Google visualization table doesn't understand my code - javascript

Can anyone point out what I'm doing wrong here, i'm literally banging my head of the table!, the data is coming off in the html source, but the page is just blank, the google table doesn't seem to like it.
google.load("visualization", "1", {packages:["table"]});
google.setOnLoadCallback(drawTable);
function drawTable() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'COND_CODE');
data.addColumn('number', 'PEICE_NO');
data.addRows([
<?php
while( $row = $result->fetch_assoc() ){
extract($row);
echo "{['$COND_CODE'], ['$PEICE_NO'],"; } ?>
]);
var table = new google.visualization.Table(document.getElementById('table_div'));
table.draw(data, {showRowNumber: true});
}
</script>
Thanks
EDIT:
Here is the html output
<html>
<head>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", {packages:["table"]});
google.setOnLoadCallback(drawTable);
function drawTable() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'COND_CODE');
data.addColumn('number', 'PEICE_NO');
data.addRows([
{['BTH'], ['03084'],{['BTH'], ['03084'],{['TC'], ['02549'],{['SM'], ['03049'],{['BTH'], ]);
var table = new google.visualization.Table(document.getElementById('table_div'));
table.draw(data, {showRowNumber: true});
}
</script>

Try this instead:
data.addRows(
<?php
$rows = array();
while( $row = $result->fetch_assoc() ){
extract($row);
$rows[] = array($COND_CODE, $PEICE_NO);
}
echo json_encode($rows, JSON_NUMERIC_CHECK);
?>
);
The should output your data in the correct format.

You have the wrong syntax for a DataTable.
try doing this instead:
echo "['$COND_CODE', '$PEICE_NO' ],"; } ?>

echo "{['$COND_CODE'], ['$PEICE_NO']},";?>
Seeyour syntax is wrrong

Related

google organisation chart : Unable to display the organisation chart

Here is my database snap:
link
Here is my code:
<?php
$db=mysqli_connect("localhost","root","","organisation"); //db connection
$query=mysqli_query($db, "SELECT name,below_whom FROM org"); //fetch data
if($query){
$data=[];
while($org_data=mysqli_fetch_assoc($query)){
$data []= [$org_data["name"],$org_data["below_whom"]]; //syntax of
associative array = $variable["value"]
}
#echo '<pre>'; print_r($data); echo '</pre>';
}
else {
"Error".mysqli_error();
}
?>
<html>
<head></head>
<body>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {packages:["orgchart"]});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'name');
data.addColumn('string', 'below_whom');
data.addColumn('string', 'ToolTip');
data.addRows(<?php echo json_encode($data); ?>);
var chart = new google.visualization.OrgChart(document.getElementById('chart_div'));
chart.draw(data, {allowHtml:true});
}
</script>
<div id="chart_div"></div>
</body>
</html>
I have been going through the documentation for quite sometime now and I am still clueless. I guess error is somewhere near addRows but I'm unable to trace it.
It seems to me that there is no issue with your code, however the issue is in your data. Your queried data will be like this:
|name |below_whom|
|-------|----------|
|Pratik | |
|-------|----------|
|Q |FTA |
|-------|----------|
So you see, the "Q" has "FTA" as the boss, but google organization chart could not find "FTA". If you change "FTA" to "Pratik", you will see magic happens.

PHP/JS - Google Graph - Echoing data out

I've looked at other questions similar to what I am asking however they are not what I need/trying to substitute the answer into my code.
<html>
<head>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {'packages':['bar']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = google.visualization.arrayToDataTable([
['Stock Price', 'Date'],
//['2014', 3000],
<?php
$DataSearchSQL = "SELECT * FROM stocklog WHERE status = 1 ORDER BY ID DESC LIMIT 7";
$DataSearchResult = mysqli_query($dbconfig,$DataSearchSQL);
while($DataSearchRow=mysqli_fetch_array($DataSearchResult,MYSQLI_ASSOC)) {
$data = $DataSearchRow["StockPrice"];
$timestamp = $DataSearchRow["Time"];
$splitTimeStamp = explode(" ",$timestamp);
$date = $splitTimeStamp[0];
$info = "['{$date}', {$data}]";
echo json_encode($info);
}
?>
]);
I believe I am messing something up with $info and json_encode however I am not sure what to do, help is much appreciated.

Parsing JSON array into Google Charts DataTable

I've done quite a bit of searching and have found solutions for issues similar to my problem but nothing that has worked so far. Any help is appreciated.
I am attempting to create a Google Line Chart from data I am querying from my database and then parsing to JSON. My query and JSON looks good but when I insert it into the DataTable the web page is blank.
This the JSON output I have:
[["date","percentage"],["0000-00-00 00:00:00",28.18],["2015-01-06 06:00:01",93.65],["2015-01-07 06:00:01",85.9],["2015-01-08 06:08:43",89.25],["2015-01-09 06:08:42",99.26],["2015-01-10 14:50:37",99.48],["2015-02-06 06:00:01",93.88],["2015-02-07 06:00:01",89.15],["2015-02-08 06:08:51",89.55],["2015-02-09 06:09:25",98.94],["2015-02-09 17:26:50",98.94],["2015-02-10 06:10:55",99.06],["2015-03-07 06:11:32",85.7],["2015-03-08 06:07:58",89.86],["2015-03-10 06:11:04",99.06],["2015-04-06 14:19:26",82.17],["2015-04-07 06:11:47",85.8],["2015-04-08 06:10:01",89.76],["2015-04-10 06:10:53",100],["2015-05-06 16:25:01",91.21],["2015-05-07 06:11:12",85.7],["2015-05-08 06:08:53",89.25],["2015-05-09 22:35:40",97.77],["2015-05-10 06:10:39",99.17],["2015-05-10 21:28:01",98.85],["2015-06-06 06:00:02",90.84],["2015-06-07 06:11:05",85.9],["2015-06-09 06:09:32",97.88],["2015-06-10 06:10:55",99.79],["2015-07-06 06:00:01",91.33],["2015-07-07 06:10:35",85.09],["2015-07-08 06:09:36",89.45],["2015-07-09 06:08:55",98.2],["2015-07-10 06:12:44",5.94],["2015-08-06 06:00:01",91.58],["2015-08-08 06:09:03",89.05],["2015-08-09 06:09:23",97.03],["2015-08-09 15:54:27",97.67],["2015-09-06 06:00:01",90.96],["2015-09-07 06:12:33",84.99],["2015-09-08 06:08:54",89.15],["2015-09-09 06:12:48",99.26],["2015-09-09 14:29:39",95.02],["2015-10-06 06:00:01",91.09],["2015-10-07 06:13:13",89.35],["2015-10-08 06:08:42",89.25],["2015-10-09 06:09:40",99.47],["2015-10-09 17:14:20",99.47],["2015-11-05 06:00:01",97.41],["2015-11-06 06:00:01",85.47],["2015-11-07 06:12:17",89.45],["2015-11-08 06:10:45",89.45],["2015-12-05 06:00:01",96.7],["2015-12-06 06:00:01",90.72],["2015-12-07 06:12:22",88.74],["2015-12-09 06:09:39",99.58]]
When I insert this into the JSON Validator at https://jsonformatter.curiousconcept.com it says it is valid JSON and when I hard code it in everything seems to work..
Here is my code:
<?php
$dbhost="localhost";
$dblogin="root";
$dbpwd="password!";
$dbname="qaDB";
$db = mysql_connect($dbhost,$dblogin,$dbpwd);
mysql_select_db($dbname);
$SQLString = "SELECT date, percentage FROM reports WHERE RTYPE_ID=1";
$result = mysql_query($SQLString);
$num = mysql_num_rows($result);
# set heading
$data[0] = array('date','percentage');
for ($i=1; $i<($num+1); $i++)
{
$data[$i] = array(substr(mysql_result($result, $i-1, "date"), 0, 20),
(float) mysql_result($result, $i-1, "percentage"));
}
echo json_encode($data);
mysql_close($db);
?>
Here is the page to create the Google line chart.
<html>
<head>
<title>JSON Chart Test</title>
<!-- Load jQuery -->
<script language="javascript" type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js">
</script>
<!-- Load Google JSAPI -->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", { packages: ["corechart"] });
google.setOnLoadCallback(drawChart);
function drawChart() {
// var newWin = window.open();
var jsonData = $.ajax({
url: "legacyDashboardJSON.php",
dataType: "json",
async: false
}).responseText;
//var newStr = jsonData.substring(1, jsonData .length-1);
//newWin.document.write(jsonData);
// var parsedData = JSON.parse(newStr);
//var obj = JSON.stringify(newStr);
var data = google.visualization.DataTable(jsonData);
var options = {
title: 'Stats'
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<div id="chart_div">
</div>
</body>
</html>
Thanks!
UPDATE Found the solution.
Here's the code:
<?php
$DB_NAME = 'qaDB';
$DB_HOST = 'localhost';
$DB_USER = 'root';
$DB_PASS = '!';
$mysqli = new mysqli($DB_HOST, $DB_USER, $DB_PASS, $DB_NAME);
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$result = $mysqli->query('SELECT date,percentage FROM reports');
$rows = array();
$table = array();
$table['cols'] = array(
array('label' => 'date', 'type' => 'string'),
array('label' => 'percentage', 'type' => 'number')
);
foreach($result as $r) {
$temp = array();
$temp[] = array('v' => (string) $r['date']);
$temp[] = array('v' => (int) $r['percentage']);
$rows[] = array('c' => $temp);
}
$table['rows'] = $rows;
$jsonTable = json_encode($table);
echo $jsonTable;
mysql_close($mysqli);
?>
<html>
<head>
<!--Load the Ajax API-->
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.2/jquery.min.js"></script>
<script type="text/javascript">
// Load the Visualization API and the piechart package.
google.load('visualization', '1', {'packages':['corechart']});
// Set a callback to run when the Google Visualization API is loaded.
google.setOnLoadCallback(drawChart);
function drawChart() {
var jsonData = $.ajax({
url: "legacyDashboardJSON.php",
dataType: "json",
async: false
}).responseText;
// Create our data table out of JSON data loaded from server.
var data = new google.visualization.DataTable(jsonData);
var options = {
title: 'Metrics',
width: 800,
height: 600
};
// Instantiate and draw our chart, passing in some options.
// Do not forget to check your div ID
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<!--this is the div that will hold the pie chart-->
<div id="chart_div"></div>
</body>
</html>
You need to provide a success function in your .ajax call that will execute when the data returns. Anything that needs the data should be placed inside this function, or passed from within the success function to another function. You could also use .done() on the end of your .ajax call and place the rest of your script in there.

Google Charts not displaying values correctly

I'm having trouble displaying Google Charts correctly. I'm trying to do this with Ajax and PHP.
This is the code that is loaded on the page:
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type='text/javascript'>
// Dummy Array for now
<?php
$php_array = array(
array('Terms', 'Visits'),
array('test', 25),
array('joke', 25),
array('funny', 50),
);
//Convert the PHP Array into a Javascript Array
$js_array = json_encode($php_array);
echo "var arrTableData = ". $js_array . ";\n";
?>
google.load("visualization", "1", {packages:["corechart"]});
google.setOnLoadCallback(drawCharts);
function drawCharts(){
// Each chart function
$.getJSON('charts_ajax.php',{'a' : 'terms', 'd' : arrTableData }, function(data){
if(data){
initGoogleChart(data)
}else {
console.log("There is no data coming back");
}
});
}
function initGoogleChart(data){
var tableData = google.visualization.arrayToDataTable(data);
var options = {
title: 'Title'
};
var chart = new google.visualization.PieChart(document.getElementById('terms-table'));
chart.draw(tableData, options);
}
</script>
and on the charts_ajax.php file there is this data:
<?php
if ($_GET['a'] == "terms") {
$arrTableData = $_GET['d'];
echo json_encode($arrTableData);
}
?>
This is what the Chart is outputting:
Can anybody shed some light on this and possible help me fix it please?
Have you tried converting the data into a Google Charts JSON format? Here's an example.
foreach($arrTableData as $r2) {
if(!isset($google_JSON2)) {
$google_JSON2 = "{\"cols\": [";
$column = array_keys($r2);
foreach($column as $key=>$value) {
$google_JSON_cols2[]="{\"id\": ".$key.", \"label\": \"".$value."\", \"type\": \"string\"}";
}
$google_JSON2 .= implode(",",$google_JSON_cols2)."],\"rows\": [";
}

Stripping last comma from PHP foreach loop

I'm wondering how I can remove the trailing comma in this foreach loop in my PHP script running inside of javascript.
<html>
<head>
<script type='text/javascript' src='https://www.google.com/jsapi'></script>
<script type='text/javascript'>
google.load('visualization', '1', {'packages': ['geochart']});
google.setOnLoadCallback(drawRegionsMap);
function drawRegionsMap() {
var data = google.visualization.arrayToDataTable([
['Country','Blocks'],
<?php
foreach ($bans as $key => $value)
print"['$key', $value],\n";
?>
]);
var options = {
backgroundColor : '#555555',
colors : ['#FFFF00', '#FF0000']
};
var chart = new google.visualization.GeoChart(document.getElementById('chart_div'));
chart.draw(data, options);
};
</script>
</head>
<body>
<div id="chart_div" style="width: 900px; height: 500px;"></div>
</body>
</html>
This causes a problem as I get a trailing comma, I've tried an implode method and rtrim method but none of those appear to be working (I've also never used those functions so I may be doing it wrong)
My implode method was:
<?php
$resultstr = array();
foreach ($bans as $key => $value)
print"['$key', $value],\n";
$resultstr = implode(",", $resultstr);
?>
My rtrim method was:
<?php
$resultstr = array();
foreach ($bans as $key => $value)
print"['$key', $value],\n";
echo rtrim($resultstr, ",");
?>
When compiled it looks like this:
<html>
google.load('visualization', '1', {'packages': ['geochart']});
google.setOnLoadCallback(drawRegionsMap);
function drawRegionsMap() {
var data = google.visualization.arrayToDataTable([
['Country','Blocks'],
['Japan', 11],
['United States', 45],
['Argentina', 1],
]);
var options = {
backgroundColor : '#555555',
colors : ['#FFFF00', '#FF0000']
};
var chart = new google.visualization.GeoChart(document.getElementById('chart_div'));
chart.draw(data, options);
};
</script>
</head>
<body>
<div id="chart_div" style="width: 900px; height: 500px;"></div>
</body>
</html>
What you should do instead of trimming the string afterwards is not generating the trailing comma at all:
$not_first = false;
foreach ($bans as $key => $value) {
if ($not_first) {
print(", ");
}
$not_first = true;
print "['$key', $value]\n";
}
This could be another approach:
var data = google.visualization.arrayToDataTable(<?php
$table = array(array('Country', 'Blocks'));
foreach($bans as $key => $value) {
$table[] = array($key, $value);
}
echo json_encode($table);
?>);
I often use json_encode so I don't have to take care of escaping all the values.
You missed something:
echo rtrim($resultstr, ",");
You could also do:
echo substr($resultstr, 0, -1);
You could create an array that contains the [key, value] pieces and then glue them with implode:
PHP
<?php
$arr = array();
$arr['key1'] = 'val1';
$arr['key2'] = 'val2';
$arr['key3'] = 'val3';
function PrepareValues(&$item, $key) {
$item = "['$key', $item]";
}
array_walk_recursive($arr, "PrepareValues");
$resultstr = implode(",\n", $arr);
print($resultstr);
?>
Output
['key1', val1],
['key2', val2],
['key3', val3]

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