Storing a value of a variable in a text file - javascript

I have created a simple mechanism to grab a persons First and Last name (this is of course the very basic code). However I want to write the value of a variable to a text file. I have used some php, however it does not seem to work:
<?php $handle = fopen("log.txt", "a");
foreach($_GET as $variable => $value) {
fwrite($handle, $variable);
fwrite($handle, "=");
fwrite($handle, $value);
fwrite($handle, "\r\n");
}
fwrite($handle, "\r\n");
fclose($handle);
exit;
?>
Therefore, I was wondering if there was any of code I could use to place this information into the text file? Your help is appreciated.
Initial code:
<head>
<script>
function getDetails()
{
var firstName = document.getElementById("firstName");
var nameElement = document.getElementById("lastName");
var theName = firstName.value;
var theLastName = lastName.value;
document.getElementById("someDiv").innerHTML += theName += theLastName;
}
</script>
</head>
<html>
<div id="someDiv">
Details:
</div>
<br><br>
<input id="firstName" type="text">
<input id="lastName" type="text">
<input type="button" value="Go!" onClick="getDetails();">
<br>
</html>
I would however prefer Javascript.

To write on a file via php, you can use the file_put_content() function.
Here's a simple code example:
// The file where to write
$file = 'db.txt';
// The content
$file_content = $your_variable;
// Write the content
file_put_contents($file, $file_content);
You can also append content to the file:
// The file where to write
$file = 'db.txt';
// Old content
$file_content = file_get_contents($file);
// Old + new content
$file_content .= $your_variable;
// Write the content
file_put_contents($file, $file_content);
You can also append to a file file_put_contents flags:
// The file where to write
$file = 'db.txt';
// New content
$file_content = $your_variable;
// Write the content
file_put_contents($file, $file_content, FILE_APPEND | LOCK_EX);
// FILE_APPEND: used to append the new contents at the end of the file
// LOCK_EX : used to avoid another user to write on the same file at the same time

Related

How can I take command input using php with shell_exec()

I am working on a project that takes users c++ code as input and compiles it from the server and sends the output to the user.
But here, If the c++ code has something like taking input from the user then that time my code fails. I want to do something from which I can take users input also on my website.
This is my php code -
<?php $code = $_POST['code']; if($_SERVER['REQUEST_METHOD'] == "POST"){
$md5hash = md5($code);
$filename = $_SERVER['DOCUMENT_ROOT'] . "/code/" . $md5hash . ".cpp";
$filexe= $_SERVER['DOCUMENT_ROOT'] . "/code/" . $md5hash . ".exe";
$dir = $_SERVER['DOCUMENT_ROOT'] . '/code';
//this will make the directory if the directory is not present
if ( !file_exists($dir) )
{
mkdir ($dir, 0777);
}
$myfile = fopen($filename,"w") or die("Unable to open file!");
fwrite($myfile,$code); //Store the user submitted code into a file
fclose($myfile);
$command1 = "C:\TDM-GCC-32\bin\g++ " . $filename . " -o ". $filexe;
$output1 = shell_exec($command1 . " 2>&1");
$output = shell_exec($filexe . " 2>&1");
$input =
if(empty($output1)){
echo $output;
}else echo $output1; } ?>
This is my index.php code
<center><textarea name="code" id="code" placeholder="Enter your C++ source code here.. " rows="15" cols="100%" style="padding:10px;font-size:18px"></textarea></center>
<center><button onclick="runcode();" style="cursor:pointer;padding:5px;display:flex;align-content:center;text-decoration:none;justify-content:space-around;background:brown;color:white;width:50%;">Run code</button>
Output -
<div>
<center><textarea placeholder="waiting.... " rows="15" cols="100%" style="padding:10px;font-size:18px" id="out"></textarea></center>
</div>
<center>Fix Bug on this code!
<?php include 'components/_footer.php' ?>
<script>
function runcode(){
document.getElementById('myoutput').setAttribute("class","show");
$codevalue= document.getElementById('code').value;
const xhr = new XMLHttpRequest();
xhr.onload = function(){
const serverResponse = document.getElementById("out");
serverResponse.innerHTML = this.responseText;
};
xhr.open("POST","runcode.php");
xhr.setRequestHeader("Content-type","application/x-www-form-urlencoded");
xhr.send("code="+$codevalue);
}
</script>
I search on internet but couldn't find a better solution please help me to take the input from the user and showing the output to user also user should be able to put there input incase some program ask for user input

Adding and displaying multiple images [duplicate]

I have experience doing this with single file uploads using <input type="file">. However, I am having trouble doing uploading more than one at a time.
For example, I'd like to select a series of images and then upload them to the server, all at once.
It would be great to use a single file input control, if possible.
Does anyone know how to accomplish this?
This is possible in HTML5. Example (PHP 5.4):
<!doctype html>
<html>
<head>
<title>Test</title>
</head>
<body>
<form method="post" enctype="multipart/form-data">
<input type="file" name="my_file[]" multiple>
<input type="submit" value="Upload">
</form>
<?php
if (isset($_FILES['my_file'])) {
$myFile = $_FILES['my_file'];
$fileCount = count($myFile["name"]);
for ($i = 0; $i < $fileCount; $i++) {
?>
<p>File #<?= $i+1 ?>:</p>
<p>
Name: <?= $myFile["name"][$i] ?><br>
Temporary file: <?= $myFile["tmp_name"][$i] ?><br>
Type: <?= $myFile["type"][$i] ?><br>
Size: <?= $myFile["size"][$i] ?><br>
Error: <?= $myFile["error"][$i] ?><br>
</p>
<?php
}
}
?>
</body>
</html>
Here's what it looks like in Chrome after selecting 2 items in the file dialog:
And here's what it looks like after clicking the "Upload" button.
This is just a sketch of a fully working answer. See PHP Manual: Handling file uploads for more information on proper, secure handling of file uploads in PHP.
There are a few things you need to do to create a multiple file upload, its pretty basic actually. You don't need to use Java, Ajax, Flash. Just build a normal file upload form starting off with:
<form enctype="multipart/form-data" action="post_upload.php" method="POST">
Then the key to success;
<input type="file" name="file[]" multiple />
do NOT forget those brackets!
In the post_upload.php try the following:
<?php print_r($_FILES['file']['tmp_name']); ?>
Notice you get an array with tmp_name data, which will mean you can access each file with an third pair of brackets with the file 'number' example:
$_FILES['file']['tmp_name'][0]
You can use php count() to count the number of files that was selected. Goodluck widdit!
Full solution in Firefox 5:
<html>
<head>
</head>
<body>
<form name="uploader" id="uploader" action="multifile.php" method="POST" enctype="multipart/form-data" >
<input id="infile" name="infile[]" type="file" onBlur="submit();" multiple="true" ></input>
</form>
<?php
echo "No. files uploaded : ".count($_FILES['infile']['name'])."<br>";
$uploadDir = "images/";
for ($i = 0; $i < count($_FILES['infile']['name']); $i++) {
echo "File names : ".$_FILES['infile']['name'][$i]."<br>";
$ext = substr(strrchr($_FILES['infile']['name'][$i], "."), 1);
// generate a random new file name to avoid name conflict
$fPath = md5(rand() * time()) . ".$ext";
echo "File paths : ".$_FILES['infile']['tmp_name'][$i]."<br>";
$result = move_uploaded_file($_FILES['infile']['tmp_name'][$i], $uploadDir . $fPath);
if (strlen($ext) > 0){
echo "Uploaded ". $fPath ." succefully. <br>";
}
}
echo "Upload complete.<br>";
?>
</body>
</html>
in the first you should make form like this :
<form method="post" enctype="multipart/form-data" >
<input type="file" name="file[]" multiple id="file"/>
<input type="submit" name="ok" />
</form>
that is right . now add this code under your form code or on the any page you like
<?php
if(isset($_POST['ok']))
foreach ($_FILES['file']['name'] as $filename) {
echo $filename.'<br/>';
}
?>
it's easy... finish
<form action="" method="POST" enctype="multipart/form-data">
Select image to upload:
<input type="file" name="file[]" multiple/>
<input type="submit" name="submit" value="Upload Image" />
</form>
Using FOR Loop
<?php
$file_dir = "uploads";
if (isset($_POST["submit"])) {
for ($x = 0; $x < count($_FILES['file']['name']); $x++) {
$file_name = $_FILES['file']['name'][$x];
$file_tmp = $_FILES['file']['tmp_name'][$x];
/* location file save */
$file_target = $file_dir . DIRECTORY_SEPARATOR . $file_name; /* DIRECTORY_SEPARATOR = / or \ */
if (move_uploaded_file($file_tmp, $file_target)) {
echo "{$file_name} has been uploaded. <br />";
} else {
echo "Sorry, there was an error uploading {$file_name}.";
}
}
}
?>
Using FOREACH Loop
<?php
$file_dir = "uploads";
if (isset($_POST["submit"])) {
foreach ($_FILES['file']['name'] as $key => $value) {
$file_name = $_FILES['file']['name'][$key];
$file_tmp = $_FILES['file']['tmp_name'][$key];
/* location file save */
$file_target = $file_dir . DIRECTORY_SEPARATOR . $file_name; /* DIRECTORY_SEPARATOR = / or \ */
if (move_uploaded_file($file_tmp, $file_target)) {
echo "{$file_name} has been uploaded. <br />";
} else {
echo "Sorry, there was an error uploading {$file_name}.";
}
}
}
?>
If you want to select multiple files from the file selector dialog that displays when you select browse then you are mostly out of luck. You will need to use a Java applet or something similar (I think there is one that use a small flash file, I will update if I find it). Currently a single file input only allows the selection of a single file.
If you are talking about using multiple file inputs then there shouldn't be much difference from using one. Post some code and I will try to help further.
Update:
There is one method to use a single 'browse' button that uses flash. I have never personally used this but I have read a fair amount about it. I think its your best shot.
http://swfupload.org/
If you use multiple input fields you can set name="file[]" (or any other name). That will put them in an array when you upload them ($_FILES['file'] = array ({file_array},{file_array]..))
partial answer: pear HTTP_UPLOAD can be usefull
http://pear.php.net/manual/en/package.http.http-upload.examples.php
there is a full example for multiple files
i have created a php function which is used to upload multiple images,
this function can upload multiple images in specific folder as well it can saves the records into the database
in the following code
$arrayimage is the array of images which is sent through form
note that it will not allow upload to use multiple but you need to create different input field with same name as will you can set dynamic add field of file unput on button click.
$dir is the directory in which you want to save the image
$fields is the name of the field which you want to store in the database
database field must be in array formate
example
if you have database imagestore and fields name like id,name,address then you need to post data like
$fields=array("id"=$_POST['idfieldname'], "name"=$_POST['namefield'],"address"=$_POST['addressfield']);
and then pass that field into function $fields
$table is the name of the table in which you want to store the data..
function multipleImageUpload($arrayimage,$dir,$fields,$table)
{
//extracting extension of uploaded file
$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $arrayimage["name"]);
$extension = end($temp);
//validating image
if ((($arrayimage["type"] == "image/gif")
|| ($arrayimage["type"] == "image/jpeg")
|| ($arrayimage["type"] == "image/jpg")
|| ($arrayimage["type"] == "image/pjpeg")
|| ($arrayimage["type"] == "image/x-png")
|| ($arrayimage["type"] == "image/png"))
//check image size
&& ($arrayimage["size"] < 20000000)
//check iamge extension in above created extension array
&& in_array($extension, $allowedExts))
{
if ($arrayimage["error"] > 0)
{
echo "Error: " . $arrayimage["error"] . "<br>";
}
else
{
echo "Upload: " . $arrayimage["name"] . "<br>";
echo "Type: " . $arrayimage["type"] . "<br>";
echo "Size: " . ($arrayimage["size"] / 1024) . " kB<br>";
echo "Stored in: ".$arrayimage['tmp_name']."<br>";
//check if file is exist in folder of not
if (file_exists($dir."/".$arrayimage["name"]))
{
echo $arrayimage['name'] . " already exists. ";
}
else
{
//extracting database fields and value
foreach($fields as $key=>$val)
{
$f[]=$key;
$v[]=$val;
$fi=implode(",",$f);
$value=implode("','",$v);
}
//dynamic sql for inserting data into any table
$sql="INSERT INTO " . $table ."(".$fi.") VALUES ('".$value."')";
//echo $sql;
$imginsquery=mysql_query($sql);
move_uploaded_file($arrayimage["tmp_name"],$dir."/".$arrayimage['name']);
echo "<br> Stored in: " .$dir ."/ Folder <br>";
}
}
}
//if file not match with extension
else
{
echo "Invalid file";
}
}
//function imageUpload ends here
}
//imageFunctions class ends here
you can try this code for inserting multiple images with its extension this function is created for checking image files you can replace the extension list for perticular files in the code

placing php inside javascript

<script>
var strWidth = document.getElementById("mydiv").style.width;
var strHeight = document.getElementById("mydiv").style.height;
var link = "<?php if(isset($_GET["ggg"])) {
echo $_GET["ggg"].".php?width=800&height=460";
} else {
echo "page1.php?width=800&height=460";
}
?>";
</script>
this is my script, php inside javascript. how do i place this variable strWidth inside
php?width=800&height=460
so becomes some how like this
php?width=strWidth&height=460
EDIT 2
well, the only thing i am trying to do here to show variable value between those line is it a big deal ?
it might be done by separating like using concatenation or something ?
Add an input-field in PHP, hide it (if necessary) and read the value of this field with JS.
First of all if you want to use php values in javascript you need the script to be written in a php file. Suppose you do this then you can do this in this way:
<script>
var strWidth = document.getElementById("mydiv").style.width;
var strHeight = document.getElementById("mydiv").style.height;
var link='<?php echo (isset($_GET["ggg"]))?isset($_GET["ggg"]):''; ?>'; // this assigns the valueto link variable
if(link==''){
// your logic starts here
}else{
// your logic starts here
}
</script>
Add an input-field and assign a value to the hidden element and then get value through javascript.
It is not a good idea to combine PHP and Javascript.
Refer this about explanation on client-side vs server-side coding.
you can't really do that. but this works
<?php
echo "<script>\n";
echo "var strWidth = document.getElementById(\"mydiv\").style.width;\n";
echo "var strHeight = document.getElementById(\"mydiv\").style.height;\n";
if(isset($_GET["ggg"])) {
echo "var link =" . $_GET["ggg"] . ".php?width=800&height=460';\n";
}
else {
echo "var link ='page1.php?width=' + strWidth + '&height=' + strHeight + '';\n";
}
echo "</script>\n";
?>
the reference to ggg completely confuses the understanding of this process so really it should be taken out:
__ page1.php
<?php
if (!isset($_GET['foundWidth'])){
//stops double hit
echo "<script>\n";
echo "var strWidth = document.getElementById(\"mydiv\").style.width;\n";
echo "var strHeight = document.getElementById(\"mydiv\").style.height;\n";
echo "var link ='/page1.php?foundWidth=true&width=' + strWidth + '&height=' + strHeight + '';\n";
echo "window.location = link;"
echo "</script>\n";
}
elseif (isset($_GET['foundWidth']) && ($_GET['foundWidth']=='true')) {
if (isset($_GET['width']) && is_numeric($_GET['width'])){
//use your width here SERVER SIDE
// or
echo "<script> alert('Width is: '+ " . $_GET['width']) . "); </script>\n";
}
if (isset($_GET['height']) && is_numeric($_GET['height'])){
//use your height here SERVER SIDE
// or
echo "<script> alert('Height is: '+ " . $_GET['height']) . "); </script>\n";
}
}
?>
using this "trick" you can then write the PHP params into the javascript url with whatever get string you like, including triggering a reload of the page with the width as a param, so if you want to test if $_GET['width'] is set to a number you can insert it etc

passing array of string from php to html

I want to tranform a php array of string into html. My php and html code are in the same page.
I have $myvar that hold my array of string. I pass $myvar with POST and insert it to $ba.
My code needs to print on html page 3 line (in while loop).
But when I pass the $be, it writes me error message: "Notice: Undefined index: myvar" (in php code)
What do I need to repair so that my code prints to my screen all the 3 lines that I get from php?
my code:(php)
foreach ($docres as $key=>$filename) {
$counter = 0;
$file = $filename +1;
$handle = fopen($dir."/".$file.'.txt',"r");
if($handle)
{
while($counter < 3)
{
$myvar[]=fgets($handle);
$counter++;
}
}
}
$ba = implode("", $myvar);
my html code:
<form action="" method="POST">
<center>
<h1> My Search Engine </h1>
<input type = 'text' size='90' value='' name = 'search' > <br>
<input type = 'submit' name = 'submit' value = 'Search source code'>
</center>
</form >
<p> <?php echo $ba ?> </p>
Simply echo the mysql query on a function and call it on HTML as follows:
UPDATE: 3rd column will be an image wich route are stored on database, and 4th col will be an image eich only the name was stored on database (because we know the full route) as example:
<?php
function printOnHtml(){
include ("connection.php");
$sql = "SELECT * FROM foo;"
if ($result = connection()->query($sql)){
$rs = $result->fetch_array(MYSQLI_NUM);
while ($rs[0] != ''){
echo "first column: ".$rs[0]." second column: ".$rs[1]." image with full route on database: <img src='".$rs[2]."' alt=''> <br> if only the img name is stored cuz we know the route: <img src='img_route/".$rs[3]."' alt=''>";
$rs = $result->fetch_array(MYSQLI_NUM);
}
}
}
Then on HTML
<html>
blablabla
<body>
blablabla
<?php
printOnHtml();
?>
blablabla
</body>
</html>
Note that it have to be a .php file to call the php function (for example index.php)
I paste the connection php script i use in order if you need it:
<?php
function connection(){
if($mysqli = new MySQLi("localhost","user","password","database_name")) echo "OK"; else echo "KO";
mysqli_set_charset($mysqli, "utf8");
return $mysqli;
}
?>
i did it with mysqli fetch array, but you can do the same using fetch assoc if you want.
UPDATE2: If you stubborness makes you follow using a txt to store data (wich, if increase will fail when you get a some thousands line txt), modify this on your code:
$myvar='';
foreach ($docres as $key=>$filename) {
$counter = 0;
$file = $filename +1;
$handle = fopen($dir."/".$file.'.txt',"r");
if($handle)
{
while($counter < 3)
{
if(isset($myvar)){
$myvar=fgets($handle);
}
$counter++;
}
}
}
and i'm supposing that you declared $dir, $file and other vars properly.
You NEVER have to use vars without declaring it (as NULL at least). You only can do this if you ensured 100% that this var will get a value at this point.
You have to convert the array to string in a correct way using implode and <br> as a separator
Then just print it using php tags (as you are using both at the same page ) you can access the variable direct and print it using <?= $ba ?> or <?php echo $ba ; ?>
Code will be :
<?php
foreach ($docres as $key=>$filename) {
$counter = 0;
$file = $filename +1;
$handle = fopen($dir."/".$file.'.txt',"r");
if($handle)
{
while($counter < 3)
{
$myvar[]=fgets($handle);
$counter++;
}
}
}
$ba = implode("<br>", $myvar);
?>
<form action="" method="POST">
<center>
<h1> My Search Engine </h1>
<input type = 'text' size='90' value='' name = 'search' > <br>
<input type = 'submit' name = 'submit' value = 'Search source code'>
</center>
</form >
<p id="deatiles"> <?= $ba ?> </p>

PHP `file_get_contents()` output pass to JavaScript and calculate length

I want to pass the output from PHP's file_get_contents() to JavaScript and calculate its length. Everything ok but when passing the variable JavaScript evaluates it as HTML code, so I have to use PHP's json_encode() to keep it "sane" but this way the string length from JavaScript will be different from the one in PHP. Using JS's JSON.parse() doesn't help because again the HTML code gets interpreted. Any idea how can I achieve the same evaluated data length?
EDIT: Basically I need to count all the characters in the page source, that includes tags and special characters. To have the same output computed in JS like the one i get in PHP's strlen($url_data).
EDIT 2: I thought about doing bin2hex() on the $url_data then reconvert in JS and check the length. Would be that reliable?
Here is what I did so far:
<?php
ini_set('display_erros', -1);
$error = '';
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
if (isset($_POST['urlinput']) && !filter_var($_POST['urlinput'], FILTER_VALIDATE_URL) === false) {
$url = filter_var($_POST['urlinput'], FILTER_SANITIZE_URL);
$url_data = #file_get_contents($url);
$js_url_data = json_encode($url_data);
//$url_src = htmlspecialchars($url, ENT_IGNORE);
$url_data_len = mb_strlen($url_data);
$url_src = strip_tags($url_data);
echo '<ul id="resultList">';
echo "<li>The following page contains " . $url_data_len . " characters</li>";
echo "<li>Page URL: " . $_POST['urlinput'] . "</li>";
echo "<li>Page title: " . page_title($url_data) . "</li>";
echo "<li>Protocol: " . parse_url($url, PHP_URL_SCHEME) . "</li>";
echo "<li>Host: " . parse_url($url, PHP_URL_HOST) . "</li>";
echo "</ul>";
//var_dump($url_src);
} else {
$error = "URL is not valid!";
}
}
function page_title($str) {
$matches = array();
if (preg_match('/<title>(.*?)<\/title>/i', $str, $matches)) {
return $matches[1];
}
else {
return null;
}
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>PHP file_get_contents()</title>
</head>
<body>
<div class="url_class">
<form id="getsrc" method="post">
<input style="width: 300px;" type="text" name="urlinput" id="urlinput" placeholder="URL">
<input type="submit" name="submit" value="Get SRC">
</form>
</div>
<textarea rows="20" cols="50">
<?php
if (!empty($url_src)) {
echo $url_src;
}
?>
</textarea>
<?php echo '<br><span style="color:red">' . $error . '<span>'; ?>
<?php
if (!empty($js_url_data)) {
$script = <<<EOT
<script>
var url_data = $js_url_data;
var node = document.createElement("li");
var textnode = document.createTextNode("JavaScript page characters: " + url_data.length);
node.appendChild(textnode);
document.getElementById("resultList").appendChild(node);
</script>
EOT;
echo $script;
}
?>
</body>
</html>
Simply use the value calculated by php, it can be used within EOT block:
...
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
if (isset($_POST['urlinput']) && !filter_var($_POST['urlinput'], FILTER_VALIDATE_URL) === false) {
...
$url_data = #file_get_contents($url);
$fileSize = strlen($url_data);
...
}
....
if (!empty($js_url_data)) {
$script = <<<EOT
<script>
...
var textnode = document.createTextNode("JavaScript page characters: " + $fileSize);
...
</script>
EOT;
echo $script;
Since no good answer, I would post my solution to my problem. The only way I could find was to hex-encode $url_data, pass it to JS, decode it and count the characters. For the pack() function I used the one ported in php.js.
...
$js_url_data = bin2hex($url_data);
...
if (!empty($js_url_data)) {
/* This is a good example when one is forced to use inline JS */
$script = <<<EOT
<script>
var url_data = "$js_url_data";
var url_data_len = pack('H*', url_data).length;
var node = document.createElement("li");
var textnode = document.createTextNode("JavaScript calculation page characters: " + url_data_len);
node.appendChild(textnode);
document.getElementById("resultList").appendChild(node);
</script>
EOT;
echo $script;
...

Categories