I want modify my regular expression to also remove # size but select only that word those are start with # sign.
Following is my code, View Live
JS
var a = "#abc #jat hi pat #jkl abc #cde vcd #cde ";
var s = a.match(/(?=(\s{1}?#[^\s]+)|(\s?))(#[^\s]+)(?=(\s))/g);
console.log(s);
Result
["#abc", "#jat", "#jkl", "#cde", "#cde"]
Expected Result
["abc", "jat", "jkl", "cde", "cde"]
Since JavaScript doesn't have look-behind, I don't think you can do it in a single match statement (without post-processing), because you'll want a capture group.
The post-processing is trivial with ES5's Array#map (which can be shimmed), of course:
var s = a.match(/(?=(\s{1}?#[^\s]+)|(\s?))(#[^\s]+)(?=(\s))/g).map(function(entry) {
return entry.substring(1);
});
Otherwise, you'll want to use a capture group and an exec loop.
BTW, I think the regular expression can be a lot simpler, if all you want is \s separation:
var a = "#abc #jat hi pat #jkl abc #cde vcd #cde ";
var s = a.match(/#\S+/g).map(function(entry) {
return entry.substring(1);
});
display(s.join(", "));
function display(msg) {
document.body.insertAdjacentHTML(
"beforeend",
"<p>" + msg + "</p>"
);
}
Unless there's some compelling reason you need to write a single regexp for this, you're much better off just doing some standard splitting and filtering.
a.split(/\s+/)
.filter(function(seg) { return seg[0]==='#'; })
.map (function(seg) { return seg.slice(1); })
It doesn't look so bad if you can use arrow functions:
a.split(/\s+/)
.filter(seg => seg[0]==='#')
.map (seg => seg.slice(1))
Related
As a follow up to this question (not by me), I need to replace leading numbers of an id with \\3n (where n is the number we're replacing).
Some examples:
"1foo" -> "\\31foo"
"1foo1" -> "\\31foo1"
"12foo" -> "\\31\\32foo"
"12fo3o4" -> "\\31\\32fo3o4"
"foo123" -> "foo123"
Below is a solution that replaces every instance of the number, but I don't know enough regex to make it stop once it hits a non-number.
function magic (str) {
return str.replace(/([0-9])/g, "\\3$1");
}
... Or is regex a bad way to go? I guess it would be easy enough to do it, just looping over each character of the string manually.
Here is a way to achieve what you need using a reverse string + look-ahead approach:
function revStr(str) {
return str.split('').reverse().join('');
}
var s = "12fo3o4";
document.write(revStr(revStr(s).replace(/\d(?=\d*$)/g, function (m) {
return m + "3\\\\";
}))
);
The regex is matching a number that can be followed by 0 or more numbers only until the end (which is actually start) of a reversed string (with \d(?=\d*$)). The callback allows to manipulate the match (we just add reversed \\ and 3. Then, we just reverse the result.
Just use two steps: first find the prefix, then operate on its characters:
s.replace(/^\d+/, function (m) {
return [].map.call(m, function (c) {
return '\\3' + c;
}).join('');
});
No need to emulate any features.
Here is how I would have done it:
function replace(str) {
var re = /^([\d]*)/;
var match = str.match(re)[0];
var replaced = match.replace(/([\d])/g, "\\3$1");
str = str.replace(match, replaced);
return str;
}
document.write(replace("12fo3o4"));
Don't get me wrong: the other answers are fine! My focus was more on readability.
How can I convert PascalCase string into underscore_case/snake_case string? I need to convert dots into underscores as well.
eg. convert
TypeOfData.AlphaBeta
into
type_of_data_alpha_beta
You could try the below steps.
Capture all the uppercase letters and also match the preceding optional dot character.
Then convert the captured uppercase letters to lowercase and then return back to replace function with an _ as preceding character. This will be achieved by using anonymous function in the replacement part.
This would replace the starting uppercase letter to _ + lowercase_letter.
Finally removing the starting underscore will give you the desired output.
var s = 'TypeOfData.AlphaBeta';
console.log(s.replace(/(?:^|\.?)([A-Z])/g, function (x,y){return "_" + y.toLowerCase()}).replace(/^_/, ""));
OR
var s = 'TypeOfData.AlphaBeta';
alert(s.replace(/\.?([A-Z])/g, function (x,y){return "_" + y.toLowerCase()}).replace(/^_/, ""));
any way to stop it for when a whole word is in uppercase. eg. MotorRPM into motor_rpm instead of motor_r_p_m? or BatteryAAA into battery_aaa instead of battery_a_a_a?
var s = 'MotorRMP';
alert(s.replace(/\.?([A-Z]+)/g, function (x,y){return "_" + y.toLowerCase()}).replace(/^_/, ""));
str.split(/\.?(?=[A-Z])/).join('_').toLowerCase();
u're welcome
var s1 = 'someTextHere';
var s2 = 'SomeTextHere';
var s3 = 'TypeOfData.AlphaBeta';
var o1 = s1.split(/\.?(?=[A-Z])/).join('_').toLowerCase();
var o2 = s2.split(/\.?(?=[A-Z])/).join('_').toLowerCase();
var o3 = s3.split(/\.?(?=[A-Z])/).join('_').toLowerCase();
console.log(o1);
console.log(o2);
console.log(o3);
Alternatively using lodash:
lodash.snakeCase(str);
Example:
_.snakeCase('TypeOfData.AlphaBeta');
// ➜ 'type_of_data_alpha_beta'
Lodash is a fine library to give shortcut to many everyday js tasks.There are many other similar string manipulation functions such as camelCase, kebabCase etc.
This solution solves the non-trailing acronym issue with the solutions above
I ported the code in 1175208 from Python to JavaScript.
Javascript Code
function camelToSnakeCase(text) {
return text.replace(/(.)([A-Z][a-z]+)/, '$1_$2').replace(/([a-z0-9])([A-Z])/, '$1_$2').toLowerCase()
}
Working Examples:
camelToSnakeCase('thisISDifficult') -> this_is_difficult
camelToSnakeCase('thisISNT') -> this_isnt
camelToSnakeCase('somethingEasyLikeThis') -> something_easy_like_this
"alphaBetaGama".replace(/([A-Z])/g, "_$1").toLowerCase() // alpha_beta_gamma
Problem - Need to convert a camel-case string ( such as a property name ) into underscore style to meet interface requirements or for meta-programming.
Explanation
This line uses a feature of regular expressions where it can return a matched result ( first pair of () is $1, second is $2, etc ).
Each match in the string is converted to have an underscore ahead of it with _$1 string provided. At that point the string looks like alpha_Beta_Gamma.
To correct the capitalization, the entire string is converted toLowerCase().
Since toLowerCase is a fairly expensive operation, its best not to put it in the looping handler for each match-case, and run it once on the entire string.
After toLowerCase it the resulting string is alpha_beta_gamma ( in this example )
This will get you pretty far: https://github.com/domchristie/humps
You will probably have to use regex replace to replace the "." with an underscore.
I found this but I edited it so suit your question.
const camelToSnakeCase = str => str.replace(/[A-Z]/g, letter => `_${letter.toLowerCase()}`).replace(/^_/,'')
Good examples for js:
Snake Case
Kebab Case
Camel Case
Pascal Case
have here
function toCamelCase(s) {
// remove all characters that should not be in a variable name
// as well underscores an numbers from the beginning of the string
s = s.replace(/([^a-zA-Z0-9_\- ])|^[_0-9]+/g, "").trim().toLowerCase();
// uppercase letters preceeded by a hyphen or a space
s = s.replace(/([ -]+)([a-zA-Z0-9])/g, function(a,b,c) {
return c.toUpperCase();
});
// uppercase letters following numbers
s = s.replace(/([0-9]+)([a-zA-Z])/g, function(a,b,c) {
return b + c.toUpperCase();
});
return s;
}
Try this function, hope it helps.
"TestString".replace(/[A-Z]/g, val => "_" + val.toLowerCase()).replace(/^_/,"")
replaces all uppercase with an underscore and lowercase, then removes the leading underscore.
A Non-Regex Answer that converts PascalCase to snake_case
Note: I understand there are tons of good answers which solve this question elegantly. I was recently working on something similar to this where I chose not to use regex. So I felt to answer a non-regex solution to this.
const toSnakeCase = (str) => {
return str.slice(0,1).toLowerCase() + str.split('').slice(1).map((char) => {
if (char == char.toUpperCase()) return '_' + char.toLowerCase();
else return char;
}).join('');
}
Eg.
inputString = "ILoveJavascript" passed onto toSnakeCase()
would become "i_love_javascript"
I have a forum and I would like to automatically parse some of the major links. For example, if a user makes a post like this:
You should visit StackOverflow. I found it on Wikipedia.
it would automatically parse it like this:
You should visit StackOverflow. I found it on Wikipedia.
Is this even doable using JavaScript only?
Thanks for assistance. :-)
What you want to create a clean and extensible code is create a library of word => link then you can iterate over that and do your replace inside your code.
Here is a fiddle demo doing that http://jsfiddle.net/MjV84/
$(function() {
var text = $('#foo').text(),
library = {
stackoverflow: 'http://stackoverflow.com',
wikipedia: 'http://wikipedia.com'
},
name;
for (name in library) {
text = text.replace(new RegExp(name, 'gi'), function(word) {
return ''+word+'';
});
};
$('#foo ').html(text);
});
If you're pre-processing the text, you can use the replace function with a callback and a regular expression using an alternation:
var str = "You should visit StackOverflow. I found it on Wikipedia.";
str = str.replace(/StackOverflow|Wikipedia|etc/gi, function(m) {
var href;
switch (m.toLowerCase()) {
case "stackoverflow";
href = "http://stackoverflow.com";
break;
case "wikipedia";
href = "http://en.wikipedia.org";
break;
// ...and so on...
}
return '' + m + '';
});
YMMD points out that the above requires defining each keyword twice, which is true. When I've had to do this with a large number of keywords, I've done it by having an object with the keywords as keys, the href values as values, and built the expression dynamically:
// ==== Setup code you presumably do once
// The substitutions -- make sure the keys are in lower case
var substitutions = {
"stackoverflow": "http://stackoverflow.com",
"wikipedia": "http://en.wikipedia.org",
// ...and so on...
};
// Build the regex. Here I've used `Object.keys` which is an ES5 feature
// but you can use an ES5 shim (since it's something a shim can provide).
// Note that if your keywords include any special regular expression
// characters, you'll have to loop through the keys manually and escape
// those.
var subrex = new RegExp(Object.keys(substitutions).join("|"), "gi");
// ==== Where you're using it
var str = "You should visit StackOverflow. I found it on Wikipedia.";
str = str.replace(subrex, function(m) {
return '' + m + '';
});
Live example | source
Yes, use String.replace(regex, replaceString) to do that.
Here is an example:
var text = "You should visit StackOverflow. I found it on Wikipedia.";
var newText=text.replace(/stackoverflow/gi,
"<a href='http://www.stackoverflow.com/'>StackOverflow</a>");
The g stands for global, so it will replace all instances, and the i means case-insensitive search.
In case you are replacing common words, like "dictionary" to link to dictionary.com it would be better if you only replaced it if your users added a special tag, for example:
"You should visit StackOverflow. I found it on Wikipedia."
shouldn't be replaced with links unless it was written like this:
"You should visit &StackOverflow. I found it on Wikipedia."
Then your method would just need to add the special symbol.
Also, I would have the data in an array like this:
var linkArray = [ ["StackOverflow", "http://www.stackoverflow.com/", "Description"],
["Wikipedia", "http://wikipedia.org/", "Free encyclopedia"] ];
Then create a loop to find and replace the instances:
function addLinks(textInput) {
for (var i=0; i<linkArray.length; i++) {
textInput = addLink(textInput, linkArray[i]);
}
return textInput;
}
function addLink(textInput, link) {
var replaceString = "<a href=\"" + link[1] + "\" title=\""
+ link[2] + "\">"
+ link[0] + "</a>";
return textInput.replace(new RegExp("&"+link[0], "gi"), replaceString);
}
All the previous answers using the i modifier on the regular expression fail if the target
string contains variants of the substitution strings differing by case. This is because the
target string substring does not match the substitutions attribute name.
This version solves this by capturing each of the substitution strings and searching the arguments array for the found string.
function substitute (str) { 'use strict';
var substitutions = {
"Stack Overflow": "http://stackoverflow.com",
"Wikipedia": "http://en.wikipedia.org",
// ...and so on...
},
skeys = Object.keys (substitutions);
// build regexp which will capture each match separtely
return str.replace (new RegExp ('(' + skeys.join(")|(") + ')', "gi"), function (m0) {
// Now scan the arguments array (omitting the last two arugments which
// are the source string and match index)
for (var ai, i = arguments.length - 2; --i;) {
// The index of the argument (less 1) corresponds to the index in skeys of
// the name in the substitutions
if ((ai = arguments[i])) {
return '' + ai + '';
}
}
return m0;
});
}
var str = "You should visit stack overflow. I found it on Wikipedia.";
// check in console log that links are correctly built.
console.log (substitute (str));
document.write (substitute (str));
See the jsfiddle : http://jsfiddle.net/NmGGN/
I'm trying to do something that would be similar to turning a url slug-like variable into text that could be used for a title.
So, I have a variable for example that is like this:
var thisID = 'athlete-profile';
function myFunc(thisID) {
// i need to use thisID as the id and href in a loop that generates a string of <li><a>'s\
function makeTitle(thisID) {
// convert thisID to text so for this example it would return 'Athlete Profile'
return 'Athlete Profile';
}
for () {
var str = '<li id="'+thisID+'">'+makeTitle(thisID)+'';
}
// make sense?
}
I'd like to not use a regex to do this if possible somehow, but I don't think there's a way to do it without one. So any one who knows how to do this type of thing let me know, it would be a great help.
Thanks
I would advise you to use regular expression. But if you really don't want to use regular expressions, the solution below would work for simple cases. Feel free to modify it as you like it.
function makeTitle(slug) {
var words = slug.split('-');
for (var i = 0; i < words.length; i++) {
var word = words[i];
words[i] = word.charAt(0).toUpperCase() + word.slice(1);
}
return words.join(' ');
}
console.log(
makeTitle("athlete-profile")
)
function titleize(slug) {
var words = slug.split("-");
return words.map(function(word) {
return word.charAt(0).toUpperCase() + word.substring(1).toLowerCase();
}).join(' ');
}
console.log(titleize("athlete-profile"))
It works pretty simply:
It splits the string by - into words.
It maps each word into title case.
It joins the resulting words with spaces.
Do it in one line:
'athlete-profile'.split("-").join(" ").replace(/\w\S*/g, function(txt){return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase()})
Output: Athlete Profile
The makeTitle() part of your question can be implemented something like this:
function makeTitle(thisID) {
return thisID.replace(/-/g, " ").replace(/\b[a-z]/g, function() {
return arguments[0].toUpperCase();
});
}
console.log(makeTitle("athlete-profile"))
The first .replace() changes all hyphens to spaces, and then the second .replace() takes any lower-case letter that follows a word boundary and makes it upper-case.
(For more information see the MDN doco for .replace().)
As far as doing it without using regular expressions, I'm not sure why you'd specifically want to avoid them, especially when the required expressions are pretty simple in this case (especially if you do the hyphen to space and first letter capitalisation in two steps as shown above). But there are endless ways to do this without regex using various combinations of JavaScript's string manipulation methods.
Do it like this
let someString = 'im a string';
console.log(someString.replace(/-/g, ' ')
.replace(/\w\S*/g, function (txt) {
return
txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase()
})
)
Output: Im A String
Short and great way:
const slugToText = (slug) => {
return slug.toLowerCase().replace(/-/g,' ')
}
Much Simplified answer
we can use String.prototype.replaceAll method to easily achieve this
function convertSlugToString(slug) {
return slug.replaceAll("-", " ");
}
incase you want to make sure the output is all lowercase then you can do the following
function convertSlugToString(slug) {
return slug.toLowerCase().replaceAll("-", " ");
}
Additional info:
String.prototype.replaceAll() is a ES2021 feature and it also has a great browser support with 93.64% global coverage, click here for more info
if you want to support IE then refer to the other answers
I need to highlight, case insensitively, given keywords in a JavaScript string.
For example:
highlight("foobar Foo bar FOO", "foo") should return "<b>foo</b>bar <b>Foo</b> bar <b>FOO</b>"
I need the code to work for any keyword, and therefore using a hardcoded regular expression like /foo/i is not a sufficient solution.
What is the easiest way to do this?
(This an instance of a more general problem detailed in the title, but I feel that it's best to tackle with a concrete, useful example.)
You can use regular expressions if you prepare the search string. In PHP e.g. there is a function preg_quote, which replaces all regex-chars in a string with their escaped versions.
Here is such a function for javascript (source):
function preg_quote (str, delimiter) {
// discuss at: https://locutus.io/php/preg_quote/
// original by: booeyOH
// improved by: Ates Goral (https://magnetiq.com)
// improved by: Kevin van Zonneveld (https://kvz.io)
// improved by: Brett Zamir (https://brett-zamir.me)
// bugfixed by: Onno Marsman (https://twitter.com/onnomarsman)
// example 1: preg_quote("$40")
// returns 1: '\\$40'
// example 2: preg_quote("*RRRING* Hello?")
// returns 2: '\\*RRRING\\* Hello\\?'
// example 3: preg_quote("\\.+*?[^]$(){}=!<>|:")
// returns 3: '\\\\\\.\\+\\*\\?\\[\\^\\]\\$\\(\\)\\{\\}\\=\\!\\<\\>\\|\\:'
return (str + '')
.replace(new RegExp('[.\\\\+*?\\[\\^\\]$(){}=!<>|:\\' + (delimiter || '') + '-]', 'g'), '\\$&')
}
So you could do the following:
function highlight(str, search) {
return str.replace(new RegExp("(" + preg_quote(search) + ")", 'gi'), "<b>$1</b>");
}
function highlightWords( line, word )
{
var regex = new RegExp( '(' + word + ')', 'gi' );
return line.replace( regex, "<b>$1</b>" );
}
You can enhance the RegExp object with a function that does special character escaping for you:
RegExp.escape = function(str)
{
var specials = /[.*+?|()\[\]{}\\$^]/g; // .*+?|()[]{}\$^
return str.replace(specials, "\\$&");
}
Then you would be able to use what the others suggested without any worries:
function highlightWordsNoCase(line, word)
{
var regex = new RegExp("(" + RegExp.escape(word) + ")", "gi");
return line.replace(regex, "<b>$1</b>");
}
Regular expressions are fine as long as keywords are really words, you can just use a RegExp constructor instead of a literal to create one from a variable:
var re= new RegExp('('+word+')', 'gi');
return s.replace(re, '<b>$1</b>');
The difficulty arises if ‘keywords’ can have punctuation in, as punctuation tends to have special meaning in regexps. Unfortunately unlike most other languages/libraries with regexp support, there is no standard function to escape punctation for regexps in JavaScript.
And you can't be totally sure exactly what characters need escaping because not every browser's implementation of regexp is guaranteed to be exactly the same. (In particular, newer browsers may add new functionality.) And backslash-escaping characters that are not special is not guaranteed to still work, although in practice it does.
So about the best you can do is one of:
attempting to catch each special character in common browser use today [add: see Sebastian's recipe]
backslash-escape all non-alphanumerics. care: \W will also match non-ASCII Unicode characters, which you don't really want.
just ensure that there are no non-alphanumerics in the keyword before searching
If you are using this to highlight words in HTML which already has markup in, though, you've got trouble. Your ‘word’ might appear in an element name or attribute value, in which case attempting to wrap a < b> around it will cause brokenness. In more complicated scenarios possibly even an HTML-injection to XSS security hole. If you have to cope with markup you will need a more complicated approach, splitting out ‘< ... >’ markup before attempting to process each stretch of text on its own.
What about something like this:
if(typeof String.prototype.highlight !== 'function') {
String.prototype.highlight = function(match, spanClass) {
var pattern = new RegExp( match, "gi" );
replacement = "<span class='" + spanClass + "'>$&</span>";
return this.replace(pattern, replacement);
}
}
This could then be called like so:
var result = "The Quick Brown Fox Jumped Over The Lazy Brown Dog".highlight("brown","text-highlight");
For those poor with disregexia or regexophobia:
function replacei(str, sub, f){
let A = str.toLowerCase().split(sub.toLowerCase());
let B = [];
let x = 0;
for (let i = 0; i < A.length; i++) {
let n = A[i].length;
B.push(str.substr(x, n));
if (i < A.length-1)
B.push(f(str.substr(x + n, sub.length)));
x += n + sub.length;
}
return B.join('');
}
s = 'Foo and FOO (and foo) are all -- Foo.'
t = replacei(s, 'Foo', sub=>'<'+sub+'>')
console.log(t)
Output:
<Foo> and <FOO> (and <foo>) are all -- <Foo>.
Why not just create a new regex on each call to your function? You can use:
new Regex([pat], [flags])
where [pat] is a string for the pattern, and [flags] are the flags.