Insert one string into another - javascript

I need to insert 'embed' into the middle of a YouTube URL, so e.g.
https://www.youtube.com/watch?v=JDCV_cK1L1A
Needs to be modified to:
https://www.youtube.com/embed/watch?v=JDCV_cK1L1A
Using only jQuery.
Do I need to use RegEx for this? It seems the only answers I can find online are either appending / prepending, or inserting a string into x position of another string... but neither solution are appropriate for what I need to achieve

You don't need a regular expression for this. If you want to add the folder right after the domain, you can use a plain replace:
url = url.replace('youtube.com/', 'youtube.com/embed/');
If you want to add it as the last folder, you can find the last slash and insert it there:
var last = url.lastIndexOf('/');
url = url.substr(0, last) + '/embed' + url.substr(last);

Related

Use jQuery to Auto Escape characters from a var

First, I'm not sure I've titled my question properly. Please feel free to correct me if needed.
My Issue:
I've created a variable, in jQuery called var siteTitle. This variable is available for other .js files to use and then get passed back to the .html page.
It all works great and there are no issues except when the var siteTitle will contain certain characters that need to be escaped. (quote, single quote, and ampersand to be specific)
What I would like to do is to use a bit of jQuery that would search a particular dom element and see if it is using any of those characters and then automatically escape them.
I've searched for some similar functions and can not seem to find exactly what I need ... the closet idea I have seen is something like this. Its not exactly what I need but it is something like what I am looking for.
pathto: function(path, file) {
var rtrim = function(str, list) {
var charlist = !list ? 's\xA0': (list + '').replace(/([\[\]\(\)\.\?\/\*\{\}\+\$\^\:])/g, '$1');
var re = new RegExp('[' + charlist + ']+$', 'g');
return (str + '').replace(re, '');
};
So, I am trying to write a function that will automatically convert those characters to be escaped or their html equivalent.
So, if the var siteTitle is used in a dom element like this:
<h1 class="titleText">' + siteTitle + '</h1>
I need to be able to make sure that any characters get escaped in that element.
Here is a jsFiddle that shows exactly what I am trying to do ...
https://jsfiddle.net/bbyrdhouse/5jb2fdsr/1/
Any help is greatly appreciated.
Since you're using jquery, use the .text() function to set the value into your HTML. It'll escape it appropriately.
var siteTitle = 'My Site "Title"';
$my('.titleText').text(siteTitle);
Also, in your fiddle, the siteTitle variable is not what you think it is, because the 2nd quotation closes that value since it's not yet escaped. I wrapped it in single quotes in my example.
Updated fiddle

javascript match and add string in dynamic Url

I have a dynamic URL, which i want to append some string at last
'http://staging.mydomain.name.com/test/7bb12c5f7b2f4f008261bea2d3f5abd2/200x200.png'
want to append "preview" before size (200x200.png which is also dynamic), something like below
'http://staging.mydomain.name.com/test/7bb12c5f7b2f4f008261bea2d3f5abd2/preview/200x200.png'
I have seen Javascript match to remove part of file name from URL - replace the last occurence but its not what i want.
Thanks
Just use a simple regular expression like:
'http://.../200x200.png'.replace(/[^\/]+$/, 'preview/$&')
You can do like str.replace(/(/\d+x\d+.)/,'/preview$1')

trouble using string.replace with regex

Given something a regex like this:
http://rubular.com/r/ai1LFT5jvK
I want to use string.replace to replace "subdir" with a string of my choosing.
Doing myStr.replace(/^.*\/\/.*\.net\/.*\/(.*)\/.*\z/,otherStr)
only returns the same string, as shown here: http://jsfiddle.net/nLmbV/
If you view the Rublar, it appears to capture what I want it to capture, but on the Fiddle, it doesn't replace it.
I'd like to know why this happens, and what I'm doing wrong. A correct regex or a correct implementation of the replace call would be nice, but most of all, I want to understand what I'm doing wrong so that I can avoid it in the future.
EDIT
I've updated the fiddle to change my regex from:
/^.*\/\/.*\.net\/.*\/(.*)\/.*\z/
to
/^.*\/\/.*\.net\/.*\/(.*)\/.*$/
And according to the fiddle, it just returns hello instead of https://xxxxxxxxxxx.cloudfront.net/dir/hello/Slide1_v2.PNG
It's that little \z in your regex.
You probably forgot to replace it with a $ sign. JavaScript uses ^ and $ as anchors, while Ruby uses \A and \z.
To answer your edit:
The match is always replaced as a whole. You'll want to group both the left side and the right side of the to-be-replaced part and reinsert it in the replacement:
url.replace(/^(.*\/\/.*\.net\/.*\/).*(\/.*)$/,"$1hello$2")
Before I get marked down, I know the question asks about regexp. The reason for this answer URLs are nearly impossible to process reliably with a regexp without writing fiendishly complex regexps. It can be done, but it makes your head hurt!
If you are doing this in a browser, you can use an A tag in your script to make things much simpler. The A tag knows how to parse them into pieces, and it lets you modify the pieces independently, so you only need to deal with the pathname:
//make a temporary a tag
var a = document.createElement('a');
//set the href property to the url you want to process
a.href = "scheme://host.domain/path/to/the/file?querystring"
//grab the path part of the url, and chop up into an array of directories
var dirs = a.pathname.split('/');
//set 2nd dir name - array is ['','path','to','file']
dirs[2]='hello';
//put the path back together
a.pathname = dirs.join('/');
a.href now contains the URL you want.
More lines, but also more hair left when you come back to change the code later.

Find Replace Short Part of URL using Javascript

Assume I have the following URL stored in variable called content:
http://www.example.com/watch?v=4444444&feature=related
Problem:
I need to replace watch?v= with embed/
I need to erase whatever comes after &
The final output would look like:
http://www.example.com/embed/4444444
I tried these two steps but didn't work:
content = content.replace('/watch?v=/', 'embed/');
content = content.replace('&*/g','');
The URL in page source code appears as:
http://www.example.com/watch?v=4444444&feature=related
You have many errors:
You are using a regular expression when you only need a string.
You are writing your regular expressions as strings.
To write 'match any characters' you need to write '.*', not just '*'. The star modifies the previous token.
There is no need to use the g flag here.
Try this instead:
content = content.replace('watch?v=', 'embed/').replace(/&.*/, '');

Javascript string replace of dots (.) within filenames

I'm trying to parse and amend some html (as a string) using javascript and in this html, there are references (like img src or css backgrounds) to filenames which contain full stops/periods/dots/.
e.g.
<img src="../images/filename.01.png"> <img src="../images/filename.02.png">
<div style="background:url(../images/file.name.with.more.dots.gif)">
I've tried, struggled and failed to come up with a neat regex to allow me to parse this string and spit it back out without the dots in those filenames, e.g.
<img src="../images/filename01.png"/> <img src="../images/filename02.png"/>
<div style="background:url(../images/filenamewithmoredots.gif)">
I only want to affect the image filenames, and obviously I want to leave the filetype alone.
A regex like:
/(.*)(?=(.gif|.png|.jpg|.jpeg))
allows me to match the main part of the filename and the extension seperately, but it also matches across the whole of the string, not just within the one filename I want.
I have no control over the incoming html, I'm just consuming it.
Help me please overflowers, you're my only hope!
I agree that this is not a problem suitable for regular expression, much less one neat expression.
But I trust that you are not here to hear that. So, in case you want to keep the input as string...
var src, result = '<img src="../images/filename.01.png"> <img src="../images/filename.02.png"><div style="background:url(../images/file.name.with.more.dots.gif)">';
do {
src = result;
result = src.replace( /((?:url(\()|href=|src=)['"]?(?:[^'"\/]*\/)*[^'"\/]*)\.(?=[^\.'")]*\.(?:gif|png|jpe?g)['")>}\s])/g, '$1' );
} while (result != src)
Basically it keeps removing the second last dot of images url's filenames until there are none. Here is a breakdown of the expression in case you need to modify it. Tread lightly:
( start main capturing group since js regx has no lookbehind.
(?:url(\()|href=|src=)['"]? Start of an url. it would be safer to force url() to be properly quoted so that we can use back reference, but unfortunately your given example is not.
(?:[^'"\/]*\/)* Folder part of the url.
[^'"\/]* Part of the file name that comes before second last dot.
) close main group.
\. This is the second last dot we want to get rid of.
(?= Look behind.
[^\.'")]* Part of the file name that goes between second last dot and last dot.
\.(?:gif|png|jpe?g) Make sure the url ends in image extension.
['")>}\s] Closing the url, which can be a quote, ')', '>', '}', or spaces. Should user back reference here if possible. (Was ['"]?\b when first answered)
) End of look behind.
Consider using the DOM instead of regular expressions. One way is to create fake elements.
var fake = document.createElement('div');
fake.innerHTML = incomingHTML: // Not really part of JS standard but all the 'main' browsers support it
var background = fake.childNodes[0].style.background;
// Now use a regex if need be: /url\(\"?(.*)\"?\)/
// If img is at childNodes[1]
var url = fake.childNodes[1].src;
With jQuery this is far easier:
$(incomingHTML).find('img').each(function() { $(this).attr('src'); });
Your problem is the greedy match in .*. Maybe better try something like this
([^\/]*)(?=(.gif|.png|.jpg|.jpeg))
[^\/] is a character class that matches every character but slashes
another point is, you need to escape the . to match it literally
([^\/]*)(?=\.(gif|png|jpg|jpeg))
The problem is that . means "any character".
Escape it:
/(.*)(?=(\.gif|\.png|\.jpg|\.jpeg))

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