I am trying to do select an anchor from one div to another using next() , shiblings(), parents(), parent() etc jquery functions
Here is an example of html
<div class="thumbs">
<div class="section">
<div class="wrap">
HOme
</div>
</div>
<div>
<div class="thumbs">
<div class="section">
<div class="wrap">
about
</div>
</div>
<div>
i want to get the second link.Suppose my current link is link.php and when i click th next button i want to get next link2.php link
You need to use:
$('[data-selector="ajax"].current')
.closest('.thumbs')
.next()
.find('a')
.attr("href"); // will return link2.php
Related
<div class="item text-center">
<div class="class1"> <p> Something </p> </div>
</div>
<div class="item text-center">
<div class="class1"> <p> Something </p> </div>
</div>
$(".class1").hide();
$(".item").click(function () {
$(".class1").show();
})
I want that when the user click div of item, its own class1 should be show();
But in my codes, when the user click item of div, all class1 shows.
How can i do that just own class can be shown?
To fix this you need to use DOM traversal to access the .class1 element(s) within the clicked .item. To do that you can use the this keyword within the event handler to access the element which raised the event. Try this:
$(".item").click(function() {
$(this).find(".class1").show();
})
.class1 { display: none; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="item text-center">
Foo
<div class="class1">
<p> Something </p>
</div>
</div>
<div class="item text-center">
Bar
<div class="class1">
<p> Something </p>
</div>
</div>
Note in the example that I used CSS to hide the .class1 elements instead of JS. This is because JS runs after the DOM has loaded, so can result in elements being visible for a short time before they are hidden. CSS runs before this, so avoids that occurrence.
$(".class1").hide();
$(".item").click(function () {
$(this).find(".class1").show();
});
<!--The parent divs should not be empty, otherwise when later in the code you call the .hide () method on their respective child divs, there would be nothing left to click on-->
<div class="item text-center">
item1
<div class="class1">
<p> Something </p>
</div>
</div>
<div class="item text-center">
item2
<div class="class1">
<p> Something </p>
</div>
</div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
You can use the find () method, the find () method returns the descendant elements of the selected element. Like the code above
I have a div which I want to surround with an <a href>. I have the jQuery to add the <a href> after the div but I struggle to set it before and close it after the div.
This is the jQuery code I have:
$('.box_service').each(function() {
var link = $(this).html();
$(this).contents().wrap('');
});
It results in this HTML:
<div class="row">
<div class="box_service">
<a href="example.com">
<div class="inner-row"></div>
</a>
</div>
</div>
However my goal is this structure:
<div class="row">
<a href="example.com">
<div class="box_service">
<div class="inner-row"></div>
</div>
</a>
</div>
I can't enter the div before because there are more boxes in this row so I would add the <a href> to everything in there
The issue is due to your call to contents() which means you're wrapping the elements inside .box_service, not that element itself. Remove that method call.
Also note that each() is redundant, you can do what you require in a single line:
$('.box_service').wrap('');
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
Box service #1
<div class="inner-row">Inner row #1</div>
</div>
</div>
<div class="row">
<div class="box_service">
Box service #2
<div class="inner-row">Inner row #2</div>
</div>
</div>
.content will wrap the contents of your div, you want to wrap the div with <a> so call wrap on the div not on contents.
$('.box_service').each(function() {
var link = $(this).html();
$(this).wrap('');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
<div class="inner-row"></div>
</div>
</div>
$('.box_service').each(function() {
var link = $(this).html();
$(this).wrap('');
});
You just need to remove contents() in between $(this).wrap() because contents() mean that you are wrapping the children of $(this).
Remove .contents() in order to wrap around each element with the class box-service:
$('.box_service').each(function() {
$(this).wrap('');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
<a href="example.com">
<div class="inner-row"></div>
</a>
</div>
</div>
$('.box_service').wrap('');
For the life of me I can't figure out how to access the first div with text "I want this one" starting with the id of div1
My attempt:
$("#div1").first().first().html();
Here is an example
<div id="div1">
<div class="row">
<div class="another">I want this one</div>
<div class="another">Not this one</div>
</div>
</div>
Try this
1.
$("#div1 .another:first").html();
2.
$("#div1 .another").first().html();
3.
$("#div1 .another").eq(0).html();
Example
If you literally want the first element within the first element, you can do it in one selector using pure javascript selectors for performance like so:
var row = $('#div1 > div:first-child > div:first-child');
alert(row.text());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<div id="div1">
<div class="row">
<div class="another">I want this one</div>
<div class="another">Not this one</div>
</div>
<div class="row">
<div class="another">Another one</div>
<div class="another">Yet another one</div>
</div>
</div>
If you have the following code:
<div class="parent">
<div class="1"></div>
<div class="2"></div>
<div class="3"></div>
<div class="4"></div>
<div class="5"></div>
</div>
How can I wrap a new div around div with class 2,3,4,5 so it looks like this:
<div class="parent">
<div class="1"></div>
<div class="sub">
<div class="2"></div>
<div class="3"></div>
<div class="4"></div>
<div class="5"></div>
</div>
</div>
wrapAll on the parent would wrap everything with a new div, is there a way to make it ignore the first div?
Use gt(0) to select all but the first one div(direct descendant) and wrapAll. This will select all divs with index greater than 0 present under .parent div.
$('.parent > div:gt(0)').wrapAll('<div class="sub">');
Fiddle
See :gt()
Output:
<div class="parent">
<div class="1">1</div>
<div class="sub">
<div class="2">2</div>
<div class="3">3</div>
<div class="4">4</div>
<div class="5">5</div>
</div>
</div>
Use the not() filter or the :not() selector.
$('.parent div').not('.1').wrapAll('<div class="sub">');
Or alternatively:
$('.parent div:not(.1)').wrapAll('<div class="sub">');
You can also use div:first-child in place of .1 if you always want to ignore the first element.
If the element you want to keep out is not necessarily the first, you could use:
$(".parent div").not("div.1").wrapAll("<div class='sub'>");
Although, this will re-order your divs so that the wrap comes first, and the unwrapped element comes last. Not a problem when it's the first element, but if it's the third, for example, the output would be:
<div class='sub'>
<div class="1"></div>
<div class="2"></div>
<div class="4"></div>
<div class="5"></div>
</div>
<div class="3"></div>
Example:
http://jsfiddle.net/tomtheman5/3TL4M/
edit: Just saw #Corion's answer... This is essentially the same, but with some more information. I'll leave it up.
I have something like this, and i need to show every div called "plink" just in the main div of each parent, so i tried to fadeIn ".plink" but its doing the same function for all the divs of "plink"
<script>
$(document).ready(function(){
$('.plink').hide();
$('.project').mouseover(function(){
$(this).next('.plink').fadeIn(400);
});
$('.project').mouseleave(function(){
$(this).next('.plink').fadeOut(200);
});
});
</script>
<div class="project">
<div class="plink">
<div class="go"></div>
<div class="goplus"><img src="images/more.png" border="0"/></div>
</div>
<div class="pic"><img src="images/portfolio_pic2.png" border="0" alt="projectname"/></div>
<div class="title">Test1</div>
</div>
<div class="spacer_project"></div>
<div class="project">
<div class="plink">
<div class="go"></div>
<div class="goplus"><img src="images/more.png" border="0"/></div>
</div>
<div class="pic"><img src="images/portfolio_pic.png" border="0" alt="projectname"/></div>
<div class="title">test2</div>
</div>
You can use find() instead of next()...
$(this).find('.plink').fadeIn(400);
because this is your .project div then you need to "find" the child elements that you are looking for. Using next() means you will get the very next element if it matches the selector (i.e. it is check to see if the next .project div matches the .plink selector)
I would go the FIND route like musefan suggested. Here is the solution code:
http://jsfiddle.net/bx7YC/
<div class="project">
<div class="plink">
<div class="go">go</div>
<div class="goplus">goplus</div>
</div>
<div class="pic">pic</div>
<div class="title">Test1</div>
</div>
<div class="spacer_project"></div>
<div class="project">
<div class="plink">
<div class="go">go</div>
<div class="goplus">goplus</div>
</div>
<div class="pic">pic</div>
<div class="title">Test2</div>
</div>
$('.plink').hide();
$('.project').mouseover(function(){
$(this).find('.plink').fadeIn(400);
});
$('.project').mouseleave(function(){
$(this).find('.plink').fadeOut(200);
});
I replaced the broken img links with simple text for the jsfiddle.