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How to get the value of title image and content in ajax php

How to display the data title, image and content?
Here's the code:
view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$dataArr = array();
$responseArr = array();
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
array_push($dataArr, $data);
}
echo json_encode($dataArr);
}
mysqli_free_result($result);
} else {
echo "No Record";
}
}
index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
alert(data)
}
});
});
});
What I'm trying to do is to get the title, image and content.
How to get the value of title, image and content?
How to call the "title", "name" and "content" from the php?
console.log('DATA: ' + data);

No need to use while loop for result. Also remove extra $dataArr and $responseArr
Update your code to:
in view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
$row = mysqli_fetch_array($result);
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
echo json_encode($data); exit;
}
mysqli_free_result($result);
}
}
$data['error'] = "No Record";
echo json_encode($data); exit;
Index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
var response = jQuery.parseJSON(data);
var title = response.title;
var name = response.name;
var content = response.content;
alert(title);
alert(name);
alert(content);
}
});
});
});
After taking data from jQuery side, you can set value in html side using id or class attribute in jQuery.

How your ajax receiving .php file should look:
$validLiteratureIds = ['yourTable1', 'yourTable2'];
if (!isset($_GET['edit_literature_id'], $_GET['literatureID']) || !in_array($_GET['literatureID'], $validLiteratureIds)) {
$response = ['error' => 'Missing/Invalid Data Submitted'];
} else {
$conn = new mysqli('localhost', 'root', '', 'dbname');
$sql = "SELECT title, name, content
FROM `{$_GET['literatureID']}`
WHERE `id` = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param("s", $_GET['edit_literature_id']);
$stmt->execute();
$stmt->bind_result($title, $name, $content);
if (!$stmt->fetch()) {
$response = ['error' => 'No Record'];
} else {
$response = [
'title'=> $title,
'name' => 'data:image/jpeg;base64,' . base64_encode($name),
'content' => $content
];
}
}
echo json_encode($response);
Important practices:
Validate the user input so that only qualifying submissions have the privilege of accessing your database.
Write the failure outcomes before success outcomes consistently throughout your project, this will make your scripts easier to read/follow.
Always use prepared statements and bind user-supplied data to placeholders into your query for stability/security.
The tablename cannot be bound like the id value; it must be written directly into your sql string -- this is why it is critical that you validate the value against a whitelist array of literature ids.
There is no need to declare new variables to receive the $_GET values; just access the values directly from the superglobal array.
I am going to assume that your id is a primary/unique key in your table(s), so you don't need to loop over your result set. Attempt to fetch one row -- it will either contain data or the result set was empty.
Call json_encode() only once and at the end of your script.
It is not worth clearing any results or closing a prepared statement or a connection, because those tasks are automatically done when the script execution is finished anyhow -- avoid the script bloat.
As for your jquery script:
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (response) {
if (response.hasOwnProperty('error')) {
console.log(response.error);
} else {
console.log(response.title, response.name, response.content);
}
}
});
});
});
I've trim away all of the irrelevant lines
changed POST to GET -- because you are merely reading data from the database, not writing
parseJSON() is not necessary -- response is a ready-to-use object.
I am checking for an error property in the response object so that the appropriate data is accessed.
Both scripts above are untested (and completely written from my phone). If I have made any typos, please leave me a comment and I'll fix it up.

Requesting data from php through ajax

Trying to request the posts made by users and loading more posts on user's request.
Getting Unexpected end of JSON input error while making ajax request in console.
Javascript
$("#ajax_load_more").click(function(){
$.ajax({
type: "GET",
url: "action.php?action=morePosts",
success: function(response){
var result = $.parseJSON(response);
console.log(result);
}
});
});
Making request to following code.
$_SESSION['posts']) stores the number of posts to be loaded in the session.
if($_GET['action']=="morePosts"){
if(isset($_SESSION['posts'])){
$_SESSION['posts'] = $_SESSION['posts'] + 4;
echo fetchAllPosts($_SESSION['posts']);
} else if(isset($_SESSION['posts'])&& $_SESSION['posts']>4){
$_SESSION['posts'] = 4;
}
}
Function for requesting all posts
function fetchAllPosts2($array_length){
$db = new db; //Class for database
$query = "SELECT * FROM `posts` ORDER BY `post_id` DESC LIMIT $array_length";
$result = $db::query($query);
$row = mysqli_fetch_all($result);
$post = array();
for($i=0; $i<$array_length; $i++){
if(!empty($row[$i])){
for($j=0;$j<count($row);$j++){
$post['id']=$row[$i][0];
$post['user_id']=$row[$i][1];
$post['title']=substr($row[$i][2], 0 ,75);
$post['text']=strip_tags(mb_substr($row[$i][3],0,50));
$post['image']=$row[$i][4];
$post['date']=$row[$i][5];
}
return json_encode($post);
}
elseif(empty($row[count($row)])){
return json_encode(array());
}
}
}
Please suggest better ways of achieving this functionality,

Try to use echo instead of return and change ajax like also you din not echo the code inside elseif part:
$("#ajax_load_more").click(function(){
$.ajax({
type: "GET",
dataType: "json",
url: "action.php?action=morePosts",
success: function(response){
console.log(response);
}
});
});

try this :
function fetchAllPosts2($array_length){
$db = new db; //Class for database
$query = "SELECT * FROM `posts` ORDER BY `post_id` DESC LIMIT $array_length";
$result = $db::query($query);
$row = mysqli_fetch_all($result);
$post = array();
if($result && mysqli_num_rows($result) > 0) {
foreach($row as $key=>$value){
$post[$key]['id']=$value['id'];
$post[$key]['user_id']=$value['user_id'];
$post[$key]['title']=substr($value['title'], 0 ,75);
$post[$key]['text']=strip_tags(mb_substr($value['text'],0,50));
$post[$key]['image']=$value['image'];
$post[$key]['date']=$value['date'];
}
return json_encode($post);
}
return json_encode(['error'=>"no post found"]);
}

Ajax call to php, get mysql data as array and use in JS function

I'm looking to make an ajax call to a PHP script to get data from MySQL, create a json array and pass it back to the success function of the ajax call, where i will then use it as parameters for a JavaScript function.
This is my ajax call,
$('button[name="message"]').click(function() {
var $row = $(this).closest("tr"); // Find the row
var $tenant_id = $row.find(".col-md-1 id").text(); // Find the tenants ID
var $landlord_id = "<?php echo $id; ?>"
$.ajax({
url : "./message.php",
type : "POST",
async : false,
data: {
landlord_id: $landlord_id,
tenant_id : $tenant_id
},
success: function(data){
console.log(data);
var messages = data;
insertChat(messages.sender_id, messages.body, messages.timestamp);
}
})
});
And this is my PHP file,
<?php
session_start();
require_once('../dbconnect.php');
// update tenants table to show deposit returned
if(isset($_POST['tenant_id'])){
$tenant_id = $_POST['tenant_id'];
$landlord_id = $_POST['landlord_id'];
$sql = "SELECT * from messages WHERE messages.sender_id OR messages.receiver_id = '$tenant_id' AND messages.sender_id OR messages.receiver_id = '$landlord_id'";
$result = mysqli_query($conn, $sql) or die("Error in Selecting " . mysqli_error($conn));
//create an array
$messages = array();
while($row =mysqli_fetch_assoc($result))
{
$messages[] = $row;
}
echo json_encode($messages);
}
?>
If anybody has a link to a tutorial or the individual parts that would be fantastic. I don't even know if the process i have outlined above is correct.
If anybody could tell me the correct way to go about this that would be of great help!
Thanks

Just a few things to adjust your javascript side (I won't explain the php sql injection issue you have... but please research prepare, bind_param and execute):
Since you are returning an ARRAY of $messages from php (json_encoded), you need to loop on those in your success handler.
Add dataType: 'JSON' to your options, so it explicitly expects json returned from php.
And you were missing a couple semicolons ;)
Adjustments added to your code:
$('button[name="message"]').click(function() {
var $row = $(this).closest("tr");
var tenant_id = $row.find(".col-md-1 id").text();
var landlord_id = "<?php echo $id; ?>";
$.ajax({
url : "./message.php",
type : "POST",
data: {
landlord_id: landlord_id,
tenant_id : tenant_id
},
dataType: 'JSON',
success: function(data){
console.log(data);
if (typeof data !== undefined) {
for(var i = 0; i < data.length; i++) {
insertChat(data[i].sender_id, data[i].body, data[i].timestamp);
}
}
}
});
});

AJAX call returning json array undefined

I've seen that there has been a lot of questions about this but I did not find any specifics that could apply to my case so if I'm creating a duplicate, sorry for that.
I am trying to retrieve data from SQL database with php file that passes the data to ajax call. Everything seems to be working fine, just when I try to output data into console I get "undefined" variable, even when I tried accessing a precise part of the array with data.story for example. I have also tried data[0].story but that gave me an error that 'story' field of undefined cannot be accessed.
The code is below:
Thanks for your help guys.
my php file:
<?php
$con = mysqli_connect('localhost','root','password','db');
if (!$con) {
die('Could not connect: ' . mysqli_error($con));
}
$array = array();
$sqlFetch = "SELECT s.storyTitle, s.story, s.lattitude, s.longitude,
u.nickname, u.platformUsed, u.sexuality, u.gender, u.age, s.category,
s.dateRecorded FROM stories AS s INNER JOIN users AS u ON u.email = s.email
WHERE s.postStatus != 'published'";
$result = mysqli_query($con,$sqlFetch);
if(!is_null($result->num_rows)){
$encode = array();
while($row = mysqli_fetch_assoc($result)) {
$encode[] = $row;
}
echo json_encode($encode);
}
?>
and ajax code:
$.ajax({
type: 'post',
url: "http://localhost/wordpress/wp-content/themes/TinDA/js/loadData.php",
dataType: 'json',
data: "",
}).done(function(data){
console.log(data);
//tried also: console.log(data.story); and data[0].story;
});

It seems that you are mixing the mysqli connection for
Procedural Style with Object Oriented Style
Procedural:
$con = mysqli_connect('localhost','root','password','db');
$result = mysqli_query($con, "SOME SELECT STATEMENT");
while ($row = mysqli_fetch_assoc($result)){
$data[] = $row;
}
$rows = mysqli_num_rows($result);
if($rows){
json_encode(array('data' => $data, 'msg'=> 'successs'));
} else {
json_encode(array('data' => $data, 'msg'=> 'error or no records...'));
}
OOP:
$con = new mysqli('localhost','root','password','db');
if($con->connect_errno){
echo "WTF didn't work!!" . $con->connect_error;
}
$res = $con->query('SOME SELECT STMNT');
while ($row = $res->fetch_assoc()){
$data[] = $row;
}
$rows = $con->num_rows;
if($rows){
json_encode(array('data' => $data, 'msg'=> 'successs'));
}else {
json_encode(array('data' => $data, 'msg'=> 'error or no records...'));
}
I also like to use this version of ajax (different with 3.0 may not work).
You can then see the data errors. Note, you can have a successful ajax call and return but still have an error.
$.ajax( '/http://localhost/...', {
type: 'POST',
dataType: 'json',
success: function( json ) {
console.log( json );
},
error: function( req, status, err ) {
console.log( 'WTF!!', status, err );
}
});

Why my php array return only recent/last post activities

I create a jquery which sent data to a php file and after query(If any data found at sql) php return data to jquery by json_encode for append it.
Jquery sent two type data to php file:
1st: page id
2nd: post ids (a jquery array sent them to php file)
If I used print_r($_REQUEST['CID']); exit; on php file for test what he get from jquery, Its return and display all post ids well.
But if I make any reply on particular post, Its only return recent post reply.
That means, if I have 3 post like: post-1st, post-2nd, post-3rd ; my php return only post-3rd activities.
I want my script update any post reply when it submitted at sql.
my wall.php
// id is dynamic
<div class="case" data-post-id="111"></div>
<div class="case" data-post-id="222"></div>
<div class="case" data-post-id="333"></div>
//Check for any update after 15 second interval by post id.
<script type="text/javascript" charset="utf-8">
var CID = [];
$('div[data-post-id]').each(function(i){
CID[i] = $(this).data('post-id');
});
function addrep(type, msg){
CID.forEach(function(id){
$("#newreply"+id).append("<div class='"+ type +""+ msg.id +"'><ul>"+ msg.detail +"</ul></div>");
});
}
var tutid = '<?php echo $tutid; ?>';
function waitForRep(){
$.ajax({
type: "GET",
url: "/server.php",
cache: false,
data: {
tutid : tutid,
CID : CID
},
timeout:15000,
success: function(data){
addrep("postreply", data);
setTimeout(
waitForRep,
15000
);
},
error: function(XMLHttpRequest, textStatus, errorThrown){
setTimeout(
waitForRep,
15000);
}
});
}
$(document).ready(function(){
waitForRep();
});
</script>
server.php (may be problem in my array or something else)
while (true) {
if($_REQUEST['tutid'] && $_REQUEST['CID']){
foreach($_REQUEST['CID'] as $key => $value){
date_default_timezone_set('Asia/Dhaka');
$datetime = date('Y-m-d H:i:s', strtotime('-15 second'));
$res = mysqli_query($dbh,"SELECT * FROM comments_reply WHERE post_id =".$value." AND qazi_id=".$_REQUEST['tutid']." AND date >= '$datetime' ORDER BY id DESC LIMIT 1") or die(mysqli_error($dbh));
} // array close
$rows = mysqli_fetch_assoc($res);
$row[] = array_map('utf8_encode', $rows);
$data = array();
$data['id'] = $rows['id'];
$data['qazi_id'] = $rows['qazi_id'];
//ect all
// do something and echo $data['detail'] = $detail;
if (!empty($data)) {
echo json_encode($data);
flush();
exit(0);
}
} // request close
sleep(5);
} // while close

Try to declare CID array like this:
var CID = new Array();

It looks like you're looping through the CIDs and running an SQL query for each one, but you're only retrieving the results once, outside of the loop. You'll only get the last query's results if you run
$rows = mysqli_fetch_assoc($res);
outside of the CIDs foreach loop.
#koc:
Unfortunately, it won't be as simple as moving the closing loop bracket. If you're trying to retrieve multiple datasets in one AJAX call, then you'll need to handle multiple datasets in your AJAX's success callback, or in your addrep() function. Here's one way to do it, but you can do it many different ways depending on what you're ultimately trying to do:
while (true) {
if($_REQUEST['tutid'] && $_REQUEST['CID']){
$data = array();
foreach($_REQUEST['CID'] as $key => $value){
date_default_timezone_set('Asia/Dhaka');
$datetime = date('Y-m-d H:i:s', strtotime('-15 second'));
$res = mysqli_query($dbh,"
SELECT *
FROM comments_reply
WHERE post_id =".$value."
AND qazi_id=".$_REQUEST['tutid']."
AND date >= '$datetime'
ORDER BY id DESC LIMIT 1
") or die(mysqli_error($dbh));
$row = mysqli_fetch_assoc($res)
$data[] = array_map('utf8_encode', $row);
} // array close
//$rows = mysqli_fetch_assoc($res);
//$row[] = array_map('utf8_encode', $rows);
//$data = array();
//$data['id'] = $rows['id'];
//$data['qazi_id'] = $rows['qazi_id'];
//ect all
// do something and echo $data['detail'] = $detail;
if (!empty($data)) {
echo json_encode($data);
flush();
exit(0);
}
} // request close
sleep(5);
} // while close
then in your Javascript:
...
success: function(data){
for (var i=0, len=data.length; i<len; i++) {
addrep("postreply", data[i]);
}
setTimeout(waitForRep, 15000);
},
...
But again, that's just an example. I don't really know what your datasets look like or how you want the data to be passed around and used. This is just an idea that hopefully gets you going in the right direction.