like button on click ajax not working - javascript

I want to make an ajax request on click with jquery, but it's not working:
This is what I have:
The button:
$photos_box .= '<a id="' . $imgID . '" class="like_button">' . $like . '</a>';
Maybe there's an error in the script:
// Like function
$('.like_button').click(function() {
$(this).toggleClass('liked');
var status = '';
if ($(this).hasClass('liked')) {
status = 'like';
$(this).html('Ya no me gusta');
console.log('like_works');
} else {
status = 'unlike';
$(this).html('Me gusta');
console.log('unlike_works');
}
var data = {
img_id : this.id,
sta : status
};
$.ajax({
type : 'POST',
url : '/includes/like.php',
data : data
}).done(function(reslike) {
if (reslike == 1) console.log('ajax_works');
});
});
And this is the like.php file:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
sec_session_start();
// User id
if (login_check($mysqli) == true) {
$user_id = $_SESSION['user_id'];
}
$img_id = $_POST['img_id'];
$status = $_POST['sta'];
$stmt = $mysqli->prepare("SELECT * FROM img_likes WHERE img_id = ? AND user_id = ?");
$stmt->bind_param("ii", $img_id, $user_id);
$stmt->execute();
$result = $stmt->get_result();
$usr_likes = $result->num_rows;
if ($status == 'like') {
if ($usr_likes == 0) {
$stmt->close();
$stmt = $mysqli->prepare("INSERT INTO img_likes (img_id, user_id) VALUES(?, ?)");
$stmt->bind_param("ii", $img_id, $user_id);
$stmt->execute();
}
}
else if ($status == 'unlike') {
if ($usr_likes != 0) {
$stmt->close();
$stmt = $mysqli->prepare("DELETE FROM img_likes WHERE img_id = ? AND user_id = ?");
$stmt->bind_param("ii", $img_id, $user_id);
$stmt->execute();
}
}
}
At last! Thanks to everyone. Hope my code help someone.

Check the URL in your ajax request, I'm not certain but I don't think '../includes/like.php' is a valid URL I think you actually have to give it a valid server URL like "http://example.com/includes/like.php"

Related

PHP data return empty not working

So I've got my password being passed to a php page and returning json data
However if it returns nothing. nothing happings. My Failed login never fires. Can someone tell what I'm doing wrong.
<script>
$(document).ready(function(){
var password = "";
//PRESSING AN INPUT KEY
$('.sixPinInput').keyup(function (k) {
if (this.value.length == this.maxLength) {
password = password+this.value;
password = password.substring(0,6);
$(this).next('.sixPinInput').focus();
$(".pinIncorrectMessage").css("display", "block");
$(".pinIncorrectMessage").html(password);
}
//PRESSING DELETE
if (k.keyCode == 8) {
$(this).prev().val("").focus();
password = password.slice(0, -1);
$(".pinIncorrectMessage").html(password);
}
});
//PRESSING LAST INPUT KEY
$("#f").keyup(function() {
if($("#f").val().length > 0) {
$.post("http://heber/QC/includes/getUserInfo.php", {user: password}, function(data, status) {
//IF SUCCESSFUL LOGIN
password = "";
$(".sixPinInput").val("");
if(data) {
$(data).each(function(index, value) {
alert(value.firstName + value.lastName)
$(".cover").fadeOut(200);
$(".sixPinInputContainer").fadeOut(200);
$("#pageBody").css("overflow", "scroll");
})
}
//IF FAILED LOGIN
if(!data) {
$(".cover").fadeOut(200);
$(".sixPinInputContainer").fadeOut(200);
$("#pageBody").css("overflow", "scroll");
}
})
}
})
});
</script>
And this is my PHP
<?php include "db.php"; ?>
<?php
if (isset($_POST['user'])) {
$password = $_POST['user'];
$query = $connect->prepare("
SELECT firstName, lastName, color1, color2, authorizationLevel FROM employee WHERE password = ? LIMIT 1");
if(!$query) {
echo "Query Failed because " . mysqli_error($connect);
}
$query->bind_param("s", $password);
$query->execute();
$result = $query->get_result();
if ($result) {
while($row = mysqli_fetch_assoc($result)) {
$firstName = $row['firstName'];
$lastName = $row['lastName'];
$color1 = $row['color1'];
$color2 = $row['color2'];
$authorizationLevel = $row['authorizationLevel'];
session_start();
$_SESSION['firstName'] = $firstName;
$_SESSION['lastName'] = $lastName;
$_SESSION['color1'] = $color1;
$_SESSION['color2'] = $color2;
$_SESSION['authorizationLevel'] = $authorizationLevel;
$array[] = array (
'firstName'=>$firstName,
'lastName'=>$lastName,
'color1'=>$color1,
'color2'=>$color2,
'authorizationLevel'=>$authorizationLevel
);
}
header('Content-type: application/json');
echo json_encode($array);
}
}
?>

Having trouble sending AND receiving information from a php file using javascript

I am sending some information to a php file that runs a query but I want to also retrieve some information from that php file at the same time. The php file executes fine but I can't get the json_encoded object.
Javascript function that sends a string and a number to a php file:
function open_close(){
var status = encodeURIComponent(SelectedTicket["Status"]);
var ticketNum = encodeURIComponent(SelectedTicket["TicketNum"]);
var info = "Status="+status+"&TicketNum="+ticketNum;
var http3 = createAjaxRequestObject();
if (http3.readyState == 4) {
if (http3.status == 200){
alert("Ticket Updated!"); //This never gets hit
getUpdatedTicket(JSON.parse(http3.responseText));
}
}
http3.open("POST", "openClose.php", true);
http3.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http3.send(info);
}
PHP File that takes the string and number and updates a table
<?php
include("config.php");
session_start();
$status = $_POST["Status"];
$num = $_POST["TicketNum"];
$newStatus = " ";
if(strcmp($status, "Open") == 0){
$newStatus = "Closed";
}
elseif(strcmp($status, "Closed") == 0){
$newStatus = "Open";
}
$sql = "UPDATE tickets SET Status = \"$newStatus\" where TicketNum = $num ";
$r = $conn ->query($sql) or trigger_error($conn->error."[$sql]");
$sql = "SELECT * FROM tickets where TicketNum = $num";
$result = $conn->query($sql);
while($row = $result->fetch_assoc()){
$data[] = $row;
}
echo json_encode($data);
?>
How can I retrieve the json_encoded object in the same javascript function?
You'd need a readyState listener to know when the request is done, and then get the data from the responseText
function open_close() {
var status = encodeURIComponent(SelectedTicket["Status"]);
var ticketNum = encodeURIComponent(SelectedTicket["TicketNum"]);
var info = "Status=" + status + "&TicketNum=" + ticketNum;
var http3 = createAjaxRequestObject();
http3.onreadystatechange = function () {
if (http3.readyState == 4) {
if (http3.status == 200) {
console.log(http3.responseText); // <- it's there
}
}
}
http3.open("POST", "openClose.php", true);
http3.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
http3.send(info);
}

Having json inside autocomplete

How come autocomplete doesnt work when I got json data that has items in it? I can se that it is becoming a list, but it is not filling with names.
Example of my json data: http://nettport.com/no/stram/search.php?term=e
<script>
$(function() {
$( "#inp_meal_a_0" ).autocomplete({
source: 'search.php'
});
$('#inp_meal_a_0').on('autocompleteselect', function (e, ui) {
var val = $('#inp_size_a_0').val();
var energy = ui.item.energy;
var proteins = ui.item.proteins;
var carbohydrates = ui.item.carbohydrates;
var fat = ui.item.fat;
$("#inp_energy_a_0").val((energy*val)/100);
$("#inp_proteins_a_0").val((proteins*val)/100);
$("#inp_carbs_a_0").val((carbohydrates*val)/100);
$("#inp_fat_a_0").val((fat*val)/100);
});
});
</script>
Search.php
<?php
header('Content-type: text/html; charset=windows-1252;');
// Make a MySQL Connection
$host = $_SERVER['HTTP_HOST'];
if($host == "127.1.1.0"){
mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("n") or die(mysql_error());
}
// Quote smart
function quote_smart($value){
// Stripslashes
if (get_magic_quotes_gpc() && !is_null($value) ) {
$value = stripslashes($value);
}
//Change decimal values from , to . if applicable
if( is_numeric($value) && strpos($value,',') !== false ){
$value = str_replace(',','.',$value);
}
if( is_null($value) ){
$value = 'NULL';
}
// Quote if not integer or null
elseif (!is_numeric($value)) {
$value = "'" . mysql_real_escape_string($value) . "'";
}
return $value;
}
if(isset($_GET['term']) && $_GET['term'] != ''){
$term = $_GET['term'];
$term = strip_tags(stripslashes($term));
$term = trim($term);
$term = strtolower($term);
$term = $term . "%";
$part_mysql = quote_smart($term);
//get matched data from skills table
$x = 0;
$query = "SELECT cc_id, cc_food_name, cc_manufactor_name, cc_serving_size, cc_serving_mesurment, cc_energy, cc_proteins, cc_carbohydrates, cc_fat FROM stram_calorie_calculation WHERE cc_food_name LIKE $part_mysql";
$r = mysql_query($query);
while ($row = mysql_fetch_array($r, MYSQL_NUM)) {
$get_cc_id = $row[0];
$get_cc_food_name = $row[1];
$get_cc_manufactor_name = $row[2];
$get_cc_serving_size = $row[3];
$get_cc_serving_mesurment = $row[4];
$get_cc_energy = $row[5];
$get_cc_proteins = $row[6];
$get_cc_carbohydrates = $row[7];
$get_cc_fat = $row[8];
if($get_cc_food_name == ""){
$result = mysql_query("DELETE FROM stram_calorie_calculation WHERE cc_id='$get_cc_id'") or die(mysql_error());
}
$data[$x] = array('food_name' => $get_cc_food_name, 'energy' => $get_cc_energy, 'proteins' => $get_cc_proteins, 'carbohydrates' => $get_cc_carbohydrates, 'fat' => $get_cc_fat);
//$data[$x] = $get_cc_food_name;
$x++;
}
//return json data
echo json_encode($data);
}
?>

mysqli query not working in foreach php

My problem now when I click on the picture on my page, for the first time it will display. But for the second time it will display fail. This process will start by sending the data to ajax, then ajax(prosess.js) will send it to the php page(process1.php).
When I remove the code in blockquote ($query = "SELECT ...") it will run, but if not, it will display fail.
process1.php
<?php
include 'session.php';
include 'connection.php';
if(isset($_POST['dataS'])) {
$table = $_POST['table'];
$concat = "";
$serial = $_POST['dataS'];
$query = "SELECT * FROM product WHERE serialNum = '$serial'";
$result = mysqli_query($conn, $query);
$row = mysqli_fetch_assoc($result);
if($row) {
$prodName = $row['prodName'];
$quanProd = 1;
$priceProd = $_POST['total'] + $row['salePrice'];
if($table == "") {
$query = "SELECT * FROM product WHERE serialNum = '$serial'";
$result = mysqli_query($conn, $query);
$row = mysqli_fetch_assoc($result);
}
else{
$DOM = new DOMDocument;
$DOM->loadHTML($table);
$items = $DOM->getElementsByTagName('tr');
$check = 0;
$check_one = 0;
$y=0;
function tdrows($elements,$check,$serial,$prodName,$y) {
$quantity="";
$item = "";
$price = "";
$delete = "";
$x = 0;
foreach($elements as $element) {
if($x == 0)
$delete = $element->nodeValue;
else if($x == 1)
$item = $element->nodeValue;
else if($x == 2)
$quantity = $element->nodeValue;
else if($x == 3)
$price = $element->nodeValue;
$x++;
}
**$query = 'SELECT prodName FROM product WHERE prodName = "$item"';
$search = mysqli_query($conn, $query) or die(mysqli_error());
$row = mysqli_fetch_assoc($search);
$s = $row['prodName'];**
if($prodName == $s) {
$quantity++;
$check = 1;
}
else {
$check = 0;
}
return $check;
}
foreach ($items as $node) {
$check = tdrows($node->childNodes,$check,$serial,$prodName,$y);
$y++;
}
}
$priceProd = number_format((float)$priceProd, 2, '.', '');
echo json_encode (
array ( //this array is used to send the data back to ajax.
"success" => "1",
"concat" => $concat,
"quantity" => $quanProd,
"price" => $priceProd,
)
);
}
else {
echo json_encode (
array ( //this array is used to send the data back to ajax.
"success" => "0",
)
);
}
}
?>
process.js
$(document).ready(
function() {
$("body").on("click","#product .add",
function(e) {
var total = document.getElementById("total").value;
var table = document.getElementById('table-list').innerHTML;
table = (table.trim) ? table.trim() : table.replace(/^\s+/,'');
var serial = $(this).attr('id');
var totalQ = document.getElementById("totalQ").value;
if(total == "")
total = 0;
else
total = parseFloat(total);
if(totalQ == "")
totalQ = 0;
else
totalQ = parseInt(totalQ);
var dataS = serial;
e.preventDefault();
$.ajax({
type : "POST",
url : "process1.php",
crossDomain: true,
data : {dataS : dataS, table : table, total : total},
dataType : 'json',
})
.done(function(html) {
if(html.success == 1) {
console.log('done: %o', html);
$("#table-list").html(html.concat).show();
document.getElementById('totalQuantity').innerHTML = html.quantity;
document.getElementById("total").value = html.price;
document.getElementById("payment").value = html.price;
document.getElementById('totalQ').value = html.quantity;
document.getElementById('title').innerHTML = html.price;
document.getElementById('input').value='';
$("#input").focus();
}
else {
alert("Wrong serial number!");
document.getElementById('input').value='';
$("#input").focus();
}
})
.fail(function(html) {
console.info('fail: %o', html);
alert("fail");
});
return false;
});
});
connection.php
<?php
$conn = mysqli_connect('localhost','root','','rds');
?>
your query is wrong:try this
$query = "SELECT prodName FROM product WHERE prodName = '".$item."'";
According to your pictures, your problem is that your database connection isn't correct. When you execute the first request it won't do any database interaction (because off the blocknotes). The second request you will send table data, which will perform a query. So the first request will succeed, while the second request will give you an error on your mysqli ($conn) object.
if($table == "") {
//Database interaction
$query = "SELECT * FROM product WHERE serialNum = '$serial'";
$result = mysqli_query($conn, $query);
$row = mysqli_fetch_assoc($result);
}
else{
//No database interaction because of the blocknotes
$DOM = new DOMDocument;
$DOM->loadHTML($table);
$items = $DOM->getElementsByTagName('tr');
$check = 0;
$check_one = 0;
$y=0;
function tdrows($elements,$check,$serial,$prodName,$y) {
$quantity="";
$item = "";
$price = "";
$delete = "";
$x = 0;
foreach($elements as $element) {
if($x == 0)
$delete = $element->nodeValue;
else if($x == 1)
$item = $element->nodeValue;
else if($x == 2)
$quantity = $element->nodeValue;
else if($x == 3)
$price = $element->nodeValue;
$x++;
}
**$query = 'SELECT prodName FROM product WHERE prodName = "$item"';
$search = mysqli_query($conn, $query) or die(mysqli_error());
$row = mysqli_fetch_assoc($search);
$s = $row['prodName'];**
if($prodName == $s) {
$quantity++;
$check = 1;
}
else {
$check = 0;
}
return $check;
}
foreach ($items as $node) {
$check = tdrows($node->childNodes,$check,$serial,$prodName,$y);
$y++;
}
}
Check your the username, password and database name. I'm pretty sure you used something wrong here. As mentioned in your connection.php file you don't use a password. Are you sure the user root doens't have a password? Can you access the database with a MySQL administration tool like phpMyAdmin?

AJAX Sends back entire page instead of result

I am having a little trouble figuring out why my ajax response is sending me the entire page.
I am not using conventional AJAX code simply because this is how the guy was doing it in a tutorial I was following. I am using firebug to track all my javascript variables and when I break the code at the responseText var it gives me the entire page. Here is the code for the javascript on the page I am working with :
function changepass() {
var u = _("username").value;
var cp = _("currentPass").value;
var np = _("newPass").value;
var cnp = _("confirmNewPass").value;
if(np != cnp) {
_("status").innerHTML = "The passwords given do not match!";
} else if (cp === "" || np === "" || cnp === "") {
_("status").innerHTML = "Please fill out all of the fields.";
} else {
_("changepassbtn").style.display = "none";
_("status").innerHTML = 'please wait ...';
var ajax = ajaxObj("POST", "change_password.php");
ajax.onreadystatechange = function() {
if(ajaxReturn(ajax) == true) {
var response = ajax.responseText;
if(response == "success"){
_("status").innerHTML = "Your password change was successful! Click the button below to proceed.<br><br>Back To Home Page";
} else if (response == "no_exist"){
_("status").innerHTML = "Your current password was entered incorrectly.";
_("changepassbtn").style.display = "initial";
} else if(response == "pass_failed"){
_("status").innerHTML = "Change password function failed to execute!";
_("changepassbtn").style.display = "initial";
} else {
_("status").innerHTML = "An unknown error occurred";
_("changepassbtn").style.display = "initial";
}
}
}
ajax.send("u="+u+"&cp="+cp+"&np="+np+"&cnp"+cnp);
}
}
Here is the AJAX code that I use to handle the requests.
function ajaxObj( meth, url ) {
var x = new XMLHttpRequest();
x.open( meth, url, true );
x.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
return x;
}
function ajaxReturn(x){
if(x.readyState == 4 && x.status == 200){
return true;
}
}
Any help would be greatly appreciated.
Thanks!
Here is the server side PHP:
if(isset($_POST["u"]) && isset($_POST['oe']) && isset($_POST['ne']) && isset($_POST['p'])) {
$oe = mysqli_real_escape_string($db_conx, $_POST['oe']);
$ne = mysqli_real_escape_string($db_conx, $_POST['ne']);
$p = md5($_POST['p']);
$u = mysqli_real_escape_string($db_conx, $_POST['u']);
var_dump($oe, $ne, $p, $u);
$sql = "SELECT username, password, email FROM users WHERE username='$u' LIMIT 1";
$query = mysqli_query($db_conx, $sql);
$row = mysqli_fetch_row($query);
$db_username = $row[0];
$db_password = $row[1];
$db_email = $row[2];
var_dump($db_username, $db_password, $db_email);
if($db_email != $oe) {
echo "bad_email";
exit();
} else if($db_password != $p) {
echo "no_exist";
exit();
} else {
$sql = "UPDATE users SET email='$ne' WHERE username='$db_username' LIMIT 1";
$query = mysqli_query($db_conx, $sql);
$sql = "SELECT email FROM users WHERE username='$db_username' LIMIT 1";
$query = mysqli_query($db_conx, $sql);
$row = mysqli_fetch_row($query);
$db_newemail = $row[0];
if($db_newemail == $ne) {
echo "success";
exit();
} else {
echo "email_failed";
exit();
}
}
}
My mistake was a simple syntax error. Gosh PHP is picky! The error occurs in the ajax.send command. I am miss an '=' on the last parameter.
Thanks for your help guys!

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