I have a callback that gets tossed around a lot. I can't figure a way to keep it through all of functions.
function a(callback) {
callback();
}
var number = 0;
function b(callback) {
number++;
c(number, callback);
}
function c(number, callback) {
if (number != 2) {
a(function () {
b();
});
} else {
callback();
}
}
a(function() {
b(function() {
console.log('hi');
});
});
I need a way to get the outermost callback (the one with console.log) to the a() function and subsequently the b() function when I call the a() function in the c() function.
Let me know if this sounds like gibberish. I will try to clarify.
You are encountering a TypeError: undefined is not a function. This is because in c you're invoking b without passing any args so when number !== 2 you've lost your reference
I re-wrote your code and it ended up working
var number = 0;
function invoke(fn) { // do you really need this? just invoke directly
fn();
}
function count(fn) {
++number;
limit(number, fn);
}
function limit(num, fn) {
if (num < 2) // this is much safer
invoke(function () {
count(fn); // passing an arg here
});
else
fn();
}
invoke(function () {
count(function () {
console.log('hello world');
});
});
You're getting dangerously close to what is known as 'callback hell'. You'll want to avoid that if you can. Since I'm not 100% sure why you need to pass around so many callback functions, you can achieve what you're looking for by doing the following:
function increment(number, callback, callback2) {
console.log('Incrementing number ' + number + ' by 1');
number++;
callback(number, increment, callback2);
}
function verify(number, callback, callback2) {
if (number < 2) {
callback(number, verify, callback2);
} else {
callback2();
}
}
var number = 0;
increment(number, verify, function () {
console.log('Hello world!');
});
You'll notice that I renamed some functions and excluded your a() function since it did nothing but execute the callback function passed to it. Unless that function is to serve another purpose, it is useless. You also don't need to create an anonymous function every time you are passing a callback. To pass a previously defined function as a parameter or callback, simply pass the function name without the (). If you are passing an undefined function as a callback, you will need to create the anonymous function which is what is being done with the console.log() callback.
Here's a jsfiddle. You can open your console log and see what it's doing.
jsfiddle
Please also be sure to read up on callback hell and how to design your code in a way that it can be avoided. Call back hell
Related
How do I pass a function as a parameter without the function executing in the "parent" function or using eval()? (Since I've read that it's insecure.)
I have this:
addContact(entityId, refreshContactList());
It works, but the problem is that refreshContactList fires when the function is called, rather than when it's used in the function.
I could get around it using eval(), but it's not the best practice, according to what I've read. How can I pass a function as a parameter in JavaScript?
You just need to remove the parenthesis:
addContact(entityId, refreshContactList);
This then passes the function without executing it first.
Here is an example:
function addContact(id, refreshCallback) {
refreshCallback();
// You can also pass arguments if you need to
// refreshCallback(id);
}
function refreshContactList() {
alert('Hello World');
}
addContact(1, refreshContactList);
If you want to pass a function, just reference it by name without the parentheses:
function foo(x) {
alert(x);
}
function bar(func) {
func("Hello World!");
}
//alerts "Hello World!"
bar(foo);
But sometimes you might want to pass a function with arguments included, but not have it called until the callback is invoked. To do this, when calling it, just wrap it in an anonymous function, like this:
function foo(x) {
alert(x);
}
function bar(func) {
func();
}
//alerts "Hello World!" (from within bar AFTER being passed)
bar(function(){ foo("Hello World!") });
If you prefer, you could also use the apply function and have a third parameter that is an array of the arguments, like such:
function eat(food1, food2) {
alert("I like to eat " + food1 + " and " + food2 );
}
function myFunc(callback, args) {
//do stuff
//...
//execute callback when finished
callback.apply(this, args);
}
//alerts "I like to eat pickles and peanut butter"
myFunc(eat, ["pickles", "peanut butter"]);
Example 1:
funct("z", function (x) { return x; });
function funct(a, foo){
foo(a) // this will return a
}
Example 2:
function foodemo(value){
return 'hello '+value;
}
function funct(a, foo){
alert(foo(a));
}
//call funct
funct('world!',foodemo); //=> 'hello world!'
look at this
To pass the function as parameter, simply remove the brackets!
function ToBeCalled(){
alert("I was called");
}
function iNeedParameter( paramFunc) {
//it is a good idea to check if the parameter is actually not null
//and that it is a function
if (paramFunc && (typeof paramFunc == "function")) {
paramFunc();
}
}
//this calls iNeedParameter and sends the other function to it
iNeedParameter(ToBeCalled);
The idea behind this is that a function is quite similar to a variable. Instead of writing
function ToBeCalled() { /* something */ }
you might as well write
var ToBeCalledVariable = function () { /* something */ }
There are minor differences between the two, but anyway - both of them are valid ways to define a function.
Now, if you define a function and explicitly assign it to a variable, it seems quite logical, that you can pass it as parameter to another function, and you don't need brackets:
anotherFunction(ToBeCalledVariable);
There is a phrase amongst JavaScript programmers: "Eval is Evil" so try to avoid it at all costs!
In addition to Steve Fenton's answer, you can also pass functions directly.
function addContact(entity, refreshFn) {
refreshFn();
}
function callAddContact() {
addContact("entity", function() { DoThis(); });
}
I chopped all my hair off with that issue. I couldn't make the examples above working, so I ended like :
function foo(blabla){
var func = new Function(blabla);
func();
}
// to call it, I just pass the js function I wanted as a string in the new one...
foo("alert('test')");
And that's working like a charm ... for what I needed at least. Hope it might help some.
I suggest to put the parameters in an array, and then split them up using the .apply() function. So now we can easily pass a function with lots of parameters and execute it in a simple way.
function addContact(parameters, refreshCallback) {
refreshCallback.apply(this, parameters);
}
function refreshContactList(int, int, string) {
alert(int + int);
console.log(string);
}
addContact([1,2,"str"], refreshContactList); //parameters should be putted in an array
You can also use eval() to do the same thing.
//A function to call
function needToBeCalled(p1, p2)
{
alert(p1+"="+p2);
}
//A function where needToBeCalled passed as an argument with necessary params
//Here params is comma separated string
function callAnotherFunction(aFunction, params)
{
eval(aFunction + "("+params+")");
}
//A function Call
callAnotherFunction("needToBeCalled", "10,20");
That's it. I was also looking for this solution and tried solutions provided in other answers but finally got it work from above example.
Here it's another approach :
function a(first,second)
{
return (second)(first);
}
a('Hello',function(e){alert(e+ ' world!');}); //=> Hello world
In fact, seems like a bit complicated, is not.
get method as a parameter:
function JS_method(_callBack) {
_callBack("called");
}
You can give as a parameter method:
JS_method(function (d) {
//Finally this will work.
alert(d)
});
The other answers do an excellent job describing what's going on, but one important "gotcha" is to make sure that whatever you pass through is indeed a reference to a function.
For instance, if you pass through a string instead of a function you'll get an error:
function function1(my_function_parameter){
my_function_parameter();
}
function function2(){
alert('Hello world');
}
function1(function2); //This will work
function1("function2"); //This breaks!
See JsFiddle
Some time when you need to deal with event handler so need to pass event too as an argument , most of the modern library like react, angular might need this.
I need to override OnSubmit function(function from third party library) with some custom validation on reactjs and I passed the function and event both like below
ORIGINALLY
<button className="img-submit" type="button" onClick=
{onSubmit}>Upload Image</button>
MADE A NEW FUNCTION upload and called passed onSubmit and event as arguments
<button className="img-submit" type="button" onClick={this.upload.bind(this,event,onSubmit)}>Upload Image</button>
upload(event,fn){
//custom codes are done here
fn(event);
}
By using ES6:
const invoke = (callback) => {
callback()
}
invoke(()=>{
console.log("Hello World");
})
If you can pass your whole function as string, this code may help you.
convertToFunc( "runThis('Micheal')" )
function convertToFunc( str) {
new Function( str )()
}
function runThis( name ){
console.log("Hello", name) // prints Hello Micheal
}
You can use a JSON as well to store and send JS functions.
Check the following:
var myJSON =
{
"myFunc1" : function (){
alert("a");
},
"myFunc2" : function (functionParameter){
functionParameter();
}
}
function main(){
myJSON.myFunc2(myJSON.myFunc1);
}
This will print 'a'.
The following has the same effect with the above:
var myFunc1 = function (){
alert('a');
}
var myFunc2 = function (functionParameter){
functionParameter();
}
function main(){
myFunc2(myFunc1);
}
Which is also has the same effect with the following:
function myFunc1(){
alert('a');
}
function myFunc2 (functionParameter){
functionParameter();
}
function main(){
myFunc2(myFunc1);
}
And a object paradigm using Class as object prototype:
function Class(){
this.myFunc1 = function(msg){
alert(msg);
}
this.myFunc2 = function(callBackParameter){
callBackParameter('message');
}
}
function main(){
var myClass = new Class();
myClass.myFunc2(myClass.myFunc1);
}
I was cleaning up my code and ran into a little trouble with callbacks, specifically getting the correct values to output when a callback is called. Could some explain to me why the following code spits out something that I'm not expecting and a possible solution without having to put in another parameter of i to the run() function, or is passing in i to know my index upon calling the callback the only way to do this?
for (var i in dls) {
run(dls[i][0], dls[i][1], function(isTrue){
if (isTrue) {
// Do true stuff here
} else {
console.log("Value is: " + dls[i][3])
}
});
}
Calling run() actually has the correct inputs inside, but upon that function calling the callback and going into the else statement, dls[i][3] spits out the same value i times.
I've tried putting different scopes around (run()) and such but to no avail and can't seem to wrap my head around this.
Thanks
EDIT:
If I wanted to split it up into a separate function, how would I do it?
var run = function(cb){
setTimeout(function() {
cb(false)
}, 3000);
}
for (var i in dls) {
run(dls[i][0], dls[i][1], (function(index) {
return extraction
})(i));
}
function extraction(isTrue){
if (isTrue) {
// stuff
} else {
console.log("Nothing changed in " + dls[i][3])
}
}
Here dls[i][3] is still incorrect and prints the same value 3 times.
You have fallen into the traditional "loop trap"
When it comes time for your callback to run i is now a different value.
What you can do is cache that value in another wrapper function:
for (var i in dls) {
run(dls[i][0], dls[i][1], (function (currentIndex) {
return function(isTrue){
if (isTrue) {
// Do true stuff here
} else {
console.log("Value is: " + dls[currentIndex][3])
}
};
})(i));
}
In regards to the edit / second question, assuming this is what you wanted to do:
// note that I changed the function signature of `run`
var run = function(val1, val2, cb) {
setTimeout(function() {
cb(false);
}, 3000);
};
// note the `wrapper` here
for (var i in dls) {
run(dls[i][0], dls[i][1], wrapper(i));
}
// this is the same as what the IIFE is doing,
// just with an external function instead
function wrapper(scopedIndex) {
// return a function to be used as the callback for `run`
return function extraction(isTrue) {
if (isTrue) {
// stuff
}
else {
// use the scoped index here
console.log("Nothing changed in " + dls[scopedIndex][3]);
}
}
}
Take a look at function makeExitCallback(i) in the other linked question, as well. It directly relates to what's going on here.
You should post what's in dls as well, just to make it easier to run your snippets locally.
Just wondering if there is anyway to fire some code when a function is called, without adding the code to the function, for example:
function doSomething(){
//Do something
}
//Code to call when doSomething is called
You can wrap the function :
(function(){
var oldFunction = doSomething;
doSomething = function(){
// do something else
oldFunction.apply(this, arguments);
}
})();
I use an IIFE here just to avoid polluting the global namespace, it's accessory.
Well, yes, it's not actually hard to do. The crucial thing is that a function's name is just an identifier like any other. You can redefine it if you want to.
var oldFn = doSomething;
doSomething = function() {
// code to run before the old function
return oldFn.apply(this, arguments);
// code to run after the old function
};
NB that it's better to do oldFn.apply(this, arguments) rather than just oldFn. In many cases it won't matter, but it's possible that the context (i.e. the value of this inside the function) and the arguments are important. Using apply means they are passed on as if oldFn had been called directly.
What about something like:
function doSomething(){
doSomething.called = true;
}
//call?
doSomething();
if(doSomething.called) {
//Code to call when doSomething is called
}
I know you said you don't want to modify the original function, but consider adding a callback. Then you can execute code based on different results in your function (such as onSucess and onError):
function doSomething(onSuccess, onError){
try {
throw "this is an error";
if(onSuccess) {
onSuccess();
}
} catch(err) {
if(onError) {
onError(err);
}
}
}
Then, when you call doSomething, you can specify what you want done with inline functions:
doSomething(function() {
console.log("doSomething() success");
}, function(err) {
console.log("doSomething() error: " + err);
});
This question already has answers here:
How can I pass a parameter to a setTimeout() callback?
(29 answers)
Closed 12 months ago.
function f1()
{
c = setTimeout(f2,200);
}
function f2()
{
//code
}
The above code is just fine. But what I want to ask that: can I use some argument in function f2() which is passed from the calling environment? That is:
function f1(v1)
{
c = setTimeout(f2(v1),200);
}
function f2(v2)
{
//code
}
Is it valid? Because I tried something like this,but the problem is that I am not able to clearTimeout by using variable c. I am not sure what to do.
Use Closure -
function f1(v1)
{
c = setTimeout(f2(v1), 200);
}
function f2(v2)
{
return function () {
// use v2 here, and put the rest of your
// callback code here.
}
}
This way you will be able to pass as many arguments as you want.
Since you are declaring c as a global variable (which is bad), you can easily clear the timeout using -
clearTimeout(c);
If you are still not being able to clear the timeout, it only means that the duration has elapsed and your callback fired, or there is some error somewhere else. In that case, post your code that you are using to clear your timeout.
You can either use the function.bind method or you can simply wrap the invocation
function f1(v1) {
c = setTimeout(function() {
f2(v1);
}, 200);
}
var timeout;
// Call `f2` with all arguments that was passed to the `f1`
function f1 () {
var args = arguments;
timeout = setTimeout(function () { f2.apply(this, args) }, 200);
}
Or in this way:
// Call `f2` with some params from `f1`
function f1 (v1) {
timeout = setTimeout(function () { f2(v1) }, 200);
}
Answer to your question: you couldn't clear the timeout because you execute function immediately.
How do I pass a function as a parameter without the function executing in the "parent" function or using eval()? (Since I've read that it's insecure.)
I have this:
addContact(entityId, refreshContactList());
It works, but the problem is that refreshContactList fires when the function is called, rather than when it's used in the function.
I could get around it using eval(), but it's not the best practice, according to what I've read. How can I pass a function as a parameter in JavaScript?
You just need to remove the parenthesis:
addContact(entityId, refreshContactList);
This then passes the function without executing it first.
Here is an example:
function addContact(id, refreshCallback) {
refreshCallback();
// You can also pass arguments if you need to
// refreshCallback(id);
}
function refreshContactList() {
alert('Hello World');
}
addContact(1, refreshContactList);
If you want to pass a function, just reference it by name without the parentheses:
function foo(x) {
alert(x);
}
function bar(func) {
func("Hello World!");
}
//alerts "Hello World!"
bar(foo);
But sometimes you might want to pass a function with arguments included, but not have it called until the callback is invoked. To do this, when calling it, just wrap it in an anonymous function, like this:
function foo(x) {
alert(x);
}
function bar(func) {
func();
}
//alerts "Hello World!" (from within bar AFTER being passed)
bar(function(){ foo("Hello World!") });
If you prefer, you could also use the apply function and have a third parameter that is an array of the arguments, like such:
function eat(food1, food2) {
alert("I like to eat " + food1 + " and " + food2 );
}
function myFunc(callback, args) {
//do stuff
//...
//execute callback when finished
callback.apply(this, args);
}
//alerts "I like to eat pickles and peanut butter"
myFunc(eat, ["pickles", "peanut butter"]);
Example 1:
funct("z", function (x) { return x; });
function funct(a, foo){
foo(a) // this will return a
}
Example 2:
function foodemo(value){
return 'hello '+value;
}
function funct(a, foo){
alert(foo(a));
}
//call funct
funct('world!',foodemo); //=> 'hello world!'
look at this
To pass the function as parameter, simply remove the brackets!
function ToBeCalled(){
alert("I was called");
}
function iNeedParameter( paramFunc) {
//it is a good idea to check if the parameter is actually not null
//and that it is a function
if (paramFunc && (typeof paramFunc == "function")) {
paramFunc();
}
}
//this calls iNeedParameter and sends the other function to it
iNeedParameter(ToBeCalled);
The idea behind this is that a function is quite similar to a variable. Instead of writing
function ToBeCalled() { /* something */ }
you might as well write
var ToBeCalledVariable = function () { /* something */ }
There are minor differences between the two, but anyway - both of them are valid ways to define a function.
Now, if you define a function and explicitly assign it to a variable, it seems quite logical, that you can pass it as parameter to another function, and you don't need brackets:
anotherFunction(ToBeCalledVariable);
There is a phrase amongst JavaScript programmers: "Eval is Evil" so try to avoid it at all costs!
In addition to Steve Fenton's answer, you can also pass functions directly.
function addContact(entity, refreshFn) {
refreshFn();
}
function callAddContact() {
addContact("entity", function() { DoThis(); });
}
I chopped all my hair off with that issue. I couldn't make the examples above working, so I ended like :
function foo(blabla){
var func = new Function(blabla);
func();
}
// to call it, I just pass the js function I wanted as a string in the new one...
foo("alert('test')");
And that's working like a charm ... for what I needed at least. Hope it might help some.
I suggest to put the parameters in an array, and then split them up using the .apply() function. So now we can easily pass a function with lots of parameters and execute it in a simple way.
function addContact(parameters, refreshCallback) {
refreshCallback.apply(this, parameters);
}
function refreshContactList(int, int, string) {
alert(int + int);
console.log(string);
}
addContact([1,2,"str"], refreshContactList); //parameters should be putted in an array
You can also use eval() to do the same thing.
//A function to call
function needToBeCalled(p1, p2)
{
alert(p1+"="+p2);
}
//A function where needToBeCalled passed as an argument with necessary params
//Here params is comma separated string
function callAnotherFunction(aFunction, params)
{
eval(aFunction + "("+params+")");
}
//A function Call
callAnotherFunction("needToBeCalled", "10,20");
That's it. I was also looking for this solution and tried solutions provided in other answers but finally got it work from above example.
Here it's another approach :
function a(first,second)
{
return (second)(first);
}
a('Hello',function(e){alert(e+ ' world!');}); //=> Hello world
In fact, seems like a bit complicated, is not.
get method as a parameter:
function JS_method(_callBack) {
_callBack("called");
}
You can give as a parameter method:
JS_method(function (d) {
//Finally this will work.
alert(d)
});
The other answers do an excellent job describing what's going on, but one important "gotcha" is to make sure that whatever you pass through is indeed a reference to a function.
For instance, if you pass through a string instead of a function you'll get an error:
function function1(my_function_parameter){
my_function_parameter();
}
function function2(){
alert('Hello world');
}
function1(function2); //This will work
function1("function2"); //This breaks!
See JsFiddle
Some time when you need to deal with event handler so need to pass event too as an argument , most of the modern library like react, angular might need this.
I need to override OnSubmit function(function from third party library) with some custom validation on reactjs and I passed the function and event both like below
ORIGINALLY
<button className="img-submit" type="button" onClick=
{onSubmit}>Upload Image</button>
MADE A NEW FUNCTION upload and called passed onSubmit and event as arguments
<button className="img-submit" type="button" onClick={this.upload.bind(this,event,onSubmit)}>Upload Image</button>
upload(event,fn){
//custom codes are done here
fn(event);
}
By using ES6:
const invoke = (callback) => {
callback()
}
invoke(()=>{
console.log("Hello World");
})
If you can pass your whole function as string, this code may help you.
convertToFunc( "runThis('Micheal')" )
function convertToFunc( str) {
new Function( str )()
}
function runThis( name ){
console.log("Hello", name) // prints Hello Micheal
}
You can use a JSON as well to store and send JS functions.
Check the following:
var myJSON =
{
"myFunc1" : function (){
alert("a");
},
"myFunc2" : function (functionParameter){
functionParameter();
}
}
function main(){
myJSON.myFunc2(myJSON.myFunc1);
}
This will print 'a'.
The following has the same effect with the above:
var myFunc1 = function (){
alert('a');
}
var myFunc2 = function (functionParameter){
functionParameter();
}
function main(){
myFunc2(myFunc1);
}
Which is also has the same effect with the following:
function myFunc1(){
alert('a');
}
function myFunc2 (functionParameter){
functionParameter();
}
function main(){
myFunc2(myFunc1);
}
And a object paradigm using Class as object prototype:
function Class(){
this.myFunc1 = function(msg){
alert(msg);
}
this.myFunc2 = function(callBackParameter){
callBackParameter('message');
}
}
function main(){
var myClass = new Class();
myClass.myFunc2(myClass.myFunc1);
}