Questions re: caching a jquery object when passing to a function? - javascript

Given that $thisObj is referenced multiple times in the function, would it be better practice to cache $(this) before passing it to myFunction($thisObj)?
function myFunction($thisObj) {
alert($thisObj.html());
alert($thisObj.html());
alert($thisObj.html());
}
Which way should it be called?
myFunction($(this));
OR
var $obj = $(this);
myFunction($obj);
Or does it not matter because the object is already "cached" once it's passed to the function? This seems like a very fundamental question, but I spent a lot of time searching this topic without a clear answer.

This doesn't make a difference inside myFunction() since the value is only calculated once when the function is called and then stored in the $thisObj parameter variable. The conde in the function just uses the contents of $thisObj, it does not evaluate $(this) repeatedly.
So I would prefer to call the function as myFunction($(this)) since it's more to the point without creating an unnecessary extra variable.
With the extra variable, somebody reading the code will wonder if that variable will be used again later on, making the code (slightly) harder to understand.

Related

Does the use of prototyping in javascript have a negative effect on ajax calls and asynchronous code?

If I had the following object and prototyped functionality added on.
function Hello (input){
this.input = input
}
Hello.prototype.ajaxcall = function(id){
$.get("/ajax/method", {parameter:input}, function(data){
$("#"id).html(data);
});
}
Forgive the syntax if not completely correct but what it should be doing is taking in an element id, performing an ajax call and assigning the ajax call result to the innerHTML of the id. Will the fact that the ajaxcall function is shared across all instances of an object cause any problems with regards to what data will be assigned to which id if for example 20 object were all created together and had this function called immediately?
If this is the case, does it make sense to put asyncronous methods inside the object constructor instead?
What would happen if 20 objects would be created and the ajaxcall function would be called? Nothing much. The ajax calls would run asynchronously. When they have finished they are queued so that they run on the main thread when the current running operation on the main thread finished.
So the callback functions run all synchronous in a queue next time there's time for it. Nothing bad can happen here.
I don't understand your question about the constructor. What would that change? If you use your Hello objects they have an instance variable. This is is enclosed in the callback closure . Creating a new function doesn't change the value in another callback function.
If you use the same IDs the content could flash when the text changes and you don't know which callback would be ran last but that's the worst thing that could happen.
There should be no issue. You're calling the function 20 distinct times with 20 different ids.
Conceptually though. I'm not seeing why this is part of your object. The function does not use anything at all from the object itself.
This particular example would work. Your function makes no use of any instance variables, so it doesn't really make sense to declare it that way, but it makes even less sense to move it into the constructor. Still it will work because the id argument will not be shared between calls.
EDIT: So now that you've changed it so that it does use an instance variable you've got the syntax wrong, it needs to be
{parameter : this.input}
But aside from that it will still work. The asynchronous behaviour is not a problem for the code shown.

Is this bad practice: getMyObject().method()

Suppose I have a function which returns an object :
getMyObject(){
//do stuff here
return object;
}
Is it bad practice to call a method (that doesn't return anything) on the function name itself:
getMyObject().method();
instead of assigning a variable to the return object and then calling the method on that variable :
var returnedObject = getMyObject();
returnedObject.method();
I am working with an html page that has many nested frames, and I have access to a function that returns one of these frames. The frame might be used several times within other functions in my script, and I was wondering if it would be ok for me to access the frame in the way asked above, or if it would be better to declare a global variable.
*EDIT: * Ahh I haven't gotten a chance to use jQuery. Good to know!
Yes, this is perfectly OK. jQuery for example uses this as well. It returns objects on which you can call methods immediatley. This is called chaining.
In your example, method chaining is the better practice IMHO. If a function returns an object, upon which you want to call a method, but you do not need to reference that object after calling that method, don't assign it to a variable.
Also, jQuery code does this all the time(1):
$('#foo').on('click',function(){});
/\ \\
|| \\
|| \\
function call returns jQ object <============|
\\ ||
\\call method "on" upon _||
(1)To clarify: I do not claim that all jQ methods return an object .attr() or .prop() don't. What I mean by "all the time" is actually that the scenario the OP describes is very common in jQ code (function call, invoke method on returned object):
var someString = $($('.foo').get(0)).attr('id');//tricky little bugger, this :)
var aBool = $('#foo').prop('checked');
Usually, no. Chaining method calls like that is usually simpler, more elegant, and easier to read. However, there are a few cases when it's better to use a variable.
If you use a method (or chain of methods) a lot of times, you can use a variable if it makes the code cleaner.
If the method takes a long time to process, it's better to cache the result. For example, if you have some method called calculateResults(), and it pulls data from a database, that takes some time. If the data doesn't change, you'll be incurring that cost for each call to the method. Better to store it in a variable and reuse it.
If the method has side effects, you should be careful about calling it more than once. Those side-effects will be inflicted each time you call it. Again, as an example, if you have a function like nextItem() that advances to the next item and returns it (a la Java iterators), then calling it more than intended will actually change the result. In this case, you have no choice but store the result, since calling it more than once will produce incorrect behavior.
Otherwise, chain away!

Method implementation difference.. need some understadning

Excuse me first. because i don't know this is question is valid or not. i if any one clear my doubt then i am happy.
Basically : what is the different between calling a method like:
object.methodname();
$('#element').methodname();
calling both way is working, but what is the different between, in which criteria make first and second type of methods. is it available in the core javascript as well?
In case if i have a function is it possible to make 2 type of method call always?
Can any one give some good reference to understand correctly?
Thanks in advance.
The first syntax:
object.methodName();
Says to call a function, methodName(), that is defined as a property of object.
The second syntax:
$('#element').methodname();
Says to call a function called $() which (in order for this to work) must return an object and then call methodname() on that returned object.
You said that "calling both way is working," - so presumably you've got some code something like this:
var myObject = $('#element');
myObject.methodname();
This concept of storing the result of the $() function in a variable is commonly called "caching" the jQuery object, and is more efficient if you plan to call a lot of methods on that object because every time you call the jQuery $() function it creates another jQuery object.
"Is it available in the core javascript as well?" Yes, if you implement functions that return objects. That is, JS supports this (it would have to, since jQuery is just a JS library) but it doesn't happen automatically, you have to write appropriate function code. For example:
function getObject() {
return {
myMethod1 : function() { alert("myMethod1"); return this; },
myMethod2 : function() { alert("myMethod2"); return this; }
};
}
getObject().myMethod1().myMethod2();
In my opinion explaining this concept in more depth is beyond the scope of a Stack Overflow answer - you need to read some JavaScript tutorials. MDN's Working With Objects article is a good place to start once you have learned the JS fundamentals (it could be argued that working with objects is a JS fundamental, but obviously I mean even more fundamental stuff than that).
The difference is very subtle.
object.methodname();
This is when JavaScript has the object at hand.
$('#element').methodname();
If you are using jQuery, you are asking jQuery to select the object that has the id of #element. After that you invoke the method on the selected object.

Can value of a JavaScript variable be changed twice in the same function?

Not sure if this is considered best practice or if you should even do this but I have a small block of Javascript and I want to know if you can declare a variable, display that variable and then reassign it and display it again? Syntactically this seems correct but I would assume that this is not best practice and should be avoided?
Note: I did not write this block I just want to know if it's ok or if I should change it and use 2 variables code below:
var u1 = 'something';
if (u1.indexOf('Accept') > 0)
{
var URL = 'some URL';
document.writeln(URL);
URL = 'another URL';
document.writeln(URL);
}
Thanks in advance.
EDIT:Thanks for the answers, thought it was a bit daft. :/
Yes you can
You can change variable's value as many times as you need to. Variables are quite often reused so we save memory resources. Not in the way you've used them (because that's an example that would be better off providing constant strings directly when calling functions) but think of an everyday example where we don't even think of multiple variable value assignments. A for loop:
for (var i = 0; i < 100; i++)
{
...
}
In this loop variable i gets assigned a new value 101 times. This is a rather obvious example, where we don't think of this at all, but other than that, we could have a set of loops and reuse the same variable more explicitly and assign it a value lots of times like:
var counter = 0;
for(var item = GetLinkedListFirstItem(); item != null; item = item.Next)
{
counter++;
}
// other code...
counter = 0;
while (counter < 10 || someOtherCondition)
{
// do something else
}
This may be a much better example of explicit variable reusability where its value gets changed lots of times and for different purposes.
Variable naming
Variable reuse is sometimes unwanted/undesired. And that's when we have a meaningful variable name like isUserLoggedIn. It's hard to reuse such variable for other purposes because it would make code unmaintainable.
Variables that are usually reused may hence be iterators (ie. i) or generally named variables without too much meaning. Or variables with more universal name (ie. finished) which can be reused in different contexts that can be associated with such variable name.
Asynchronous code
There are certain situations where you may have problems even though looking at code may seem perfectly fine. And that's when you use async functions which is frequently the case when using Ajax calls or time-deferred calls (ie. setTimeout). Consider the following code:
var loaded = false;
$.ajax({
url: "...",
type: "POST",
success: function(){
loaded = true;
}
});
if (loaded === true)
{
// do something important
}
// ok loaded not used any more, so we can reuse it
// we can easily change its type from number to string or anything else
loaded = "Peter loaded his gun";
This code has a bug, because important code won't be executed. Ever! This is quite a frequent misconception by unsavvy developers not understanding asynchronism.
Hint: When code issues an Ajax call it doesn't wait for a response but rather continues execution and executes if statement. Even though Ajax call would respond in 0time ticks, success function wouldn't execute until this currently running code wouldn't finish execution. That's how Javascript works. Queued code execution. In the end when Ajax async code would execute it would eventually overwrite the string that was stored in the variable.
Why not? Of course, it's normal to change variable value as much times as you want. That's actually reason why it's called "variable", not "constant" :)
I'd say it's perfectly fine to do so.
However, keep in mind that it can cause problems with asynchronous code. Take the following example for instance, where async accepts a callback that runs some time later:
var a = 123;
async(function() {
alert(a); // alerts 456, because `a` was set to 456
// *before* this callback was run.
// Because there is only one `a`, that variable
// has been overridden
});
a = 456;
async(function() {
alert(a); // alerts 456
});
Yes it is possible, and in this case there is no point in creating a new variable. However, if you have a lot of code reassigning a variable later could definitely be confusing especially if at first it's an object then later it is a string.
Variables can be reassigned in JavaScript. Whether they should or not is a question of style and context.
I normally prefer to re-use variables rather than create new ones

JQuery/JavaScript performance using $(this)

I find myself doing a lot of this kind of JQuery:
$('.filter-topic-id').each(function () {
var me = $(this);
if (me.text() == topics[k]) {
me.parent().show();
}
});
I store $(this) in a variable called me because I'm afraid it will re-evaluate $(this) for no reason. Are the major JavaScript engines smart enough to know that it doesn't have to re-evaluate it? Maybe even JQuery is smart enough somehow?
They are not smart enough to know not to revaluate $(this) again, if that's what your code says. Caching a jQuery object in a variable is a best practice.
If your question refers to your way in the question compared to this way
$('.filter-topic-id').each(function () {
if ($(this).text() == topics[k]) { // jQuery object created passing in this
$(this).parent().show(); // another jQuery object created passing in this
}
});
your way is the best practice.
Are the major JavaScript engines smart enough to know that it doesn't have to re-evaluate it?
No. But if you are using jQuery you are presumably aiming for readability rather than necessarily maximum performance.
Write whichever version you find easiest to read and maintain, and don't worry about micro-optimisations like this until your page is too slow and you've exhausted other more significant sources of delay. There is not a lot of work involved in calling $(node).
You could try to profile your code with Firebug and see if using $(this) many times slows your app or not
There is no good way that a javascript can determine that the following is true:-
fn(x) == fn(x);
Even if this was possible not calling the second fn could only be valid if it could be guaraneed that fn has not have other side-effects. When there is other code between calls to fn then its even more difficult.
Hence Javascript engines have no choice but to actually call fn each time it is invoked.
The overhead of calling $() is quite small but not insignificant. I would certainly hold the result in a local variable as you are doing.
this is just a reference to the current DOM element in the iteration, so there's little or no overhead involved when calling $(this). It just creates a jQuery wrapper around the DOM element.
I think you'll find that calling the jQuery function by passing a dom element is perhaps the least-intensive of ways to construct the object. It doesn't have to do any look-ups or query the DOM, just wrap it and return it.
That said, it definitely doesn't hurt to use the method you're using there, and that's what I do all the time myself. It certainly helps for when you create nested closures:
$('div').click(function() {
var $this = $(this);
$this.find("p").each(function() {
// here, there's no reference to the div other than by using $this
alert(this.nodeName); // "p"
});
});

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