First: I KNOW this is a duplicate. I am creating this because none of the answers to all the other questions satisfy me. I have a very particular situation where I'm using yii and tryi I can't send it through ajax because the php and javascript are on the same page on the same page.
Basically what I'm asking is if you have a page that uses yii and chart js, and you need to render a page that requires two arguments from the clicked bar, which is represented by activeBars[0]:
<script>
canvas.onclick = function(event) {
var activeBars = getBarsAtEvent(event);
<?php $controller->functionThatRendersView($arg1 /**(activeBars[0].value*/,$arg2 /**(activeBars[0].label*/); ?>
}
I don't care if it will render automatically, that is another problem. I just need to get those arguments to the php.
Thanks.
Also, if it helps, I am passing those two values to javascript through php for loops:
labels: [<?php for ($i=1;$i<=$numberIssues;$i++) {
echo $i . ",";
}?>],
The problem with grabbing $i and putting it into the label argument is that I don't know which bar label is the clicked one, I need javascript to pass the clicked bar values back to php.
Explain to us again why you can't use ajax. You say "because the php and javascript are on the same page". That's not what ajax is - you need a different URL for the ajax request, and a separate PHP file or something to handle it.
Without ajax it's impossible for javascript to send information to PHP, because the PHP runs on the server before the javascript runs on the client. Unless of course you want to do a complete page refresh, which is slower and generally worse from the user perspective.
I found an answer to my question! I'm just doing this for anyone else who is stumbling:
To pass javasctipt variable var jsInteger = 5; to php you type (in javascript):
window.location.href = "yourPhpFile.php?phpInteger="+jsInteger;
You access the variable in php like so:
$phpInteger = $_GET['phpInteger'];
This will require a page refresh, and will redirect you to the php file.
Related
After a form is submitted from my php file it checks it, and then is supposed to call an exec function that will execute a binary file using the second file listed in the code. Shown below:
if (isset($_POST['admin']) && !empty($_POST['admin'])) {
echo exec('/home/mainshee/public_html/wp-content/themes/twentyseventeen/phantom/phantomjs-directory/bin/phantomjs /home/mainshee/public_html/wp-content/themes/twentyseventeen/phantom/phantomjs-directory/examples/bigdaddy.js');
}
The problem here is that the preceding javascript file bigdaddy.js has to take three arguments of its own in order to function. To solve this issue, I tried the following:
echo exec('/home/mainshee/public_html/wp-content/themes/twentyseventeen/phantom/phantomjs-directory/bin/phantomjs /home/mainshee/public_html/wp-content/themes/twentyseventeen/phantom/phantomjs-directory/examples/bigdaddy.js' $_POST['admin'] $_POST['user'] $_POST['password']);
This bricked my site.
Does anybody have any ideas how this may be done? All of the possible solutions I have found detail PHP to PHP, NOT PHP to Javascript. Thanks all!
you have to post back the javascript variable to your server before the server can handle the value. To do this you can either program a javascript function that submits a form - or you can use ajax / jquery. jQuery.post
Maybe the most easiest approach for you is something like this
function myJavascriptFunction() {
var javascriptVariable = "John";
window.location.href = "myphpfile.php?name=" + javascriptVariable;
}
On your myphpfile.php you can use $_GET['name'] after your javascript was executed.
I am selecting a payment method and making an AJAX call But I am not able to print the paymentOption parameter
I tried storing it in a cookie
if(paymentOption == "default_cod"){
processOrderWithCOD();
optionPayment = Cash;
}
document.cookie = "$payment_option = $this.optionPayment";
PHP:
<?php
$paymentOptionDisplay = $_COOKIE['payment_option'];
echo $paymentOptionDisplay ?>
I am just trying to print paymentOption but later on its value is changed so need to save it and print
You have to remember that if JS and PHP live in the same document, the PHP will be executed first (at the server) and the JS will be executed second (at the browser)--and the two will NEVER interact (excepting where you output JS with PHP, which is not really an interaction between the two engines).
In other words, if the two live in the same document and no extra interaction with the server is performed, JS can NOT cause any effect in PHP. Furthermore, PHP is limited in its effect on JS to the simple ability to output some JS or something in context of JS.
$paymentOptionDisplay = $_COOKIE['payment_option'];
Cookies usually will not be available until the page is reloaded / refreshed, which is why you're not getting the value that you're expecting. You'd really have to do the payment calculation in PHP and store it in a $_SESSION if you're looking for it to persist like a cookie.
I like to get fingerprint as php variable, I get the follow but do not want to work.
<p>fingerprint2: <strong id="fp2"></strong></p>
<script src="/fingerprintjs2/fingerprint2.js"></script>
<script>
var fp2 = new Fingerprint2();
fp2.get(function(result) {
console.log(result);
$("#fp2").text(result);
});
</script>
$myphpvar = "<script>document.write(fp2.get());</script>";
echo $myphpvar;
That's really not how PHP works at all. PHP cannot process client side JavaScript. If you want access to client side information in PHP then you should probably put it in a form and post it to another page in PHP. There are many good tutorials on PHP forms, such as this one.
The Javascript is run after the PHP has completed. Client side VS server side code. I have solved this in the past by running the PHP within a PHP file that renders an image. This method is often referred to pixel tracking.
Here are the basics, you need to pass your variables in Javascript to a PHP file that renders an image:
document.write("<img src=fingerprint.php?x="+x+"&y="+y+" width=1 height=1>");
In the above case it passed Javascript variables x and y to the PHP image.
Then the fingerprint.php script looks like:
<?php
header("Content-type: image/png");
session_start();
$x = $_REQUEST['x'];
$y = $_REQUEST['y'];
$_SESSION['x'] = $x;
$_SESSION['y'] = $y
// SHOW THE IMAGE
$im = imagecreatefrompng("fingerprint.png");
imagepng($im);
imagedestroy($im);
?>
The png image can be anything you want as it will just be a 1 x 1 image on your final screen. You now have the Javascript variables in your PHP. As the code starts a session you could write the variables to a session and collect them later in another script, or write them to a database and recover later. Try with my simple example to ensure you have it working then expand from there.
There are lots of ways you can send data from JavaScript back serverside
set a cookie and read it in the next request
request further content by injecting a script / IMG / iframe tag (but not using document.write) adding the fingerprint in the query of the url
make an AJAX request
add a hidden input to a form on the page - requires the user to navigate out of the page using the form
This question already has answers here:
How do I pass JavaScript variables to PHP?
(16 answers)
Closed 3 years ago.
First I thought that I had to convert JavaScript to PHP, but then I found out that I cannot because of server and client side executions. So now I simply want to send ONE variable
<script type="text/javascript">
function scriptvariable()
{
var theContents = "the variable";
}
</script>
to a PHP variable
<?php
$phpvariable
?>
That function in the JavaScript executes when let's say I click on a button.
Now I have no idea on how to assign that phpvariable to the JavaScript one to use the phpvariable to look up stuff in my database. I know I can add it to my url or some thing and refresh the page, but I would like to do it with AJAX as I might have to use this Ajax method further in my webpage.
So is there an easy way to do this without having to dump pages of code on my page to do one simple thing?
PHP runs on the server and Javascript runs on the client, so you can't set a PHP variable to equal a Javascript variable without sending the value to the server. You can, however, set a Javascript variable to equal a PHP variable:
<script type="text/javascript">
var foo = '<?php echo $foo ?>';
</script>
To send a Javascript value to PHP you'd need to use AJAX. With jQuery, it would look something like this (most basic example possible):
var variableToSend = 'foo';
$.post('file.php', {variable: variableToSend});
On your server, you would need to receive the variable sent in the post:
$variable = $_POST['variable'];
As Jordan already said you have to post back the javascript variable to your server before the server can handle the value. To do this you can either program a javascript function that submits a form - or you can use ajax / jquery. jQuery.post
Maybe the most easiest approach for you is something like this
function myJavascriptFunction() {
var javascriptVariable = "John";
window.location.href = "myphpfile.php?name=" + javascriptVariable;
}
On your myphpfile.php you can use $_GET['name'] after your javascript was executed.
It depends on the way your page behaves. If you want this to happens asynchronously, you have to use AJAX. Try out "jQuery post()" on Google to find some tuts.
In other case, if this will happen when a user submits a form, you can send the variable in an hidden field or append ?variableName=someValue" to then end of the URL you are opening. :
http://www.somesite.com/send.php?variableName=someValue
or
http://www.somesite.com/send.php?variableName=someValue&anotherVariable=anotherValue
This way, from PHP you can access this value as:
$phpVariableName = $_POST["variableName"];
for forms using POST method or:
$phpVariableName = $_GET["variableName"];
for forms using GET method or the append to url method I've mentioned above (querystring).
This question already has answers here:
How do I pass JavaScript variables to PHP?
(16 answers)
Closed 3 years ago.
First I thought that I had to convert JavaScript to PHP, but then I found out that I cannot because of server and client side executions. So now I simply want to send ONE variable
<script type="text/javascript">
function scriptvariable()
{
var theContents = "the variable";
}
</script>
to a PHP variable
<?php
$phpvariable
?>
That function in the JavaScript executes when let's say I click on a button.
Now I have no idea on how to assign that phpvariable to the JavaScript one to use the phpvariable to look up stuff in my database. I know I can add it to my url or some thing and refresh the page, but I would like to do it with AJAX as I might have to use this Ajax method further in my webpage.
So is there an easy way to do this without having to dump pages of code on my page to do one simple thing?
PHP runs on the server and Javascript runs on the client, so you can't set a PHP variable to equal a Javascript variable without sending the value to the server. You can, however, set a Javascript variable to equal a PHP variable:
<script type="text/javascript">
var foo = '<?php echo $foo ?>';
</script>
To send a Javascript value to PHP you'd need to use AJAX. With jQuery, it would look something like this (most basic example possible):
var variableToSend = 'foo';
$.post('file.php', {variable: variableToSend});
On your server, you would need to receive the variable sent in the post:
$variable = $_POST['variable'];
As Jordan already said you have to post back the javascript variable to your server before the server can handle the value. To do this you can either program a javascript function that submits a form - or you can use ajax / jquery. jQuery.post
Maybe the most easiest approach for you is something like this
function myJavascriptFunction() {
var javascriptVariable = "John";
window.location.href = "myphpfile.php?name=" + javascriptVariable;
}
On your myphpfile.php you can use $_GET['name'] after your javascript was executed.
It depends on the way your page behaves. If you want this to happens asynchronously, you have to use AJAX. Try out "jQuery post()" on Google to find some tuts.
In other case, if this will happen when a user submits a form, you can send the variable in an hidden field or append ?variableName=someValue" to then end of the URL you are opening. :
http://www.somesite.com/send.php?variableName=someValue
or
http://www.somesite.com/send.php?variableName=someValue&anotherVariable=anotherValue
This way, from PHP you can access this value as:
$phpVariableName = $_POST["variableName"];
for forms using POST method or:
$phpVariableName = $_GET["variableName"];
for forms using GET method or the append to url method I've mentioned above (querystring).