How to keep divs position fixed even after deleting its neighbors? - javascript

I have a simple script that creates and deletes divs when pushing buttons.
$("#add").click(function(){
$(document.body).append('<div class="bloc">'+(++_INDEX)+'</div>');
});
$("#del").click(function(){
$(".bloc:first").remove();
});
My issue is with the "Delete" part, I need all the divs to stay at their current position when deleting anything.
And once I recreate new ones, they should take up the blank space left from previously deleted ones.
Could this be done through HTML/CSS only ? If not, how can I solve this ?
Please see the code example here: https://jsfiddle.net/t6wvLyjb/

It is difficult to do that because once a div has been removed from the dom rest of the elements will rearrange. One way to do is create elements absolutely(which is also difficult) and store their locations. While deleting you will not have a problem but while adding you have to add them to the previously stored locations.
Another option is to change the visibility of blocks instead of removing them. When adding instead of creating new ones first make all the blocks visible first and then create new ones.
You can do something like this
var _INDEX = 0;
$(document).ready(function(){
$("#add").click(function(){
if(!$('.bloc.removed').length){
$(document.body).append('<div class="bloc">'+(++_INDEX)+'</div>');
}else{
$(".bloc.removed").first().removeClass('removed');
}
});
$("#del").click(function(){
$(".bloc:not(.removed)").first().addClass('removed');
});
});
var _INDEX = 0;
$(document).ready(function() {
$("#add").click(function() {
if (!$('.bloc.removed').length) {
$(document.body).append('<div class="bloc">' + (++_INDEX) + '</div>');
} else {
$(".bloc.removed").first().removeClass('removed');
}
});
$("#del").click(function() {
$(".bloc:not(.removed)").first().addClass('removed');
});
});
.bloc {
background-color: red;
margin: 8px;
padding: 6px;
float: left;
width: 200px;
height: 64px;
}
.removed {
visibility: hidden;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="button" value="Add" id="add" />
<input type="button" value="Del" id="del" />
<br/>
Here is a demo https://jsfiddle.net/dhirajbodicherla/t6wvLyjb/1/

Try using CSS making the position fixed or absolute. This way you will have the position of the element fixed to place.
I don't know if it will work when you delete elements but worth a shot.

Related

Iterate over Array on mouse move left or right over a div

I have an static Array of Strings and a div that contains a p element that contains one string at a time. What im trying to do is when you move across the div, you iterate over the array and change your text based on the current mouse position and thus position in the array.
The way i thought of doing this was
Getting div size in pixels, dividing this by the amounts of elements in the array.
Then i would check the mouseposition every time it changes and depending on its position (eg in the 52 section of the div) would change it to the 52 item in the array.
Am i overthinking this? Is there an easier way to do this?
Something like the solution below should work for you. Add a div/span/container of your choice for each string you want to add. Add an event listener that shows your string's container when you mouse-in, and removes the event listener when you mouse out. We use 'visibility: hidden' instead of 'display: none' to make sure your containing blocks still exist in the DOM.
Index.html:
<div class="container">
</div>
Main.css:
.container {
display: flex;
flex-direction: row;
background: #DDD;
width: 100%;
height: 200px;
}
.child {
width: 100%;
height: 100%;
color: black;
}
.hide {
visibility: hidden;
}
Index.js:
//Replace this with however you're getting your strings now
var stringContent = ["String #1", "String #2", "String #3"]
$(document).ready(function(){
//You can remove this if the number of strings are not dynamic and replace with the hardcoded html tags
for (var i = 0; i < stringContent.length; i++)
{
var eleToAdd = `<div class='child hide'>${stringContent[i]}</div>`
$(".container").append(eleToAdd)
}
$(".child").on("mouseenter", function(){
$(this).removeClass("hide");
})
$(".child").on("mouseout", function(){
$(this).addClass("hide");
})
})

Show div if another div has content

So I don't get why this isn't working. I want to show a Div when another div has a value. I got this code from stackoverflow and it's pretty simple. But it doesn't work for me. No console errors..
$(document).ready(function(){
if ($(".txt").html().length > 0) {
$('.btn-01').show();
}
});
If the html value of .txt is larger then 0 then show btn-01.
But it doesn't. In my web inspector it just says:
<div style="display: block;" class="btn-01"><p>Things</p></div>
If I remove the script it says:
<div class="btn-01"><p>Things</p></div>
So it does do something. I tried changing the show to hide. But no go.
<div style="display: none;" class="btn-01"><p>Things</p></div>
I tried:
$(document).ready(function(){
if ($(".txt").html().length > 0) {
$('.btn-01').addClass('showme);
}
});
btn-01 css:
.btn-01 {
background: #f60;
color: #fff;
border-radius: 2px;
padding: 5px;
text-align: center;
margin: 40px auto 0px auto;
width: 90%;
}
But that didn't work either. Does anyone know whats going on here?
Maybe I should work with an else statement? Help would be much appreciated.
JsFiddle
You need to either set the button to display none prior to the window loading or add an "else" statement to hide the element:
.btn-01{
display:none;
}
OR
$(document).ready(function(){
if ($(".txt").html().length > 0) {
$('.btn-01').show();
}
else
{
$('.btn-01').hide();
}
});
See the fiddle: https://jsfiddle.net/r89gg7tp/
IMPORTANT TO CONSIDER
If you have entered a line break between the starting and closing tags of the element, this will add to the length. You need to set the txt div to be in the following format:
<div class='txt'></div>
It may be better to change your function to this:
$(document).ready(function(){
if ($(".txt").html().trim(' ').length > 0) {
$('.btn-01').show();
} else {
$('.btn-01').hide();
}
});
This way you trim the whitespace before checking.
See the second fiddle: https://jsfiddle.net/r89gg7tp/3/
You need to hide the btn-01 with a "display:none" in the stylesheet and then execute your script.
I think you are having a "display:none !important" which is overriding the jquery show() function inline style.
This might help you.
$(document).ready(function(){
if (!$.trim($(".txt").html())){
$('.btn-01').addClass('showme');
}
});
Please let me know if you've any queries.
You can use .contents() with .toggle():
$(document).ready(function() {
$('.btn-01').toggle($(".txt").contents().length > 0);
});
.btn-01{display:none;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="txt">
<h3>Things Title</h3>
</div>
<div class="btn-01">
<p>Things</p>
</div>
You guys where all right. I needed to place the code in some Session file (Ajax). Now its working with the original code and even some that you provide.
Thanks!

How can I make the parent div draggable

I have a div containing three buttons. The div needs to be draggable, so that you can drag all three buttons around the screen together. That works fine, but the problem is that when I click on of the individual buttons it inherits the draggable id and it is draggable on it's own. I do not want that to happen. So my question is: how do I make my buttons draggable, but make them always stay together and keep them clickable. I added the code below, but here is a JSFiddle: http://jsfiddle.net/2ga50vvt/
So to be clear: the div also needs to be draggable through dragging one of the individual buttons, but then the rest of the div needs to stick with it. Now dragging an individual button only moves the button.
P.S. I do not want to use JQuery UI
HTML:
<div id="draggable" class="ui-widget-content">
<button ng-click="menu.shown = !menu.shown">MENU</button>
<br>
<button ng-click="disconnect()">CLOSE</button>
<br>
<button ng-click="">KEYS</button>
</div>
JS
$(document).ready(function() {
var $dragging = null;
$('body').on("mousedown", "#draggable", function(e) {
$(this).attr('unselectable', 'on').addClass('dragged');
var el_w = $('.dragged').outerWidth(),
el_h = $('.dragged').outerHeight();
$('body').on("mousemove", function(e) {
if ($dragging) {
$dragging.offset({
top: e.pageY - el_h / 2,
left: e.pageX - el_w / 2
});
}
});
$dragging = $(e.target);
}).on("mouseup", ".dragged", function(e) {
$dragging = null;
$(this).removeAttr('unselectable').removeClass('dragged');
});
});
CSS:
body {
padding: 50px;
}
.dragged {
background-color: yellow;
}
#draggable {
position: fixed;
width: 150px;
height 150px;
padding: 0.5em;
background: red;
background-color: black;
z-index: 1000;
cursor: move;
float: left;
}
Update 1
This is a working solution: http://jsfiddle.net/2ga50vvt/3/
However when I click on the div and start dragging the center of the div jumps to my cursor. It works great, but it looks a bit wonky. Is there a way to prevent the div from moving to my cursor?
Your help is most welcome.
You can read the target property of the event and return false to avoid all not #draggable to be draggable.
if(e.target.id !== "draggable") {
return false;
}
The edited fiddle:
http://jsfiddle.net/2ga50vvt/1/
It works perfectly, but one suggestion: don't target with ids because with this code you can't drag more of one element (ids must be unique), so the workaround is to write an attribute or a classname and play with it.
Good luck.
Use $dragging = $('#draggable'); instead of $dragging = $('e.target');
It will drag div if you try to drag using cursor on button. It will drag #draggable instead of target.
Working Fiddle
Presuming you're opposed to JQueryUI for it's file size, I'd still recommend a prebuilt solution because why reinvent the wheel?
Draggabilly is a really nifty library that I've used when resource size has been an issue. It's 20k minified (obviously even smaller gzipped) and available on a CDN - which in itself has lots of benefits e.g. caching.
$(function() {
$( "#draggable" ).draggabilly();
});
There's a few CSS hooks, different options, events etc.
JSFiddle here

Select <divs> within parent <div> using jQuery

I have a parent <div>, #amwcontentwrapper, which has a series of divs within it with their own classes and ids.
I want to use jQuery to select these child divs, and IF they have the class .amwhidden, do nothing, but if not, remove the .amwshown class and add the .amwhidden class.
This is what I have so far, but it is not working. I think it may be my selecting of the child divs within the parent.
Can anybody see any obvious problems? Thanks for your help.
if ($('#amwcontentwrapper > div').hasClass('amwhidden')){
} else {
$('#amwcontentwrapper > div').fadeIn(600, function(){
$('#amwcontentwrapper > div').removeClass('amwshown');
$('#amwcontentwrapper > div').addClass('amwhidden');
});
}
And here is the basic html that I am using:
<div class="amwshown" id="amwintro">
Intro Section, which should have the 'amwshown' class removed, and the
'amwhidden' class added, when the jQuery runs. Currently, this does not happen.
</div>
UPDATE: Using War10ck's solution in the comments below (i.e. $('#amwcontentwrapper > div.amwshown')) I have managed to get the classes changing as I wished. However, those which have had the .amwshown class removed and .amwhidden class added still show on the page, despite the CSS looking like this:
.amwhidden {
display:none;
}
.amwshown {
display:block;
}
Looking at the Dev Tools, it seems that, when the jQuery is run (on a click event) the classes are changing, but any classes which are having the .amwshown class added (thus displaying them on the page) are also having the a <style> tag added to them which makes them display:block;
When I then press another button, which should hide the aformentioned <div> to make way for another one, the class is being changed to .amwhidden, but that <style> tag is not being deleted, so even though it has the .amwhidden class, it is still on the page.
I've created a JSFiddle here, if anybody still wants to help!
`
$(document).ready(function() {
$('#buybutton').click(function() {
$('#amwcontentwrapper > div.amwshown').fadeIn(600, function() {
$(this).removeClass('amwshown').addClass('amwhidden');
});
if ($('#amwbuy').hasClass('amwshown')) {} else {
$('#amwbuy').fadeIn(600, function() {
$('#amwbuy').removeClass('amwhidden');
$('#amwbuy').addClass('amwshown');
});
}
});
$('#phdbutton').click(function() {
$('#amwcontentwrapper > div.amwshown').fadeIn(600, function() {
$(this).removeClass('amwshown').addClass('amwhidden');
});
if ($('#amwphd').hasClass('amwshown')) {} else {
$('#amwphd').fadeIn(600, function() {
$('#amwphd').removeClass('amwhidden');
$('#amwphd').addClass('amwshown');
});
}
});
});
#sidebar {
position: absolute;
left: 1%;
top: 1%;
font-size: 5em;
color: #000000;
width: 10%;
display: block;
background-color: red;
}
#amwcontentwrapper {
position: absolute;
left: 20%;
top: 5%;
}
.amwshown {
display: block;
}
.amwhidden {
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="amwsidebar">
<span class="sidebarbutton" id="phdbutton">PhD Button</span>
<br />
<br />
<span class="sidebarbutton" id="buybutton">Buy Button</span>
</div>
<div id="amwcontentwrapper">
<div class="amwshown" id="amwintro">
<p>An intro section to welcome the visitor. Disappears when one of the other sections is clicked.</p>
<br />
<br />
</div>
<div class="amwhidden" id="amwbuy">
Buy Section
</div>
<div class="amwhidden" id="amwphd">
PhD Section
</div>
</div>
`
You can use not to remove the elements you do not want, like this:
$('#amwcontentwrapper > div').not('.amwhidden')
.removeClass('amwshown')
.addClass('amwhidden');
And work with that.
Try this
$(document).ready(function() {
$("#amwcontentwrapper").children().each(function(elem, x) {
if ($(x).attr("class") == "amwhidden") {
alert($(x).attr("class"));
$(x).removeClass("amwhidden").addClass("amwshow");
alert($(x).attr("class"));
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div id="amwcontentwrapper">
<div class="amwhidden"></div>
<div></div>
<div></div>
</div>
You can try each as follow,
$("#amwcontentwrapper div").each(function(){
if($(this).hasClass('amwhidden'))
//DO something
else
//DO something
});
Thank you for all help, it has prompted some brainstorming which has solved this issue.
Instead of adding the .amwhidden class and removing the .amwhidden class using jQuery, I have just created a .amwsection class, which all the sections belong to which has an initial display value of none. So far, so good; all of the sections are not there when you load up the page.
Then I use the .css jQuery function to change the display:none to display:block when the corresponding button is clicked, and changing all other .amwsections to display:none. This works just fine, but the effect is quite abrupt; there is no fading in, as you would get if you used the .animate function. .animate, however, does not work with the display value.
.fadeOut and .fadeIn to the rescue! By wrapping the .css change in these, I can create a fading in/out effect and can still use the display value.
Here is one example of this code.
The #buybutton is the button to be pressed.
#amwintro is just something which appears when the page loads - it will now be set to display:none if this is the first button pressed.
The .amwsection are all of the hidden sections. This portion of the code just resets all of them. This and the #amwintro section happen very quickly (1/100th of a second) to keep response time good.
The #amwbuy is the specific section that I want to reveal. As you can see, this fades in over a longer period.
Currently only tested in Chrome, but I think I've got it!
$(document).ready(function () {
$('#buybutton').click(function() {
$('#amwintro').fadeOut(1, function() {
$(this).css({
display:'none',
});
});
$('.amwsection').fadeOut(1, function() {
$(this).css({
display:'none',
});
});
$('#amwbuy').fadeIn(600, function() {
$(this).css({
display:'block',
});
});
});
});

Created div elements' random margins not working

Problem and source code
I'm trying to create <div>s within another <div> at the click of a button. When the button is clicked, a new inner <div> is created (within the outer <div>) with a unique id. I have this part working but here's where I'm running into an issue: I want each inner <div> to have a random margin-top.
Javascript
function pressButton() {
number += 1;
makeDiv(number);
};
function makeDiv(x) {
var innerDiv = document.createElement("innerDiv" + x);
outer.appendChild(innerDiv);
innerDiv.setAttribute("style", "margin-top:" + Math.floor(Math.random()*51) + ";display:inline-block;width:48px;height:48px;background-color:#000;");
};
CSS:
#outer {
position:absolute;
white-space:nowrap;
height:118px;
overflow:auto;
width:100%;
padding:2px;
}
Result (after button is clicked 4 times)
<div id="outer">
<innerDiv1 style="margin-top:15;display:inline-block;width:48px;height:48px;background-color:#000;"></innerDiv1>
<innerDiv2 style="margin-top:23;display:inline-block;width:48px;height:48px;background-color:#000;"></innerDiv2>
<innerDiv3 style="margin-top:37;display:inline-block;width:48px;height:48px;background-color:#000;"></innerDiv3>
<innerDiv4 style="margin-top:0;display:inline-block;width:48px;height:48px;background-color:#000;"></innerDiv4>
</div>
The result (which I got from inspecting the inner elements in my browser) looks like everything worked - all the margin-tops are random like I wanted. However, the visual result is this:
As you can see, the black inner <div>s all have the same margin-top. What am I doing wrong? How can I make the created <div>s all have random margin-tops?
The CSS spec requires that a length (other than zero) that is missing a unit be treated as an error (and thus ignored). Therefore, add px to the end of your generated margin number, and all should be well.
Live Demo
Description
This happens, because you set the display:inline-block; property. This makes them all to be in one line, so they will allign to the innerDivx that has the highest margin-top.
Delete the display:inline-block; property and give them float:left;. If you want to keep the gap between them, also add margin-left:5px;. And don't forget that margin-top's value needs a unit. I think you wanted to use px.
Also <innerDivx> is not a valid HTML tag. You should change them to a <div> and use innerDivx as an id attribute. Also your tags use almost the same CSS styles so you should put the same ones to a class and add the class instead.
Full solution code
HTML
<button id="button1">Add box</button>
<div id="outer"></div>
JavaScript
var number = 0;
document.getElementById("button1").addEventListener("click", pressButton, false);
function pressButton() {
++number;
makeDiv(number);
};
function makeDiv(x) {
var innerDiv = document.createElement("div");
outer.appendChild(innerDiv);
innerDiv.className += " box";
innerDiv.setAttribute("id", "innerDiv" + x);
innerDiv.setAttribute("style", "margin-top:" + Math.floor(Math.random()*51) + "px;");
};
CSS
#outer {
position: absolute;
white-space: nowrap;
height: 118px;
overflow: auto;
width: 100%;
padding: 2px;
}
.box {
float: left;
width: 48px;
height: 48px;
background-color: #000;
margin-left: 5px;
}
This is likely caused by the position model used for inline-block elements - they're all being vertically-aligned at their bottom line in a row.
I suggest that you simplify this and use position: block with float: left
http://jsfiddle.net/2y5bJ/4/
I also suggest that you stick to standard elements to ensure cross-browser compatibility - don't create your own elements called innerDiv1 etc, but use div elements with unique IDs.
function makeDiv(x) {
var innerDiv = document.createElement("div");
outer.appendChild(div);
innerDiv.setAttribute('id', 'innerDiv' + x);
innerDiv.setAttribute("style", "margin-top:" + Math.floor(Math.random()*51) + "px;");
};
I think there is no tag available with name
<innerDiv1>
This may be the cause.

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