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Tried to get data from a form and append it to a global array, but for some reason the data isn't being added

I am trying to get data from a form and append it to a global array but for some reason, the data isn't being added to the array. The code should basically accept the input from the form and store it into the global array. I updated the HTML so you can see the entire syntax. The value should basically be taken from the form and placed into the global array using the "addnew" function.
function addnew()
{
//calculateAge();
//Accept values entered in form
const fname = document.getElementById('fname').value;
const mname = document.getElementById('mname').value;
const lname= document.getElementById('lname').value;
const dob= document.getElementById('dob').value;
const genderM = document.getElementsByName('male').checked;
const genderF = document.getElementsByName('female').checked;
const age = calculateAge.bYear;
const bodyType = document.getElementById('Body Type').value;
const occu= document.getElementById('occu').value;
const height= document.getElementById('height').value;
if (fname==null || fname=="")
{
alert();
}
if(mname==null || mname=="")
{
alert();
}
if (lname==null || lname=="")
{
alert();
}
if(dob==null || dob=="")
{
alert();
}
if (genderM.checked == false || genderF.checked == false){
alert();
}
if (age <=18 || age >=75)
{
alert();
}
if(height>=170 || height<=200)
{
alert();
}
if(bodyType==null || bodyType==""){
alert();
}
if(oocu==null || oocu=="")
{
alert();
}
//Append To array
records.push(fname);
records.push(mname);
records.push(lname);
records.push(dob);
records.push(genderM);
records.push(genderF);
records.push(age);
records.push(bodyType);
records.push(occu);
records.push(height);
for(i=0;i<records.length;i++)
{
console.log(records[i]);
}
//showAll();
//<h1 class="logo"><img src="New folder/logo.jpg" /></h1>
Information.addEventListener('submit', addnew);
}
</script>
```

first of all. name attribute has nothing to do with form element.
second. Information.addEventListener('submit', addnew); has no meaning because Information is not defined.
and to the core. when submiing a form, the page refreshes defaultly, so the addNew function is aborted like all the other variables. in order to prevent it you have to do as follows.
on submit button ad an id attribute:
<button id="submit" type="submit"> Submit </button>
then on top of your JS, get the button element and add an event listener to it:
let submit = document.getElementById('submit');
submit.addEventListener('click', addnew );
and here is the final step. on the addNew function, add an event argument. and on the begining of the function's code, fire the preventDefault method:
function addnew(event) {
event.preventDefault();
// the rest of the code here
}
by the way. you have a typo here. it should be occu.
if (oocu == null || oocu == "") {
alert();
}
good luck!

Onclick and jQuery click working together but return false not working in jquery

Onclick and jQuery click working together but return false not working in jquery. I want to validate fields before on onclick open next page. Problem with my code is that if filed are blank in that case it open next page. I use return false in each empty case. So until all fields are not filled up. next page should not open.
Html Code
<button id="onepage-guest-register-button" type="button" class="button secondary" onclick="$('login:guest').checked=true; checkout.setMethod();"><span><span><?php //echo $this->__('Checkout as Guest') ?></span></span></button>
jQuery Code
jQuery('#onepage-guest-register-button').click(function(e){
var email=jQuery('#login-email').val();
jQuery('.validate-email').attr('value', email);
var login_name = jQuery('#login_name').val();
var login_phone = jQuery('#login_phone').val();
var login_email = jQuery('#login_email').val();
alert("name"+login_name+'phone'+login_phone+'email'+login_email);
if(login_name==''){ jQuery('.login_name').text('Please enter full name'); return false; }else{ jQuery('.login_name').empty();}
if(login_phone==''){ jQuery('.login_phone').text('Please enter Phone Number');return false;}else{ jQuery('.login_phone').empty();}
if(login_email==''){ jQuery('.login_email').text('Please enter Phone email');return false;}else{ jQuery('.login_email').empty();}
//alert('trigger');
jQuery('#onepage-guest-register-button').trigger('onclick');
});

Don't mix onclick attribute with onclick event handler. It's just plain silly.
In most cases, it's better to go with the latter.
1) Remove onclick attribute
<button id="onepage-guest-register-button" type="button" class="button secondary"><span><span><?php echo $this->__('Continue') ?></span></span></button>
2) Move the logic into your onclick event handler.
jQuery('#onepage-guest-register-button').click(function(e){
// no idea
var email = jQuery('#login-email').val();
jQuery('.validate-email').attr('value', email);
// get values
var login_name = jQuery('#login_name').val();
var login_phone = jQuery('#login_phone').val();
var login_email = jQuery('#login_email').val();
// flag if errors is found; assume no errors by default
var err = false;
// clear errors?
jQuery('.login_name').empty();
jQuery('.login_phone').empty();
jQuery('.login_email').empty();
// show errors if any
if (login_name == '') {
jQuery('.login_name').text('Please enter full name');
err = true;
}
if (login_phone == ''){
jQuery('.login_phone').text('Please enter Phone Number');
err = true;
}
if (login_email == ''){
jQuery('.login_email').text('Please enter Phone email');
err = true;
}
// do the appropriate action depending if there are errors or not
if (err) {
return false;
} else {
$('login:guest').prop('checked', true);
checkout.setMethod();
}
});

Stop postback after alert by javascript in ASP.NET Code

I have a textbox and a button, on button's clientClick I call javascript function and there is also server side coding.
Problem is, the page gets post back even if I have return False in the javascript.
Here is my javascript function:
function checkALphaNumericFormat(str) {
//get previous value before editing
var txtUserId = document.getElementById('<%=txtUserId.ClientID%>');
var userId = txtUserId.value;
var patternAlphaNumeric = /^[A-z0-9]+$/gi;
var match = userId.match(patternAlphaNumeric);
//Check Null values
if (txtUserId.value != null && txtUserId.value != "") {
//Check for AlphaNumeric values for User Id
if (match == null) {
alert("Please provide valid AlphaNumeric User Id");
return false ;
}
return false ;
}
else {
alert("User Id field should not be null");
return false ;
}
return false ;
}
and I am calling this function on my Form as:
<asp:Button runat="server" ID="btnCreate" CssClass="loginButton" style="margin:0px 0px 1px 30px;" OnClientClick ="return checkALphaNumericFormat(this.value);" Text="CREATE" />

Try to call JavaScript function as below:
OnClientClick="if(!validateform()){return false;}
where validateform() should be your java script function. Your java script function should have return = true; at the end of function in successfull execution, like in below function:
function validateform()
{
var txtSearch = document.getElementById('<%=txtKeywordSearch.ClientID%>')
if(txtSearch.value == '')
{
alert('No Search Creatria Selected!');
return false;
}
return true;
}
Please try and let me know if it works for you.
Thanks,
Harish

JQuery Validation for Two Password Fields

Two entered passwords should be the same, and I want to display a notification when they're not matching. The target is to display the notification during typing and not after pressing the save Button.
I am new to javascript and I have also tried the functionname function() notation.
following js:
function updateError (error) {
if (error == true) {
$(".error").hide(500);
}else{
$(".error").show(500);
}
};
function checkSame() {
var passwordVal = $("input[name=password-check]").val();
var checkVal = $("input[name=password]").val();
if (passwordVal == checkVal) {
return true;
}
return false;
};
document.ready(function(){
$("input[name=password-check]").keyup(function(){updateError(checkSame());});
$("input[name=password]").keyup(function(){updateError(checkSame());});
});
and HTML:
#Html.Password("password")
#Html.Password("password-check")
<span class="error">Errortext</span> </td></tr>
but it doesn't works..
Thx!
Edit:
Now i've changed the JS code to:
$("input[name=password-check]").keyup(function(){updateError(checkSame());});
$("input[name=password]").keyup(function(){updateError(checkSame());});
--> now it works, but only once, after the user typed a matching password, validation stops working
Solved, problem was Quoting:
$("input[name='password-check']").keyup(function(){updateError(checkSame());});
$("input[name='password']").keyup(function(){updateError(checkSame());});

You are doing opposite
if (error == true) {
    $(".error").show(500);
}else{
 $(".error").hide(500);
}
Edit as per comment :
Try placing name within quotes like
$("input[name='password-check']").keyup(function(){updateError(checkSame());});
$("input[name='password']").keyup(function(){updateError(checkSame());});

In the checkSame, you may want to use indexOf to check if passwordVal contains checkVal since when typing, the password is not equal yet.
if (passwordVal.indexOf(checkVal)>-1 || checkVal.indexOf(passwordVal)>-1 ) {
return true;
}

As int2000 said, fire the checkSame on keyup seems weird, but if it's what you want, OK.
Try to change your checkSame function as follows:
function checkSame() {
var passwordVal = $("input[name=password-check]").val();
var checkVal = $("input[name=password]").val();
if (passwordVal == checkVal) {
return false;
}
return true;
};
Remember that you're passing the result of checkSame to updateError, so if the passwords are the same you have no error.

Javascript form validation

I'm trying to have two functions checking each form input, one for onchange() and the other for onkeypress(); my reason for this would be to show if the input was valid once you leave the input field using onchange() or onblur(), and the I also wanted to check if the input field was ever empty, to remove the message indicating that bad input was entered using onkeypress() so that it would update without having to leave the field (if the user were to delete what they had in response to the warning message.)
It simply isn't working the way I intended, so I was wondering if there was something obviously wrong.
My code looks like this:
<form action="database.php" method = post>
Username
<input type='text' id='un' onchange="checkname()" onkeypress="checkempty(id)" />
<div id="name"></div><br>
.....
</form>
And the Javascript:
<script type="text/javascript">
function checkname() {
var name = document.getElementById("un").value;
var pattern = /^[A-Z][A-Za-z0-9]{3,19}$/;
if (name.search(pattern) == -1) {
document.getElementById("name").innerHTML = "wrong";
}
else {
document.getElementById("name").innerHTML = "right!";
}
}
function checkempty(id) {
var temp = document.getElementById(id).value;
if (!temp) {
document.getElementById("name").innerHTML = '';
}
}
</script>

Per your clarification in the comments, I would suggest using the onkeyup event instead of onkeypress (onkeypress only tracks keys that generate characters - backspace does not). Switching events will allow you to validate when the user presses backspace.
Here's a working fiddle.
Edit:
See this SO question for further clarification: Why doesn't keypress handle the delete key and the backspace key

This function should below should check for empty field;
function checkempty(id) {
var temp = document.getElementById(id).value;
if(temp === '' || temp.length ===0){
alert('The field is empty');
return;
}
}
//This should work for check name function
function checkname() {
var name = document.getElementById("un").value;
var pattern = /^[A-Z][A-Za-z0-9]{3,19}$/;
if (!name.test(pattern)) {
document.getElementById("name").innerHTML = "wrong";
}
else {
document.getElementById("name").innerHTML = "right!";
}
}