Trying to pass POST from JavaScript to PHP - javascript

For a few days now I have been trying to pass a simple POST call to a php script from JavaScript. I've done countless amounts of searching online without any positive results.
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
function successHandler(location) {
var dataString = '?lat=' + location.coords.latitude + '&long=' + location.coords.longitude + '&accuracy=' + location.coords.accuracy;
alert(dataString);
if (location.coords.latitude == '0') {
} else {
alert("AJAX made");
$.ajax({
type: "POST",
url: "updatepos.php",
data: dataString,
cache: false,
success: function(html) {
alert(html);
}
});
setTimeout(navigator.geolocation.getCurrentPosition(successHandler),15000);
}
}
function getLocation() {
navigator.geolocation.getCurrentPosition(successHandler);
}
getLocation();
</script>
Above is my JavaScript file. The datastring gets made, and it alerts it out to my browser. No problem there. The problem is, my variables don't get passed to PHP whatsoever.
Here is the PHP that is in the same directory as the JavaScript.
<?php
include 'wp-load.php';
/*global $current_user;
get_currentuserinfo();
echo $current_user->user_login;*/
include('dbconnect.php');
global $current_user;
get_currentuserinfo();
$lat = $_POST['lat'];
$long = $_POST['long'];
$accuracy = $_POST['accuracy'];
/*$lat = $_GET['lat'];
$long = $_GET['long'];
$accuracy = $_GET['accuracy'];*/
$query = "UPDATE ltc_users SET lat='$lat',accuracy=$accuracy,lon='$long' WHERE name='$current_user->user_login'";
mysqli_query($GLOBALS['DB'],$query);
echo mysqli_error($GLOBALS['DB']);
echo $lat;
echo $long;
echo $accuracy;
echo $current_user->user_login;
?>
I may note that before the script would return mysql syntax errors as it was echoed in php due to missing variables. The syntax works if I use the $_GET method and just type in the data into my browser address bar for testing. It just doesn't get the JavaScript variables for whatever reason.

You're passing a string to jquery. When you do that, the string is sent out as-is by jquery. Since it's just a bare string, and not a key:value pair, there's no key for PHP to glom onto and populate $_POST with.
In fact, you shouldn't ever have to manually build a string of key:value pairs for ajax - jquery will take an array/object and do it all for you:
var stuff = {
lat : location.coords.latitude,
long : location.coords.longitude,
accuracy : location.coords.accuracy
}
$.ajax({
data: stuff
});

Here is your code combined with #Marc B
<script src = "http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js" > </script>
<script type="text/javascript">
function successHandler(location) {
if (location.coords.latitude == '0') {
} else {
alert("AJAX made ");
$.ajax({
type: "POST",
url: "updatepos.php",
data: {
"lat":location.coords.latitude,
"long":location.coords.longitude,
"accuracy":location.coords.accuracy
},
dataType: "json",
async:true,
cache: false,
success: function(html) {
alert(html);
},error: function(a,b,c){
console.log(a.responseText);
}
});
setTimeout(function(){navigator.geolocation.getCurrentPosition(successHandler);},15000);
}
}
function getLocation() {
navigator.geolocation.getCurrentPosition(successHandler);
}
$(function(){
getLocation();
});
</script>
code in jsfiddle http://jsfiddle.net/y7f1vkej/ it seems to be working for me

Related

Unable to send multiple data parameters with jQuery AJAX

I am trying to send values to other page Using Ajax
But i am unable to receive those values , i don't know where i am wrong
here is my code
<script type="text/javascript">
function get_more_info() { // Call to ajax function
var fval = document.getElementById('get_usecompny').value;
var dataString1 = "fval="+fval;
alert(fval);
var sval = document.getElementById('country').value;
var dataString2 = "sval="+sval;
alert(sval);
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: "{'data1':'" + dataString1+ "', 'data2':'" + dataString2+ "'}",
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
in alert i am getting those value but in page 'getmoreinfo.php' i am not receiving any values
here is my 'getmoreinfo.php' page code
if ($_POST) {
$country = $_POST['fval'];
$country1 = $_POST['sval'];
echo $country1;
echo "<br>";
echo $country;
}
Please let me know where i am wrong .! sorry for bad English
You are passing the parameters with different names than you are attempting to read them with.
Your data: parameter could be done much more simply as below
<script type="text/javascript">
function get_more_info() { // Call to ajax function
var fval = document.getElementById('get_usecompny').value;
var sval = document.getElementById('country').value;
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: {fval: fval, sval: sval},
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
Or cut out the intermediary variables as well and use the jquery method of getting data from an element with an id like this.
<script type="text/javascript">
function get_more_info() { // Call to ajax function
$.ajax({
type: "POST",
url: "getmoreinfo.php", // Name of the php files
data: { fval: $("#get_usecompny").val(),
sval: $("#country").val()
},
success: function(html)
{
$("#get_more_info_dt").html(html);
}
});
}
</script>
No need to create 'dataString' variables. You can present data as an object:
$.ajax({
...
data: {
'fval': fval,
'sval': sval
},
...
});
In your PHP, you can then access the data like this:
$country = $_POST['fval'];
$country1 = $_POST['sval'];
The property "data" from JQuery ajax object need to be a simple object data. JQuery will automatically parse object as parameters on request:
$.ajax({
type: "POST",
url: "getmoreinfo.php",
data: {
fval: document.getElementById('get_usecompny').value,
sval: document.getElementById('country').value
},
success: function(html) {
$("#get_more_info_dt").html(html);
}
});

How to avoid 500 Internal Server Error if a JS session variable null

I created this script to read from various web sources. This script updates all notifications (mail, post, friends) and their own drop-down window's details and also two side update bars together. I used this script in my top manu.php page.
This script is working well for login user.
Now I pass a session id variable with JavaScript var uid = '<? echo $session->id; ?>'; So when a user is not logged in, my browser console displays 500 Internal Server Error because here the session has no ID so it passes uid= ''
How do I overcome this problem?
Here is my JavaScript script:
var uid = '<? echo $session->id; ?>';
function addmailno(type, msg){
//Do something for display mail/friend/post notification
}
function addmailup(type, msg){
//Do something for display mail/post/friend drop-down.
}
function addside(type, msg){
//Do something for display all friend/new post in side bar.
}
function waitFormailno(){
$.ajax({
type: "GET",
url: "serverforupandside.php",
cache: false,
async : false,
dataType : 'json',
data: "uid="+ uid,
timeout:15000,
success: function(data){
addmailno("MyDivClass", data);
addmailup("MyDivClass", data);
addside("MyDivId", data);
setTimeout(waitFormailno, 15000);
},
error: function(){
setTimeout(waitFormailno, 15000);
}
});
}
$(document).ready(function(){
waitFormailno();
});
serverforupandside.php
<?php
include("db.php");
include_once("mysession.php");
while (true) {
if($_GET['uid']){
global $dbh;
//All php query is here one after one
//Output is here by data
$data = array();
$data['upmail'] = $upmail;
$data['upfollow'] = $upfollow;
$data['uppost'] = $uppost;
// etc all
if (!empty($data)) {
echo json_encode($data);
flush();
mysqli_close($dbh);
}
}
mysqli_close($dbh);
}
?>
Your Javascript code should be modified to:
function waitFormailno(){
$.ajax({
type: "GET",
url: "serverforupandside.php",
cache: false,
async : false,
dataType : 'json',
data: "uid="+ uid,
timeout:15000,
success: function(data){
addmailno("MyDivClass", data);
addmailup("MyDivClass", data);
addside("MyDivId", data);
}
});
}
$(document).ready(function(){
setInterval(waitFormailno, 15000); // calls a function or evaluates an expression at specified intervals (in milliseconds)
});
PHP Code:
<?php
include("db.php");
include_once("mysession.php");
if (!empty($_GET['uid'])) {
global $dbh;
//All php query is here one after one
//Output is here by data
$data = array();
$data['upmail'] = $upmail;
$data['upfollow'] = $upfollow;
$data['uppost'] = $uppost;
// etc all
if (!empty($data)) {
echo json_encode($data);
}
}
Also, you should add validations before filling $data array.

Using ajax to call php and return multiple variables?

I am trying to use javascript to call a php script which then will return multiple variables back to my javascript so I can manipulate them.
This is my JS.
$.ajax({
url: 'test.php',
data: { id : lastFileId },
success: function(output) {
alert(output);
}
});
my PHP
<?php
$fileId = ($_GET['id']);
$num1 = 1;
$num2 = 2;
?>
From here, how can I return variables $num1 and $num2 so i can use them in my javascript. Is it possible?
also this is a very basic idea of what I have planned to do if I can achieve this.
You can return as many variables as you want with json_encode().
Try in your PHP:
<?php
echo json_encode(array($num1, $num2));
?>
You can add to that array , $num3, $num4, ... and so on.
In your JS, you can access each number as follows.
First, you will need this line of code to parse the encoded JSON string, in your success function.
var result = $.parseJSON(output);
That sets result as a JSON object. Now you can access all fields within result:
result[0] -- $num1 in PHP
result[1] -- $num2 in PHP
You can go for Json in PHP and javascript if you want array in response for a ajax request
PHP Code
<?php
$fileId = isset($_GET['id'])?$_GET['id']:0;
echo json_encode(array("field"=>$fileId,"num1"=>1,"num2"=>2));
?>
Js Code
jQuery.ajax({
type: "GET",
url: 'test.php',
dataType: "json",
success: function(response) {
console.log(response);
alert(response.num1);
}
});
convert json to object
jQuery.ajax({
type: "GET",
url: 'test.php',
dataType: "json",
success: function(response) {
item=JSON.parse(response);
console.log(item);
alert(item.num1);
}
});
Use a simply string and explode(split) it further in ajax response. Here is PHP code
<?php
$fileId = ($_GET['id']);
echo $num1."|".$num2;
?>
Now split(explode) the response with JavaScript
$.ajax({
url: 'test.php',
data: { id : lastFileId },
success: function(output) {
var my_arr = output.split("|");
console.log(my_arr[0] + "" + my_arr[1]);
}
});
you can simply return it like that
return ['num1'=>$num1,'num2' => $num2];
and also, you can access it as followed,
respone.num1

json import breaks down but from same server source

I am exploring the ajax synchronous json import into my javascript code.
The JSON source link I want to use is
http://www.nusantech.com/hendak/default.php?m=galaksi&galaksi=1&viewID=1&t=json
But to keep server loads down, a week ago or so I created a static page showing the same data at
http://www.nusantech.com/hendak/noobjson.php
My javascript import is as below:
<head>
<title>Nusantech</title>
<script src="\OpenLayers213\OpenLayers.js"></script>
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<script type="text/javascript">
var jsonData = {};
$.ajax({
url: "http://hendak.seribudaya.com/noobjson.php",
async: false,
dataType: 'json',
success: function(data) {
jsonData = data;
}
});
alert("Galaksi value retrieved from JSON (expected: 1) : "+jsonData.galaksi);
</script>
<script type="text/javascript">
function kemasMaklumat(id,content) {
var container = document.getElementById(id);
container.innerHTML = content;
}
</script>
</head>
From there I retrieve the values I want on jsonData, eg, (x,y) coordinates as
(jsonData.planets[7].coordinates[0].x,jsonData.planets[7].coordinates[0].y)
It works fine with the noobjson.php link, but when I point it back to default.php, nothing appears. The page took a while to load which make it seem like its loading the json values, but the alert("Galaksi value retrieved") returns undefined.
I copy & pasted the output from the default.php page on a JSON verifier on the web and it showed OK. I don't know why the static link works but the $_GET based link doesn't.
Can someone suggest me what is happening?
EDIT
I have tried:
<script type="text/javascript">
var jsonData = {};
$.ajax({
// url: "http://hendak.seribudaya.com/noobjson.php",
url: "http://hendak.seribudaya.com/default.php?"+encodeURIComponent("galaksi=1&viewID=1&m=galaksi&t=json"),
// url: "http://hendak.seribudaya.com/default.php?galaksi=1&viewID=1&m=galaksi&t=json",
async: false,
dataType: 'json',
type: 'GET',
contentType: "application/json",
success: function(data) {
jsonData = JSON.parse(JSON.stringify(eval("("+data+")")));
alert("Success");
},
error: function(data) {
alert("Failed to download info." + data);
}
});
</SCRIPT>
enter code here
I always get the Failed to download info unless I use the noobjson URL.
It is as if that URL with the GET doesn't exist.
You have to encode the URL component before sending the request. Try:
$.ajax({
url: "http://www.nusantech.com/hendak/default.php?" + encodeURIComponent('m=galaksi&galaksi=1&viewID=1&t=json'),
async: false,
dataType: 'json',
success: function(data) {
jsonData = data;
}
});
Reference: encodeURIComponent()
I have solved it.
In the default.php, what I have done was:
if ($_GET["t"]=="json") {
$viewID=$_GET["viewID"];
$galaksi=$_GET["galaksi"];
$con=mysqli_connect($server, $user, $password, $database);
$sql="SELECT Hari FROM berita WHERE Galaksi=".$galaksi;
$hari=1;
$result = mysqli_query($con,$sql); while(($row = mysqli_fetch_array($result)) ){$hari=$row['Hari']; }
$lb="";
if ($_GET["t"]!="json") { echo "<PRE>\n"; $lb="\n"; }
echo "{\"galaksi\": ".$galaksi.",";
echo $lb."\"hari\": ".$hari.",";
echo $lb."\"planets\": [";
//etc
//etc
}
So I replaced all the individual echoes with $JSONstr like below.
if ($_GET["t"]=="json") {
$viewID=$_GET["viewID"];
$galaksi=$_GET["galaksi"];
$con=mysqli_connect($server, $user, $password, $database);
$sql="SELECT Hari FROM berita WHERE Galaksi=".$galaksi;
$hari=1;
$result = mysqli_query($con,$sql); while(($row = mysqli_fetch_array($result)) ){$hari=$row['Hari']; }
$lb="";
$JSONstr="";
// if ($_GET["t"]!="json") { $JSONstr="<PRE>\n"; $lb="\n"; }
$JSONstr=$JSONstr."{\"galaksi\": ".$galaksi.",";
$JSONstr=$JSONstr.$lb."\"hari\": ".$hari.",";
$JSONstr=$JSONstr.$lb."\"planets\": [";
//etc
//etc
//and at the end:
echo $JSONstr;
}
Then I added the echo $JSONstr; at the end. Originally I did that so that I can do :
echo json_encode($JSONstr);
but this creates {\"Galaksi\" : 1} at the JSON output instead of the intended { "Galaksi": 1 }
So I removed the json_encode and just output the string.
Also I had to remove the
if ($_GET["t"]!="json"){ $JSONstr="<PRE>\n"; $lb="\n"; }
I also used a different JSON tester this time.
Originally I used http://www.freeformatter.com/json-validator.html which says JSON Valid for my initial JSON output. Then I used this one, which said that my JSON output url was invalid, although if I copy+paste the output string it returned valid. http://jsonformatter.curiousconcept.com/
So after making those changes and removing the "<PRE>", the curiousconcept validator gave me a valid status.
Then I used this in the javascript, and I am now able to retrieve expected values.
Thank you all, hope this helps someone else too.

mysql query executed even though fields are empty

I have created a simple tagging system for my schools websites for the students. Now the tagging system is working perfectly now i also have to save tags in a notifications table with respective article id to later notify the students which article they have been tagged in even that i managed to do. But now if by chance you want to remove the tags sometime realizing while typing the article you don't need to tag that person, then the first put tag also gets updated in the db.
//ajax code (attach.php)
<?php
include('config.php');
if(isset($_POST))
{
$u=$_POST['v'];
mysql_query("INSERT INTO `notify` (`not_e`) VALUES ('$u')");
}
?>
// tagsystem js code
<script type="text/javascript">
var id = '<?php echo $id ?>';
$(document).ready(function()
{
var start=/%/ig;
var word=/%(\w+)/ig;
$("#story").live("keyup",function()
{
var content=$(this).text();
var go= content.match(start);
var name= content.match(word);
var dataString = 'searchword='+ name;
if(go.length>0)
{
$("#msgbox").slideDown('show');
$("#display").slideUp('show');
$("#msgbox").html("Type the name of someone or something...");
if(name.length>0)
{
$.ajax({
type: "POST",
url: "boxsearch.php",
data: dataString,
cache: false,
success: function(html)
{
$("#msgbox").hide();
$("#display").html(html).show();
}
});
}
}
return false();
});
$(".addname").live("click",function()
{
var username=$(this).attr('title');
$.ajax({
type: "POST",
url: "attach.php",
data: {'v': username},
});
var old=$("#story").html();
var content=old.replace(word,"");
$("#story").html(content);
var E="<a class='blue' contenteditable='false' href='profile2.php?id="+username+"'>"+username+"</a>";
$("#story").append(E);
$("#display").hide();
$("#msgbox").hide();
$("#story").focus();
});
});
</script>
Looks like your problem appears on the if statement in php code:
even though $_POST['v'] is empty and the sql still get excuted.
There is the quote from another thread:
"
Use !empty instead of isset. isset return true for $_POST because $_POST array is superglobal and always exists (set).
Or better use $_SERVER['REQUEST_METHOD'] == 'POST'
"
Or in my opinion.
Just put
if ($_POST['v']){
//sql query
}
Hope it helps;)
<?php
include('config.php');
$u = $_POST["v"];
//echo $a;
if($u != '')
{
mysql_query("your insert query");
}
else
{
}
?>

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