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I am trying to get the day 90 days after today. This is my code:
var today = new Date();
var threeMonthsFromToday = new Date(today.setDate(today.getDate() + 90));
When I print threeMonthsFromToday, I get the correct date: 2017-04-24T15:17:42.641Z. However, when I try to reformat the date to be in the form dd/mm/yyyy using this code:
var day = ('0' + threeMonthsFromToday.getDate()).slice(-2);
var month = ('0' + threeMonthsFromToday.getMonth() + 1).slice(-2);
var year = threeMonthsFromToday.getFullYear();
var date = day + '/' + month + '/' + year;
I get a completely different and invalid date: 24/31/2017.
I have been debugging this for hours and still can't seem to figure what I am doing wrong.
Well, '0' + threeMonthsFromToday.getMonth() give you a string : "03" then you add 1 converted to string giving you "031" for month before slice.
Use this :
var month = ('0' + (threeMonthsFromToday.getMonth() + 1)).slice(-2);
You are missing the basic BODMAS rule here please modify your code as follows
var today = new Date();
var threeMonthsFromToday = new Date(today.setDate(today.getDate() + 90));
var day = ('0' + threeMonthsFromToday.getDate()).slice(-2);
var month = ('0' + (threeMonthsFromToday.getMonth() + 1)).slice(-2);
var year = threeMonthsFromToday.getFullYear();
var date = day + '/' + month + '/' + year;
the operations are performed from left to right, so month is getting converted to string before being added to a number. Including a bracket will first perform operation inside bracket and then make it a string
Can you use toLocaleString?
threeMonthsFromToday.toLocaleDateString('en-GB')
Below does the trick for you ...
getMonth() +1 before adding the "0" to it so that you get an arithematic +1
var today = new Date();
var threeMonthsFromToday = new Date(today.setDate(today.getDate() + 90));
var day = ('0' + threeMonthsFromToday.getDate()).slice(-2);
var month = ('0' + (threeMonthsFromToday.getMonth()+1)).slice(-2);
var year = threeMonthsFromToday.getFullYear();
var date = day + '/' + month + '/' + year;
console.log(date);
This should work.
var day = threeMonthsFromToday.getDate()
if(day < 10){
day = '0' + day
}
var month = threeMonthsFromToday.getMonth()+1
if(month<10){
month = '0' + month
}
var year = threeMonthsFromToday.getFullYear()
var date = day + '/' + month + '/' + year
Use Simple toLocaleDateString method
The toLocaleDateString() method returns a string with a language sensitive representation of the date portion of this date.
var today = new Date();
var threeMonthsFromToday = new Date(today.setDate(today.getDate() + 90));
var date = threeMonthsFromToday.toLocaleDateString();
console.log(date);
//result in console : "24/04/2017"
Try it out on your console.
I have a date in format YYYYMMDDTHHMMSS and need to get the date in format DD.MM.YYYY HH:MM:SS .
I do such:
var dateTimeFormat;
var dateAsString = dataTimeFormat.split('', dateTimeFormat.lenght);
var year = dateAsString.splice(0, 4).join('');
var month = dateAsString.splice(0, 2).join('');
var day = dateAsString.splice(0, 2).join('');
var hours = dateAsString.splice(1, 2).join('');
var minutes = dateAsString.splice(1, 2).join('');
var seconds = dateAsString.splice(1, 2).join('');
var date = day + '.' + month + '.' + year + ' ' + hours + ':' + minutes + ':' + seconds;
return date;
But how can I convert date to Date format?
After transforming string into a known format, Date::parse() will be enough:
var yourDate = new Date(Date.parse(date));
WORKING DEMO:
var date = "2016.06.15 10:10:10";
var yourDate = new Date(Date.parse(date));
alert(yourDate);
NOTE: your format is a bit weird, but maybe parse will accept it as long as it accept many string formats such as:
Date.parse("Aug 9, 1995");
Date.parse("Wed, 09 Aug 1995 00:00:00");
Date.parse("Wed, 09 Aug 1995 00:00:00 GMT");
i think this is easy way to do this =). hope it help
<script>
dateTimeFormat = '20161506T112130';
str = dateTimeFormat.split("");
date = str[0] + str[1] + str[2] + str[3] + '.' + str[4] + str[5] + '.' + str[6] + str[7] + ' ' + str[9] + str[10] + ':' + str[11] + str[12] + ':' + str[13] + str[14];
console.log(date);
</script>
how can I get the date in this format [mm/dd/yy] using javascript. I am struggling to get the 'year' to a 2 digit figure as opposed to the full 4 digits. Thanks!
var date = new Date();
var datestring = ("0" + (date.getMonth() + 1).toString()).substr(-2) + "/" + ("0" + date.getDate().toString()).substr(-2) + "/" + (date.getFullYear().toString()).substr(2);
This guarantees 2 digit dates and months.
Try this:
HTML
<div id="output"></div>
JS
(function () {
// Get current date
var date = new Date();
// Format day/month/year to two digits
var formattedDate = ('0' + date.getDate()).slice(-2);
var formattedMonth = ('0' + (date.getMonth() + 1)).slice(-2);
var formattedYear = date.getFullYear().toString().substr(2,2);
// Combine and format date string
var dateString = formattedMonth + '/' + formattedDate + '/' + formattedYear;
// Reference output DIV
var output = document.querySelector('#output');
// Output dateString
output.innerHTML = dateString;
})();
Fiddle: http://jsfiddle.net/kboucher/4mLe1Lrd/
How About this for the year
String(new Date().getFullYear()).substr(2)
And since you need your Month from 01 through 12 do this
var d = new Date("2013/8/3");
(d.getMonth() < 10 ? "0" : "") + (d.getMonth() + 1)
Do the same thing for days, Minutes and seconds
Working Demo
I want to know how to use the Date() function in jQuery to get the current date in a yyyy/mm/dd format.
Date() is not part of jQuery, it is one of JavaScript's features.
See the documentation on Date object.
You can do it like that:
var d = new Date();
var month = d.getMonth()+1;
var day = d.getDate();
var output = d.getFullYear() + '/' +
(month<10 ? '0' : '') + month + '/' +
(day<10 ? '0' : '') + day;
See this jsfiddle for a proof.
The code may look like a complex one, because it must deal with months & days being represented by numbers less than 10 (meaning the strings will have one char instead of two). See this jsfiddle for comparison.
If you have jQuery UI (needed for the datepicker), this would do the trick:
$.datepicker.formatDate('yy/mm/dd', new Date());
jQuery is JavaScript. Use the Javascript Date Object.
var d = new Date();
var strDate = d.getFullYear() + "/" + (d.getMonth()+1) + "/" + d.getDate();
Using pure Javascript your can prototype your own YYYYMMDD format;
Date.prototype.yyyymmdd = function() {
var yyyy = this.getFullYear().toString();
var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
var dd = this.getDate().toString();
return yyyy + "/" + (mm[1]?mm:"0"+mm[0]) + "/" + (dd[1]?dd:"0"+dd[0]); // padding
};
var date = new Date();
console.log( date.yyyymmdd() ); // Assuming you have an open console
In JavaScript you can get the current date and time using the Date object;
var now = new Date();
This will get the local client machine time
Example for jquery LINK
If you are using jQuery DatePicker you can apply it on any textfield like this:
$( "#datepicker" ).datepicker({dateFormat:"yy/mm/dd"}).datepicker("setDate",new Date());
function GetTodayDate() {
var tdate = new Date();
var dd = tdate.getDate(); //yields day
var MM = tdate.getMonth(); //yields month
var yyyy = tdate.getFullYear(); //yields year
var currentDate= dd + "-" +( MM+1) + "-" + yyyy;
return currentDate;
}
Very handy function to use it, Enjoy. You do not require any javascript framework. it just works in with plain javascript.
I know I am Late But This Is All You Need
var date = (new Date()).toISOString().split('T')[0];
toISOString() use built function of javascript.
cd = (new Date()).toISOString().split('T')[0];
console.log(cd);
alert(cd);
Since the question is tagged as jQuery:
If you are also using jQuery UI you can use $.datepicker.formatDate():
$.datepicker.formatDate('yy/mm/dd', new Date());
See this demo.
Here is method top get current Day, Year or Month
new Date().getDate() // Get the day as a number (1-31)
new Date().getDay() // Get the weekday as a number (0-6)
new Date().getFullYear() // Get the four digit year (yyyy)
new Date().getHours() // Get the hour (0-23)
new Date().getMilliseconds() // Get the milliseconds (0-999)
new Date().getMinutes() // Get the minutes (0-59)
new Date().getMonth() // Get the month (0-11)
new Date().getSeconds() // Get the seconds (0-59)
new Date().getTime() // Get the time (milliseconds since January 1, 1970)
See this.
The $.now() method is a shorthand for the number returned by the expression (new Date).getTime().
Moment.js makes it quite easy:
moment().format("YYYY/MM/DD")
this object set zero, when element has only one symbol:
function addZero(i) {
if (i < 10) {
i = "0" + i;
}
return i;
}
This object set actual full time, hour and date:
function getActualFullDate() {
var d = new Date();
var day = addZero(d.getDate());
var month = addZero(d.getMonth()+1);
var year = addZero(d.getFullYear());
var h = addZero(d.getHours());
var m = addZero(d.getMinutes());
var s = addZero(d.getSeconds());
return day + ". " + month + ". " + year + " (" + h + ":" + m + ")";
}
function getActualHour() {
var d = new Date();
var h = addZero(d.getHours());
var m = addZero(d.getMinutes());
var s = addZero(d.getSeconds());
return h + ":" + m + ":" + s;
}
function getActualDate() {
var d = new Date();
var day = addZero(d.getDate());
var month = addZero(d.getMonth()+1);
var year = addZero(d.getFullYear());
return day + ". " + month + ". " + year;
}
HTML:
<span id='full'>a</span>
<br>
<span id='hour'>b</span>
<br>
<span id='date'>c</span>
JQUERY VIEW:
$(document).ready(function(){
$("#full").html(getActualFullDate());
$("#hour").html(getActualHour());
$("#date").html(getActualDate());
});
EXAMPLE
//convert month to 2 digits<p>
var twoDigitMonth = ((fullDate.getMonth().length+1) === 1)? (fullDate.getMonth()+1) : '0' + (fullDate.getMonth()+1);
var currentDate = fullDate.getFullYear()+ "/" + twoDigitMonth + "/" + fullDate.getDate();
console.log(currentDate);<br>
//2011/05/19
You can achieve this with moment.js as well.
Include moment.js in your html.
<script src="moment.js"></script>
And use below code in script file to get formatted date.
moment(new Date(),"YYYY-MM-DD").utcOffset(0, true).format();
FYI - getDay() will give you the day of the week... ie: if today is Thursday, it will return the number 4 (being the 4th day of the week).
To get a proper day of the month, use getDate().
My example below... (also a string padding function to give a leading 0 on single time elements. (eg: 10:4:34 => 10:04:35)
function strpad00(s)
{
s = s + '';
if (s.length === 1) s = '0'+s;
return s;
}
var currentdate = new Date();
var datetime = currentdate.getDate()
+ "/" + strpad00((currentdate.getMonth()+1))
+ "/" + currentdate.getFullYear()
+ " # "
+ currentdate.getHours() + ":"
+ strpad00(currentdate.getMinutes()) + ":"
+ strpad00(currentdate.getSeconds());
Example output: 31/12/2013 # 10:07:49If using getDay(), the output would be 4/12/2013 # 10:07:49
This will give you current date string
var today = new Date().toISOString().split('T')[0];
Try this....
var d = new Date();
alert(d.getFullYear()+'/'+(d.getMonth()+1)+'/'+d.getDate());
getMonth() return month 0 to 11 so we would like to add 1 for accurate month
Reference by : https://www.w3schools.com/jsref/jsref_obj_date.asp
you can use this code:
var nowDate = new Date();
var nowDay = ((nowDate.getDate().toString().length) == 1) ? '0'+(nowDate.getDate()) : (nowDate.getDate());
var nowMonth = ((nowDate.getMonth().toString().length) == 1) ? '0'+(nowDate.getMonth()+1) : (nowDate.getMonth()+1);
var nowYear = nowDate.getFullYear();
var formatDate = nowDay + "." + nowMonth + "." + nowYear;
you can find a working demo here
var d = new Date();
var today = d.getFullYear() + '/' + ('0'+(d.getMonth()+1)).slice(-2) + '/' + ('0'+d.getDate()).slice(-2);
The jQuery plugin page is down. So manually:
function strpad00(s)
{
s = s + '';
if (s.length === 1) s = '0'+s;
return s;
}
var now = new Date();
var currentDate = now.getFullYear()+ "/" + strpad00(now.getMonth()+1) + "/" + strpad00(now.getDate());
console.log(currentDate );
console.log($.datepicker.formatDate('yy/mm/dd', new Date()));
Using the jQuery-ui datepicker, it has a handy date conversion routine built in so you can format dates:
var my_date_string = $.datepicker.formatDate( "yy-mm-dd", new Date() );
Simple.
This is what I came up with using only jQuery. It's just a matter of putting the pieces together.
//Gather date information from local system
var ThisMonth = new Date().getMonth() + 1;
var ThisDay = new Date().getDate();
var ThisYear = new Date().getFullYear();
var ThisDate = ThisMonth.toString() + "/" + ThisDay.toString() + "/" + ThisYear.toString();
//Gather time information from local system
var ThisHour = new Date().getHours();
var ThisMinute = new Date().getMinutes();
var ThisTime = ThisHour.toString() + ":" + ThisMinute.toString();
//Concatenate date and time for date-time stamp
var ThisDateTime = ThisDate + " " + ThisTime;
You can do this:
var now = new Date();
dateFormat(now, "dddd, mmmm dS, yyyy, h:MM:ss TT");
// Saturday, June 9th, 2007, 5:46:21 PM
OR Something like
var dateObj = new Date();
var month = dateObj.getUTCMonth();
var day = dateObj.getUTCDate();
var year = dateObj.getUTCFullYear();
var newdate = month + "/" + day + "/" + year;
alert(newdate);
var d = new Date();
var month = d.getMonth() + 1;
var day = d.getDate();
var year = d.getYear();
var today = (day<10?'0':'')+ day + '/' +(month<10?'0':'')+ month + '/' + year;
alert(today);
I just wanted to share a timestamp prototype I made using Pierre's idea. Not enough points to comment :(
// US common date timestamp
Date.prototype.timestamp = function() {
var yyyy = this.getFullYear().toString();
var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
var dd = this.getDate().toString();
var h = this.getHours().toString();
var m = this.getMinutes().toString();
var s = this.getSeconds().toString();
return (mm[1]?mm:"0"+mm[0]) + "/" + (dd[1]?dd:"0"+dd[0]) + "/" + yyyy + " - " + ((h > 12) ? h-12 : h) + ":" + m + ":" + s;
};
d = new Date();
var timestamp = d.timestamp();
// 10/12/2013 - 2:04:19
Get current Date format dd/mm/yyyy
Here is the code:
var fullDate = new Date();
var twoDigitMonth = ((fullDate.getMonth().toString().length) == 1)? '0'+(fullDate.getMonth()+1) : (fullDate.getMonth()+1);
var twoDigitDate = ((fullDate.getDate().toString().length) == 1)? '0'+(fullDate.getDate()) : (fullDate.getDate());
var currentDate = twoDigitDate + "/" + twoDigitMonth + "/" + fullDate.getFullYear();
alert(currentDate);
function createDate() {
var date = new Date(),
yr = date.getFullYear(),
month = date.getMonth()+1,
day = date.getDate(),
todayDate = yr + '-' + month + '-' + day;
console.log("Today date is :" + todayDate);
You can add an extension method to javascript.
Date.prototype.today = function () {
return ((this.getDate() < 10) ? "0" : "") + this.getDate() + "/" + (((this.getMonth() + 1) < 10) ? "0" : "") + (this.getMonth() + 1) + "/" + this.getFullYear();
}
This one-liner will give you YYYY-MM-DD:
new Date().toISOString().substr(0, 10)
'2022-06-09'
When we call getMonth() and getDate() on date object, we will get the single digit number.
For example :
For january, it displays 1, but I need to display it as 01. How to do that?
("0" + this.getDate()).slice(-2)
for the date, and similar:
("0" + (this.getMonth() + 1)).slice(-2)
for the month.
If you want a format like "YYYY-MM-DDTHH:mm:ss", then this might be quicker:
var date = new Date().toISOString().substr(0, 19);
// toISOString() will give you YYYY-MM-DDTHH:mm:ss.sssZ
Or the commonly used MySQL datetime format "YYYY-MM-DD HH:mm:ss":
var date2 = new Date().toISOString().substr(0, 19).replace('T', ' ');
Why not use padStart ?
padStart(targetLength, padString) where
targetLength is 2
padString is 0
// Source: https://stackoverflow.com/a/50769505/2965993
var dt = new Date();
year = dt.getFullYear();
month = (dt.getMonth() + 1).toString().padStart(2, "0");
day = dt.getDate().toString().padStart(2, "0");
console.log(year + '/' + month + '/' + day);
This will always return 2 digit numbers even if the month or day is less than 10.
Notes:
This will only work with Internet Explorer if the js code is transpiled using babel.
getFullYear() returns the 4 digit year and doesn't require padStart.
getMonth() returns the month from 0 to 11.
1 is added to the month before padding to keep it 1 to 12.
getDate() returns the day from 1 to 31.
The 7th day will return 07 and so we do not need to add 1 before padding the string.
Example for month:
function getMonth(date) {
var month = date.getMonth() + 1;
return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}
You can also extend Date object with such function:
Date.prototype.getMonthFormatted = function() {
var month = this.getMonth() + 1;
return month < 10 ? '0' + month : '' + month; // ('' + month) for string result
}
The best way to do this is to create your own simple formatter (as below):
getDate() returns the day of the month (from 1-31)
getMonth() returns the month (from 0-11) < zero-based, 0=January, 11=December
getFullYear() returns the year (four digits) < don't use getYear()
function formatDateToString(date){
// 01, 02, 03, ... 29, 30, 31
var dd = (date.getDate() < 10 ? '0' : '') + date.getDate();
// 01, 02, 03, ... 10, 11, 12
var MM = ((date.getMonth() + 1) < 10 ? '0' : '') + (date.getMonth() + 1);
// 1970, 1971, ... 2015, 2016, ...
var yyyy = date.getFullYear();
// create the format you want
return (dd + "-" + MM + "-" + yyyy);
}
I would do this:
var date = new Date(2000, 0, 9);
var str = new Intl.DateTimeFormat('en-US', {
month: '2-digit',
day: '2-digit',
year: 'numeric'
}).format(date);
console.log(str); // prints "01/09/2000"
The following is used to convert db2 date format
i.e YYYY-MM-DD using ternary operator
var currentDate = new Date();
var twoDigitMonth=((currentDate.getMonth()+1)>=10)? (currentDate.getMonth()+1) : '0' + (currentDate.getMonth()+1);
var twoDigitDate=((currentDate.getDate())>=10)? (currentDate.getDate()) : '0' + (currentDate.getDate());
var createdDateTo = currentDate.getFullYear() + "-" + twoDigitMonth + "-" + twoDigitDate;
alert(createdDateTo);
Just another example, almost one liner.
var date = new Date();
console.log( (date.getMonth() < 9 ? '0': '') + (date.getMonth()+1) );
function monthFormated(date) {
//If date is not passed, get current date
if(!date)
date = new Date();
month = date.getMonth();
// if month 2 digits (9+1 = 10) don't add 0 in front
return month < 9 ? "0" + (month+1) : month+1;
}
If it might spare some time I was looking to get:
YYYYMMDD
for today, and got along with:
const dateDocumentID = new Date()
.toISOString()
.substr(0, 10)
.replace(/-/g, '');
function monthFormated() {
var date = new Date(),
month = date.getMonth();
return month+1 < 10 ? ("0" + month) : month;
}
This was my solution:
function leadingZero(value) {
if (value < 10) {
return "0" + value.toString();
}
return value.toString();
}
var targetDate = new Date();
targetDate.setDate(targetDate.getDate());
var dd = targetDate.getDate();
var mm = targetDate.getMonth() + 1;
var yyyy = targetDate.getFullYear();
var dateCurrent = leadingZero(mm) + "/" + leadingZero(dd) + "/" + yyyy;
Using Moment.js it can be done like that:
moment(new Date(2017, 1, 1)).format('DD') // day
moment(new Date(2017, 1, 1)).format('MM') // month
const today = new Date().toISOString()
const fullDate = today.split('T')[0];
console.log(fullDate) //prints YYYY-MM-DD
Not an answer but here is how I get the date format I require in a variable
function setDateZero(date){
return date < 10 ? '0' + date : date;
}
var curr_date = ev.date.getDate();
var curr_month = ev.date.getMonth() + 1;
var curr_year = ev.date.getFullYear();
var thisDate = curr_year+"-"+setDateZero(curr_month)+"-"+setDateZero(curr_date);
Hope this helps!
Ternary Operator Solution
A simple ternary operator can add a "0" before the number if the month or day is less than 10 (assuming you need this information for use in a string).
let month = (date.getMonth() < 10) ? "0" + date.getMonth().toString() : date.getMonth();
let day = (date.getDate() < 10) ? "0" + date.getDate().toString() : date.getDate();
The more modern approach perhaps, using "padStart"
const now = new Date();
const day = `${now.getDate()}`.padStart(2, '0');
const month = `${now.getMonth()}`.padStart(2, '0');
const year = now.getFullYear();
then you can build as a template string if you wish:
`${day}/${month}/${year}`
Tip from MDN :
function date_locale(thisDate, locale) {
if (locale == undefined)
locale = 'fr-FR';
// set your default country above (yes, I'm french !)
// then the default format is "dd/mm/YYY"
if (thisDate == undefined) {
var d = new Date();
} else {
var d = new Date(thisDate);
}
return d.toLocaleDateString(locale);
}
var thisDate = date_locale();
var dayN = thisDate.slice(0, 2);
var monthN = thisDate.slice(3, 5);
console.log(dayN);
console.log(monthN);
http://jsfiddle.net/v4qcf5x6/
new Date().getMonth() method returns the month as a number (0-11)
You can get easily correct month number with this function.
function monthFormatted() {
var date = new Date(),
month = date.getMonth();
return month+1 < 10 ? ("0" + month) : month;
}
I would suggest you use a different library called Moment https://momentjs.com/
This way you are able to format the date directly without having to do extra work
const date = moment().format('YYYY-MM-DD')
// date: '2020-01-04'
Make sure you import moment as well to be able to use it.
yarn add moment
# to add the dependency
import moment from 'moment'
// import this at the top of the file you want to use it in
Hope this helps :D
How it easy?
new Date().toLocaleString("en-US", { day: "2-digit" })
Another options are available such:
weekday
year
month
More info here.
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleDateString#using_options
function GetDateAndTime(dt) {
var arr = new Array(dt.getDate(), dt.getMonth(), dt.getFullYear(),dt.getHours(),dt.getMinutes(),dt.getSeconds());
for(var i=0;i<arr.length;i++) {
if(arr[i].toString().length == 1) arr[i] = "0" + arr[i];
}
return arr[0] + "." + arr[1] + "." + arr[2] + " " + arr[3] + ":" + arr[4] + ":" + arr[5];
}
And another version here https://jsfiddle.net/ivos/zcLxo8oy/1/, hope to be useful.
var dt = new Date(2016,5,1); // just for the test
var separator = '.';
var strDate = (dt.getFullYear() + separator + (dt.getMonth() + 1) + separator + dt.getDate());
// end of setup
strDate = strDate.replace(/(\b\d{1}\b)/g, "0$1")
The answers here were helpful, however I need more than that: not only month, date, month, hours & seconds, for a default name.
Interestingly, though prepend of "0" was needed for all above, " + 1" was needed only for month, not others.
As example:
("0" + (d.getMonth() + 1)).slice(-2) // Note: +1 is needed
("0" + (d.getHours())).slice(-2) // Note: +1 is not needed
My solution:
function addLeadingChars(string, nrOfChars, leadingChar) {
string = string + '';
return Array(Math.max(0, (nrOfChars || 2) - string.length + 1)).join(leadingChar || '0') + string;
}
Usage:
var
date = new Date(),
month = addLeadingChars(date.getMonth() + 1),
day = addLeadingChars(date.getDate());
jsfiddle: http://jsfiddle.net/8xy4Q/1/
var net = require('net')
function zeroFill(i) {
return (i < 10 ? '0' : '') + i
}
function now () {
var d = new Date()
return d.getFullYear() + '-'
+ zeroFill(d.getMonth() + 1) + '-'
+ zeroFill(d.getDate()) + ' '
+ zeroFill(d.getHours()) + ':'
+ zeroFill(d.getMinutes())
}
var server = net.createServer(function (socket) {
socket.end(now() + '\n')
})
server.listen(Number(process.argv[2]))
if u want getDate() function to return the date as 01 instead of 1, here is the code for it....
Lets assume Today's date is 01-11-2018
var today = new Date();
today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + today.getDate();
console.log(today); //Output: 2018-11-1
today = today.getFullYear()+ "-" + (today.getMonth() + 1) + "-" + ((today.getDate() < 10 ? '0' : '') + today.getDate());
console.log(today); //Output: 2018-11-01
I wanted to do something like this and this is what i did
p.s. i know there are right answer(s) on top, but just wanted to add something of my own here
const todayIs = async () =>{
const now = new Date();
var today = now.getFullYear()+'-';
if(now.getMonth() < 10)
today += '0'+now.getMonth()+'-';
else
today += now.getMonth()+'-';
if(now.getDay() < 10)
today += '0'+now.getDay();
else
today += now.getDay();
return today;
}
If you'll check smaller than 10, you haven't to create a new function for that. Just assign a variable into brackets and return it with ternary operator.
(m = new Date().getMonth() + 1) < 10 ? `0${m}` : `${m}`
currentDate(){
var today = new Date();
var dateTime = today.getFullYear()+'-'+
((today.getMonth()+1)<10?("0"+(today.getMonth()+1)):(today.getMonth()+1))+'-'+
(today.getDate()<10?("0"+today.getDate()):today.getDate())+'T'+
(today.getHours()<10?("0"+today.getHours()):today.getHours())+ ":" +
(today.getMinutes()<10?("0"+today.getMinutes()):today.getMinutes())+ ":" +
(today.getSeconds()<10?("0"+today.getSeconds()):today.getSeconds());
return dateTime;
},