I am trying to reverse the table row order , with the exception of the first/last row. Have a jsfiddle set up , that is reversing all tr but need to make last row and first row exempt for script
http://jsfiddle.net/Ybyjx/6/
<table id="league_chat">
<tbody>
<tr><td>ALWAYS LEAVE THIS TR AT THE TOP/td></tr>
<tr><td>lots of custom content</td></tr>
<tr><td>lots of other custom content</td></tr>
<tr><td>more custom content</td></tr>
<tr><td>even more custom content</td></tr>
<tr class="reportfooter"><td>ALWAYS LEAVE THIS TR AT THE BOTTOM</td></tr>
</tbody>
</table>
tbody = $('#league_chat tbody');
tbody.children().each(function (i, tr) {
tbody.prepend(tr);
});
You can use get() to get the native nodeList, then reverse() to reverse it, and just add it back.
The last one is excluded with not()
var tbody = $('#league_chat tbody');
$('tr:first', tbody).after( $('tr', tbody).not(':last', ':first').get().reverse() );
FIDDLE
tbody = $('#league_chat tbody');
tbody.children().not(':first').not(":last").each(function (i, tr) {
tbody.find('tr:first').after(tr);
});
In most circumstances where you need to keep the first row and last row constant you probably need to use a header and footer Sample Solution
<table id="league_chat">
<thead>
<tr><td>ALWAYS LEAVE THIS TR AT THE TOP</td></tr>
</thead>
<tbody>
<tr><td>lots of custom content</td></tr>
<tr><td>lots of other custom content</td></tr>
<tr><td>more custom content</td></tr>
<tr><td>even more custom content</td></tr>
</tbody>
<tfoot>
<tr class="reportfooter"><td>ALWAYS LEAVE THIS TR AT THE BOTTOM</td></tr>
</tfoot>
</table>
This is a simple way to do it.
tbody.children().not('.reportfooter').each(function (i, tr) {
$('#league_chat tbody tr:first').after(tr);
});
Related
I need to append data to a table dynamically from a JSON object.
After adding the titles as th elements, I am finding it difficult to add tr elements in the same column as the corresponding th element. Please help me.
{
"Category2":"Item2",
"Category1":"Item1",
"Category3":"Item3"
}
<table>
<th>Category1</th>
<th>Category2</th>
<th>Category3</th>
</table>
Now, I need to add items in td tags in the columns same as their corresponding th elements. like:
<table>
<th>Category1</th>
<th>Category2</th>
<th>Category3</th>
<tr>
<td>Item1</td>
</tr>
<tr>
<td>Item2</td>
</tr>
<tr>
<td>Item3</td>
</tr>
</table>
How can I do this using jQuery? (My problem is bigger than this. I simplified it so that it can be understood. Thank you!)
Here you go, Press Run code snippet and check if this works for you.
var nodes = {
"Category2":"Item2",
"Category1":"Item1",
"Category3":"Item3"
};
$(function(){
var th_elements = $('table').find('th'); // find <th> in HTML
th_elements.each(function(){ // Loop as much <th> found
var html = $.trim($(this).html()); // get HTML and compare with nodes key
$('table').append('<td>'+nodes[html]+'</td>'); // append data to table
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<table>
<th>Category1</th>
<th>Category2</th>
<th>Category3</th>
</table>
I am trying to append data to a table, that gets selected using jquery. The problem is, this table may have nested tables within it. What happens is that when I append the data, not just the parent table's tbody gets appended but so too does all the children tables tbody. Here is my code:
var template = window.app.getTemplate('myTemplate');
var image = {id: imageId, name: imageName, imageList: imageTypes, extension: ext, thumbNail: thumbNailPath};
$("#MyTable tbody:first").append(template(image));
Where myTemplate is set up like this:
<tr>
<td>
<table>
<tr>
<td></td>
</tr>
<tr>
<td></td>
</tr>
</table>
</td>
<tr>
</tr>
<td></td>
</tr>
and MyTable is set up like this:
<table id="MyTable" data-attr="images">
<thead>
</thead>
<tbody>
</tbody>
</table>
Like I said, when the append happens, if there is more than one table within tbody, all tbody's get appended to. So, how do I select only the first?
thanks
JQuery uses the CSS selectors to reach the element.
$("#MyTable > tbody:first")
E > F Matches any F element that is a child of an element E.
See more at http://www.w3.org/TR/CSS2/selector.html#child-selectors
Maybe if you update your jquery selector
$("#MyTable > tbody:first")
Try:
$("#MyTable > tbody").append(template(image));
Suppose this is my table:
<table>
<tr id="a">
<TD>a</TD>
</tr>
<tr id="b">
<TD>b</TD>
</tr>
</table>
How can I get row id using the row index from a table?
Above is just an example where id is static but in my case my id is dynamic, so I can't use
document.getElementById().
Assuming you have only one table on your page:
document.getElementsByTagName("tr")[index].id;
Preferably though, you'd give your table a id, though, and get your row like this:
<table id="tableId">
<tr id="a">
<td>a</td>
</tr>
<tr id="b">
<td>b</td>
</tr>
</table>
var table = document.getElementById("tableId");
var row = table.rows[index];
console.log(row.id);
This way, you can be certain you don't get any interference, if you have multiple tables in your page.
"So, How can i get row id using row Index from a table"
You would select the table, and use the .rows property to get the row by index.
var table = document.getElementsByTagName("table")[0]; // first table
var secondRow = table.rows[1]; // second row
Then you just get the ID in the typical manner.
console.log(secondRow.id); // "b"
DEMO: http://jsfiddle.net/MErPk/
Answer has been edited
With CSS3 you can use the nth-child selctor. Here the example shows the rowIndex = 2
alert(document.querySelector("table tr:nth-child(2)").id);
In jQuery you can do this with
alert($("table tr:nth-child(2)").attr('id'));
The same syntax nth-child() can be used in CSS
<style>
tr:nth-child(2) {
color: red;
}
</style>
I want to use jQuery to check if the 2nd cell in each table row of a table contains any text, if the 2nd cell doesn't contain any text then set the table row to display: none;
Whats the best way to go about this?
HTML:
<table id="results">
<tr>
<td>Results</td>
<td>1000</td>
</tr>
<tr>
<td>Description</td>
<td></td> <!-- This cell is empty so hide row -->
</tr>
<tr>
<td>Time/Date</td>
<td>14:03 22/01/12</td>
</tr>
</table>
Have a look at the :empty selector:
$('table tr').has('td:empty:nth-child(2)').hide()
$('table tr').each(function() {
if(!$(this).find('td').eq(1).html().length) {
$(this).hide();
}
});
This will loop through each tr, find the second element using $.eq(1) (arrays start from zero) and see if it contains anything using $.html().length. If it's empty, it hides the tr with $(this).hide().
a simple solution, make use of :empty selector
$("#results tr").find('td:eq(1):empty').parent().hide();
fiddle : http://jsfiddle.net/GHg7f/2/
I used to have something like,
$(elem).parents('li').find(...)
Where elem was an item in a list, so it was easy to get a reference to all of the items in the list. Now however I have added more information and decided to use a table, where the list fits into the table as follows.
[header][header][header]
[list 1][ cell ][ cell ]
[list 2][ cell ][ cell ]
[list 3][ cell ][ cell ]
I'm a little stuck creating the equivalent JQuery do a .find() on just the cells that have the list items in it. The list items are always in the left-most table cells excluding the header.
Here is what the table looks like in html.
<table id="my-table">
<tr>
<th>Column 1</th>
<th>Column 2</th>
<th>Column 3</th>
<th>Column 4</th>
</tr>
<tr>
<td>list item 1</td>
<td>junk</td>
<td>junk</td>
<td>junk</td>
</tr>
<tr>
<td>list item 2</td>
<td>junk</td>
<td>junk</td>
<td>junk</td>
</tr>
</table>
Use:
$(elem).closest('tr').find(...)
If the li's are always in the first cell of each row then this should work:
$('td:first-child>li')
If you make use of thead and tbody you can find rows only in the body much easier.
Change your markup to something like this:
<table>
<thead>
... header rows ...
</thead>
<tbody>
... body rows ...
</tbody>
</table>
Then you can simply include tbody in your jquery selector to find just rows which are body rows.
Something like #my-table tbody td:first-child. Where first-child will get you the first column.
This will give you only the first column in each row.
var rows = $('tr :nth-child(1)', '#my-table').not('th');
If you want to loop through and do something to each of these now, just use:
rows.each(function()
{
//Do something with the columnn
});
The solution below will output the matching elements, first <td> in each row, to <div id="#results"
Working example at: http://jsfiddle.net/6faUf/
HTML:
<table border="5">
<thead>
<tr><th>1</th><th>2</th><th>3</th></tr>
</thead>
<tbody>
<tr><td><ul><li>List1</li></ul></td><td>2</td><td>3</td></tr>
<tr><td><ul><li>List2</li></ul></td><td>2</td><td>3</td></tr>
</tbody>
</table>
<div id="results">The list values are: </div>
JavaScript (jQuery):
$('td:first-child').each(function(){
var value = $(this).text();
$("#results").append(value);
});
If you need the cells that have the list items in them, you'd need the :has() selector, so there'd be something like that:
$(elem).closest('table').find('td:has(li) ...') — if you need all the li in the table
or $(elem).closest('tr').find('td:has(li) ...') — if you need all the li in the raw