>
</div>
<?php
}
?>
</div>
<?php
if (!empty($_SESSION['userID']) )
{
?>
<form method="POST" class="post-frm" action="index.php" >
<label>New Comment</label>
<textarea id="comment" name="comment" class="comment"></textarea>
<input type="hidden" name="postid" value="<?php echo $postid ?>">
<input type="submit" name ="submit" class="submitComment"/>
</form>
<?php
}
echo "</div>";
echo "<br /> <br /><br />";
}
require_once("footer.php") ?>
Again the problem being is the first form works fine but the second one and onwaord dont work properly
try this:
var comment = $('.comment',form);
instead of
var comment = $('#comment');
That way you're targeting the textarea belonging to the form you're validating
ps.
remove the id's from the elements or make them unique with php, all element id's should be unique
I am working on a web site which displays some data that is retrieved from a database using php. Now, there are also other chekcboxes, which are included in a form. Based on the user input on these checkboxes, i wanted the div displaying the data to reload. For example, after a user checks one of the boxes and clicks apply, the div displaying should recompute the results. I realise that the form data must be passed onto an ajax function. Which would convert this form data into a json object and send it across to a php file. The php file can then access the form variables using $_POST['var']. I hope i have got the theory correct. Nevertheless, i have a number of problems during execution.
Firstly, the php code that deals with the form variables in on the same page as the form. I want to know how to direct the form data from the ajax function to this code.
Secondly, the ajax function is getting executed alright, the form is getting submitted, the page isn't reloading (as desired) but however, I am not able to access the submitted variables in the php code.
Here is my code:
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('#filter_form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'index.php',
data: $('#filter_form').serialize(),
success: function () {
alert('form was submitted');
}
});
e.preventDefault();
});
});
</script>
<div style="float: left;margin-left: -175px;" class="box2">
<h2>Filter by :</h2>
<form id="filter_form" name="filter_form" href="#">
<!--<form id="filter_form" name="filter_form" action="<?php echo $_SERVER['PHP_SELF'];?>" method ="post" href="#">-->
<h3>Location</h3>
<?php
//Get all the distinct values for filter. For example, Get all the locations available, display them in a container. Similarly for the party type as well. Connect to to the database once, get all these values,
//store them in arrays and use the arrays to display on screen.
$query = "Select LOCATION, PARTY_TYPE, GENRE, HAPPY_HOURS, OUTDOOR_ROOFTOP from venue_list order by HAPPY_HOURS";
$result = mysqli_query($con,$query);
$filter_array = array(5);
for($i=0; $i<5; $i++){
$filter_array[$i] = array();
}
while($row = mysqli_fetch_array($result)){
array_push($filter_array[0],$row['LOCATION']);
array_push($filter_array[1],$row['PARTY_TYPE']);
array_push($filter_array[2],$row['GENRE']);
array_push($filter_array[3],$row['HAPPY_HOURS']);
array_push($filter_array[4],$row['OUTDOOR_ROOFTOP']);
}
for($i=0; $i<5; $i++){
$filter_array[$i] = array_unique($filter_array[$i]);
}
?>
<ul>
<?php
foreach($filter_array[0] as $location){
?>
<li>
<input type="checkbox" id="f1" name="location[]" value="<?php echo $location?>" <?php if (isset($_POST['location'])){echo (in_array($location,$_POST['location']) ? 'checked' : '');}?>/>
<label for="f1"><?php echo $location?></label>
</li>
<?php
}
?>
</ul>
<br>
<h3>Party Type</h3>
<ul>
<?php
foreach($filter_array[1] as $party_type){
?>
<li>
<input type="checkbox" id="f2" name="party_type[]" value="<?php echo $party_type?>" <?php if (isset($_POST['party_type'])){echo (in_array($party_type,$_POST['party_type']) ? 'checked' : '');}?>/>
<label for="f2"><?php echo $party_type?></label>
</li>
<?php
}
?>
</ul>
<br><h3>Genre</h3>
<ul>
<?php
foreach($filter_array[2] as $genre){
?>
<li>
<input type="checkbox" id="f3" name="genre[]" value="<?php echo $genre?>" <?php if (isset($_POST['genre'])){echo (in_array($genre,$_POST['genre']) ? 'checked' : '');}?>/>
<label for="f3"><?php echo $genre?></label>
</li>
<?php
}
?>
</ul>
<br>
<h3>Happy Hours</h3>
<ul>
<?php
foreach($filter_array[3] as $happy_hours){
?>
<li>
<input type="checkbox" id="f4" name="happy_hours[]" value="<?php if($happy_hours){ echo $happy_hours;} else {echo "Dont Bother";} ?>" <?php if (isset($_POST['happy_hours'])){echo (in_array($happy_hours,$_POST['happy_hours']) ? 'checked' : '');}?>/>
<label for="f4"><?php echo $happy_hours?></label>
</li>
<?php
}
?>
</ul>
<br>
<h3>Outdoor/Rooftop</h3>
<ul>
<?php
foreach($filter_array[4] as $outdoor_rooftop){
?>
<li>
<input type="checkbox" id="f5" name="outdoor_rooftop[]" value="<?php echo $outdoor_rooftop?>" <?php if (isset($_POST['outdoor_rooftop'])){echo (in_array($location,$_POST['outdoor_rooftop']) ? 'checked' : '');}?>/>
<label for="f5"><?php echo $outdoor_rooftop?></label>
</li>
<?php
$i=$i+1;
}
?>
</ul>
<br><br><br>
<div id="ContactForm" action="#">
<input name="filter_button" type="submit" value="Apply" id="filter_button" class="button"/>
</div>
<!--
<h2>Sort by :</h2>
<input type="radio" id="s1" name="sort" value="Name" <?php if (isset($_POST['sort'])){echo ($_POST['sort'] == 'Name')?'checked':'';}?>/>
<label for="f1"><?php echo 'Name'?></label>
<input type="radio" id="s1" name="sort" value="Location" <?php if (isset($_POST['sort'])){echo ($_POST['sort'] == 'Location')?'checked':'';}?>/>
<label for="f1"><?php echo 'Location'?></label>
<br><br><br>
<input name="filter_button" type="submit" value="Apply" id="filter_button" class="button"/>
-->
</form>
</div>
<div class="wrapper">
<h2>Venues</h2>
<br>
<div class="clist" id="clublist" href="#">
<?php
?>
<table id = "venue_list">
<tbody>
<?php
//Functions
//This function builds the query as every filter attribute is passed onto it.
function query_builder($var_name){
$append = strtoupper($var_name)." in (";
$i=0;
foreach($_POST[$var_name] as $array){
$append = $append."'{$array}'";
$i=$i+1;
if($i < count($_POST[$var_name])){
$append = $append.",";
}
else{
$append=$append.")";
}
}
return $append;
}
//We first need to check if the filter was set in the previous page. If yes, then the query needs to be built with a 'where'. If not the query will just display all values.
//We also need to check if order by is required. If yes, we will apply the corresponding sort, else we will just sort on the basis of location.
//The below 2 variables do the same.
$filter_set = 0;
$filter_variables = array('location','party_type','genre','happy_hours','outdoor_rooftop');
$map_array = array();
if(isset($_POST['location'])){
$filter_set = 1;
}
if(isset($_POST['party_type'])){
$filter_set = 1;
}
if(isset($_POST['genre'])){
$filter_set = 1;
}
if(isset($_POST['happy_hours'])){
$filter_set = 1;
}
if(isset($_POST['outdoor_rooftop'])){
$filter_set = 1;
}
if($filter_set == 1){
$query = "Select * from venue_list where ";
$append_query=array(5);
$j=0;
foreach($filter_variables as $var){
if(isset($_POST[$var])){
$append_query[$j] = query_builder($var);
$j=$j+1;
}
}
$h=0;
//Once all the individual where clauses are built, they are appended to the main query. Until then, they are stored in an array from which they are
//sequentially accessed.
foreach($append_query as $append){
$query=$query.$append;
$h=$h+1;
if($h < $j){
$query=$query." AND ";
}
}
}
else{
$query = "Select * from venue_list";
}
$result = mysqli_query($con,$query);
while($row = mysqli_fetch_array($result))
{
$name = $row['NAME'];
$img = $row['IMAGE_SRC'];
$addr = $row['ADDRESS'];
$location = $row['LOCATION'];
echo "<script type='text/javascript'>map_function('{$addr}','{$name}','{$img}');</script>";
?>
<tr>
<td>
<img src="<?php echo $img.".jpg"?>" height="100" width="100">
</td>
<td>
<?php echo $name?>
</td>
<td style="display:none;">
<?php echo $location?>
</td>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
<br>
</div>
All the 3 components are part of index.php. Kindly notify me if the code is unreadable or inconvenient I will edit it. Awaiting a solution. Thank you.
in this case change your javascript code to
var submiting = false;
function submitmyforum()
{
if ( submiting == false )
{
submiting = true;
$.ajax({
type: 'post',
url: 'index.php',
data: $('#filter_form').serialize(),
success: function () {
alert('form was submitted');
submiting = false;
}
});
}else
{
alert("Still working ..");
}
}
and change the form submit button to
<input name="filter_button" type="button" onclick="submitmyforum();" value="Apply" id="filter_button" class="button"/>
don't forget to change submit button type="submit" to type="button"