I need help getting a value of a clicked button and send this information using AJAX. the two scripts work individually. but i need the "buttonvalue" to be passed to AJAX "data" value "action". what i am using is below.
$("document").ready(function(){
$(".js-ajax-php-json").on("click", "button[name=mysqljob]", function (){
var buttonvalue = $(this).attr("value");
alert(buttonvalue);
});
$(".js-ajax-php-json").submit(function(){
var data = {"action": buttonvalue};
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "phpVars/ajaxUpload.php", //Relative or absolute path to response.php file
data: data,
success: function(data) {
$(".the-return").html(
data["form"]
);
// alert("Form submitted successfully.\nReturned json: " + data["json"]);
}
});
return false;
});
});
I would prevent the form from submitting do what you want then post the data via an ajax call. Try the following:
$("document").ready(function(){
$(".js-ajax-php-json").on("click", "button[name=mysqljob]", function (e){
e.preventDefault();
var buttonvalue = $(this).attr("value");
var data = {"action": buttonvalue, "formData": $(this).serialize() + "&" + $.param(data) };
$.ajax({
type: "POST",
dataType: "json",
url: "phpVars/ajaxUpload.php", //Relative or absolute path to response.php file
data: data,
success: function(data) {
$(".the-return").html(
data["form"]
);
// alert("Form submitted successfully.\nReturned json: " + data["json"]);
}
});
return false;
});
});
Not tested.
Related
I'm having an issue with AJAX as for some reason it either isn't being called or isn't working
$(document).ready(function() {
$("#my_form").submit(function(event) {
alert("submited");
event.preventDefault("#my_form");
var post_url = $(this).attr("action"); //get form action url
var request_method = $(this).attr("method"); //get form GET/POST method
var form_data = $(this).serialize(); //Encode form elements for submission
alert(post_url + "" + request_method + " " + form_data);
$.ajax({
type: post_url,
url: request_method,
data: form_data,
success: function(data) {
alert(data);
$("server-results").html(data);
}
});
$('#loadingDiv').hide().ajaxStart(function() {
$(this).show();
});
//.ajaxStop(function() {
// $(this).hide();
//});
});
});
I've debugged as much as I could and there is no issue with the form function being activated in JavaScript or the 3 variables being transported into the JS code block. However ajaxStart doesn't activate which makes me believe that the problem is with just ajax.
I also checked the link to ajax and it seems to be working however I'm not sure if its the right link or if it's not valid for whatever reason.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
FYI the ajax link is at the top of the page above both HTML and JS.
You have passed wrong parameters:
type: post_url,
url: request_method,
You need to pass post_url in url and request_method in type. Just change it to:
type: request_method,
url: post_url,
$("server-results").html(data); here you have not specified if server-results is a class or id and therefore the output of the server will never be printed on the page
jQuery .ajaxStart()
As reported in jQuery's official documentation, the ajaxStart event can not be activated by the #loadingDiv element, but you must use the document.
$( document ).ajaxStart(function() {
$( ".log" ).text( "Triggered ajaxStart handler." );
});
Summing up the code should be something like this.
$(document).ready(function() {
$("#my_form").submit(function(event) {
alert("submited");
event.preventDefault("#my_form");
var post_url = $(this).attr("action"); //get form action url
var request_method = $(this).attr("method"); //get form GET/POST method
var form_data = $(this).serialize(); //Encode form elements for submission
alert(post_url + "" + request_method + " " + form_data);
$.ajax({
type: post_url,
url: request_method,
data: form_data,
success: function(data) {
alert(data);
$(".server-results").html(data);
}
});
$(document).ajaxStart(function() {
$('#loadingDiv').show();
});
.ajaxStop(function() {
$('#loadingDiv').hide();
});
});
});
I'm sending form data via jquery and cannot get the window.location.assign() to fire off. I am getting a successful submission. I've also tried window.location.href =
<form>
<div>
<a id="submitDesk" type="button" class="btn submitDesk">Submit Request</a>
</div>
</form>
$( document ).ready(function() {
$( "#submitDesk" ).click(function() {
var firstname = document.querySelector('#firstname').value;
var lastname = document.querySelector('#lastname').value;
var email = document.querySelector('#email').value;
$.ajax({
type: "POST",
url: "http://foo.com/desk.php",
dataType: 'json',
data: 'firstname='+ firstname + '&lastname='+ lastname+ '&email=' + email + '&location='+ location,
success: function(data) {
console.log(data);
window.location.assign('/thank-you/');
}
});
});
});
Kindly use below. data parameter string was not proper, String was getting break, SO i have added " ' " to make it a proper string.
$.ajax({
type: "POST",
url: "http://foo.com/desk.php",
dataType: 'json',
data: 'firstname='+ firstname + '&lastname='+ lastname+ '&email='+ email+ '&location='+ location,
success: function(data) {
console.log(data);
window.location.assign('http://foo.com/thank-you/');
}
});
The backend file was sending incorrect responses causing there to always be an error even though the form was a success.
This is my ajax:
$("#submit").on("click",function()
{
$("#add_car_form").submit(function(){
var data = {
"action": "test"
};
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "text",
url: "add_car_submit.php", //Relative or absolute path to response.php file
data: data,
success: function(data) {
$(".the-return").html("<br />JSON: " + data );//this outputs
{"car_name":";ll","car_maker":"njk","car_type":"nkj","passanger":"1","rate":["89","67","45","34","23"],"action":"test"}
}
});
document.getElementById("add_car_form").reset();
return false;
});
});
I simply echo from php script like this: echo $return["json"]; and it will output like this:
{"car_name":";ll","car_maker":"njk","car_type":"nkj","passanger":"1","rate":["89","67","45","34","23"],"action":"test"}
How do append to a div in html table form like this?
Car Name: name
Car Maker: maker
......
try this in your success function
data = jQuery.parseJSON( data ); //parse data if this is text other wise use data directly. hope this is a text param in your case.
var out = '<table>';
$.each(data, function( key, value ) {
out += '<tr><td>'+key+': '+ value +'</td></tr>';
});
out += '</table>';
//append out to your div
$(".the-return").html(out);
You should not create a form submit handler inside a click handler as it could create multiple listeners for single click event.
I think you could just encode the data use json_encode in the server side then, accept the response as json in the client using dataType: 'json' then
$("#submit").on("click", function () {
var $form = $("#add_car_form")
var data = {
"action": "test"
};
data = $form.serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "add_car_submit.php", //Relative or absolute path to response.php file
data: data,
success: function (data) {
$(".the-return").html("Car Name" + data.car_name + '<br />Car Maker' + data.car_maker); //Add more properties here
}
});
document.getElementById("add_car_form").reset();
return false;
});
Script:
function buttonBuild(id, building, nick)
{
$("#BuildedBox").ajax({
type: "POST",
url: "BlockEditor/build.php",
data: 'block_id=' + id + '&building=' + building + '&nick=' + nick,
cache: false,
success: function(response)
{
alert("Record successfully updated");
$.load("#BuildedBox")
}
});
}
build.php:
include_once("$_SERVER[DOCUMENT_ROOT]/db.php");
$block_id = $_GET['block'];
$building = $_GET['building'];
$nick = $_GET['nick'];
echo"$block_id - $building - $nick";
index.php:
<a href=\"#\" onClick=\"buttonBuild(k152, digger, Name);\" >[BUILD]</a>
<div id="BuildedBox"></div>
seems my script wont work. what i have done wrong?
check this out
function buttonBuild(id, building, nick)
{
$.ajax({
type: "POST",
url: "BlockEditor/build.php",
data: 'block_id=' + id + '&building=' + building + '&nick=' + nick,
cache: false,
success: function(response)
{
alert("Record successfully updated");
/***************/
$("#BuildedBox").html(response);
/***************/
}
});
}
var weightd = $("#weight").val();
var user_id = 43;
$.ajax({
type: "POST",
url:"<?php bloginfo('template_directory')?>/ajax/insert.php",
data: { weight:weightd,user_ids:user_id},
success:function(result){
$("#result1").html(result);
});
<div id="result1">Result div</div>
change $.load("#BuildedBox") to $("#BulderBox").html(response).
When you ask the script for data via ajax, the data provided gets into the "response" variable. As you want to write this data into the div, you must use the ".html" method.
Easier using "load" in this way:
function buttonBuild(id, building, nick)
{
$("#BuildedBox").load("BlockEditor/build.php?block_id=" + id + "&building=" + building + "&nick=" + nick);
}
The "load" method loads data from the server and writes the result html into the element: https://api.jquery.com/load/
EDIT:
As #a-wolff says in the comment, to use POST in load, you should construct like this:
function buttonBuild(id, building, nick)
{
$("#BuildedBox").load("BlockEditor/build.php",{
block_id:id,
building:building,
nick:nick
});
}
Hi i have jquery request like below ,
$('#filterForm').submit(function(e){
e.preventDefault();
var dataString = $('#filterForm').serialize();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn')
{
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
}
else
{
document.getElementById("2011").className='yearOn';
}
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});
and my Form is like ,
<form method="post" name="filterForm" id="filterForm">
<!-- some input elements -->
</form>
Well, I am triggering jquery submit on submit event of a form ,(it's working fine)
I want pass one extra parameter inside form which is not in above form content but it's outside in page
it's like below
[Check this image link for code preview][1]
So how can i trigger above event , on click of , element with class yearOn ( check above html snippet ) and class yearOff , with additional parameter of year set to either 2011 or 2010
$(document).ready(function () {
$('#filterForm').submit(function (e) {
e.preventDefault();
var dataString = $('#filterForm').serialize();
if ($("#2011").hasClass('yearOn')) {
dataString += '&year=2011';
$("#2011").removeClass('yearOn').addClass('yearOff');
}
else {
$("#2011").removeClass('yearOff').addClass('yearOn');
}
$.ajax({
url: "/myServlet",
type: "POST",
data: dataString,
success: function (data) {
/*var a = data;
alert(data);*/
}
});
});
});
1.) If you are using jQuery already, you can use the $.post() function provided by jquery. It will make your life easier in most cases.
2.) I have always had a successful post with extra parameters this way:
Build you extra parameters here
commands={
year:'2011'
};
Combine it with your form serialize
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
Perform your post here
$.post("myServlet",data,
function(data) {
/*var a = data;
alert(data);*/
}
);
OR use $.ajax if you really love it
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
In the end, here is the full code the way you are doing it now
$('#filterForm').submit(function(e){
e.preventDefault();
var class2011 = document.getElementById("2011").className;
//var validate = validateFilter();
alert(dataString);
if(class2011=='yearOn') {
dataString+='&year=2011';
document.getElementById("2011").className='yearOff';
} else {
document.getElementById("2011").className='yearOn';
}
commands={
year:'2011'
};
var dataString=$.param(commands)+'&'+$("#filterForm").serialize();
alert (dataString);
$.ajax({
type: "POST",
url: "myServlet",
data: dataString,
success: function(data) {
/*var a = data;
alert(data);*/
}
});