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Js how to set an item at a nested index in an empty array [duplicate]

I hope someone can help me with this Javascript.
I have an Object called "Settings" and I would like to write a function that adds new settings to that object.
The new setting's name and value are provided as strings. The string giving the setting's name is then split by the underscores into an array. The new setting should get added to the existing "Settings" object by creating new nested objects with the names given by each part of the array, except the last part which should be a string giving the setting's value. I should then be able to refer to the setting and e.g. alert its value. I can do this in a static way like this...
var Settings = {};
var newSettingName = "Modules_Video_Plugin";
var newSettingValue = "JWPlayer";
var newSettingNameArray = newSettingName.split("_");
Settings[newSettingNameArray[0]] = {};
Settings[newSettingNameArray[0]][newSettingNameArray[1]] = {};
Settings[newSettingNameArray[0]][newSettingNameArray[1]][newSettingNameArray[2]] = newSettingValue;
alert(Settings.Modules.Mediaplayers.Video.Plugin);
... the part that creates the nested objects is doing this ...
Settings["Modules"] = {};
Settings["Modules"]["Video"] = {};
Settings["Modules"]["Video"]["Plugin"] = "JWPlayer";
However, as the number of parts that make up the setting name can vary, e.g. a newSettingName could be "Modules_Floorplan_Image_Src", I'd like to do this dynamically using a function such as...
createSetting (newSettingNameArray, newSettingValue);
function createSetting(setting, value) {
// code to create new setting goes here
}
Can anyone help me work out how to do this dynamically?
I presume there has to be a for...loop in there to itterate through the array, but I haven't been able to work out a way to create the nested objects.
If you've got this far thanks very much for taking the time to read even if you can't help.

Put in a function, short and fast (no recursion).
var createNestedObject = function( base, names ) {
for( var i = 0; i < names.length; i++ ) {
base = base[ names[i] ] = base[ names[i] ] || {};
}
};
// Usage:
createNestedObject( window, ["shapes", "triangle", "points"] );
// Now window.shapes.triangle.points is an empty object, ready to be used.
It skips already existing parts of the hierarchy. Useful if you are not sure whether the hierarchy was already created.
Or:
A fancier version where you can directly assign the value to the last object in the hierarchy, and you can chain function calls because it returns the last object.
// Function: createNestedObject( base, names[, value] )
// base: the object on which to create the hierarchy
// names: an array of strings contaning the names of the objects
// value (optional): if given, will be the last object in the hierarchy
// Returns: the last object in the hierarchy
var createNestedObject = function( base, names, value ) {
// If a value is given, remove the last name and keep it for later:
var lastName = arguments.length === 3 ? names.pop() : false;
// Walk the hierarchy, creating new objects where needed.
// If the lastName was removed, then the last object is not set yet:
for( var i = 0; i < names.length; i++ ) {
base = base[ names[i] ] = base[ names[i] ] || {};
}
// If a value was given, set it to the last name:
if( lastName ) base = base[ lastName ] = value;
// Return the last object in the hierarchy:
return base;
};
// Usages:
createNestedObject( window, ["shapes", "circle"] );
// Now window.shapes.circle is an empty object, ready to be used.
var obj = {}; // Works with any object other that window too
createNestedObject( obj, ["shapes", "rectangle", "width"], 300 );
// Now we have: obj.shapes.rectangle.width === 300
createNestedObject( obj, "shapes.rectangle.height".split('.'), 400 );
// Now we have: obj.shapes.rectangle.height === 400
Note: if your hierarchy needs to be built from values other that standard objects (ie. not {}), see also TimDog's answer below.
Edit: uses regular loops instead of for...in loops. It's safer in cases where a library modifies the Array prototype.

function assign(obj, keyPath, value) {
lastKeyIndex = keyPath.length-1;
for (var i = 0; i < lastKeyIndex; ++ i) {
key = keyPath[i];
if (!(key in obj)){
obj[key] = {}
}
obj = obj[key];
}
obj[keyPath[lastKeyIndex]] = value;
}
Usage:
var settings = {};
assign(settings, ['Modules', 'Video', 'Plugin'], 'JWPlayer');

My ES2015 solution. Keeps existing values.
const set = (obj, path, val) => {
const keys = path.split('.');
const lastKey = keys.pop();
const lastObj = keys.reduce((obj, key) =>
obj[key] = obj[key] || {},
obj);
lastObj[lastKey] = val;
};
Example:
const obj = {'a': {'prop': {'that': 'exists'}}};
set(obj, 'a.very.deep.prop', 'value');
console.log(JSON.stringify(obj));
// {"a":{"prop":{"that":"exists"},"very":{"deep":{"prop":"value"}}}}

Using ES6 is shorten. Set your path into an array.
first, you have to reverse the array, to start filling the object.
let obj = ['a','b','c'] // {a:{b:{c:{}}}
obj.reverse();
const nestedObject = obj.reduce((prev, current) => (
{[current]:{...prev}}
), {});

Another recursive solution:
var nest = function(obj, keys, v) {
if (keys.length === 1) {
obj[keys[0]] = v;
} else {
var key = keys.shift();
obj[key] = nest(typeof obj[key] === 'undefined' ? {} : obj[key], keys, v);
}
return obj;
};
Example usage:
var dog = {bark: {sound: 'bark!'}};
nest(dog, ['bark', 'loudness'], 66);
nest(dog, ['woff', 'sound'], 'woff!');
console.log(dog); // {bark: {loudness: 66, sound: "bark!"}, woff: {sound: "woff!"}}

I love this ES6 immutable way to set certain value on nested field:
const setValueToField = (fields, value) => {
const reducer = (acc, item, index, arr) => ({ [item]: index + 1 < arr.length ? acc : value });
return fields.reduceRight(reducer, {});
};
And then use it with creating your target object.
const targetObject = setValueToField(['one', 'two', 'three'], 'nice');
console.log(targetObject); // Output: { one: { two: { three: 'nice' } } }

Lodash has a _.set method to achieve this
let obj = {}
_.set(obj, ['a', 'b', 'c', 'd'], 'e')
or
_.set(obj, 'a.b.c.d', 'e')
// which generate the following object
{
"a": {
"b": {
"c": {
"d": "e"
}
}
}
}

Here is a simple tweak to jlgrall's answer that allows setting distinct values on each element in the nested hierarchy:
var createNestedObject = function( base, names, values ) {
for( var i in names ) base = base[ names[i] ] = base[ names[i] ] || (values[i] || {});
};
Hope it helps.

Here is a functional solution to dynamically create nested objects.
const nest = (path, obj) => {
const reversedPath = path.split('.').reverse();
const iter = ([head, ...tail], obj) => {
if (!head) {
return obj;
}
const newObj = {[head]: {...obj}};
return iter(tail, newObj);
}
return iter(reversedPath, obj);
}
Example:
const data = {prop: 'someData'};
const path = 'a.deep.path';
const result = nest(path, data);
console.log(JSON.stringify(result));
// {"a":{"deep":{"path":{"prop":"someData"}}}}

Inspired by ImmutableJS setIn method which will never mutate the original. This works with mixed array and object nested values.
function setIn(obj = {}, [prop, ...rest], value) {
const newObj = Array.isArray(obj) ? [...obj] : {...obj};
newObj[prop] = rest.length ? setIn(obj[prop], rest, value) : value;
return newObj;
}
var obj = {
a: {
b: {
c: [
{d: 5}
]
}
}
};
const newObj = setIn(obj, ["a", "b", "c", 0, "x"], "new");
//obj === {a: {b: {c: [{d: 5}]}}}
//newObj === {a: {b: {c: [{d: 5, x: "new"}]}}}

Appreciate that this question is mega old! But after coming across a need to do something like this in node, I made a module and published it to npm.
Nestob
var nestob = require('nestob');
//Create a new nestable object - instead of the standard js object ({})
var newNested = new nestob.Nestable();
//Set nested object properties without having to create the objects first!
newNested.setNested('biscuits.oblong.marmaduke', 'cheese');
newNested.setNested(['orange', 'tartan', 'pipedream'], { poppers: 'astray', numbers: [123,456,789]});
console.log(newNested, newNested.orange.tartan.pipedream);
//{ biscuits: { oblong: { marmaduke: 'cheese' } },
orange: { tartan: { pipedream: [Object] } } } { poppers: 'astray', numbers: [ 123, 456, 789 ] }
//Get nested object properties without having to worry about whether the objects exist
//Pass in a default value to be returned if desired
console.log(newNested.getNested('generic.yoghurt.asguard', 'autodrome'));
//autodrome
//You can also pass in an array containing the object keys
console.log(newNested.getNested(['chosp', 'umbridge', 'dollar'], 'symbols'));
//symbols
//You can also use nestob to modify objects not created using nestob
var normalObj = {};
nestob.setNested(normalObj, 'running.out.of', 'words');
console.log(normalObj);
//{ running: { out: { of: 'words' } } }
console.log(nestob.getNested(normalObj, 'random.things', 'indigo'));
//indigo
console.log(nestob.getNested(normalObj, 'improbable.apricots'));
//false

Inside your loop you can use lodash.set and will create the path for you:
...
const set = require('lodash.set');
const p = {};
const [type, lang, name] = f.split('.');
set(p, [lang, type, name], '');
console.log(p);
// { lang: { 'type': { 'name': '' }}}

try using recursive function:
function createSetting(setting, value, index) {
if (typeof index !== 'number') {
index = 0;
}
if (index+1 == setting.length ) {
settings[setting[index]] = value;
}
else {
settings[setting[index]] = {};
createSetting(setting, value, ++index);
}
}

I think, this is shorter:
Settings = {};
newSettingName = "Modules_Floorplan_Image_Src";
newSettingValue = "JWPlayer";
newSettingNameArray = newSettingName.split("_");
a = Settings;
for (var i = 0 in newSettingNameArray) {
var x = newSettingNameArray[i];
a[x] = i == newSettingNameArray.length-1 ? newSettingValue : {};
a = a[x];
}

I found #jlgrall's answer was great but after simplifying it, it didn't work in Chrome. Here's my fixed should anyone want a lite version:
var callback = 'fn.item1.item2.callbackfunction',
cb = callback.split('.'),
baseObj = window;
function createNestedObject(base, items){
$.each(items, function(i, v){
base = base[v] = (base[v] || {});
});
}
callbackFunction = createNestedObject(baseObj, cb);
console.log(callbackFunction);
I hope this is useful and relevant. Sorry, I've just smashed this example out...

You can define your own Object methods; also I'm using underscore for brevity:
var _ = require('underscore');
// a fast get method for object, by specifying an address with depth
Object.prototype.pick = function(addr) {
if (!_.isArray(addr)) return this[addr]; // if isn't array, just get normally
var tmpo = this;
while (i = addr.shift())
tmpo = tmpo[i];
return tmpo;
};
// a fast set method for object, put value at obj[addr]
Object.prototype.put = function(addr, val) {
if (!_.isArray(addr)) this[addr] = val; // if isn't array, just set normally
this.pick(_.initial(addr))[_.last(addr)] = val;
};
Sample usage:
var obj = {
'foo': {
'bar': 0 }}
obj.pick('foo'); // returns { bar: 0 }
obj.pick(['foo','bar']); // returns 0
obj.put(['foo', 'bar'], -1) // obj becomes {'foo': {'bar': -1}}

A snippet for those who need to create a nested objects with support of array keys to set a value to the end of path. Path is the string like: modal.product.action.review.2.write.survey.data. Based on jlgrall version.
var updateStateQuery = function(state, path, value) {
var names = path.split('.');
for (var i = 0, len = names.length; i < len; i++) {
if (i == (len - 1)) {
state = state[names[i]] = state[names[i]] || value;
}
else if (parseInt(names[i+1]) >= 0) {
state = state[names[i]] = state[names[i]] || [];
}
else {
state = state[names[i]] = state[names[i]] || {};
}
}
};

Set Nested Data:
function setNestedData(root, path, value) {
var paths = path.split('.');
var last_index = paths.length - 1;
paths.forEach(function(key, index) {
if (!(key in root)) root[key] = {};
if (index==last_index) root[key] = value;
root = root[key];
});
return root;
}
var obj = {'existing': 'value'};
setNestedData(obj, 'animal.fish.pet', 'derp');
setNestedData(obj, 'animal.cat.pet', 'musubi');
console.log(JSON.stringify(obj));
// {"existing":"value","animal":{"fish":{"pet":"derp"},"cat":{"pet":"musubi"}}}
Get Nested Data:
function getNestedData(obj, path) {
var index = function(obj, i) { return obj && obj[i]; };
return path.split('.').reduce(index, obj);
}
getNestedData(obj, 'animal.cat.pet')
// "musubi"
getNestedData(obj, 'animal.dog.pet')
// undefined

Try this: https://github.com/silkyland/object-to-formdata
var obj2fd = require('obj2fd/es5').default
var fd = obj2fd({
a:1,
b:[
{c: 3},
{d: 4}
]
})
Result :
fd = [
a => 1,
b => [
c => 3,
d => 4
]
]

Here is a decomposition to several useful functions, that each preserve existing data. Does not handle arrays.
setDeep: Answers question. Non-destructive to other data in the object.
setDefaultDeep: Same, but only sets if not already set.
setDefault: Sets a key if not already set. Same as Python's setdefault.
setStructure: Helper function that builds the path.
// Create a nested structure of objects along path within obj. Only overwrites the final value.
let setDeep = (obj, path, value) =>
setStructure(obj, path.slice(0, -1))[path[path.length - 1]] = value
// Create a nested structure of objects along path within obj. Does not overwrite any value.
let setDefaultDeep = (obj, path, value) =>
setDefault(setStructure(obj, path.slice(0, -1)), path[path.length - 1], value)
// Set obj[key] to value if key is not in object, and return obj[key]
let setDefault = (obj, key, value) =>
obj[key] = key in obj ? obj[key] : value;
// Create a nested structure of objects along path within obj. Does not overwrite any value.
let setStructure = (obj, path) =>
path.reduce((obj, segment) => setDefault(obj, segment, {}), obj);
// EXAMPLES
let temp = {};
// returns the set value, similar to assignment
console.log('temp.a.b.c.d:',
setDeep(temp, ['a', 'b', 'c', 'd'], 'one'))
// not destructive to 'one'
setDeep(temp, ['a', 'b', 'z'], 'two')
// does not overwrite, returns previously set value
console.log('temp.a.b.z: ',
setDefaultDeep(temp, ['a', 'b', 'z'], 'unused'))
// creates new, returns current value
console.log('temp["a.1"]: ',
setDefault(temp, 'a.1', 'three'))
// can also be used as a getter
console.log("temp.x.y.z: ",
setStructure(temp, ['x', 'y', 'z']))
console.log("final object:", temp)
I'm not sure why anyone would want string paths:
They are ambiguous for keys with periods
You have to build the strings in the first place

Since I started with something from this page, I wanted to contribute back
Other examples overwrote the final node even if it was set, and that wasn't what I wanted.
Also, if returnObj is set to true, it returns the base object. By default, falsy, it returns the deepest node.
function param(obj, path, value, returnObj) {
if (typeof path == 'string') path = path.split(".");
var child = obj;
path.forEach((key, i) => {
if (!(key in child)) {
child[key] = (i < path.length-1) ? {} : value || {};
}
child = child[key];
});
return returnObj ? obj : child;
}
var x = {};
var xOut = param(x, "y.z", "setting")
console.log(xOut);
xOut = param(x, "y.z", "overwrite") // won't set
console.log(xOut);
xOut = param(x, "y.a", "setting2")
console.log(xOut);
xOut = param(x, "y.a", "setting2", true) // get object rather than deepest node.
console.log(xOut);
You can also do something where numeric keys are placed in arrays (if they don't already exist). Note that numeric keys won't convert to arrays for the first element of the path, since that's set by the type of your base-object.
function isNumber(n) {
return !isNaN(parseFloat(n)) && isFinite(n);
}
function param(obj, path, value, returnObj) {
if (typeof path == 'string') path = path.split(".");
var child = obj;
path.forEach((key, i) => {
var nextKey = path[i+1];
if (!(key in child)) {
child[key] = (nextKey == undefined && value != undefined
? value
: isNumber(nextKey)
? []
: {});
}
child = child[key];
});
return returnObj ? obj : child;
}
var x = {};
var xOut = param(x, "y.z", "setting")
console.log(xOut);
xOut = param(x, "y.z", "overwrite") // won't set
console.log(xOut);
xOut = param(x, "y.a", "setting2")
console.log(xOut);
xOut = param(x, "y.a", "setting2", true) // get object rather than deepest node.
xOut = param(x, "1.0.2.a", "setting")
xOut = param(x, "1.0.1.a", "try to override") // won't set
xOut = param(x, "1.0.5.a", "new-setting", true) // get object rather than deepest node.
console.log(xOut);
Naturally, when the numeric keys are greater than 0, you might see some undefined gaps.
Practical uses of this might be
function AddNote(book, page, line) {
// assume a global global notes collection
var myNotes = param(allNotes, [book, page, line], []);
myNotes.push('This was a great twist!')
return myNotes;
}
var allNotes = {}
var youthfulHopes = AddNote('A Game of Thrones', 4, 2, "I'm already hooked, at least I won't have to wait long for the books to come out!");
console.log(allNotes)
// {"A Game of Thrones": [undefined, undefined, undefined, undefined, [undefined, undefined, ["I'm already hooked, at least I won't have to wait long for the books to come out!"]]]}
console.log(youthfulHopes)
// ["I'm already hooked, at least I won't have to wait long for the books to come out!"]

function initPath(obj, path) {
path.split('.').reduce((o, key) => (
Object.assign(o, {[key]: Object(o[key])}),
o[key]
), obj);
return obj;
}
Usage
const obj = { a: { b: 'value1' } };
initPath(obj, 'a.c.d').a.c.d='value2';
/*
{
"a": {
"b": "value1",
"c": {
"d": "value2"
}
}
}
*/

simple answer. on es6, im using this
const assign = (obj, path, value) => {
let keyPath = path.split('.')
let lastKeyIndex = keyPath.length - 1
for (let i = 0; i < lastKeyIndex; ++i) {
let key = keyPath[i]
if (!(key in obj)) {
obj[key] = {}
}
obj = obj[key]
}
obj[keyPath[lastKeyIndex]] = value
}
example json
const obj = {
b: 'hello'
}
you can add new key
assign(obj, 'c.d.e', 'this value')
and you get like bellow
console.log(obj)
//response example
obj = {
b: 'hello',
c: {
d: {
e: 'this value'
}
}
}

function createObj(keys, value) {
let obj = {}
let schema = obj
keys = keys.split('.')
for (let i = 0; i < keys.length - 1; i++) {
schema[keys[i]] = {}
schema = schema[keys[i]]
}
schema[keys.pop()] = value
return obj
}
let keys = 'value1.value2.value3'
let value = 'Hello'
let obj = createObj(keys, value)

Eval is probably overkill but the result is simple to visualize, with no nested loops or recursion.
function buildDir(obj, path){
var paths = path.split('_');
var final = paths.pop();
for (let i = 1; i <= paths.length; i++) {
var key = "obj['" + paths.slice(0, i).join("']['") + "']"
console.log(key)
eval(`${key} = {}`)
}
eval(`${key} = '${final}'`)
return obj
}
var newSettingName = "Modules_Video_Plugin_JWPlayer";
var Settings = buildDir( {}, newSettingName );
Basically you are progressively writing a string "obj['one']= {}", "obj['one']['two']"= {} and evaling it;

How to find unique key with desire array value?

I want to get unique p which c values contain all desire_c value !
So here object's p:1 has c value like 1,2,3 . That is match desire_c array value , so I want to get
{p:1} as final result !
Here I am looping in using for loop :(
var object = [{p:1,c:1},{p:1,c:2},{p:1,c:3},{p:2,c:1},{p:3,c:3}];
var desire_c = [1,2,3];
var helper = {};
for(var o in object) {
var current = object[o];
if(typeof helper[current.p] != 'object') {
helper[current.p] = {};
}
helper[current.p][current.c] = null;
}
for(var c of helper) {
for(var d in desire_c) {
c[desire_c[d]]
}
}

You could take a map for p and a set for each c value and check then if all wanted values are in a set.
var object = [{ p: 1, c: 1 }, { p: 1, c: 2 }, { p: 1, c: 3 }, { p: 2, c: 1 }, { p: 3, c: 3 }],
desire_c = [1, 2, 3],
map = new Map,
result;
object.forEach(({ p, c }) => map.has(p) ? map.get(p).add(c) : map.set(p, new Set([c])));
result = [...map.keys()].filter(p => desire_c.every(c => map.get(p).has(c)));
console.log(result);

You can use this auxiliary function to find the unique value:
function findKey(objects, desire){
const map = {}; // Creates a new object to map all keys to all their values, instead of having an array of objects
objects.forEach(obj => {
map[obj.p] = map[obj.p] || []; // Ensures the key has an array of values before pushing a new value
map[obj.p].push(obj.c);
});
return Object.keys(map).find(key => desire.every(des => map[key].includes(des))); // Tries to find a key that contains all desired values
}
Then, just call it like that:
findKey(object, desire_c); // Returns 1 for your example

Please check below code.
var desire_c = [1,2,3];
var data=[{p:1,c:1},{p:1,c:2},{p:1,c:3},{p:2,c:1},{p:3,c:3}];;
var helper = {},element = "p";
for (var i = 0; i < data.length; i++) {
if (!helper[data[i][element]])
helper[data[i][element]] = [];
helper[data[i][element]].push(data[i]["c"]);
};
for (key in helper) {
if (helper.hasOwnProperty(key)) {
if (helper[key].length){
var arr=helper[key];
if(JSON.stringify(arr)==JSON.stringify(desire_c))
{
console.log({"p":key});
}
}
}
}

const hash = {};
for(const {p, c} of object){
if(!hash[p]){
hash[p] = desire_c;
}
hash[p] = hash[p].filter(n => n !== c);
}
const result = [];
for(const [key, val] of Object.entries(hash))
if(!val.length) result.push(key);
This just goes over every p and c in the array, and removes c from the array stored inside the hashtable under p. This array is initialized to your wanted array, so if all elements are removed from it (!val.length) the corresponding key is the one we are looking for.

Finding if an array is in a 2D array

I want to know whether if an array is inside of a 2D array.
This is what I tried:
var x=[1,2];
var y=[[1,1],[1,2],[2,2],[3,3]];
y.includes(x); //should return true

you can create a hash:
var ar = [
[1,1],[1,2],[2,2],[3,3]
];
var hash = {};
for(var i = 0 ; i < ar.length; i += 1) {
hash[ar[i]] = i;
}
var val = [1,2];
if(hash.hasOwnProperty(val)) {
document.write(hash[val]);
}

You can do this with chained array methods!
var ar = [
[1,1],[1,2],[2,2],[3,3]
];
hasDuplicates(ar, [1,"1"]); //false
hasDuplicates(ar, [1,1]); //true
//Use some to determine at least 1 inner array matches
function hasDuplicates(array, valueToCheck) {
return array.some(function(a, i) {
//Check each inner arrays index, and verify that it equals on the same index of the array we want to check
return a.every(function(ax, ix) {
return valueToCheck[ix] === ax; //triple equals for equality!
})
});
}
Demo: https://jsfiddle.net/a3rq70hL/1/

compare object value with length of array in an object with javascript

EDIT: SOLVED See final solution below
EDIT: The value names are not the same
object 1
var obj1 = {
val1a : 4,
val2a : 3 ,
val3a : 7
}
object 2 with arrays
var obj2 = {
val1b : [one, two, three],
val2b : [oneA, twoA, threeA],
val3b : [oneB]
}
I am trying to do is the following
if(obj1.val1a === obj2.val1b.length){
// code
}
but I do not want it to be so specific. Is there a way to loop over each object and return the values of obj2 that do not match obj1
SOLUTION with underScore
function checkData(obj1, obj2) {
result = []
var keys_obj1 = Object.keys( obj1)
var keys_obj2 = Object.keys( obj2)
_.each(keys_obj1, function(num, i){
if(obj1[keys_obj1[i]].length !== obj2[keys_obj2[i]]) {
result.push(keys_obj1[i]);
}
})
return result;
}

The best way to do this is if both objects have the same name (for a given pair), then using The For/In Loop iterate over one of them and return the value of both, and then compare.
Remade the fiddle using Object.keys to make an array of keys for both objects, now it works even when the keys aren't the same (following the object index)
var obj1 = {
val1a : 4,
val2a : 3 ,
val3a : 7
}
var obj2 = {
val1b : ['one', 'two', 'three'],
val2b : ['oneA', 'twoA', 'threeA'],
val3b : ['oneB']
}
var keys_obj1 = Object.keys( obj1 )
var keys_obj2 = Object.keys( obj2 )
for (i = 0; i < keys_obj1.length; i++) {
console.log(keys_obj1[i]+'-'+obj1[keys_obj1[i]])
console.log(keys_obj2[i]+'-'+obj2[keys_obj2[i]].length);
if(obj1[keys_obj1[i]] === obj2[keys_obj2[i]].length) {
//match
}
}
console output :
"val1a-4"
"val1b-3"
"val2a-3"
"val2b-3"
"val3a-7"
"val3b-1"

If your model is not the definitive one, you could use an array of object like :
var object = [
{table : [one, two, three], length : 3},
{table : [one, two, three], length : 4},
... ];
and compare values using :
object[i].table.length === object[i].length
It's a little bit different from your model
but i hope it may helps.

Quite long-winded, but the only way I could think to do it:
// for each object you are going to...
function pullData(obj) {
var out = {};
var token;
// grab the keys
var keys = Object.keys(obj).map(function (el) {
// token is the character at the end of the key
// the key that is returned is the key without the token
token = el.slice(-1)
return el.slice(0, 4);
});
// for each key, add it to the output object
for (var i = 0, l = keys.length; i < l; i++) {
out[keys[i]] = obj[keys[i] + token]
}
// return an object containing the data and the token
return {data: out, token: token};
}
// take both the output from both objects being parsed
function isNotMatch(obj1, obj2) {
var out = [];
// loop over the first object using the now identical keys
for (var p in obj1.data) {
// check the values and lengths
// if they're not the same push the key and the token as a string
// to the output array
if (obj1.data[p] !== obj2.data[p].length) {
out.push(p + obj2.token);
}
}
// return the array of non-matches
return out;
}
isNotMatch(pullData(obj1), pullData(obj2));
DEMO

UPDATED:
Maybe something like this. You would have to make sure the property names are the same:
var obj1 = {
val1a : 4,
val2a : 3 ,
val3a : 7
};
var obj2 = {
val1a : ['one', 'two', 'three'],
val2a : ['oneA', 'twoA', 'threeA'],
val3a : ['oneB']
};
for(var name in obj1) {
if(obj1[name] === obj2[name].length) {
alert("match");
}
}

Javascript natural sort array/object and maintain index association

I have an array of items as follows in Javascript:
var users = Array();
users[562] = 'testuser3';
users[16] = 'testuser6';
users[834] = 'testuser1';
users[823] = 'testuser4';
users[23] = 'testuser2';
users[917] = 'testuser5';
I need to sort that array to get the following output:
users[834] = 'testuser1';
users[23] = 'testuser2';
users[562] = 'testuser3';
users[823] = 'testuser4';
users[917] = 'testuser5';
users[16] = 'testuser6';
Notice how it is sorted by the value of the array and the value-to-index association is maintained after the array is sorted (that is critical). I have looked for a solution to this, tried making it, but have hit a wall.
By the way, I am aware that this is technically not an array since that would mean the indices are always iterating 0 through n where n+1 is the counting number proceeding n. However you define it, the requirement for the project is still the same. Also, if it makes a difference, I am NOT using jquery.

The order of the elements of an array is defined by the index. So even if you specify the values in a different order, the values will always be stored in the order of their indices and undefined indices are undefined:
> var arr = [];
> arr[2] = 2;
> arr[0] = 0;
> arr
[0, undefined, 2]
Now if you want to store the pair of index and value, you will need a different data structure, maybe an array of array like this:
var arr = [
[562, 'testuser3'],
[16, 'testuser6'],
[834, 'testuser1'],
[823, 'testuser4'],
[23, 'testuser2'],
[917, 'testuser5']
];
This can be sorted with this comparison function:
function cmp(a, b) {
return a[1].localeCompare(b[1]);
}
arr.sort(cmp);
The result is this array:
[
[834, 'testuser1'],
[23, 'testuser2'],
[562, 'testuser3'],
[823, 'testuser4'],
[917, 'testuser5'],
[16, 'testuser6']
]

If I understand the question correctly, you're using arrays in a way they are not intended to be used. In fact, the initialization style
// Don't do this!
var array = new Array();
array[0] = 'value';
array[1] = 'value';
array[2] = 'value';
teaches wrong things about the nature and purpose of arrays. An array is an ordered list of items, indexed from zero up. The right way to create an array is with an array literal:
var array = [
'value',
'value',
'value'
]
The indexes are implied based on the order the items are specified. Creating an array and setting users[562] = 'testuser3' implies that there are at least 562 other users in the list, and that you have a reason for only knowing the 563rd at this time.
In your case, the index is data, and is does not represent the order of the items in the set. What you're looking for is a map or dictionary, represented in JavaScript by a plain object:
var users = {
562: 'testuser3',
16: 'testuser6',
834: 'testuser1',
823: 'testuser4',
23: 'testuser2',
917: 'testuser5'
}
Now your set does not have an order, but does have meaningful keys. From here, you can follow galambalazs's advice to create an array of the object's keys:
var userOrder;
if (typeof Object.keys === 'function') {
userOrder = Object.keys(users);
} else {
for (var key in users) {
userOrder.push(key);
}
}
…then sort it:
userOrder.sort(function(a, b){
return users[a].localeCompare(users[b]);
});
Here's a demo

You can't order arrays like this in Javascript. Your best bet is to make a map for order.
order = new Array();
order[0] = 562;
order[1] = 16;
order[2] = 834;
order[3] = 823;
order[4] = 23;
order[5] = 917;
In this way, you can have any order you want independently of the keys in the original array.
To sort your array use a custom sorting function.
order.sort( function(a, b) {
if ( users[a] < users[b] ) return -1;
else if ( users[a] > users[b] ) return 1;
else return 0;
});
for ( var i = 0; i < order.length; i++ ) {
// users[ order[i] ]
}
[Demo]

Using the ideas from the comments, I came up with the following solution. The naturalSort function is something I found on google and I modified it to sort a multidimensional array. Basically, I made the users array a multidimensional array with the first index being the user id and the second index being the user name. So:
users[0][0] = 72;
users[0][1] = 'testuser4';
users[1][0] = 91;
users[1][1] = 'testuser2';
users[2][0] = 12;
users[2][1] = 'testuser8';
users[3][0] = 3;
users[3][1] = 'testuser1';
users[4][0] = 18;
users[4][1] = 'testuser7';
users[5][0] = 47;
users[5][1] = 'testuser3';
users[6][0] = 16;
users[6][1] = 'testuser6';
users[7][0] = 20;
users[7][1] = 'testuser5';
I then sorted the array to get the following output:
users_sorted[0][0] = 3;
users_sorted[0][1] = 'testuser1';
users_sorted[1][0] = 91;
users_sorted[1][1] = 'testuser2';
users_sorted[2][0] = 47;
users_sorted[2][1] = 'testuser3';
users_sorted[3][0] = 72;
users_sorted[3][1] = 'testuser4';
users_sorted[4][0] = 20;
users_sorted[4][1] = 'testuser5';
users_sorted[5][0] = 16;
users_sorted[5][1] = 'testuser6';
users_sorted[6][0] = 18;
users_sorted[6][1] = 'testuser7';
users_sorted[7][0] = 12;
users_sorted[7][1] = 'testuser8';
The code to do this is below:
function naturalSort(a, b) // Function to natural-case insensitive sort multidimensional arrays by second index
{
// setup temp-scope variables for comparison evauluation
var re = /(-?[0-9\.]+)/g,
x = a[1].toString().toLowerCase() || '',
y = b[1].toString().toLowerCase() || '',
nC = String.fromCharCode(0),
xN = x.replace( re, nC + '$1' + nC ).split(nC),
yN = y.replace( re, nC + '$1' + nC ).split(nC),
xD = (new Date(x)).getTime(),
yD = xD ? (new Date(y)).getTime() : null;
// natural sorting of dates
if ( yD )
if ( xD < yD ) return -1;
else if ( xD > yD ) return 1;
// natural sorting through split numeric strings and default strings
for( var cLoc = 0, numS = Math.max(xN.length, yN.length); cLoc < numS; cLoc++ ) {
oFxNcL = parseFloat(xN[cLoc]) || xN[cLoc];
oFyNcL = parseFloat(yN[cLoc]) || yN[cLoc];
if (oFxNcL < oFyNcL) return -1;
else if (oFxNcL > oFyNcL) return 1;
}
return 0;
}
// Set values for index
var users = Array();
var temp = Array();
users.push(Array('72', 'testuser4'));
users.push(Array('91', 'testuser2'));
users.push(Array('12', 'testuser8'));
users.push(Array('3', 'testuser1'));
users.push(Array('18', 'testuser7'));
users.push(Array('47', 'testuser3'));
users.push(Array('16', 'testuser6'));
users.push(Array('20', 'testuser5'));
// Sort the array
var users_sorted = Array();
users_sorted = users.sort(naturalSort);

I'd use map once to make a new array of users,
then a second time to return the string you want from the new array.
var users= [];
users[562]= 'testuser3';
users[16]= 'testuser6';
users[834]= 'testuser1';
users[823]= 'testuser4';
users[23]= 'testuser2';
users[917]= 'testuser5';
var u2= [];
users.map(function(itm, i){
if(itm){
var n= parseInt(itm.substring(8), 10);
u2[n]= i;
}
});
u2.map(function(itm, i){
return 'users['+itm+']= testuser'+i;
}).join('\n');
/*returned value: (String)
users[834]= testuser1
users[23]= testuser2
users[562]= testuser3
users[823]= testuser4
users[917]= testuser5
users[16]= testuser6
*/
If you want to avoid any gaps. use a simple filter on the output-
u2.map(function(itm, i){
return 'users['+itm+']= testuser'+i;
}).filter(function(itm){return itm}).join('\n');

Sparse arrays usually spell trouble. You're better off saving key-value pairs in an array as objects (this technique is also valid JSON):
users = [{
"562": "testuser3"
},{
"16": "testuser6"
}, {
"834": "testuser1"
}, {
"823": "testuser4"
}, {
"23": "testuser2"
}, {
"917": "testuser5"
}];
As suggested, you can use a for loop to map the sorting function onto the array.

Array.prototype.sort() takes an optional custom comparison function -- so if you dump all of your users into an array in this manner [ [562, "testuser3"], [16, "testuser6"] ... etc.]
Then sort this array with the following function:
function(comparatorA, comparatorB) {
var userA = comparatorA[1], userB = comparatorB[1]
if (userA > userB) return 1;
if (userA < userB) return -1;
if (userA === userB) return 0;
}
Then rebuild your users object. (Which will loose you your sorting.) Or, keep the data in the newly sorted array of arrays, if that will work for your application.

A oneliner with array of array as a result:
For sorting by Key.
let usersMap = users.map((item, i) => [i, item]).sort((a, b) => a[0] - b[0]);
For sorting by Value. (works with primitive types)
let usersMap = users.map((item, i) => [i, item]).sort((a, b) => a[1] - b[1]);