We Keep Coding

Project Euler - 67 - javascript

I was working through problem 67 on Project Euler, and this is the following code I used: (sorry if kind of messy
var everything = 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34,45,09,97,86,71,03,15,56,19,15,44,97,31,90,04,87,87,76,08,12,30,24,62,84,28,12,85,82,53,99,52,13,94,06,65,97,86,09,50,94,68,69,74,30,67,87,94,63,07,78,27,80,36,69,41,06,92,32,78,37,82,30,05,18,87,99,72,19,99,44,20,55,77,69,91,27,31,28,81,80,27,02,07,97,23,95,98,12,25,75,29,47,71,07,47,78,39,41,59,27,76,13,15,66,61,68,35,69,86,16,53,67,63,99,85,41,56,08,28,33,40,94,76,90,85,31,70,24,65,84,65,99,82,19,25,54,37,21,46,33,02,52,99,51,33,26,04,87,02,08,18,96,54,42,61,45,91,06,64,79,80,82,32,16,83,63,42,49,19,78,65,97,40,42,14,61,49,34,04,18,25,98,59,30,82,72,26,88,54,36,21,75,03,88,99,53,46,51,55,78,22,94,34,40,68,87,84,25,30,76,25,08,92,84,42,61,40,38,09,99,40,23,29,39,46,55,10,90,35,84,56,70,63,23,91,39,52,92,03,71,89,07,09,37,68,66,58,20,44,92,51,56,13,71,79,99,26,37,02,06,16,67,36,52,58,16,79,73,56,60,59,27,44,77,94,82,20,50,98,33,09,87,94,37,40,83,64,83,58,85,17,76,53,02,83,52,22,27,39,20,48,92,45,21,09,42,24,23,12,37,52,28,50,78,79,20,86,62,73,20,59,54,96,80,15,91,90,99,70,10,09,58,90,93,50,81,99,54,38,36,10,30,11,35,84,16,45,82,18,11,97,36,43,96,79,97,65,40,48,23,19,17,31,64,52,65,65,37,32,65,76,99,79,34,65,79,27,55,33,03,01,33,27,61,28,66,08,04,70,49,46,48,83,01,45,19,96,13,81,14,21,31,79,93,85,50,05,92,92,48,84,59,98,31,53,23,27,15,22,79,95,24,76,05,79,16,93,97,89,38,89,42,83,02,88,94,95,82,21,01,97,48,39,31,78,09,65,50,56,97,61,01,07,65,27,21,23,14,15,80,97,44,78,49,35,33,45,81,74,34,05,31,57,09,38,94,07,69,54,69,32,65,68,46,68,78,90,24,28,49,51,45,86,35,41,63,89,76,87,31,86,09,46,14,87,82,22,29,47,16,13,10,70,72,82,95,48,64,58,43,13,75,42,69,21,12,67,13,64,85,58,23,98,09,37,76,05,22,31,12,66,50,29,99,86,72,45,25,10,28,19,06,90,43,29,31,67,79,46,25,74,14,97,35,76,37,65,46,23,82,06,22,30,76,93,66,94,17,96,13,20,72,63,40,78,08,52,09,90,41,70,28,36,14,46,44,85,96,24,52,58,15,87,37,05,98,99,39,13,61,76,38,44,99,83,74,90,22,53,80,56,98,30,51,63,39,44,30,91,91,04,22,27,73,17,35,53,18,35,45,54,56,27,78,48,13,69,36,44,38,71,25,30,56,15,22,73,43,32,69,59,25,93,83,45,11,34,94,44,39,92,12,36,56,88,13,96,16,12,55,54,11,47,19,78,17,17,68,81,77,51,42,55,99,85,66,27,81,79,93,42,65,61,69,74,14,01,18,56,12,01,58,37,91,22,42,66,83,25,19,04,96,41,25,45,18,69,96,88,36,93,10,12,98,32,44,83,83,04,72,91,04,27,73,07,34,37,71,60,59,31,01,54,54,44,96,93,83,36,04,45,30,18,22,20,42,96,65,79,17,41,55,69,94,81,29,80,91,31,85,25,47,26,43,49,02,99,34,67,99,76,16,14,15,93,08,32,99,44,61,77,67,50,43,55,87,55,53,72,17,46,62,25,50,99,73,05,93,48,17,31,70,80,59,09,44,59,45,13,74,66,58,94,87,73,16,14,85,38,74,99,64,23,79,28,71,42,20,37,82,31,23,51,96,39,65,46,71,56,13,29,68,53,86,45,33,51,49,12,91,21,21,76,85,02,17,98,15,46,12,60,21,88,30,92,83,44,59,42,50,27,88,46,86,94,73,45,54,23,24,14,10,94,21,20,34,23,51,04,83,99,75,90,63,60,16,22,33,83,70,11,32,10,50,29,30,83,46,11,05,31,17,86,42,49,01,44,63,28,60,07,78,95,40,44,61,89,59,04,49,51,27,69,71,46,76,44,04,09,34,56,39,15,06,94,91,75,90,65,27,56,23,74,06,23,33,36,69,14,39,05,34,35,57,33,22,76,46,56,10,61,65,98,09,16,69,04,62,65,18,99,76,49,18,72,66,73,83,82,40,76,31,89,91,27,88,17,35,41,35,32,51,32,67,52,68,74,85,80,57,07,11,62,66,47,22,67,65,37,19,97,26,17,16,24,24,17,50,37,64,82,24,36,32,11,68,34,69,31,32,89,79,93,96,68,49,90,14,23,04,04,67,99,81,74,70,74,36,96,68,09,64,39,88,35,54,89,96,58,66,27,88,97,32,14,06,35,78,20,71,06,85,66,57,02,58,91,72,05,29,56,73,48,86,52,09,93,22,57,79,42,12,01,31,68,17,59,63,76,07,77,73,81,14,13,17,20,11,09,01,83,08,85,91,70,84,63,62,77,37,07,47,01,59,95,39,69,39,21,99,09,87,02,97,16,92,36,74,71,90,66,33,73,73,75,52,91,11,12,26,53,05,26,26,48,61,50,90,65,01,87,42,47,74,35,22,73,24,26,56,70,52,05,48,41,31,18,83,27,21,39,80,85,26,08,44,02,71,07,63,22,05,52,19,08,20,17,25,21,11,72,93,33,49,64,23,53,82,03,13,91,65,85,02,40,05,42,31,77,42,05,36,06,54,04,58,07,76,87,83,25,57,66,12,74,33,85,37,74,32,20,69,03,97,91,68,82,44,19,14,89,28,85,85,80,53,34,87,58,98,88,78,48,65,98,40,11,57,10,67,70,81,60,79,74,72,97,59,79,47,30,20,54,80,89,91,14,05,33,36,79,39,60,85,59,39,60,07,57,76,77,92,06,35,15,72,23,41,45,52,95,18,64,79,86,53,56,31,69,11,91,31,84,50,44,82,22,81,41,40,30,42,30,91,48,94,74,76,64,58,74,25,96,57,14,19,03,99,28,83,15,75,99,01,89,85,79,50,03,95,32,67,44,08,07,41,62,64,29,20,14,76,26,55,48,71,69,66,19,72,44,25,14,01,48,74,12,98,07,64,66,84,24,18,16,27,48,20,14,47,69,30,86,48,40,23,16,61,21,51,50,26,47,35,33,91,28,78,64,43,68,04,79,51,08,19,60,52,95,06,68,46,86,35,97,27,58,04,65,30,58,99,12,12,75,91,39,50,31,42,64,70,04,46,07,98,73,98,93,37,89,77,91,64,71,64,65,66,21,78,62,81,74,42,20,83,70,73,95,78,45,92,27,34,53,71,15,30,11,85,31,34,71,13,48,05,14,44,03,19,67,23,73,19,57,06,90,94,72,57,69,81,62,59,68,88,57,55,69,49,13,07,87,97,80,89,05,71,05,05,26,38,40,16,62,45,99,18,38,98,24,21,26,62,74,69,04,85,57,77,35,58,67,91,79,79,57,86,28,66,34,72,51,76,78,36,95,63,90,08,78,47,63,45,31,22,70,52,48,79,94,15,77,61,67,68,23,33,44,81,80,92,93,75,94,88,23,61,39,76,22,03,28,94,32,06,49,65,41,34,18,23,08,47,62,60,03,63,33,13,80,52,31,54,73,43,70,26,16,69,57,87,83,31,03,93,70,81,47,95,77,44,29,68,39,51,56,59,63,07,25,70,07,77,43,53,64,03,94,42,95,39,18,01,66,21,16,97,20,50,90,16,70,10,95,69,29,06,25,61,41,26,15,59,63,35];
function getRow(row) {
if(row == 1) return 59;
else {
var num = 0;
var array = [];
for(var i = 1;i < row;i ++) {
num += i;
}
for(var i = 0;i < row;i ++) {
array = array.concat(everything[i + num])
}
return array;
}
}
function pickHighest(lastnumplace, lastrow) {
var highest = [];
var row = getRow(lastrow + 1);
highest = highest.concat(Math.max(row[lastnumplace - 1], row[lastnumplace]));
highest = highest.concat(lastrow + 1);
if(Math.max(row[lastnumplace - 1], row[lastnumplace]) == row[lastnumplace - 1]) highest = highest.concat(lastnumplace);
else highest = highest.concat(lastnumplace + 1);
return highest;
}
var sum = 0;
var highest;
for(var i = 1;i <= 100;i ++) {
if(i == 1) {
highest = [59, 1, 1];
sum += 59;
}
else {
highest = pickHighest(highest[2], i - 1);
sum += highest[0];
}
document.write(sum + " " + highest + "<br>");
}
alert(sum);
alert(i);
For some strange reason, I always get 6580.
https://projecteuler.net/problem=67
Help?

In 'getRow' function you are adding all row elements in the loop, but it is not increasing by the number of elements as you wrote but '2^row number' - you just summed the elements from the previous row.
From row 3 it will not work.

Related

I want to calculate how many Y's & N's appear in an array / range defined:
Cell Range: D4:D42
function myFunction() {
var count = SpreadsheetApp.getActiveSheet().getRange(5, 3, 40, 1);
var numRows = count.getNumRows();
var numCols = count.getNumColumns();
var y = 0;
var n = 0;
for (var i = 1; i <= numRows; i++) {
for (var j = 1; j <= numCols; j++) {
var currentValue = count.getCell(i, j).getValue();
if (currentValue = "y") {
y = y + 1;
} else if (currentValue = "n") {
n = n + 1;
}
}
}
Browser.msgBox("There are " + y + " paid & " + n + " not paid");
}
This returns 40 Y's and 0 N's
Not sure what I am doing wrong here but I think it's a simple fix!

The problem is in this line:
if (currentValue = "y") {
You are assigning "y" to currentValue. To actually check for equality, you should try the "===" operator. Try this and see if it solves your problem:
function myFunction() {
var count = SpreadsheetApp.getActiveSheet().getRange(5, 4, 39, 1);
var numRows = count.getNumRows();
var numCols = count.getNumColumns();
var y = 0;
var n = 0;
for (var i = 1; i <= numRows; i++) {
for (var j = 1; j <= numCols; j++) {
var currentValue = count.getCell(i, j).getValue();
if (currentValue === "y") {
y = y + 1;
} else if (currentValue === "n") {
n = n + 1;
}
}
}
Browser.msgBox("There are " + y + " paid & " + n + " not paid");
}
I also updated the getRange() parameters to match D4:D42. In your code, they matched C5:C44. See the getRange() function documentation.

I try to develop a simple program that prints all numbers in between 1 and 100 that divide by 3 without any residual and calculate the total sum
I did it with for loop:
var sum = 0;
for (var i = 3; i <= 100; i = i + 3) {
document.write("<br/>" + i);
sum = sum + i;
}
document.write("<br/>sum = " + sum); //1683
But I failed when I wanted to do it with array:
var numbers = [];
var sum = 0;
for (var i = 0; i <= 100; i = i + 3) {
numbers[i - 1] = i;
}
for (var index = 0; index < 100; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + i;
}
document.write("<br/>sum = " + sum);

Use it like this,
Array indexes should start from 0, that is why I have introduced another variable j=0
var numbers = [];
var sum = 0;
for (var i = 0, j = 0; i <= 100; i = i + 3, ++j) {
numbers[j] = i;
}
Update
First Issue:
In your code, ie. below code of yours,
for (var i = 0; i <= 100; i = i + 3) {
numbers[i - 1] = i;
}
In the first iteration,
i = 0;
numbers[0-1] = i // i.e numbers[-1] = 0;
and in your second loop, you are starting the index from 0
for (var index = 0; index < 100; index++) {
Second issue:
Also, if you don't use a sequential counter to fill the Array, you will end with undefined values for the ones you did not fill.
If you notice, the output after the loop, it says numbers.length = 99 which is wrong it will not have that many items in it.
Third Issue:
In below code, even if you introduce a sequential counter, this is still wrong
for (var i = 0; i <= 100; i = i + 3) {
numbers[i - 1] = i;
}
because i should start with 3 instead of 0, otherwise you will end up with 34 elements in the array because numbers[0] will be 0;
Fourth Issue:
In this code,
for (var index = 0; index < 100; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + i;
}
You don't actually have to loop it till 100, you already have the numbers array filled, so you just need to use numbers.length, like this
var len = numbers.length;
for (var index = 0; index < len; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + i;
}
A better way to write this
var numbers = [];
for (var i = 3, j=0; i <= 100; i = i + 3, j++) {
numbers[j] = i;
}
var sum = numbers.reduce((a, b) => a+b);
console.log(sum);
The line var sum = numbers.reduce((a, b) => a+b); uses Array.reduce() method.

adding number to array
var numbers = [];
for(var i = 3; i <= 100; i = i +3){
numbers.push(i);
}
summation and printing values
var sum = 0;
for (var i = 0; i < numbers.length; i++) {
document.write("<br/>" + numbers[i]);
sum = sum + numbers[i];
}
document.write("<br/>sum = " + sum); //1683

There are few issues in your code.
for (var i = 0; i <= 100; i = i + 3) {
numbers[i - 1] = i;
}
1: array is 0 based. so first insertion into the array goes for a toss.
2: the number array created will have skipping index like 3, 6 ,9
for (var index = 0; index < 100; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + i;
}
3: Here you are iterating index till 100 , you should iterate it till the length of the numbers array only.
when index is 1,2
number[index] will become undefined.
4: sum = sum + i (i ??????)
You should try like this or you can also use push()
var numbers = [];
var sum = 0;
for (var i = 0,j=0; i <= 100; i = i + 3, j= j+1) {
numbers[j] = i; // array is 0 based.
}
for (var index = 0; index < numbers.length; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + numbers[index];
}
document.write("<br/>sum = " + sum);

Indexes in an array begin with zero.
for (var i = 0; i <= 100; i = i + 3) {
numbers[i - 1] = i; // In the first iteration, there will be numbers[-1] = i;
}

You have several issues i suppose.
var numbers = [];
var sum = 0;
for (var i = 0; i <= 100; i = i + 3) {
numbers.push(i);
}
for (var index = 0; index < numbers.length; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + i;
}
document.write("<br/>sum = " + sum);
Also for array you can use:
for (var i in array) {
console.log(array[i]);
}
And I'm pretty sure, that array of number sequence is absolutely useless, if there is no other information in it.

Try this
var numbers = [];
var sum = 0;
for (var i = 0; i <= 100; i = i + 3) {
numbers[(i-3)/3] = i;
}
for (var index = 0; index < numbers.length; index++) {
document.write("<br/>" + numbers[index]);
sum = sum + numbers[index];
}
document.write("<br/>sum = " + sum);
Here is the fiddle i tried
https://jsfiddle.net/4ncgnd7c/

This should work using a single loop
var numbers = [];
var sum = 0;
for (var i = 3; i <= 100; i = i + 3) {
numbers[i] = i;
document.write("<br/>" + i);
sum = sum + i;
}
document.write("<br/>sum = " + sum);

I wrote a JavaScript function to find the number of odd integers, number of negative integers, average, and median value.
The code is accomplishing everything that I wanted it to, however, I am wondering if I can rewrite it to get the function to return an object rather than just the console log values. I've also included a link to my JS Bin (https://jsbin.com/digagozuru/edit?html,css,js,console,output)
Any advice or suggestions would be appreciated! Thanks.
var arrayAnalyzer = function(myArray) {
var odds = 0;
var negatives = 0;
var avg;
var median;
for (var i = 0; i < myArray.length; i++) {
if (myArray[i] % 2 !== 0) {
odds += 1;
}
if (myArray[i] < 0) {
negatives += 1;
}
}
console.log("There are " + odds + " odd numbers.");
console.log("There are " + negatives + " negative numbers.");
var sum = myArray.reduce(function(previousValue, currentValue) {
return previousValue + currentValue;
});
avg = sum / myArray.length;
console.log("The average is " + avg.toFixed(2));
var orderedArray = myArray.sort(function(a, b) {
return a - b;
});
if (orderedArray.length % 2 === 0) {
var position1 = orderedArray.length / 2;
var position2 = position1 - 1;
median = (orderedArray[position1] + orderedArray[position2]) / 2;
} else {
var position = Math.floor(orderedArray.length / 2);
median = orderedArray[position];
}
console.log("The median is " + median);
};
arrayAnalyzer([7, -3, 0, 12, 44, -5, 3]);

var arrayAnalyzer = function(myArray) {
var odds = 0;
var negatives = 0;
var avg;
var median;
for (var i = 0; i < myArray.length; i++) {
if (myArray[i] % 2 !== 0) {
odds += 1;
}
if (myArray[i] < 0) {
negatives += 1;
}
}
console.log("There are " + odds + " odd numbers.");
console.log("There are " + negatives + " negative numbers.");
var sum = myArray.reduce(function(previousValue, currentValue) {
return previousValue + currentValue;
});
avg = sum / myArray.length;
console.log("The average is " + avg.toFixed(2));
var orderedArray = myArray.sort(function(a, b) {
return a - b;
});
if (orderedArray.length % 2 === 0) {
var position1 = orderedArray.length / 2;
var position2 = position1 - 1;
median = (orderedArray[position1] + orderedArray[position2]) / 2;
} else {
var position = Math.floor(orderedArray.length / 2);
median = orderedArray[position];
}
console.log("The median is " + median);
// Returns an object with named attributes
return {
odds:odds,
negatives:negatives,
avg:avg,
median:median
};
};
var myArray = arrayAnalyzer([7, -3, 0, 12, 44, -5, 3]);
console.log("Odds: " + myArray.odds +
"\nNegatives: " + myArray.negatives +
"\nAverage:" + myArray.avg +
"\nMedian: " + myArray.median);

I'm not sure if I get your question right, but why dont create an object at the beginning of your method and then write the values in the object as soon as you calculated them?
var arrayAnalyzer = function(myArray) {
var odds = 0;
var negatives = 0;
var avg;
var median;
var result = {};
for (var i = 0; i < myArray.length; i++) {
if (myArray[i] % 2 !== 0) {
odds += 1;
}
if (myArray[i] < 0) {
negatives += 1;
}
}
result.negatives = negatives;
result.odds = odds;
var sum = myArray.reduce(function(previousValue, currentValue) {
return previousValue + currentValue;
});
avg = sum / myArray.length;
result.avg = avg;
var orderedArray = myArray.sort(function(a, b) {
return a - b;
});
if (orderedArray.length % 2 === 0) {
var position1 = orderedArray.length / 2;
var position2 = position1 - 1;
median = (orderedArray[position1] + orderedArray[position2]) / 2;
} else {
var position = Math.floor(orderedArray.length / 2);
median = orderedArray[position];
}
result.median = median;
return result;
};
console.log(arrayAnalyzer([7, -3, 0, 12, 44, -5, 3]));

My results for numbers between 1 and 28321 (limit)
sum of all numbers: 395465626
sum of all abundant numbers: 392188885
sum of all non abundant numbers: 3276741 (correct answer is 4179871)
var divisors = function(number){
sqrtNumber = Math.sqrt(number);
var sum = 1;
for(var i = 2; i<= sqrtNumber; i++)
{
if (number == sqrtNumber * sqrtNumber)
{
sum += sqrtNumber;
sqrtNumber--;
}
if( number % i == 0 )
{
sum += i + (number/i);
}
}
if (sum > number) {return true;}
else {return false;}
};
var abundent = [], k = 0;
var upperLimit = 28123;
for (var i = 1; i <= upperLimit; i++)
{
if (divisors(i))
{abundent[k] = i; k++};
}
var abundentCount = abundent.length;
var canBeWrittenAsAbundant = [];
for (var i = 0; i < abundentCount; i++){
for (var j = i; j < abundentCount; j++){
if (abundent[i] + abundent[j] <= upperLimit){canBeWrittenAsAbundant[abundent[i]+abundent[j]] = true;}
else {
break;
}
}
}
for (i=1; i <= upperLimit; i++){
if (canBeWrittenAsAbundant[i] == true){continue;}
else {canBeWrittenAsAbundant[i] = false;}
}
var sum = 0;
for (i=1; i <= upperLimit; i++)
{
if (!canBeWrittenAsAbundant[i]){
sum += i;
}
}
console.log(sum);
I'm using http://www.mathblog.dk/project-euler-23-find-positive-integers-not-sum-of-abundant-numbers/ as guidance, but my results are different. I'm a pretty big newb in the programming community so please keep that in mind.

You do not need to calculate the sum of all numbers using a cycle, since there is a formula, like this:
1 + 2 + ... + number = (number * (number + 1)) / 2
Next, let's take a look at divisors:
var divisors = function(number){
sqrtNumber = Math.sqrt(number);
var sum = 1;
for(var i = 2; i<= sqrtNumber; i++)
{
if (number == sqrtNumber * sqrtNumber)
{
sum += sqrtNumber;
sqrtNumber--;
}
if( number % i == 0 )
{
sum += i + (number/i);
}
}
if (sum > number) {return true;}
else {return false;}
};
You initialize sum with 1, since it is a divisor. However, I do not quite understand why do you iterate until the square root instead of the half of the number. For example, if you call the function for 100, then you are iterating until i reaches 10. However, 100 is divisible with 20 for example. Aside of that, your function is not optimal. You should return true as soon as you found out that the number is abundant. Also, the name of divisors is misleading, you should name your function with a more significant name, like isAbundant. Finally, I do not understand why do you decrease square root if number happens to be its exact square and if you do so, why do you have this check in the cycle. Implementation:
var isAbundant = function(number) {
var sum = 1;
var half = number / 2;
for (var i = 2; i <= half; i++) {
if (number % i === 0) {
sum += i;
if (sum > number) {
return true;
}
}
}
return false;
}
Note, that perfect numbers are not considered to be abundant by the function.
You do not need to store all numbers, since you are calculating aggregate data. Instead, do it like this:
//we assume that number has been initialized
console.log("Sum of all numbers: " + ((number * (number + 1)) / 2));
var abundantSum = 0;
var nonAbundantSum = 0;
for (var i = 0; i <= number) {
if (isAbundant(i)) {
abundantSum += i;
} else {
nonAbundantSum += i;
}
}
console.log("Sum of non abundant numbers: " + nonAbundantSum);
console.log("Sum of abundant numbers: " + abundantSum);
Code is not tested. Also, beware overflow problems and structure your code.

Below is the Corrected Code for NodeJS..
var divisors = function (number) {
sqrtNumber = Math.sqrt(number);
var sum = 1;
var half = number / 2;
for (var i = 2; i <= half; i++) {
if (number % i === 0) { sum += i; }
}
if (sum > number) { return true; }
else { return false; }
};
var abundent = [], k = 0;
var upperLimit = 28123;
for (var i = 1; i <= upperLimit; i++) {
if (divisors(i)) { abundent[k] = i; k++ };
}
var abundentCount = abundent.length;
var canBeWrittenAsAbundant = [];
for (var i = 0; i < abundentCount; i++) {
for (var j = i; j < abundentCount; j++) {
if (abundent[i] + abundent[j] <= upperLimit) { canBeWrittenAsAbundant[abundent[i] + abundent[j]] = true; }
else {
break;
}
}
}
for (i = 1; i <= upperLimit; i++) {
if (canBeWrittenAsAbundant[i] == true) { continue; }
else { canBeWrittenAsAbundant[i] = false; }
}
var sum = 0;
for (i = 1; i <= upperLimit; i++) {
if (!canBeWrittenAsAbundant[i]) {
sum += i;
}
}
console.log(sum);

When I run this program I am only getting the even number count and the odd sum. The odd count and even sum just gives me 0 every time.
Does anyone have any idea what I am missing? Thanks!
I am trying to generate 100 random numbers and keep count of the evens/odds and then get the sum of each.
var min = 1;
var max = 1000;
var randomNumArray = []
var oddCount = []
var evenCount = []
var oddSum = []
var evenSum = []
function isEven(x){
if (x % 2 == 0)
return true;
else
return false;
}
function sumOfArray(evenSum){
for(i = 0; i< evenSum.length; i++){
if (isEven){
return(evenSum);
}
else{
return (oddSum);
}
}
}
for( i = 0; i < 100; i++){
var randNumber = Math.floor(min + (Math.random() * max));
randomNumArray.push(randNumber);
}
for( i = 0; i< randNumber.length; i++){
if (isEven(evenCount[i])){
return evenCount;
}
else{
return oddCount;
}
}
console.log('Even Number Count: ' + evenCount);
console.log('Odd Number Count: ' + oddCount);
console.log('Sum Even: ' + evenSum);
console.log('Sum Odd: ' + oddSum);

I would just use 1 function to check if its even or odd and then decide to add the sum by the number itself and the count by 1. You are making it way more complicated and I'm wondering why u are using arrays.

Try something like this:
for( i = 0; i < 100; i++){
var randNumber = Math.floor(min + (Math.random() * max));
if(isEven(randNum)){
evenSum = evensum+randNum;
evenCount ++;
}else{
oddSum= oddSum+randNum;
oddSum++;
}
}

var oddCount = 0
var evenCount = 0
for(i=0; i<randomNumArray.length; i++) {
if(randomNumArray[i] % 2 == 0) {
evenCount++
} else {
oddCount++
}
};
Something like that should work?