Loop with native promises; - javascript

I'm trying to make an asynchronous loop with native ES6 promises It kind of works, but incorrectly. I suppose I made a huge mistake somewhere and I need someone to tell me where it is and how it's done correctly
var i = 0;
//creates sample resolver
function payloadGenerator(){
return function(resolve) {
setTimeout(function(){
i++;
resolve();
}, 300)
}
}
// creates resolver that fulfills the promise if condition is false, otherwise rejects the promise.
// Used only for routing purpose
function controller(condition){
return function(resolve, reject) {
console.log('i =', i);
condition ? reject('fin') : resolve();
}
}
// creates resolver that ties payload and controller together
// When controller rejects its promise, main fulfills its thus exiting the loop
function main(){
return function(resolve, reject) {
return new Promise(payloadGenerator())
.then(function(){
return new Promise(controller(i>6))
})
.then(main(),function (err) {
console.log(err);
resolve(err)
})
.catch(function (err) {
console.log(err , 'caught');
resolve(err)
})
}
}
new Promise(main())
.catch(function(err){
console.log('caught', err);
})
.then(function(){
console.log('exit');
process.exit()
});
Now the output:
/usr/local/bin/iojs test.js
i = 1
i = 2
i = 3
i = 4
i = 5
i = 6
i = 7
fin
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
error: [TypeError: undefined is not a function]
caught [TypeError: undefined is not a function]
exit
Process finished with exit code 0
The good part: it reaches the end.
The bad part: it catches some errors and I don't know why.

Any helper function with promise looping I have seen actually made it much worse than what you can do out of the box with recursion.
It is a little nicer with .thenReturn but yeah:
function readFile(index) {
return new Promise(function(resolve) {
setTimeout(function() {
console.log("Read file number " + (index +1));
resolve();
}, 500);
});
}
// The loop initialization
Promise.resolve(0).then(function loop(i) {
// The loop check
if (i < len) { // The post iteration increment
return readFile(i).thenReturn(i + 1).then(loop);
}
}).then(function() {
console.log("done");
}).catch(function(e) {
console.log("error", e);
});
See it in jsfiddle http://jsfiddle.net/fd1wc1ra/
This is pretty much exactly equivalent to:
try {
for (var i = 0; i < len; ++i) {
readFile(i);
}
console.log("done");
} catch (e) {
console.log("error", e);
}
If you wanted to do nested loops it is exactly the same:
http://jsfiddle.net/fd1wc1ra/1/
function printItem(item) {
return new Promise(function(resolve) {
setTimeout(function() {
console.log("Item " + item);
resolve();
}, 500);
});
}
var mdArray = [[1,2], [3,4], [5,6]];
Promise.resolve(0).then(function loop(i) {
if (i < mdArray.length) {
var array = mdArray[i];
return Promise.resolve(0).then(function innerLoop(j) {
if (j < array.length) {
var item = array[j];
return printItem(item).thenReturn(j + 1).then(innerLoop);
}
}).thenReturn(i + 1).then(loop);
}
}).then(function() {
console.log("done");
}).catch(function(e) {
console.log("error", e);
});

If all you're trying to do is count to 7 with promises, then this will do it:
function f(p, i) {
return p.then(function() {
return new Promise(function(r) { return setTimeout(r, 300); });
})
.then(function() { console.log(i); });
}
var p = Promise.resolve();
for (var i = 0; i < 8; i++) {
p = f(p, i);
}
p.then(function() { console.log('fin'); })
.catch(function(e) { console.log(e.message); });
Looping with promises is hard, because it's almost impossible not to fall into JavaScript's closures in a loop trap, but it is doable. The above works because it pushes all use of .then() into a sub-function f of the loop (i.e. away from the loop).
A safer solution, that I use, is to forgo loops altogether and seek out patterns like forEach and reduce whenever I can, because they effectively force the sub-function on you:
[0,1,2,3,4,5,6,7].reduce(f, Promise.resolve())
.then(function() { console.log('fin'); })
.catch(function(e) { console.log(e.message); });
here f is the same function as above. Try it.
Update: In ES6 you can also use for (let i = 0; i < 8; i++) to avoid the "closures in a loop" trap without pushing code into a sub-function f.
PS: The mistake in your example is .then(main(), - it needs to be .then(function() { return new Promise(main()); }, but really, I think you're using the pattern wrong. main() should return a promise, not be wrapped by one.

Try logging err.stack instead of just err when catching promise errors.
In this case, it looks like resolve and reject are not defined within the anonymous function that gets return from main after the initial iteration is complete. I can't totally follow your control flow, but that seems to make sense - after the 7 iterations are complete, there should no longer be any new promises. However, it seems like the code is still trying to run like there are more promises to resolve.
Edit: This is the problem .then(main(),function (err) {. Invoking main on its own will cause resolve and reject inside the anonymous function to be undefined. From the way I read it, main can only be invoked as an argument to the Promise constructor.

I had a similar need and tried the accepted answer, but I was having a problem with the order of operations. Promise.all is the solution.
function work(context) {
return new Promise((resolve, reject) => {
operation(context)
.then(result => resolve(result)
.catch(err => reject(err));
});
}
Promise
.all(arrayOfContext.map(context => work(context)))
.then(results => console.log(results))
.catch(err => console.error(err));

I've looked around for various solutions too and couldn't find one that satisfied me, so I ended up creating my own. Here it is in case it's useful to someone else:
The idea is to create an array of promise generators and to give this array to a helper function that's going to execute the promises one after another.
In my case the helper function is simply this:
function promiseChain(chain) {
let output = new Promise((resolve, reject) => { resolve(); });
for (let i = 0; i < chain.length; i++) {
let f = chain[i];
output = output.then(f);
}
return output;
}
Then, for example, to load multiple URLs one after another, the code would be like this:
// First build the array of promise generators:
let urls = [......];
let chain = [];
for (let i = 0; i < urls.length; i++) {
chain.push(() => {
return fetch(urls[i]);
});
}
// Then execute the promises one after another:
promiseChain(chain).then(() => {
console.info('All done');
});
The advantage of this approach is that it creates code that's relatively close to a regular for loop, and with minimal indentation.

Related

How to run setTimeout synchronously in a loop [duplicate]

for (let i = 0; i < 10; i++) {
const promise = new Promise((resolve, reject) => {
const timeout = Math.random() * 1000;
setTimeout(() => {
console.log(i);
}, timeout);
});
// TODO: Chain this promise to the previous one (maybe without having it running?)
}
The above will give the following random output:
6
9
4
8
5
1
7
2
3
0
The task is simple: Make sure each promise runs only after the other one (.then()).
For some reason, I couldn't find a way to do it.
I tried generator functions (yield), tried simple functions that return a promise, but at the end of the day it always comes down to the same problem: The loop is synchronous.
With async I'd simply use async.series().
How do you solve it?
As you already hinted in your question, your code creates all promises synchronously. Instead they should only be created at the time the preceding one resolves.
Secondly, each promise that is created with new Promise needs to be resolved with a call to resolve (or reject). This should be done when the timer expires. That will trigger any then callback you would have on that promise. And such a then callback (or await) is a necessity in order to implement the chain.
With those ingredients, there are several ways to perform this asynchronous chaining:
With a for loop that starts with an immediately resolving promise
With Array#reduce that starts with an immediately resolving promise
With a function that passes itself as resolution callback
With ECMAScript2017's async / await syntax
With ECMAScript2020's for await...of syntax
But let me first introduce a very useful, generic function.
Promisfying setTimeout
Using setTimeout is fine, but we actually need a promise that resolves when the timer expires. So let's create such a function: this is called promisifying a function, in this case we will promisify setTimeout. It will improve the readability of the code, and can be used for all of the above options:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
See a snippet and comments for each of the options below.
1. With for
You can use a for loop, but you must make sure it doesn't create all promises synchronously. Instead you create an initial immediately resolving promise, and then chain new promises as the previous ones resolve:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
for (let i = 0, p = Promise.resolve(); i < 10; i++) {
p = p.then(() => delay(Math.random() * 1000))
.then(() => console.log(i));
}
So this code creates one long chain of then calls. The variable p only serves to not lose track of that chain, and allow a next iteration of the loop to continue on the same chain. The callbacks will start executing after the synchronous loop has completed.
It is important that the then-callback returns the promise that delay() creates: this will ensure the asynchronous chaining.
2. With reduce
This is just a more functional approach to the previous strategy. You create an array with the same length as the chain you want to execute, and start out with an immediately resolving promise:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
[...Array(10)].reduce( (p, _, i) =>
p.then(() => delay(Math.random() * 1000))
.then(() => console.log(i))
, Promise.resolve() );
This is probably more useful when you actually have an array with data to be used in the promises.
3. With a function passing itself as resolution-callback
Here we create a function and call it immediately. It creates the first promise synchronously. When it resolves, the function is called again:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
(function loop(i) {
if (i >= 10) return; // all done
delay(Math.random() * 1000).then(() => {
console.log(i);
loop(i+1);
});
})(0);
This creates a function named loop, and at the very end of the code you can see it gets called immediately with argument 0. This is the counter, and the i argument. The function will create a new promise if that counter is still below 10, otherwise the chaining stops.
When delay() resolves, it will trigger the then callback which will call the function again.
4. With async/await
Modern JS engines support this syntax:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
(async function loop() {
for (let i = 0; i < 10; i++) {
await delay(Math.random() * 1000);
console.log(i);
}
})();
It may look strange, as it seems like the promises are created synchronously, but in reality the async function returns when it executes the first await. Every time an awaited promise resolves, the function's running context is restored, and proceeds after the await, until it encounters the next one, and so it continues until the loop finishes.
5. With for await...of
With EcmaScript 2020, the for await...of found its way to modern JavaScript engines. Although it does not really reduce code in this case, it allows to isolate the definition of the random interval chain from the actual iteration of it:
const delay = ms => new Promise(resolve => setTimeout(resolve, ms));
async function * randomDelays(count, max) {
for (let i = 0; i < count; i++) yield delay(Math.random() * max).then(() => i);
}
(async function loop() {
for await (let i of randomDelays(10, 1000)) console.log(i);
})();
You can use async/await for this. I would explain more, but there's nothing really to it. It's just a regular for loop but I added the await keyword before the construction of your Promise
What I like about this is your Promise can resolve a normal value instead of having a side effect like your code (or other answers here) include. This gives you powers like in The Legend of Zelda: A Link to the Past where you can affect things in both the Light World and the Dark World – ie, you can easily work with data before/after the Promised data is available without having to resort to deeply nested functions, other unwieldy control structures, or stupid IIFEs.
// where DarkWorld is in the scary, unknown future
// where LightWorld is the world we saved from Ganondorf
LightWorld ... await DarkWorld
So here's what that will look like ...
async function someProcedure (n) {
for (let i = 0; i < n; i++) {
const t = Math.random() * 1000
const x = await new Promise(r => setTimeout(r, t, i))
console.log (i, x)
}
return 'done'
}
someProcedure(10)
.then(console.log)
.catch(console.error)
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
done
See how we don't have to deal with that bothersome .then call within our procedure? And async keyword will automatically ensure that a Promise is returned, so we can chain a .then call on the returned value. This sets us up for great success: run the sequence of n Promises, then do something important – like display a success/error message.
Based on the excellent answer by trincot, I wrote a reusable function that accepts a handler to run over each item in an array. The function itself returns a promise that allows you to wait until the loop has finished and the handler function that you pass may also return a promise.
loop(items, handler) : Promise
It took me some time to get it right, but I believe the following code will be usable in a lot of promise-looping situations.
Copy-paste ready code:
// SEE https://stackoverflow.com/a/46295049/286685
const loop = (arr, fn, busy, err, i=0) => {
const body = (ok,er) => {
try {const r = fn(arr[i], i, arr); r && r.then ? r.then(ok).catch(er) : ok(r)}
catch(e) {er(e)}
}
const next = (ok,er) => () => loop(arr, fn, ok, er, ++i)
const run = (ok,er) => i < arr.length ? new Promise(body).then(next(ok,er)).catch(er) : ok()
return busy ? run(busy,err) : new Promise(run)
}
Usage
To use it, call it with the array to loop over as the first argument and the handler function as the second. Do not pass parameters for the third, fourth and fifth arguments, they are used internally.
const loop = (arr, fn, busy, err, i=0) => {
const body = (ok,er) => {
try {const r = fn(arr[i], i, arr); r && r.then ? r.then(ok).catch(er) : ok(r)}
catch(e) {er(e)}
}
const next = (ok,er) => () => loop(arr, fn, ok, er, ++i)
const run = (ok,er) => i < arr.length ? new Promise(body).then(next(ok,er)).catch(er) : ok()
return busy ? run(busy,err) : new Promise(run)
}
const items = ['one', 'two', 'three']
loop(items, item => {
console.info(item)
})
.then(() => console.info('Done!'))
Advanced use cases
Let's look at the handler function, nested loops and error handling.
handler(current, index, all)
The handler gets passed 3 arguments. The current item, the index of the current item and the complete array being looped over. If the handler function needs to do async work, it can return a promise and the loop function will wait for the promise to resolve before starting the next iteration. You can nest loop invocations and all works as expected.
const loop = (arr, fn, busy, err, i=0) => {
const body = (ok,er) => {
try {const r = fn(arr[i], i, arr); r && r.then ? r.then(ok).catch(er) : ok(r)}
catch(e) {er(e)}
}
const next = (ok,er) => () => loop(arr, fn, ok, er, ++i)
const run = (ok,er) => i < arr.length ? new Promise(body).then(next(ok,er)).catch(er) : ok()
return busy ? run(busy,err) : new Promise(run)
}
const tests = [
[],
['one', 'two'],
['A', 'B', 'C']
]
loop(tests, (test, idx, all) => new Promise((testNext, testFailed) => {
console.info('Performing test ' + idx)
return loop(test, (testCase) => {
console.info(testCase)
})
.then(testNext)
.catch(testFailed)
}))
.then(() => console.info('All tests done'))
Error handling
Many promise-looping examples I looked at break down when an exception occurs. Getting this function to do the right thing was pretty tricky, but as far as I can tell it is working now. Make sure to add a catch handler to any inner loops and invoke the rejection function when it happens. E.g.:
const loop = (arr, fn, busy, err, i=0) => {
const body = (ok,er) => {
try {const r = fn(arr[i], i, arr); r && r.then ? r.then(ok).catch(er) : ok(r)}
catch(e) {er(e)}
}
const next = (ok,er) => () => loop(arr, fn, ok, er, ++i)
const run = (ok,er) => i < arr.length ? new Promise(body).then(next(ok,er)).catch(er) : ok()
return busy ? run(busy,err) : new Promise(run)
}
const tests = [
[],
['one', 'two'],
['A', 'B', 'C']
]
loop(tests, (test, idx, all) => new Promise((testNext, testFailed) => {
console.info('Performing test ' + idx)
loop(test, (testCase) => {
if (idx == 2) throw new Error()
console.info(testCase)
})
.then(testNext)
.catch(testFailed) // <--- DON'T FORGET!!
}))
.then(() => console.error('Oops, test should have failed'))
.catch(e => console.info('Succesfully caught error: ', e))
.then(() => console.info('All tests done'))
UPDATE: NPM package
Since writing this answer, I turned the above code in an NPM package.
for-async
Install
npm install --save for-async
Import
var forAsync = require('for-async'); // Common JS, or
import forAsync from 'for-async';
Usage (async)
var arr = ['some', 'cool', 'array'];
forAsync(arr, function(item, idx){
return new Promise(function(resolve){
setTimeout(function(){
console.info(item, idx);
// Logs 3 lines: `some 0`, `cool 1`, `array 2`
resolve(); // <-- signals that this iteration is complete
}, 25); // delay 25 ms to make async
})
})
See the package readme for more details.
If you are limited to ES6, the best option is Promise all. Promise.all(array) also returns an array of promises after successfully executing all the promises in array argument.
Suppose, if you want to update many student records in the database, the following code demonstrates the concept of Promise.all in such case-
let promises = students.map((student, index) => {
//where students is a db object
student.rollNo = index + 1;
student.city = 'City Name';
//Update whatever information on student you want
return student.save();
});
Promise.all(promises).then(() => {
//All the save queries will be executed when .then is executed
//You can do further operations here after as all update operations are completed now
});
Map is just an example method for loop. You can also use for or forin or forEach loop. So the concept is pretty simple, start the loop in which you want to do bulk async operations. Push every such async operation statement in an array declared outside the scope of that loop. After the loop completes, execute the Promise all statement with the prepared array of such queries/promises as argument.
The basic concept is that the javascript loop is synchronous whereas database call is async and we use push method in loop that is also sync. So, the problem of asynchronous behavior doesn't occur inside the loop.
here's my 2 cents worth:
resuable function forpromise()
emulates a classic for loop
allows for early exit based on internal logic, returning a value
can collect an array of results passed into resolve/next/collect
defaults to start=0,increment=1
exceptions thrown inside loop are caught and passed to .catch()
function forpromise(lo, hi, st, res, fn) {
if (typeof res === 'function') {
fn = res;
res = undefined;
}
if (typeof hi === 'function') {
fn = hi;
hi = lo;
lo = 0;
st = 1;
}
if (typeof st === 'function') {
fn = st;
st = 1;
}
return new Promise(function(resolve, reject) {
(function loop(i) {
if (i >= hi) return resolve(res);
const promise = new Promise(function(nxt, brk) {
try {
fn(i, nxt, brk);
} catch (ouch) {
return reject(ouch);
}
});
promise.
catch (function(brkres) {
hi = lo - st;
resolve(brkres)
}).then(function(el) {
if (res) res.push(el);
loop(i + st)
});
})(lo);
});
}
//no result returned, just loop from 0 thru 9
forpromise(0, 10, function(i, next) {
console.log("iterating:", i);
next();
}).then(function() {
console.log("test result 1", arguments);
//shortform:no result returned, just loop from 0 thru 4
forpromise(5, function(i, next) {
console.log("counting:", i);
next();
}).then(function() {
console.log("test result 2", arguments);
//collect result array, even numbers only
forpromise(0, 10, 2, [], function(i, collect) {
console.log("adding item:", i);
collect("result-" + i);
}).then(function() {
console.log("test result 3", arguments);
//collect results, even numbers, break loop early with different result
forpromise(0, 10, 2, [], function(i, collect, break_) {
console.log("adding item:", i);
if (i === 8) return break_("ending early");
collect("result-" + i);
}).then(function() {
console.log("test result 4", arguments);
// collect results, but break loop on exception thrown, which we catch
forpromise(0, 10, 2, [], function(i, collect, break_) {
console.log("adding item:", i);
if (i === 4) throw new Error("failure inside loop");
collect("result-" + i);
}).then(function() {
console.log("test result 5", arguments);
}).
catch (function(err) {
console.log("caught in test 5:[Error ", err.message, "]");
});
});
});
});
});
In ES6, you should use 'for await':
(async () => {
for await (const num of asyncIterable) {
console.log(num);
}
// My action here
})();
For more information, see this for await...of.
I see the previous answers and feel confused. And I coded the following by the answers' inspiration. I think its logic is more obvious, I call the function to replace original for loop:
async function pointToCountry(world, data) { // Data is for loop array
if (data.length > 0) { // For condition
const da = data.shift(); // Get current data and modified data one row code
// Some business logic
msg = da.info
pointofView(world, da);
// Await the current task
await new Promise(r => setTimeout(_ => {
r() // Resolve and finish the current task
}, 5000))
// Call itself and enter the next loop
pointToCountry(world, data)
} else { // Business logic after all tasks
pointofView(world, { longitude: 0, latitude: 0 });
world.controls().autoRotate = true;
}
}
// This is my main function - calculate all project by city
const projectCity = async (req, res, next) => {
try {
let record = [];
let cityList = await Cityodel.find({active:true});
for (let j = 0; j < cityList.length; j++) {
let arr = [];
let projectList = await getProduct(cityList[j]._id)
arr.push({
_id:cityList[j]._id,
name:cityList[j].name,
projectList:projectList
})
record.push(arr);
}
return res.status(200).send({
status: CONSTANT.REQUESTED_CODES.SUCCESS,
result: record });
} catch (error) {
return res.status(400).json(UTILS.errorHandler(error));
}
};
async function getProduct(city){
let projectList = await ProjectModel.find({city:city});
return projectList;
}
I've created a snippet in Angular that loops a promise function indefinitely. You can start it, stop it, or restart it.
You basically need to recursively call the same method and await it's current process like so:
async autoloop(): Promise<void> {
if(this.running){
await this.runMe();
await this.autoloop();
}
return Promise.resolve();
}
JavaScript:
import { Component } from '#angular/core';
#Component({
selector: 'my-app',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css'],
})
export class AppComponent {
messages: string[] = [];
counter = 1;
running = false;
constructor() {
this.start();
}
onClick(): void {
this.running = !this.running;
if(this.running){
this.start();
}
else{
this.stop();
}
}
async onRestartClick(): Promise<void>{
await this.stop();
this.messages = [];
this.counter = 1;
this.start();
}
start(): void{
this.running = true;
this.autoloop();
}
async stop(): Promise<void>{
this.running = false;
await this.delay(1000);
}
async autoloop(): Promise<void> {
if(this.running){
await this.runMe();
await this.autoloop();
}
return Promise.resolve();
}
async runMe(): Promise<void> {
await this.delay(1000);
if(this.running){
this.messages.push(`Message ${this.counter++}`);
}
return Promise.resolve();
}
async delay(ms: number) {
await new Promise<void>((resolve) => setTimeout(() => resolve(), ms));
}
}
Html:
<h1>Endless looping a promise every 1 second</h1>
<button (click)="onClick()">Start / stop</button>
<button (click)="onRestartClick()">Restart</button>
<p *ngFor="let message of messages">
{{message}}
</p>

Trying to define a promise.all

I am trying to understand how promises work by creating the Promise.all method from an exercise of this book:
https://eloquentjavascript.net/11_async.html#i_Ug+Dv9Mmsw
I tried looping through the whole array that's given as argument to the method itself, using .then for successful promises where the body of the handler pushes the result to a binding i defined previously outside of the loop, for rejected promises, i used .catch in a way that it takes the rejected value as a "reason" and rejects the main promise giving it an error
function Promise_all(promises) {
return new Promise((resolve, reject) => {
if(promises.length == 0) resolve(promises);
let fullArray = [];
for(let i=0; i<promises.length ; i++){
promises[i]
.then(x => fullArray.push(x))
.catch(reason => reject(new Error(reason)));
}
resolve(fullArray);
});
}
What i expected the function to do the following:
-Pick a promise from the "Promises" array.
-Solve the promise (if successful) by using the .then method on it with a handler function that just pushes the result to "fullArray".
-Solve the promise (if rejected) by using the .catch method on it with a handler function that simply calls the reject handler of the main promise that will be returned by "Promise_all".
-When the loop finishes, simply resolve the promise the "fullArray" of successful promises.
The code simply doesn't work the way i thought it would, using the test code of the book doesn't return the expected results:
Promise_all([]).then(array => {
console.log("This should be []:", array);
});
function soon(val) {
return new Promise(resolve => {
setTimeout(() => resolve(val), Math.random() * 500);
});
}
Promise_all([soon(1), soon(2), soon(3)]).then(array => {
console.log("This should be [1, 2, 3]:", array);
});
Promise_all([soon(1), Promise.reject("X"), soon(3)])
.then(array => {
console.log("We should not get here");
})
.catch(error => {
if (error != "X") {
console.log("Unexpected failure:", error);
}
});
The issue with the code, as #Bergi said, was that the ".then" and ".catch" callbacks are called asynchronously and as a consequence of this, "fullArray" wasn't even filled when "resolve()" was called even when it was outside of the loop. To solve this, i simply added "resolve()" inside of the promise that finishes last, to do this, i simply added a "counter" binding that has the value of the length of the "promises" array, and is reduced by 1 every time ".then" was called on a promise and when this "counter" equals 0, it calls "resolve()".
But that only solves the problem of filling the "fullArray" with the promises, not the issue of those promises being ordered correctly by the order they were called, to solve this i simply enumerated them in the array with the "i" binding of the loop, the end result was this:
function Promise_all(promises) {
return new Promise((resolve, reject) => {
if(promises.length == 0) resolve(promises);
let fullArray = [],
counter = promises.length;
for(let i=0; i< promises.length ; i++){
promises[i]
.then(x => {
fullArray[i] = x;
counter--;
if(counter == 0) resolve(fullArray)})
.catch(reason => reject(new Error(reason)));
}
});
}

Loops and Callback hell

Suppose you have an Array/Object that contains a list of values. Lets say those a mysql commands or urls or filespaths. Now you want to iterate over all of them and execute some code over every entry.
for(let i = 0; i < urls.length; i++){
doSthWith(urls[i]);
}
No Problem so far. But now lets say each function has a callback and needs the result of the last execution. e.g. you request something from one website and you want to use the results of this request for one of your following requests.
for(let i = 0; i < urls.length; i++){
if(resultOfLastIteration.successful){ //or some other result besides the last one
doSthWith(urls[i]);
}
}
Now lets say the length of urls (or sth similar) is over 100. Thats why you normaly use a loop so you dont need to write the same function a 100 times. That also means that Promises wont do the trick either (except Im unaware trick a trick), because you have the same problem:
doSthWith(urls[0]).then(...
doSthWith(urls[1]).then(... //either put them inside each other
).then(...
doSthWith(urls[i]) //or in sequence
...
).catch(err){...}
Either way I dont see a way to use a loop.
A way that I found but isnt really "good" is to use the package "wait.for"(https://www.npmjs.com/package/wait.for). But what makes this package tricky is to launch a fiber each time you want to use wait.for:
//somewhere you use the function in a fiber Context
wait.for(loopedExecutionOfUrls, urls);
//function declaration
function loopedExecutionOfUrls(urls, cb){
//variables:
for(let i = 0; i < urls.length; i++){
if(someTempResultVar[i-1] === true){
someTempResultVar = wait.for(doSthWith,urls[i]);
} else if(...){...}
}
}
But Im not sure if this approach is really good, besides you always have to check if you have wrapped the whole thing in a Fiber so for each function that has loops with functions that have callbacks. Thus you have 3 levels: the lauchFiber level, wait.for(loopedFunction) level and the wait.for the callback function level. (Hope I that was formulated understandable)
So my questions is: Do you guys have a good approach where you can loop throw callback functions and can use results of those whenever you like?
good = easy to use, read, performant, not recursive,...
(Im sorry if this question is stupid, but I really have problems getting along with this asynchronous programming)
If you want to wait for doSthWith to finish before doing the same but with the nex url, you have to chain your promises and you can use array.prototype.reduce to do that:
urls = ["aaa", "bbb", "ccc", "ddd"];
urls.reduce((lastPromise, url) => lastPromise.then((resultOfPreviousPromise) => {
console.log("Result of previous request: ", resultOfPreviousPromise); // <-- Result of the previous request that you can use for the next request
return doSthWith(url);
}), Promise.resolve());
function doSthWith(arg) { // Simulate the doSthWith promise
console.log("do something with: ", arg);
return new Promise(resolve => {
setTimeout(() => resolve("result of " + arg), 2000);
});
}
Use async, specifically async.each:
const async = require('async');
function doSthWith(url, cb) {
console.log('doing something with ' + url);
setTimeout(() => cb(), 2000);
}
const urls = ['https://stackoverflow.com/', 'https://phihag.de/'];
async.each(urls, doSthWith, (err) => {
if (err) {
// In practice, likely a callback or throw here
console.error(err);
} else {
console.log('done!');
}
});
Use async.map if you are interested in the result.
When I need to loop over promises I use my handy dandy ploop function. Here is an example:
// Function that returns a promise
var searchForNumber = function(number) {
return new Promise(function(resolve, reject) {
setTimeout(function() {
var min = 1;
var max = 10;
var val = Math.floor(Math.random()*(max-min+1)+min);
console.log('Value is: ' + val.toString());
return resolve(val);
}, 1000);
});
};
// fn : function that should return a promise.
// args : the arguments that should be passed to fn.
// donefn : function that should check the result of the promise
// and return true to indicate whether ploop should stop or not.
var ploop = function(fn, args, donefn) {
return Promise.resolve(true)
.then(function() {
return(fn.apply(null, args));
})
.then(function(result) {
var finished = donefn(result);
if(finished === true){
return result;
} else {
return ploop(fn, args, donefn);
}
});
};
var searchFor = 4;
var donefn = function(result) {
return result === searchFor;
};
console.log('Searching for: ' + searchFor);
ploop(searchForNumber, [searchFor], donefn)
.then(function(val) {
console.log('Finally found! ' + val.toString());
process.exit(0);
})
.catch(function(err) {
process.exit(1);
});

Pattern for dynamic Javascript promises

Inside a promise, I need to call and process an indeterminate number of asynch API responses after individually calling them either inside another promise, or after said promise, but before another so the order of execution is respected.
var promiseA = function() {
return new Promise(function(resolve, reject) {
// 1. Establish objects needed from one API endpoint
// 2. Call API endpoint for each object and parse
// 3. Only then continue to next promise
}
}
var finalPromise = function() {
return new Promise(function(resolve, reject) {
//
}
}
promiseA()
.then(finalPromise)
So inside promiseA, I find out how many objects I'll need to poll individually from an API. Each request is of course asynchronous. I need to make these calls and process the response before the final promise is called.
I am struggling to determine a pattern for this with promises, where I can dynamically create these promises and only allow the final promise to execute after the indeterminate and asynchronous have executed and processed. I've worked with other languages where this is possible, but I'm struggling to see it here with Promises.
Any help is appreciated.
I have changed the answer to incorporate the comments below. Since, you mentioned ES6 promises I shall stick to that. There are two basic types of callbacks that we might care about.
DOM load or other one time event callbacks (window.onload and so on)
Async method callback (AJAX call, setTimout and so on)
Since,
1.DOM load or other one time event
var p = new Promise(function(res, rej) {
window.onload = res();
};
2.Plain callback: these are callbacks that don't conform to a convention. e.g. setTimeout
var p = new Promise(function(res, rej){
setTimeout(function() {
//your business/view logic
success? res():rej(); //if successful resolve else reject
}, 2000);
});
In each of the above case the promise (var p) can be wrapped to be returned by a function.
var myAsyncMethod = function () {
var p = new ... // as mentioned in 1 or 2
return p;
}
Then the usage:
myAsyncMethod()
.then(function(){/* success-handler */})
.catch(function(/* failure-handler */));
Specific to your question you may have many such methods:
function baseAJAXCall (url) {
new Promise(functoin(rej, res) {
$.get(url, function(err, data){
if(err) {
rej();
}
else {
resolve(data);
}
});
}
};
function callAPIEndpoint(url) {
return baseAJAXCall(url);
}
function finalPromiseHandler () {
//your final business/view logic
}
//USAGE
callAPIEndpoint('/my-first-call')
.then(function(data){
var promiseArray = data.map(function(item){
return baseAJAXCall(item.url);
});
return Promise.all(promiseArray);
})
.then(finalPromiseHandler)
.catch(function(){
console.log('.error-message.');
});
Ref:
How do I convert an existing callback API to promises?.
http://www.datchley.name/es6-promises/
Links from comments below.
---OLD ANSWER: PLEASE OVERLOOK---
I am familiar with this library : https://github.com/kriskowal/q. And, you can do this using using the q.all and q.allSettled constructs. May be that is what you are looking for.
Normally, the pattern is to create a function that returns a promise.
function someAsyncFuncName1(url) {
var def = q.defer();
//async function
$.get(url, function(err, data){ //suppose
if(err){
def.reject();
}
else {
def.resolve(data); //pass the data to the .then() handler.
}
});
return def.promise;
}
function someAsyncFuncName2() {
var def = q.defer();
//async function
setTimeout(function(){ //suppose
//do something
if(good) {
def.resolve();
} else {
def.reject();
}
}, 1000); //arbitrary timeout of 1 second
return def.promise;
}
USAGE:
q.all([someAsyncFuncName1('/api-1'), someAsyncFuncName2()])
.then(function() {
//final handler
});
On a similar line of thought one can use q.allSettled() if you want to wait for all promises to return.
Hope this helps.
---EOF OLD ANSWER---
First of all, if async functions used in PromiseA don't return promises, you need to promisify them. You can do that with Promise constructor, but it's much better to use libraries, such as bluebird with their promisify methods.
Let's imagine, that we have two functions getUserIdsAsync and getUserAsync. The first on returns a list of user ids, getUserAsync returns an user data by userId. And you need to get a list of users by their ids. The code of PromiseA could look so:
var promiseA = function() {
return getUserIdsAsync()
.then(userIds => {
let ops = users.map(uid => getUserAsync(uid));
return Promise.all(ops);
});
}
The following snippet shows a solution without using any external library like bluebird. It follows the code snippet in your question (which seems to be more complicate than needed).
You have to collect all api promisses in an array. Then you can call Promise.all() to get a Promise for the end of all api promisses. Then you can do some final stuff, like parsing the result of each promise and continue afterwards.
function getRandomInt(min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
var apiEndpoint = function (name) {
return new Promise( (resolve, reject) => {
setTimeout(() => resolve('API ' + name + ' job done'), 1000);
});
}
var promiseA = function() {
return new Promise( (resolve, reject) => {
const promisses = [];
for (var i=1; i < getRandomInt(3,6); i++) {
// 1. Establish objects needed from one API endpoint
promisses.push(apiEndpoint('This is number ' + i));
}
Promise.all(promisses).then( results => {
// do final stuff
for (const s of results) {
// 2. Call API endpoint for each object and parse
console.log(s);
}
// continue ...
// 3. Only then continue to next promise
resolve('now it is finished');
}).catch( err => reject(err) );
});
}
var finalPromise = function() {
return new Promise( (resolve, reject) => {
console.log('finalPromise');
resolve();
});
}
promiseA()
.then( () => finalPromise())
.catch(err => console.log(err) );
Please hold in mind that this solution is not easy to read. Using external libraries or reducing promisses can improve readability. Maybe you should take a look to the async/await pattern to get a much more better (readable) solution.
Here is a solution with async/await:
function getRandomInt(min, max) {
return Math.floor(Math.random() * (max - min + 1)) + min;
}
const apiEndpoint = function (name) {
return new Promise( (resolve, reject) => {
setTimeout(() => resolve('API ' + name + ' job done'), 1000);
});
}
async function promiseParallel () {
const promisses = [];
for (let i = 1; i < getRandomInt(3,6); i++) {
promisses.push(apiEndpoint('This is number ' + i));
}
for (const p of promisses) {
const x = await p;
console.log(x);
}
return ('everything is done');
}
promiseParallel().then( result => {
console.log(result);
}).catch( err => console.log(err) );
If you want call the promisses sequentially you can replace with:
async function promiseSequ () {
for (let i = 1; i < getRandomInt(3,6); i++) {
const x = await apiEndpoint('This is number ' + i);
console.log(x);
}
return ('everything is done');
}

For loop does not complete inside Promise

I'm trying to write a function that includes a for loop inside a Promise, however the loop only performs on iteration and the promise is never resolved.
My code looks like this:
function appendPosts() {
return functionThatReturnsAPromise()
.then( result => {
return new Promise( (resolve, reject) => {
var list = [];
result.forEach( item => {
//do stuff to item
list.push(item);
});
resolve(list);
});
})
.then( list => {
return new Promise( (resolve, reject) => {
//This loop only runs once, even when list has contains many items
for ( var i = 0; i < list.length; i++ ) {
document.querySelector("someSelector").appendChild( list[i] );
}
resolve();
});
});
}
Clearly I'm doing something wrong. Any ideas?
Thanks for your time.
- Daniel
#MaazSyedAdeeb is right. There was an exception thrown in the loop and I didn't have a catch block in place. Thanks.
The selector probably did not return a match, and so appendChild was called on undefined, triggering an exception translated to a rejected promise.
You could treat this error if in your call you add a .catch:
appendPosts().then(function () {
console.log('all done');
}).catch(function (err) {
console.log('error occurred: ', err);
});
But it should also be mentioned that you are using the promise constructor anti-pattern. Namely, in a then callback you can just return a value, and that value will become the promised value of the promise that then will return. So there is no need to do new Promise(). Instead, do this:
function appendPosts() {
return functionThatReturnsAPromise().then( result => {
// Just return the mapped array:
return result.map( item => {
//do stuff to item
return item;
}).then( list => {
for ( var i = 0; i < list.length; i++ ) {
// Make sure the selector will result in a match:
document.querySelector("someSelector").appendChild( list[i] );
}
});
});
}

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