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Get string from a successful regex?

I'm trying to manipulate a string that has tested as a positive match against my regex statement.
My regex statement is /\[table=\d](.*?)\[\/table] / gmi and an example of a positive match would be [table=1]Cell 1[c]Cell 2[/table]. I'm searching for matches within a certain div, which I'll call .foo in the code below.
However, once the search comes back saying it has found a match, I want to have the section that was identified as a match returned back to me so that I can start manipulating a specific section of it, namely count the number of times [c] appears and reference the number in [table=1].
(function(regexCheck) {
var regex = /\[table=\d](.*?)\[\/table] / gmi;
$('.foo').each(function() {
var html = $(this).html();
var change = false;
while (regex[0].test(html)) {
change = true;
//Somehow return string?
}
});
})(jQuery);
I'm quite new to javascript and especially new to RegEx, so I apologise if this code is crude.
Thanks for all of your help in advance.

Use exec instead of test and keep the resulting match object:
var match;
while ((match = regex[0].exec(html)) != null) {
change = true;
// use `match[0]` for the full match, or `match[1]` and onward for capture groups
}
Simple example (since your snippet isn't runnable, I've just created a simple one instead):
var str = "test 1 test 2 test 3";
var regex = /test (\d)/g;
var match;
while ((match = regex.exec(str)) !== null) {
console.log("match = " + JSON.stringify(match));
}

How to replace strings and get what I need in this case?

I am trying to replace a string with two sets of patterns. For example,
var pattern1 = '12345abcde/'; -> this is dynamic.
var myString = '12345abcde/hd123/godaddy_item'
my end goal is to get the value between two slashes which is hd123
I have
var stringIneed = myString.replace(pattern1, '').replace('godaddy_item','');
The above codes work but I think there is more elegant solution. Can anyone help me out on this? Thanks a lot!
UPDATE:
To be more clear, the pattern is per environement string. For example,
pattern1 could be something like:
https://myproject-development/item on development environment.
and
https://myproject/item on Production
myString could usually be like
https://myproject/item/hd123/godaddy_item
or
https://myproject-development/item/hd123/godaddy_item
and I need to get 'hd123' in my case.

I'd strongly suggest not using regular expressions for this, especially when simple String and Array methods will easily suffice and be far more understandable, such as:
// your question shows you can anticipate the sections you
// don't require, so put both/all of those portions into an
// array:
var unwanted = ['12345abcde', 'godaddy_item'],
// the string you wish to find the segment from:
myString = '12345abcde/hd123/godaddy_item',
// splitting the String into an array by splitting on the '/'
// characters, filtering that array using an arrow function
// in which the section is the current array-element of the
// array over which we're iterating; and here we keep those
// sections which are not found in the unwanted Array (the index
// an element not found in an Array is returned as -1):
desired = myString.split('/').filter(section => unwanted.indexOf(section) === -1);
console.log(desired); // ["hd123"]
Avoiding Arrow functions, for browsers not supporting ES6 (and having removed the code comments):
var unwanted = ['12345abcde', 'godaddy_item'],
myString = '12345abcde/hd123/godaddy_item',
desired = myString.split('/').filter(function (section) {
return unwanted.indexOf(section) === -1;
});
console.log(desired); // ["hd123"]
Or:
// the string to start with and filter:
var myString = '12345abcde/hd123/godaddy_item',
// splitting the string by the '/' characters and keeping those whose
// index is greater than 0 (so 'not the first') and also less than the
// length of the array-1 (since JS arrays are zero-indexed while length
// is 1-based):
wanted = myString.split('/').filter((section, index, array) => index > 0 && index < array.length - 1);
console.log(wanted); // ["hd123"]
JS Fiddle demo
If, however, the requisite string to be found is always the penultimate portion of the supplied string, then we can use Array.prototype.filter() to return only that portion:
var myString = '12345abcde/hd123/godaddy_item',
wanted = myString.split('/').filter((section, index, array) => index === array.length - 2);
console.log(wanted); // ["hd123"]
JS Fiddle demo.
References:
Array.prototype.filter().
Arrow functions.
String.prototype.split().

You can use
.*\/([^\/]+)\/.*$
Regex Demo
JS Demo
var re = /.*\/([^\/]+)\/.*$/g;
var str = '12345abcde/hd123/godaddy_item';
while ((m = re.exec(str)) !== null) {
document.writeln("<pre>" + m[1] + "</br>" + "</pre>");
}

You can easily do something like this:
myString.split('/').slice(-2)[0]
This will return the item directly, in simple most way.
var myString = 'https://myproject/item/hd123/godaddy_item';
console.log(myString.split('/').slice(-2)[0]); // hd123
myString = 'https://myproject-development/item/hd123/godaddy_item';
console.log(myString.split('/').slice(-2)[0]); // hd123

Try using match() as shown below:
var re = /\/(.*)\//;
var str = '12345abcde/hd123/godaddy_item';
var result = str.match(re);
alert(result[1]);

To say that David's answer will "easily suffice and be far more understandable" is a matter of opinion - this regex option (which includes building up the expression from variables) really couldn't be much simpler:
var pathPrefix = '12345abcde/'; //dynamic
var pathToTest = '12345abcde/hd123/godaddy_item';
var pattern = new RegExp(pathPrefix + '(.*?)\/')
var match = pattern.exec(pathToTest);
var result = (match != null && match[1] != null ? '[' + match[1] + ']' : 'no match was found.'); //[hd123]

Remove part of string that contains a tag

I have a variable in JavaScript that holds the below value:
<label>AAA</label>
I need just the AAA. I try to replace the characters but it is failing. Would someone please suggest the best approach?
var company="<label>AAA</label>";// I am getting this value from element
var rx = new RegExp("((\\$|)(([1-9]\\d{0,2}(\\,\\d{3})*|([1-9]\\d*))(\\.\\d{2})))|(\\<)*(\\>)");
var arr = rx.exec(company);
var arr1 = company.match(rx);
if (arr[1] != null) {
var co = arr[1].replace(",", "");
}
}

As you say you need only AAA, consider the below code.
I have taken a substring between the first '>' character in the string company, added 1 to that and the last < character. However, if the company var contains more of such < or >, you could go for a regex approach.
var company="<label>AAA</label>";
alert(company.substring(company.indexOf('>')+1, company.lastIndexOf('<')));

Capture value out of query string with regex?

I am trying to select just what comes after name= and before the & in :
"/pages/new?name=J&return_url=/page/new"
So far I have..
^name=(.*?).
I am trying to return in this case, just the J, but its dynamic so it could very several characters, letters, or numbers.
The end case situation would be allowing myself to do a replace statement on this dynamic variable found by regex.

/name=([^&]*)/
remove the ^ and end with an &
Example:
var str = "/pages/new?name=J&return_url=/page/new";
var matches = str.match(/name=([^&]*)/);
alert(matches[1]);
The better way is to break all the params down (Example using current address):
function getParams (str) {
var queryString = str || window.location.search || '';
var keyValPairs = [];
var params = {};
queryString = queryString.replace(/.*?\?/,"");
if (queryString.length)
{
keyValPairs = queryString.split('&');
for (pairNum in keyValPairs)
{
var key = keyValPairs[pairNum].split('=')[0];
if (!key.length) continue;
if (typeof params[key] === 'undefined')
params[key] = [];
params[key].push(keyValPairs[pairNum].split('=')[1]);
}
}
return params;
}
var url = "/pages/new?name=L&return_url=/page/new";
var params = getParams(url);
params['name'];
Update
Though still not supported in any version of IE, URLSearchParams provides a native way of retrieving values for other browsers.

The accepted answer includes the hash part if there is a hash right after the params. As #bishoy has in his function, the correct regex would be
/name=([^&#]*)/

Improving on previous answers:
/**
*
* #param {string} name
* #returns {string|null}
*/
function getQueryParam(name) {
var q = window.location.search.match(new RegExp('[?&]' + name + '=([^&#]*)'));
return q && q[1];
}
getQueryParam('a'); // returns '1' on page http://domain.com/page.html?a=1&b=2

here is the full function (tested and fixed for upper/lower case)
function getParameterByName (name)
{
name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var regexS = "[\\?&]" + name.toLowerCase() + "=([^&#]*)";
var regex = new RegExp(regexS);
var results = regex.exec(window.location.search.toLowerCase());
if (results == null)
return "";
else
return decodeURIComponent(results[1].replace(/\+/g, " "));
}

The following should work:
\?name=(.*?)&

var myname = str.match(/\?name=([^&]+)&/)[1];
The [1] is because you apparently want the value of the group (the part of the regex in brackets).
var str = "/pages/new?name=reaojr&return_url=/page/new";
var matchobj = str.match(/\?name=([^&]+)&/)[1];
document.writeln(matchobj); // prints 'reaojr'

Here's a single line answer that prevents having to store a variable (if you can't use URLSearchParams because you still support IE)
(document.location.search.match(/[?&]name=([^&]+)/)||[null,null])[1]
By adding in the ||[null,null] and surrounding it in parentheses, you can safely index item 1 in the array without having to check if match came back with results. Of course, you can replace the [null,null] with whatever you'd like as a default.

You can get the same result with simple .split() in javascript.
let value = url.split("name=")[1].split("&")[0];

This might work:
\??(.*=.+)*(&.*=.+)?

One string multiple variables to check with indexOf

I have written a little JQuery / Javascript add on for our form, that takes a single full name input and breaks it into first and last name components. It opens a modal if there are three or more names in the input and asks which combo is correct.
My next step is finding and stripping any suffix that may have been entered such as Jr, Sr, III, etc. I am currently stripping off the last four characters and checking them with indexOf to see if they contain a suffix string (Jr, Sr, III, etc). But each line checks only one possible suffix and I am wondering is there is some js magic that will check multiple suffixs in one line. My current code is below:
var nameVal = $('#name').val();
var suffix = nameVal.slice(-4);
if (suffix.toLowerCase().indexOf(" jr") != -1) {
var nameSplit = nameVal.slice(0, -3).split(" ");
} elseif (suffix.toLowerCase().indexOf(" iii") != -1) {
var nameSplit = nameVal.slice(0, -4).split(" ");
} else {
var nameSplit = nameVal.split(" "); }
I can always do the good old || and keep adding extra (suffix.toLowerCase().indexOf(" jr") != -1) with a different indexOf value, but I am hoping to keep the code more compact if possible, my "little" script is already 3k.
Once I get this sorted the last step will be figuring out how to retain the last name value, so that further down the form when other names are entered and the script is called again it can check to see if the selected last name matches the new entry and bypass the modal pop up.

You can use a regular expression. Try something like this;
nameVal = nameVal.replace(/ (jr|sr|I?II)$/gi, "");
In more detail;
(jr|sr|I?II) = jr or sr or II or III
$ = at the end of line
/i = case insensitive
/g match globally

Probably best to use regexps for this, for example:
var names = [
"Joe Jr.",
"Mark Sr.",
"Loui III",
"Mark Lockering",
];
var suffixRes = [
/Jr\.$/, /Sr\.$/, 'III',
];
$(names).each(function(i, name) {
var str = name;
$(suffixRes).each(function(j, suffixRe) {
str = str.replace(suffixRe, '');
});
console.log(str);
});
Live example:
http://jsfiddle.net/am7QD/

In this case I usually make an array of values, (because I'm not good with regex)
var suffixArr = [' jr',' iii', ' ii'];
//then run a loop
for(var i = 0; i < suffixArr.length;i++){
if(suffixArr[i].toLowerCase().indexOf(suffixArr[i]) != -1){
nameSplit = nameVal.slice(0, - suffixArr[i].length).split(" ");
}
}