I want to position my loading animation on the same line, inside my input box, to the right.
I tried :
<span>
<input id="searchbox" placeholder="Enter Catalog # " type="text" />
<img style="float:right;" id='loading' width="100px" src="http://rpg.drivethrustuff.com/shared_images/ajax-loader.gif"/>
</span>
I get :
I couldn't get it to show inside my input box. :(
You can also do it as a background image in CSS. Just create a CSS class and apply at the time of loading the data. After Ajax call is completed remove the "loading" CSS class from the text input box.
.loading {
background-color: #ffffff;
background-image: url("http://loadinggif.com/images/image-selection/3.gif");
background-size: 25px 25px;
background-position:right center;
background-repeat: no-repeat;
}
You can view it here: http://jsfiddle.net/tejsoft/7pzgtevv/4/
I agree with #Sam in that it could be the background of the element, and all you'd have to toggle would be a class. If you set it up like:
input {
box-sizing: border-box;
border: 1px solid #ccc;
height: 30px;
padding: 10px;
}
input.loading {
background: url(http://www.xiconeditor.com/image/icons/loading.gif) no-repeat right center;
}
And then you can toggle the class as you're making your ajax call like:
$(document).on('blur', 'input', function(e) {
var $t = $(e.currentTarget);
$t.addClass('loading');
$.ajax({
url: $t.data('ajax'),
success: function(data) {
//dostuff
$t.removeClass('loading');
}
});
});
That, in my opinion, would be the simplest and most effective way of doing it. If you want to look further, here's a fiddle
Try fiddling around with absolutely positioning the element.
fiddle
img {
position: absolute;
left: 112px;
top: -22px;
}
https://jsfiddle.net/kmbxawdd/2/
Furthermore, you can set the containing elements position to relative, meaning you can style directly to these dimensions rather than the documents.
My solution: add a class to the input element that defines a background image, then modify its position with background-position-x and background-position-y
.Loading {
background-image: url("bg.gif");
background-repeat: no-repeat ;
background-position-x: 99% ;
background-position-y: 50% ;
}
you can also use keywoords for postioning
background-position-x: right;
background-position-y: center;
or combine them
background-position: center right;
then, you can just add or remove this class to show/hide the animation
Try the following:
Place the animation after the input field in the HTML
Set position: relative; on the image
Allows you to tweak the position of the element from where it would be by default
Use the top CSS attribute to shift the animation upward to the point where it is directly on top of the input field.
Place both the input and the img inside a div and make that div look like a text box. I am currently on my phone so it might not be perfect but I think you get the point.
http://jsfiddle.net/soz8jq2x/
just include <img> element inside <input> element.then you can use js to show and hide this image using id attribute.
<img class="loading" src="http://loadinggif.com/images/image-selection/3.gif" id="img-loading">
.loading {
position: absolute;
top: 206px;
right: 30px;
display: none;
}
Related
I have a menu containing onclick calls. Then my js script catches the data and sends it to a php script for processing and returns it back to my js script which is supposed to place the results into the defined document element. Simple enough, right.
For some reason though, if I set the background color in my css the results will not show. Here are the relevant parts of my code. Can someone point out to me if there is a flaw in my code; and if not, why does this behavior happen and is there a work around.
My css...
.decade { margin-left: 150px; padding: 20px; color: green; }
.slaby { position: fixed; left: 200px; bottom: 86px; top: 50px; right:50px; color: black; padding: 20px; background-color: #ddd; border: 2px solid grey; }
My html...
<div class='tln'>
<span class='point' onclick='mes(this)' go='a' >The 70's</span>
<span class='point' onclick='mes(this)' go='b' >The 80's</span>
</div>
<div id='decade' class='decade'>
<div id='slab' class='slaby'></div>
</div>
My js...
function mes(span) {
var clam = span.getAttribute('go'); var shot = 1;
$.ajax({ url:'', type:'POST',
data:{ page: clam, shoot: shot, },
success: function(snowy){
$('#slab').html(snowy);
$('#decade').html(snowy);}});}
In my js script I am placing the results in both 'slab' and 'decade' elements just for testing purposes. Now with my css the way that it is, div(decade) is showing the results, while div(slab) is still blank.
For some reason: if I remove the background color from the div(slab) The results show here; if I add a background color to the div(decade) the results still show here.
I'm looking for a way to display the results in div(slab); as well as, having css style div(slab)'s background color. Thank you all for any help and have a great day.
Some of the other comments pointed out that #slab is "inside" of #decade so when you are doing $('#decade).html() you are replacing/removing #slab.
Use
$('#decade').append()
instead or alternatively
$('#decade').prepend()
(SOLVED) why will jquery not put results in div with background color set.
I am not sure why the query contents were not being displayed, but changing the style for div(slab) with a z-index provided the results I was looking for.
I set the z-index for div(slab) to z-index: -1; and 'voila', works perfect.
.slaby { position: fixed; left: 200px; bottom: 86px; top: 50px; right:50px; color: black; padding: 20px; z-index: -1; background-color: #ddd; border: 2px solid grey; }
I have no idea why this works because no other element inside or outside of it has a z-index set.
Thank you all for your input and effort. I hope this solution helps somebody.
I have a search function that does 3 things:
1) first, when a user hover over the icon, it should change the icon, and the color of border around it as well:
HTML:
<div class="searchbox">
<img id="search" src="Icons/magnifier2.png"
onmouseover="this.src='Icons/magnifier.png'"
onmouseout="this.src='Icons/magnifier2.png'"/>
</div>
CSS:
.searchbox #search {
display: inline;
border: 2px solid #c8c8c8;
position: relative;
height: 20px;
width: 20px;
float: right;
padding: 4px;
border-radius: 5px;
transition: all 500ms;
}
.searchbox #search:hover {
display: inline;
border: 2px solid #808080;
position: relative;
float: right;
padding: 4px;
border-radius: 5px;
transition: all 500ms;
}
So far so good. In this bit, im unsure why the image isnt applied any transition at all when hovered... Is there a way in which you can change color on a single .png icon, instead of juggling between two .pngs?
2) The user is supposed to click on this icon, whereafter it expands with a new icon and a changed border width (padding-left: 130px;). Here goes the following jQuery code:
$(function () {
var search = $("#search");
search.click(function () {
search.attr("src", "Icons/magnifier.png").css({
"border": "2px",
"border-style": "solid",
"border-color": "#808080",
"padding-left": "130px",
"transition": "all 500ms" });
});
});
3) When the user clicks on the HTML body, the border should slide back to normal position and apply the original CSS:
$('html').click(function (e) {
if (e.target.id != 'search') {
$("#search").attr("src", "Icons/magnifier2.png");
$("#search").removeAttr('style');;
}
});
My issue is, the HTML onmouseover/out shown in the top of my post, is still active when the function is fired upon clicking the icon.(if i place my mouse inside and outside the expanded border, it still changes the icon.)
My idea of an easy fix:
It would be a lot easier if the :hover parameter in the CSS could change both the color of the .png and the border, however i've been searching alot for this specific solution, and it doesnt seem to be available!
The second solution would be to add some kind of code in the jQuery, search.click(function() that deactivates the onmouseover/out and reactivates it in the 2'nd .click(function().
I hope im clear enough with my question.
How do i overcome this onmouseover/out issue?
I've added a jsfiddle just for you to see my example:
https://jsfiddle.net/bfytnbs3/
It would be a lot easier if the :hover parameter in the CSS could
change both the color of the .png and the border, however i've been
searching alot for this specific solution, and it doesnt seem to be
available!
You can accomplish that using a CSS sprite. More reading is here: http://www.w3schools.com/css/css_image_sprites.asp
Basically, you'd have one magnifier.png image that would have both states for the icon. Then you'd use some CSS to switch between them.
.searchbox {
background: url('magnifier.png') 0px 0px;
}
.searchbox:hover {
background: url('magnifier.png') 0px -25px;
}
In this example, you'd have a sprite image that was 25px by 50px, with each state of the image being 25px by 25px.
Hope that helps!
Edit to add: Here is a JS Fiddle Example so you can see how it works:
https://jsfiddle.net/s51zjre4/1/
The problem:
I have a form with a button underneath it to submit (post) from data with jQuery ajax(). I want for the button to be replaced with a spinner (animated png) for the duration of server ajax call. But such a trivial task is impossible in css to do right.
What i have tried:
I have placed button and image inside a bootstrap row. Ox ajax call I have set button display to none and img display to block. But because this two are not of the same size makes the whole page flicker, breaks the positioning of other elements and so on.
Another idea was to try to place both elements on top of each other with absolute positioning. But, stupid as css is I cannot center it on the middle of the row.
Is there a way to position both elements on top of each other so I can control their visibility?
Please bear in mind that I cannot used absolute position in pixel, because this is a web page and I do not not how wide the browser will be, image can change in the future, text in the button can change in the future, all this things affect absolute size.
If there is another solution to my problem which would prevent the page from jumping up and down it would also be great.
EDIT
Link to one of fiddle experiments:
https://jsfiddle.net/ofb2qdt8/
.button {
position: relative;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: relative;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This renders second element underneath on screen. Not on different z layer.
Experiment 2:
https://jsfiddle.net/ofb2qdt8/
.button {
position: absolute;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: absolute;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This does not center both elements, and they are pushed to the top of the containing div. The element with less height should be centered.
Check this working demo: https://jsfiddle.net/ofb2qdt8/3/
Add in a few lines of jquery and update your css.
Position your loading div according to button div's position, width, height using jquery.
*Click the button to see loading div, and try to play the margin of the button to any pixel.
###JQUERY
$(document).ready(function () {
$('.c2').each(function () {
$(this).css({
'width': $(this).siblings('.c1').outerWidth(),
'height': $(this).siblings('.c1').outerHeight(),
'top': $(this).siblings('.c1').offset().top,
'left': $(this).siblings('.c1').offset().left
});
});
$('.c2').on('click', function () {
$(this).hide(0);
});
});
###CSS
.c1 {
margin: 100px auto;
width: 100px;
text-align: center;
padding: 5px 10px;
background: blue;
z-index: 1;
}
.c2 {
position: fixed;
text-align: center;
background: red;
z-index: 2;
cursor: pointer;
}
Rough, ready and untested:
HTML
<div>
<input type='submit' />
<img src="spinneyIMage.gif" />
</div>
CSS
div{ text-align: center; }
div img{ display: none; }
jQuery
$('submit').click(function(e){
e.preventDefault();
$(this).hide().next().show();
});
After the Ajax call completes reverse the above jQuery.
As I haven't been able to find a working solution I have reverted to my first idea which I discarded at first. Albeit with a little twist.
HTML
<div class="row>
<div id="container-button" class="col-xs-12>
<button id="button" onclick="button_OnClick(e)">submit form via ajax</button>
<img src="img/spinner.png" sytle="display: none" />
</div>
</div>
JS
function btnContact_OnClick() {
// show the soinner and hide the button
showSpinner();
$.ajax(
{
type: 'POST',
url: "someurl.com/target",
data: $("#form").serialize(),
dataType: "json",
complete: function() { hideSpinner();},
success: onAjaxSuccess,
error : onAjaxError
});
}
function hideSpinner() {
$("#spinner").hide();
$("#button").show();
// make container height non-fixed and content adjustable again
$("#container-button").height('auto');
}
function showSpinner() {
// THis is the trick !!!
// Make the container fixed height as it was before displaying spinner, so it does not change with content (spinner is not the same height as button
$("#container-button").height($("#container-button").height());
$("#button").hide();
$("#spinner").show();
}
This is not the perfect solution but the best I could make.
Drawbacks:
it is not clean, you have to use javasript to fix what is css layout
problem
it still causes a little flicker
the height of container while displaying spinner is dependant on button, this may cause clipping if spinner is too big
I created a div in html and assigned a background image to it, and i want to make an onclick event to that photo and don't know how, that's the div :
.add_btn {
background-color: #099;
position: absolute;
height: 35px;
width: 200px;
background-image: url(img/add.png);
background-repeat: no-repeat;
background-position: center center;
top: 265px;
You didn't give any information about your DOM except that you have an element with that class. It's hard to give a good answer but I'll try.
The following code will attach a function to the onclick events of all the elements with the add_btn class.
document.getElementsByClassName("add_btn").onclick =
function () {
alert("Hello");
};
Background image click is not possible. Because you have a foreground layer.
But you can use this JQuery for foreground image click...
$('.className > .Inner_Classname2= > img').click(function(e) {
alert("Ok");
});
i am totally new in web design, and i am right now struggling with creating part of my website, i need to somehow make this happen:
When PART of the BODY BACKGROUND is HOVERED, make the background change to "B", and when the mouse is not over that part, I need it to change back to background "A".
I have seen some examples here but as i am a beginner, i have no idea how to use javascript, if you could please give me some light here, either on pure CSS or on how to apply javascript.
This is accomplished very easily using a third party javascript library called JQuery http://jquery.com, you can see a working example here: http://jsfiddle.net/bbp8G/
$(document).ready(function(){
$("#hover").mouseenter(function(){
$(this).css("background","#009900");
}).mouseleave(function(){
$(this).css("background","#ffffff");
});
});
Here's the easiest way I know how to do what you've described...
<!-- POSITION THIS DIV WHEREVER YOU WANT THE
USER TO HOVER SO THAT THE BACKGROUND WILL CHANGE -->
<div id="hover">
</div>
<!-- PUT THIS CODE IN YOUR <HEAD> -->
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js" />
<style>
#hover { width: 200px; height: 200px; position: relative; top: 200px; background: green; }
.myNewBackround { background-color: red; }
</style>
<script>
$(document).ready(function() {
// when the #hover DIV is hovered, change the background of the body
$('#hover').hover(function() {
$('body').addClass('myNewBackground');
});
});
</script>
Here's a JS FIDDLE:
http://jsfiddle.net/ZKaJn/
Or you can do it with pure CSS
<div id="left"> </div>
<div id="right"> </div>
And the CSS part:
#left
{
background-color:#000;
float:left;
width:50%;
height:200px;
}
#right
{
background-color:#FF0;
float:right;
width:50%;
height:200px;
}
#right:hover
{
background-color:#00F;
}
#left:hover
{
background-color:#F00;
}
You can replace the div's and values with whatever you like, the main part is the #right:hover and #left:hover
Actually with just css it is not possible to change the background of the body when hovering a DOM element. This is because CSS does not allow you (yet) to travel up the DOM tree (select a parent), only down (select a child).
That being said, it is however possible to mimic the effect, and it is even quiet easy if it is the body background you want to change. You can lay a pseudo element with a background on top of your body background, and underneath the actual content. This way it looks as if the body background has changed.
The css to achieve this would look something like this:
.hover-me:hover:after {
content: '';
top: 0;
left: 0;
right: 0;
bottom: 0;
position: fixed;
background: url(http://placekitten.com/600/300) center center;
background-size: cover;
z-index: -1;
}
And a small fiddle to demonstrate: http://jsfiddle.net/3dwzt/
Should be compatible with IE8 and up