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Javascript replace on multiple Japanese character

I want to replace this
"】|"
character from string with this"】".
mystring is ="【権利確定月】|1月"
and desired output is
"【権利確定月】1月".
I have tried with array operation and also with this code:
mystring.replace(/】|/g, '】')
but not working.
I only want to this with sequence for"】|".
Because after that string will grow like this
example:
"【権利確定月】1月|other|other|【other】other|other|other".
I have tried many other solution provided on stack overflow but all regex contain single character I want for above sequence character.

You need to escape the | because it has a special meaning within regex. 】| equates to 】 or (an empty string) so the result is that it replaces 】 with itself and inserts 】 between all the other characters in the string.
var mystring ="【権利確定月】|1月"
var myModifiedString = mystring.replace(/】\|/g, '】');
console.log(myModifiedString);

You need to escape the logical OR operator as it is a metacharacter in RegEx.
var x = "【権利確定月】|1月".replace(/】\|/g, '】');
console.log(x);

You can define the strings that need to be replaced in separate variables. Following worked for me.
var x = "】|";
var y = "】";
var word = "【権利確定月】|1月";
word.replace(x, y)

You can split your string by 】| and join by 】. Or (as was answered before me) escape | in regex.
const string = '【権利確】|】|定月】|1月';
let splitAndJoin = string.split('】|').join('】');
let replaceRegex = string.replace(/】\|/g, '】');
console.log(splitAndJoin);
console.log(replaceRegex);

regex for serial number in javascript

var serialNumber = $('#SerialNumber').val();
var serialNumberPattern = new RegExp('^[\s\da-zA-z\-.]+$');
if (!serialNumberPattern.test(serialNumber)) {
}
Above is the code I am using to validate a serial number which has alphanumeric characters, dots (.), dashes (-), and slashes (/) in it but somehow it's not working. Where am I going wrong? Please help.

When you're passing regex to RegExp constructor which uses " as regex delimiter, you have to escape all the backslashes one more time. Or otherwise it would be treated as an escape sequence.
var serialNumberPattern = new RegExp("^[\\s\\da-zA-Z.-]+$");
alphanumeric,dot(.),Dash(-),Slash(/) in it.
var serialNumberPattern = new RegExp("^[\\da-zA-Z./-]+$");

Just use /^[\s\da-zA-Z\-.\/]+$/, it's simple and works just fine.
You should only use the RegExp constructor when parts of the expression use a variable. This is not true in your case and just adds additional confusion.
document.write(/^[\s\da-zA-Z\-.\/]+$/.test('23 43-89'))

Javascript: RegExp not working no matter what my expression is

Ok, I've been using RegExp a number of times but for some reason I cannot get it to work this time. I am trying to test for latitude (0 to +/- 90 degrees). No matter what expression I use, it always returns false. Here's my code:
var regexLatitude = new RegExp("^-?([1-8]?[0-9]\.{1}\d{1,6}$|90\.{1}0{1,6}$)");
var status = regexLatitude.test("89.5");
I also tried without quotes:
var status = regexLatitude.test(89.5);
Any idea?

Your \ characters are being parsed by the Javascript string literal.
You need to use a regex literal:
var regexLatitude = /^-?([1-8]?[0-9]\.{1}\d{1,6}$|90\.{1}0{1,6}$)/;

Regexp for floating number

I found this regexp for validating floats. But I cant see how 2-1 will accepted. The below evaluates to true. I can't use parseFloat because I need to be able to accept "," instead of "." also. I wrote re2, same result though.
var re1 = new RegExp("^[-+]?[0-9]*\.?[0-9]+$");
console.log(re1.test("2-1"));
var re2 = new RegExp("^([0-9]+)\.([0-9]+)$");
console.log(re2.test("2-1"));

If you generate the regex using the constructor function, you have to to escape the backslash, i.e. \ becomes \\:
var re1 = new RegExp("^[-+]?[0-9]*\\.?[0-9]+$");
Another option is to use the literal syntax which doesn't require escaping:
var re1 = /^[-+]?[0-9]*\.?[0-9]+$/

Sometimes when you create a regex string, you even have to escape the backslash; this can of course be done with a backslash, so the final regex looks something like "\\.*", etc.
Doing this, I was able to get the correct results, as seen here:
var re1 = new RegExp("^[-+]?[0-9]*\\.?[0-9]+$");
console.log(re1.test("2-1"));
var re2 = new RegExp("^([0-9]+)\\.([0-9]+)$");
console.log(re2.test("2-1"));
console.log(re1.test("2.1"));
console.log(re2.test("2.1"));​

What about replacing a comma (",") with a period (".") and then using parseFloat?

RegExp.test not working?

I am trying to validate year using Regex.test in javascript, but no able to figure out why its returning false.
var regEx = new RegExp("^(19|20)[\d]{2,2}$");
regEx.test(inputValue) returns false for input value 1981, 2007
Thanks

As you're creating a RegExp object using a string expression, you need to double the backslashes so they escape properly. Also [\d]{2,2} can be simplified to \d\d:
var regEx = new RegExp("^(19|20)\\d\\d$");
Or better yet use a regex literal to avoid doubling backslashes:
var regEx = /^(19|20)\d\d$/;

Found the REAL issue:
Change your declaration to remove quotes:
var regEx = new RegExp(/^(19|20)[\d]{2,2}$/);

Do you mean
var inputValue = "1981, 2007";
If so, this will fail because the pattern is not matched due to the start string (^) and end string ($) characters.
If you want to capture both years, remove these characters from your pattern and do a global match (with /g)
var regEx = new RegExp(/(?:19|20)\d{2}/g);
var inputValue = "1981, 2007";
var matches = inputValue.match(regEx);
matches will be an array containing all matches.

I've noticed, for reasons I can't explain, sometimes you have to have two \\ in front of the d.
so try [\\d] and see if that helps.