I'm trying to create a grid layout that sizes all child divs to match the tallest div in the group. For example, I have a 2x2 grid, with each div in the grid containing some text. The div that contains the most text is tallest, and should push the height on the other 3 divs to match.
I can get the div heights to match on each row using display: flex; and flex-wrap: wrap;, but I need all rows to match in height.
Is this possible to accomplish with CSS, or will I need to resort to jQuery?
<section class="grid two">
<div>
<div>
<p>The top left div</p>
</div>
</div>
<div>
<div>
<p>The top right div</p>
</div>
</div>
<div>
<div>
<p>The bottom left div</p>
</div>
</div>
<div>
<div>
<p>The bottom right div</p>
<p>this has more text, and should casue the rest to strecth to match its height.</p>
</div>
</div>
</section>
And my current CSS is:
.grid {
display: flex;
flex-wrap: wrap;
}
.grid > div {
box-sizing: border-box;
display: flex;
flex-directon: column;
padding: 10px;
width: 50%;
}
.grid > div > div {
background: #EEE;
flex: 1 1 auto;
width: 100%;
}
Here's a fiddle: http://jsfiddle.net/g41xas6w/
Update 1: I can't used a fixed height for two reasons:
The client will be able to edit this text, so I can't always know what the height will be.
This is a responsive site, so I'd have to do a whole bunch of breaks to ensure that things are always displaying at the correct height.
http://brm.io/jquery-match-height/
Please see the link above. These guys have created a jQuery plugin to achieve the effect you are after.
Your solution would work only for the 4 DIVs in a single horizontal line. Change the width and look! If you require the 2X2, the dynamically getting the height of all 4 to be same is not possible with only CSS. You need to either use script to control it or have a height set which would stop being dynamic!
If you put a height tag in the .grid > div with for example 200px it will all be 200px
.grid > div {
box-sizing: border-box;
display: flex;
flex-directon: column;
padding: 10px;
width: 50%;
height: 200px;
}
Related
Hello I'm not too good with css/floats/blocks etc.
I have this sort of setup
<div class="blue">1</div>
<div class="red">2</div>
<div class="blue">3</div>
<div class="red">4</div>
<div class="blue">5</div>
<div class="red">6</div>
I want to style it so 1 and 2 are on the same line (floated left and right), then 3 and 4 are on the same line (floated left and right) and so on and so forth.
Currently these elements are created in a loop. I have tried all sorts of methods to get the elements to line up how I want to no avail.
I think you want to make them two per row correct?
You can add a flex property to the parent container. Set the flex-wrap to wrap, then add a 50% width on your child elements (taking into account any inherited margin or padding effecting the layouts width to not overflow the flex-wrap), then justify-content to space-between, this will force the elements to their respective sides or a better way to put it is; place the "left over" space the children on that row are not taking up, in the middle of the two elements.
* { /* set box-sizing on all elements to border-box */
box-sizing: border-box;
}
body { /* remove any margin or padding from the body */
margin: 0;
padding: 0;
}
#cont { /* add display flex, flex-wrap and justify-content to space between */
display: flex;
flex-wrap: wrap;
justify-content: space-between;
}
#cont>div { /* Set your child divs to a percentage that will only give you two per row
the flex-wrap will push elements down */
width: 50%;
}
.blue {
background-color: lightblue;
border: 1px solid darkblue;
}
.red {
background-color: pink;
border: 1px solid darkred;
text-align: right; /* remove if you want standard left side text-alignment on red elements */
}
<div id="cont">
<div class="blue">1</div>
<div class="red">2</div>
<div class="blue">3</div>
<div class="red">4</div>
<div class="blue">5</div>
<div class="red">6</div>
</div>
If this is not what you were looking for let me know and I can edit or remove this answer.
My problem is that I want the flexbox with variable range width, and all works well, but not on the last row. I want the same dimension for all children even where the row is not full of children (the last row).
#products-list {
position:relative;
display: flex;
flex-flow: row wrap;
width:100%;
}
#products-list .product {
min-width:150px;
max-width:250px;
margin:10px 10px 20px 10px;
flex:1;
}
I created a dynamic situation in jsFiddle
My flex divs can shrink until 150px and grow up to 250px, but all must be with the same size (and obviously I want a CSS solution, with JS I know the way).
Unfortunately, in the current iteration of flexbox (Level 1), there is no clean way to solve the last-row alignment problem. It's a common problem.
It would be useful to have a flex property along the lines of:
last-row
last-column
only-child-in-a-row
alone-in-a-column
This problem does appear to be a high priority for Flexbox Level 2:
CSS Working Group Wiki - Specification Issues and Planning
https://lists.w3.org/Archives/Public/www-style/2015Jan/0150.html
Although this behavior is difficult to achieve in flexbox, it's simple and easy in CSS Grid Layout:
Equal width flex items even after they wrap
In case Grid is not an option, here's a list of similar questions containing various flexbox hacks:
Properly sizing and aligning the flex item(s) on the last row
Flex-box: Align last row to grid
Flexbox wrap - different alignment for last row
How can a flex item keep the same dimensions when it is forced to a new row?
Selector for an element alone in a row?
Aligning elements in last flexbox row
How can I allow flex-items to grow while keeping the same size?
Left-align last row of flexbox using space-between and margins
Inconsistent margin between flex items on last row
How to keep wrapped flex-items the same width as the elements on the previous row?
How to align left last row/line in multiple line flexbox
Last children of grid get giant gutter cause of flexbox space-between
Managing justify-content: space-between on last row
Flexbox space between behavior combined with wrap
Possible to use CSS Flexbox to stretch elements on every row while maintaining consistent widths?
As a quick and dirty solution one can use:
.my-flex-child:last-child/*.product:last-child*/ {
flex-grow: 100;/*Or any number big enough*/
}
You could try using grid instead of flexbox here:
#products-list {
display: grid;
grid-gap: 5px;
grid-template-columns: repeat(auto-fit, minmax(100px, 250px)); //grid automagic
justify-content: start; //start left
}
Fiddle link
There is a great solution that works always.
add a div with class product (The same class for other items that are under flex) and add a style for this div:height:0px;
you need to add as many dives that are possible to be in one row.
<div class="product" style="height:0px">
as many that can be in one row.
That's all. Works always.
If all your rows have the same number of items, you can use :nth-last-child. For example, if all the rows have 3 items, you can do something like this to remove the margin of the last 3 items:
.container{
display: flex;
flex-wrap: wrap;
background: yellow;
}
.item{
width: calc((100% - 2*10px)/3);
height: 50px;
background: blue;
color: white;
margin-right: 10px;
margin-bottom: 10px;
padding: 5px;
box-sizing: border-box;
}
/* last item of each row */
.item:nth-child(3n){
margin-right: 0;
font-size: 150%;
}
/* last 3 items */
.item:nth-last-child(-n+3){
margin-bottom: 0;
background: green;
}
<div class="container">
<div class="item" >1</div>
<div class="item" >2</div>
<div class="item" >3</div>
<div class="item" >4</div>
<div class="item" >5</div>
<div class="item" >6</div>
<div class="item" >7</div>
</div>
A simple trick adds a flexible space to fill the rest of the last row:
#products-list{
display:flex;
flex-flow: row wrap;
justify-content:space-between;
}
#products-list::after {
content: "";
flex: auto;
flex-basis: 200px;/*your item width*/
flex-grow: 0;
}
But you shouldn't use margins on items then. Rather wrap them into containers with padding.
I used this workaround, even if it's not very elegant and it doesn't use the power of Flexbox.
It can be carried out on the following conditions:
All the items have the same width
The items have a fixed width
You use SCSS/SASS (can be avoided though)
If this is the case, you can use the following snippet:
$itemWidth: 400px;
$itemMargin: 10px;
html, body {
margin: 0;
padding: 0;
}
.flex-container {
display: flex;
flex-direction: row;
flex-wrap: wrap;
margin: 0 auto;
border: solid 1px blue;
}
#for $i from 1 through 10 {
#media only screen and (min-width: $i * $itemWidth + 2 * $i * $itemMargin) {
.flex-container {
width: $i * $itemWidth + 2 * $i * $itemMargin;
}
}
}
.item {
flex: 0 0 $itemWidth;
height: 100px;
margin: $itemMargin;
background: red;
}
<div class="flex-container">
<div class="item"></div>
<div class="item" style="flex: 500 0 200px"></div>
<div class="item"></div>
<div class="item"></div>
<div class="item"></div>
</div>
Here I have created an example on codepen which also implements margin.
The second and the third conditions can be avoided respectively using css variables (if you decided to provide support for it) and compiling the above scss snippet.
Well, it's true, we could do it also before flexbox, but display: flex can be still essential for a responsive design.
I was facing this same issue where I wanted to have a variable number of items in a resizable container.
I wanted to use all of the horizontal space, but have all of the flex items at the same size.
I ultimately came up with a javascript approach that dynamically added padding spacers as the container was resized.
function padLastFormRow() {
let topList = [];
let nSpacersToAdd = 0;
$('#flexContainer').find('.formSpacer').remove();
$('#flexContainer').find('.formItem').each(function(i, formItem) {
topList.push($(formItem).position().top);
});
let allRowLengths = getFlexLineLengths(topList);
let firstRowLength = allRowLengths[0];
let lastRowLength = allRowLengths[((allRowLengths.length) - 1)];
if (lastRowLength < firstRowLength) {
nSpacersToAdd = firstRowLength - lastRowLength ;
}
for (var i = 1; i <= nSpacersToAdd; i ++) {
$('#flexContainer').append(formSpacerItem);
}
}
Please see my Fiddle:
http://jsfiddle.net/Harold_Buchman/z5r3ogye/11/
I was having a similar challenge with menu rows. I wanted more spacing on the top of the second row of menu items.
The use of flex-box's row-gap worked well.
https://developer.mozilla.org/en-US/docs/Web/CSS/row-gap
.menu {
display: flex;
flex-wrap: wrap;
row-gap: 10px;
}
This added a margin-top type effect to menu items were wrapped to the second line.
If all your rows have the same number of items, you can use :nth-last-child. For example, if all the rows have 3 items, you can do something like this:
.container{
display: flex;
flex-wrap: wrap;
background: yellow;
}
.item{
width: calc((100% - 2*10px)/3);
height: 50px;
background: blue;
color: white;
margin-right: 10px;
margin-bottom: 10px;
padding: 5px;
box-sizing: border-box;
}
// last item of each row
.item:nth-child(3n){
margin-right: 0;
background: green;
}
// last 3 items
.item:nth-last-child(-n+3){
margin-bottom: 0;
font-size: 150%;
}
<div class="container">
<div class="item" >1</div>
<div class="item" >2</div>
<div class="item" >3</div>
<div class="item" >4</div>
<div class="item" >5</div>
<div class="item" >6</div>
<div class="item" >7</div>
</div>
I am working on react web app which has less styling, so under
wrapper I have 3 columns, such that leftWrap is col-3, rightWrap is
col-4, and rest width is centerWrap. How can i apply flex while i just
know its col-* classnames
<div className={styles.Home__wrapper}>
<div className={styles.Home__leftWrap}> .... </div>
<div className={styles.Home__centerWrap}> .... </div>
<div className={styles.Home__rightWrap}> .... </div>
</div>
.Home {
&__wrapper {
display : flex;
flex-wrap: nowrap;
width : 100%;
box-sizing: border-box;
}
&__leftWrap {
display : flex;
}
&__rightWrap {
display : flex;
}
&__centerWrap {
display : flex;
}
}
How to set width to each column className as per above mentioned, is
it through cal() method
Set the display CSS attribute on the container div to flex, and play with the flex attribute on the children elements. Flex will sum up the flex number assigned to each children element to calculate the "total" steps to be filled, then calculate the value of each step based on the available space remaining and calculate the display width of each child by multiplying the calculated step width value by the child element flex value. In your case, it looks like your left and right children have fixed widths, and you want the center element to take the remaining space, so just set flex to 1 on the center element.
._wrapper {
display : flex;
flex-wrap: nowrap;
box-sizing: border-box;
}
._leftWrap {
width: 50px;
background-color: red;
}
._rightWrap {
width: 100px;
background-color: blue;
}
._centerWrap {
flex: 1;
background-color: yellow;
}
<div class="_wrapper">
<div class="_leftWrap"> .... </div>
<div class="_centerWrap"> .... </div>
<div class="_rightWrap"> .... </div>
</div>
I'm using display flex to display multiple items in one big container (parentDiv). The code is working fine but I get big problems with horizontal centering the items (especially If there are only a few items they should get horizontally centered) so I was using justify-content what leads to big issues:
The parent div is not able to display all items anymore. The first item that gets displayed is the item "04" while it should be "01". How to avoid this?
Please have a look at this code:
#bigDiv {
position: absolute;
width: 100%;
height: 100%;
}
#parentDiv {
width: 90%;
height: 50%;
overflow-y: hidden;
overflow-x: scroll;
text-align: center;
white-space: nowrap;
background: red;
display: flex;
justify-content: center;
align-items: center;
}
.item {
color: white;
background: blue;
flex: 0 0 4%;
margin: 0 3%;
}
.item::after {
content: "";
display: block;
padding-bottom: 100%;
}
<div id="bigDiv">
<div id="parentDiv">
<div class="item">01</div>
<div class="item">02</div>
<div class="item">03</div>
<div class="item">04</div>
<div class="item">05</div>
<div class="item">06</div>
<div class="item">07</div>
<div class="item">08</div>
<div class="item">09</div>
<div class="item">10</div>
<div class="item">11</div>
<div class="item">12</div>
<div class="item">13</div>
<div class="item">14</div>
<div class="item">15</div>
<div class="item">16</div>
</div>
</div>
See this image:
My intentions: The parent div should be able to show all of the items (starting with "01" - and the last element should be the "16"-one)
Note: If there are only 4 or less items they should get centered horizontally. (The reason why I added justify-content).
You're fiting 160% into 100%. And you want it centered. And it works: the 160% total width of the resulting children is nicely centered.
But you're also expecting whatever is outside the parent to be accessible.
It's pretty much like making a child element go outside of its parent by -30% to the left or to the top (by any other method) and expecting the parent to allow you to scroll to it. It's not going to happen!
If it did, the child would no longer be placed at -30%, it would be placed at 0%. Scrollbars will never scroll to left or top negative space. It's by design. You need to take it into consideration when designing your page.
Whenever you center a bigger child into a smaller parent you won't be able to use parent's scrollbars to scroll to the beginning of the child. So anything preventing the child positioning in the parent's left negative space will fix it.
I have a page, where I'm showing images side by side according to the category they belong to, each image array begins with the category it belongs to. Images vary in their width & height, but are put into a div with an absolute height of 330px.
CSS:
.front-index {
margin: 0 1em 0 2em;
}
.front-work {
margin: 0 2em 2em 0;
display: table;
width: 66px;
position: relative;
height: 330px;
background-color:#f0f0f0;
}
.front-work img {
margin: .3em 0 .3em 0;
}
.wraptocenter {
display: table-cell;
text-align: center;
vertical-align: middle;
}
.wraptocenter * {
vertical-align: middle;
}
.front-index,
.front-work {
float: left;
}
HTML:
<div class="front-index"><p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p></div>
<div class="front-work">
<div class="wraptocenter">
<img width="162" height="250" src="http://images.fanpop.com/images/image_uploads/Yellow-Wallpaper-yellow-646738_800_600.jpg"/>
</div>
</div>
<div class="front-work">
<div class="wraptocenter">
<img width="250" height="166" src="http://www.takenseriouslyamusing.com/wp-content/uploads/2012/08/Blue.png"/>
</div>
</div>
…
JSFIDDLE: http://jsfiddle.net/rCAKa/9/
I'd like to align the text to the same line as the first image on the right.
What I had in mind, is that may-be this should be done in jquery. Ie. somehow measure the image distance from the top inside the .front-work div and then assign the value to the .front-index div as an inline code (top: whatever px ).
Maybe someone of you have faced this kind of problem and know a solution to this kind of problem? CSS or JS.
In my humble opinion I don't think that what you're doing is possible through CSS - it requires some simple JavaScript trickery because you have to know the relative position (from the top of the container) of the first image on the right in order to position the text - something which CSS isn't quite designed for.
The strategy in JS would be:
Loop through each element with text that you want to position
Fetch the vertical top offset of the first image to the right (relative to containing parent)
Set top padding matching to top position of image. Alternatively, you can set the top position, paddings or margins of the child elements, or other ways to reposition the text.
$(document).ready(function() {
$(".front-index").each(function() {
var fromTop = $(this).next().find("img").position().top;
$(this).css({
"padding-top":fromTop
});
});
});
I have forked your fiddle, and you can see it in action here - http://jsfiddle.net/teddyrised/LT54V/1/
p/s: On a related note, .wraptocenter * { } is probably not the best (as in, most efficient) selector out there, because if you have many child elements in the element (who may or may have even more child elements), CSS will have to iterate through all of them. Instead, try using .wraptocenter > * { } or just .wraptocenter img { } :)
I first tried to solve the problem using css. After a while I figured out the following logics:
Create a div with the same height as the cell on the right with the display set as table
Make a table-cell div in the first one that centers vertically
In this div make another subdiv with the same height as the image.
The HTML code is then this:
<div class="front-index">
<div class="front-index-inner">
<div style="height:250px;">
<p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p>
</div>
</div>
</div>
and as my CSS part this:
.front-index {
margin: 0 1em 0 2em;
display: table;
height: 330px;
overflow: hidden;
}
.front-index-inner {
display: table-cell;
width: 100%;
vertical-align: middle;
}
You can see the result over here: http://jsfiddle.net/rCAKa/10/
I hope this brings a solution to you that is clear, understandable and useful.
Greetings,
Jef