I am trying to remove some spaces from a few dynamically generated strings. Which space I remove depends on the length of the string. The strings change all the time so in order to know how many spaces there are, I iterate over the string and increment a variable every time the iteration encounters a space. I can already remove all of a specific type of character with str.replace(' ',''); where 'str' is the name of my string, but I only need to remove a specific occurrence of a space, not all the spaces. So let's say my string is
var str = "Hello, this is a test.";
How can I remove ONLY the space after the word "is"? (Assuming that the next string will be different so I can't just write str.replace('is ','is'); because the word "is" might not be in the next string).
I checked documentation on .replace, but there are no other parameters that it accepts so I can't tell it just to replace the nth instance of a space.
If you want to go by indexes of the spaces:
var str = 'Hello, this is a test.';
function replace(str, indexes){
return str.split(' ').reduce(function(prev, curr, i){
var separator = ~indexes.indexOf(i) ? '' : ' ';
return prev + separator + curr;
});
}
console.log(replace(str, [2,3]));
http://jsfiddle.net/96Lvpcew/1/
As it is easy for you to get the index of the space (as you are iterating over the string) , you can create a new string without the space by doing:
str = str.substr(0, index)+ str.substr(index);
where index is the index of the space you want to remove.
I came up with this for unknown indices
function removeNthSpace(str, n) {
var spacelessArray = str.split(' ');
return spacelessArray
.slice(0, n - 1) // left prefix part may be '', saves spaces
.concat([spacelessArray.slice(n - 1, n + 1).join('')]) // middle part: the one without the space
.concat(spacelessArray.slice(n + 1)).join(' '); // right part, saves spaces
}
Do you know which space you want to remove because of word count or chars count?
If char count, you can Rafaels Cardoso's answer,
If word count you can split them with space and join however you want:
var wordArray = str.split(" ");
var newStr = "";
wordIndex = 3; // or whatever you want
for (i; i<wordArray.length; i++) {
newStr+=wordArray[i];
if (i!=wordIndex) {
newStr+=' ';
}
}
I think your best bet is to split the string into an array based on placement of spaces in the string, splice off the space you don't want, and rejoin the array into a string.
Check this out:
var x = "Hello, this is a test.";
var n = 3; // we want to remove the third space
var arr = x.split(/([ ])/); // copy to an array based on space placement
// arr: ["Hello,"," ","this"," ","is"," ","a"," ","test."]
arr.splice(n*2-1,1); // Remove the third space
x = arr.join("");
alert(x); // "Hello, this isa test."
Further Notes
The first thing to note is that str.replace(' ',''); will actually only replace the first instance of a space character. String.replace() also accepts a regular expression as the first parameter, which you'll want to use for more complex replacements.
To actually replace all spaces in the string, you could do str.replace(/ /g,""); and to replace all whitespace (including spaces, tabs, and newlines), you could do str.replace(/\s/g,"");
To fiddle around with different regular expressions and see what they mean, I recommend using http://www.regexr.com
A lot of the functions on the JavaScript String object that seem to take strings as parameters can also take regular expressions, including .split() and .search().
Related
Working with Javascript I need to be able to search a string input from a user and replace occurrences of semicolons with commas. Issue I have ran into is I need to be able to search the string for any commas that already exist, and quote around to the last and next occurrence of the semicolon.
Example:
User input is 12345;Joran,Michael;02;17;63 it should be converted to 12345,"Joran,Michael",02,17,63
My includes is able to locate the occurrence of a comma in the original string var srch = source.includes(","); and my replace is var converted = source.replace(/;/g, ","); which works fine, just need to figure out how to get to the last/next semicolon to place the quotes.
Using an if/else depending on if srch evaluates to True -- if true, add the quotes and then convert the rest of the string and return to the user; if false, convert and return.
I'm sure there's a way to do this with regex that just hasn't came to me yet so any suggestions on what to look at would be great.
I'd do this in two steps. First match non-; characters which have at least one ,, and surround them with quotes. Then replace all ;s in the result with ,:
console.log(
'12345;Joran,Michael;02;17;63'
.replace(/[^;,]*,[^;]*/g, '"$&"')
.replace(/;/g, ',')
);
Split the string by ;
.split(';')
which gives you an array.
Convert the elements that include a ',' to "${element}"
.map(s => s.includes(',') ? `"${s}"` : s )
Convert the array back to string
.join(',')
var str = '12345;Joran,Michael;02;17;63';
var arr = str.split(";");
var letters = /^[A-Za-z]/;
var final_str = "";
for (var i = 0; i < arr.length; i++) {
final_str = arr[i].match(letters)?final_str +'"'+ arr[i]+'"'+",":final_str + arr[i]+",";
}
console.log(final_str.substring(0,final_str.length -1));
So I have this code
function upperCase (text) {
let arr = text.split(" ");
let arr2 = [];
for(i = 0; i < arr.length; i++) {
arr2.push(arr[i].charAt(0).toUpperCase()+arr[i].slice(1));
}
return arr2.join(" ");
}
console.log(upperCase("something something"));
The current output is Something Something. But if I change the values in both .join() from .join(" ") to .join(""), the output is all capitalized (SOMETHING SOMETHING). I dont understand why does this happen? How does one space between "" make all characters capitalized?
split(" ") splits it into "something","something"
split("") splits it into "s","o","m","e","t","h","i","n","g", "s","o","m","e","t","h","i","n","g"
The uppercasing is done because you operate on lots of 1 element lists in the second case and every one gets its first character uppercased.
The parameter of split() states the character on witch the string is split. So if you provide a blank space " " your string will split on every "word".
But if you provide no character at all with "", the string will get split on every position, like Patrick Artner pointed out.
You could also split on comma "," or semicolon ";" or anything else.
In Javascript I have several words separated by either a dot or one ore more whitepaces (or the end of the string).
I'd like to replace certain parts of it to insert custom information at the appropriate places.
Example:
var x = "test1.test test2 test3.xyz test4";
If there's a dot it should be replaced with ".X_"
If there's one or more space(s) and the word before does not contain a dot, replace with ".X "
So the desired output for the above example would be:
"test1.X_test test2.X test3.X_xyz test4.X"
Can I do this in one regex replace? If so, how?
If I need two or more what would they be?
Thanks a bunch.
Try this:
var str = 'test1.test test2 test3.xyz test4';
str = str.replace(/(\w+)\.(\w+)/g, '$1.X_$2');
str = str.replace(/( |^)(\w+)( |$)/g, '$1$2.X$3');
console.log(str);
In the first replace it replaces the dot in the dotted words with a .X_, where a dotted word is two words with a dot between them.
In the second replace it adds .X to words that have no dot, where words that have no dot are words that are preceded by a space OR the start of the string and are followed by a space OR the end of the string.
To answer this:
If there's a dot it should be replaced with ".X_"
If there's one or more spaces it should be replaced with ".X"
Do this:
x.replace(/\./g, '.X_').replace(/\s+/g, '.X');
Edit: To get your desired output (rather than your rules), you can do this:
var words = x.replace(/\s+/g, ' ').split(' ');
for (var i = 0, l = words.length; i < l; i++) {
if (words[i].indexOf('.') === -1) {
words[i] += ".X";
}
else {
words[i] = words[i].replace(/\./g, '.X_');
}
}
x = words.join(' ');
Basically...
Strip all multiple spaces and create an array of "words"
Loop through each word.
If it doesn't have a period in it, then add ".X" to the end of the word
Else, replace the periods with ".X_"
Join the "words" back into a string and separate it by spaces.
Edit 2:
Here's a solution using only javascript's replace function:
x.replace(/\s+/g, ' ') // replace multiple spaces with one space
.replace(/\./g, '.X_') // replace dots with .X_
// find words without dots and add a ".X" to the end
.replace(/(^|\s)([^\s\.]+)($|\s)/g, "$1$2.X$3");
I only want to remove the first 100 words and keep whats remaining from the string.
The code I have below does the exact opposite:
var short_description = description.split(' ').slice(0,100).join(' ');
Remove the first argument:
var short_description = description.split(' ').slice(100).join(' ');
Using slice(x, y) will give you elements from x to y, but using slice(x) will give you elements from x to the end of the array. (note: this will return the empty string if the description has less than 100 words.)
Here is some documentation.
You could also use a regex:
var short_description = description.replace(/^([^ ]+ ){100}/, '');
Here is an explanation of the regex:
^ beginning of string
( start a group
[^ ] any character that is not a space
+ one or more times
then a space
) end the group. now the group contains a word and a space.
{100} 100 times
Then replace those 100 words with nothing. (note: if the description is less than 100 words, this regex will just return the description unchanged.)
//hii i am getting result using this function
var inputString = "This is file placed on Desktop"
inputString = removeNWords(inputString, 2)
console.log(inputString);
function removeNWords(input,n) {
var newString = input.replace(/\s+/g,' ').trim();
var x = newString.split(" ")
return x.slice(n,x.length).join(" ")
}
The reason this is doing the opposite, is that slice returns the selected elements (in this case, the first one hundred) and returns them in it's own array. To get all of the elements after one hundred, you would have to do something like description.slice(100) to get the split array properly, and then your own join to merge back the array.
var short_description = description.split(' ').slice(100).join(' ');
I'm trying to split a string into an array based on the second occurrence of the symbol _
var string = "this_is_my_string";
I want to split the string after the second underscore. The string is not always the same but it always has 2 or more underscores in it. I always need it split on the second underscore.
In the example string above I would need it to be split like this.
var split = [this_is, _my_string];
var string = "this_is_my_string";
var firstUnderscore = string.indexOf('_');
var secondUnderscore = string.indexOf('_', firstUnderscore + 1);
var split = [string.substring(0, secondUnderscore),
string.substring(secondUnderscore)];
Paste it into your browser's console to try it out. No need for a jsFiddle.
var string = "this_is_my_string";
var splitChar = string.indexOf('_', string.indexOf('_') + 1);
var result = [string.substring(0, splitChar),
string.substring(splitChar, string.length)];
This should work.
var str = "this_is_my_string";
var matches = str.match(/(.*?_.*?)(_.*)/); // MAGIC HAPPENS HERE
var firstPart = matches[1]; // this_is
var secondPart = matches[2]; // _my_string
This uses regular expressions to find the first two underscores, and captures the part up to it and the part after it. The first subexpression, (.*?_.*?), says "any number of characters, an underscore, and again any number of characters, keeping the number of characters matched as small as possible, and capture it". The second one, (_.*) means "match an underscore, then any number of characters, as much of them as possible, and capture it". The result of the match function is an array starting with the full matched region, followed by the two captured groups.
I know this post is quite old... but couldn't help but notice that no one provided a working solution. Here's one that works:
String str = "this_is_my_string";
String undScore1 = str.split("_")[0];
String undScore2 = str.split("_")[1];
String bothUndScores = undScore1 + "_" + undScore2 + "_";
String allElse = str.split(bothUndScores)[1];
System.out.println(allElse);
This is assuming you know there will always be at least 2 underscores - "allElse" returns everything after the second occurrence.