i want to pass one function generated value to another function.
example :
function mainFunc(){
var x = 1;
}
function doMatch(){
var tot = x + 1;
}
only if doMath() Function calls it will calculate total. it shouldn't call mainFunc() Again.
not like this
function mainFunc(){
var x = 1;
return x;
}
function doMatch(){
var tot = mainFunc() + 1;
}
How can i do this. i think if we can make it global variable after it generated from the mainFunc() then every other function can access it.
we cant edit global variable value from function right?
You can define a variable outside the scope of both of these methods that is accessible from each.
function mainFunc(){
window.x = 1;
}
function doMatch(){
var tot = x + 1;
}
Related
I'm currently learning javascript and I would appreciate some help.
I've been playing around trying to create a program that would multiply two numbers without using the * operator. I already found an easier way to do it than my approach but I'd like to know why the code I wrote doesn't work:
function addToItself(a) {
a = a + a;
return a;
}
function times(b) {
for (count = 0; count < b; count++) {
addToItself(a)
}
return a;
}
function multiply (x, y) {
a = x;
times(y);
}
let output = multiply(5, 2);
alert(output);
Is it not working because the binding "a" in the addToItself function has a local scope and the multiply function can't read it or is it something else?
Thanks a lot in advance!
The issue is with the scope of each variable. In JavaScript, a variable declated within a function is scoped to that function. This means that a variable declared within a function can only be accessed within the function. Scopes are nested, so a variable declared globally is accessible inside a function too, though that's often discouraged.
Additionally, function arguments (such as a in addToItself and b in times) are treated like variables scoped to the function.
I would advise looking at the MDN docs for "scope" and familiarizing yourself with how variables are scoped in JavaScript.
I have included a fixed version of your code is below, for reference:
function addToItself(a) {
// I used a new variable here since reassigning to an argument is discouraged
const twoA = a + a;
return twoA;
}
console.log('5 + 5 = ' + addToItself(5));
function times(value, times) {
let temp = 0;
for (let count = 0; count < times; count++) {
temp += value;
}
return temp;
};
console.log('5 * 5 = ' + times(5, 5));
No you can't read variable inside another function, there are easier way, like
function multiply(x, y) {
var result = 0;
for (var count = 0; count < y; count++) {
result += x
}
return result;
}
console.log("5 * 2 = " + multiply(5, 2));
I need to have multiple counters so I created a function, the problem is that I can't store the value in the variable outside the function. I thought this would be easy but I couldn't find anything online.
myCounter = 2;
function count(counter) {
counter++;;
}
count(myCounter);
I would get the value in myCounter to update every time I call the function, thanks for any help you can provide
You can use a closure function that returns an object with a getter so you can initialize as many individual instances as you need
function counter() {
let _count = 0;
return {
get count() {
return ++_count;
}
}
}
let ct1 = new counter();
console.log('ct1', ct1.count, ct1.count)
let ct2 = new counter();
console.log('ct2', ct2.count, ct2.count, ct2.count)
Try this.
var myCounter = 2;
var myCounter2 = 3;
function count(counter) {
return ++counter;
}
myCounter = count(myCounter);
myCounter2 = count(myCounter2);
console.log('myCounter: ' + myCounter);
console.log('myCounter2: ' + myCounter2);
Everytime I run this function, the p1_Balance will always reset back to 10 and will not hold the new value of an increment or decrement.
function Balance() {
var p1_Balance=10;
var x= Math.floor(10*Math.random());
if (x<5) {
p1_Balance=p1_Balance-1;
} else {
p1_Balance=p1_Balance+1;
}
return p1_Balance;
}
Pass p1_Balance into the function instead of initializing it each time the function is called with: var p1_Balance = 10;
p1_Balance should be declared outside the scope of the function (meaning not within the function itself). Otherwise, each time the function is called, the initializer that sets the value to 10 runs as well.
var p1_Balance=10;
function Balance(){ ...
You can use Javascript closures to create a function that does what you want, as you can see below:
var Balance = (function() {
var p1_Balance = 10;
return function() {
var x = Math.floor(10 * Math.random());
if (x < 5)
return p1_Balance += 1;
else
return p1_Balance -= 1;
};
})();
for (var i = 0; i < 10; i++)
console.log(Balance());
Alternatively, you will need to define the p1_Balance variable outside the function or pass it as an argument.
There could be several solutions:
one is declaring p1_Balance as a global variable.
var p1_Balance=10;
function Balance(){
var x= Math.floor(10*Math.random());
if (x<5) {
p1_Balance=p1_Balance-1;
}
else {
p1_Balance=p1_Balance+1;
}
return p1_Balance;
}
another is you could pass balance as a function parameter:
function Balance(p1_Balance){
var x= Math.floor(10*Math.random());
if (x<5) {
p1_Balance=p1_Balance-1;
}
else {
p1_Balance=p1_Balance+1;
}
return p1_Balance;
}
.....
value = Balance(10);// value=something that you want to change by that function.
Why am i getting two different results from the below code. The only change i am doing is passing the value to a function, in first code i am getting the value of global variable "count" as 10 and in the second code the global variables("count") value changes to 30.
function addTen(count) {
count = count + 20;
return count;
}
var count = 10
var result = addTen(count);
console.log(count); //10
console.log(result); //30
function addTen(num) {
count = num + 20;
return count;
}
var count = 10
var result = addTen(count);
console.log(count); //30
console.log(result); //30
In your second function, the statement
count = num + 20;
assigns to the global variable (it's the only count in scope). To make it a local variable for the function scope only, and not affect the global, use
var count = num + 20;
In your first function, the parameter count implicitly declares such a local variable, shadowing the global variable of the same name.
Suppose we define a function that simply increments its input by some stored value dd:
var obj={}
obj.dd=1
obj.f=function(x){
return x+this.dd
}
Alternatively you could create a closure for dd as follows but this would create a static increment as opposed to one that could be altered later:
var dd=1
var f=function(x){
return x+dd
}
We could alternatively store dd in the function itself:
var obj={}
obj.f=function(x){
return x+this.f.dd
}
obj.f.dd=1
I am curious as to whether it is possible for a function to retrieve a variable attached to itself without going through a parent object, something like a self keyword that would refer to the function itself and would allow the following:
var f=function(x){
return x+self.dd
}
f.dd=1
I know it is unnecessary to do such a thing but I think it would be cool if you could.
You can give function literals a name:
var f = function me(x) {
return x + me.dd;
};
f.dd = 1;
This doesn’t work properly in older versions of IE/JScript, though, as me and f don’t reference the same object. The (deprecated and not usable in strict mode) alternative is arguments.callee:
var f = function(x) {
return x + arguments.callee.dd;
};
f.dd = 1;
Also, your note about the closure isn’t quite right; it can be altered later, even through another function:
var dd = 1;
var f = function(x) {
return x + dd;
};
var setdd = function(_dd) {
dd = _dd;
};
A function is an object. If you reference the var holding the function:
var f = function (x) {
return x + f.dd
};
f.dd = 1;
alert(f(1));
result: 2
If the function is named, you can do the same:
function foo(x) {
return x + foo.dd;
}
foo.dd = 1;
alert(foo(1));
result: 2