Using getImageData, I'm trying to create a radial fade effect on an image where point(0,0) has an alpha of 0 and point(img.width, img.height) has an alpha of 0.5 sort of like this:
(The last point has an alpha of 1.0, but imagine it's 0.5.)
I've been able to create a linear alpha increase in my for loop using
imgData.data[i+3]=i/imgData.length;
but the left edge (obviously) becomes more defined as the loop iterates.
I've tried using two loops, one to create row "breaks" in the array, and the other to handle the alpha manipulation like so:
for(var j=0;j<imgData.height;j++){
for(var i=0;i<imgData.data.length;i+=4){
imgData.data[i+3] = 0 + 125 * i/imgData.data.length;
}
}
but the performance of this is really slow and it doesn't achieve the fade that I'm looking for. I'm also not sure I'm doing that properly. I also tried Faster Canvas Pixel Manipulation with Typed Arrays as outlined on the Mozilla Hacks site, but the image wasn't even drawn to the canvas using that method. (I'm using Chrome - not sure if that's the issue or if it's my code.)
Any ideas?
EDIT: Thanks to markE for the great solution - it's beautifully quick. I mentioned this in my comment to him, but here's the full code for creating a greyscale image (part of my requirements) that has the fade pictured in mark's demo.
img_width = window.innerWidth/2.5;
img_height = img_width * (9/16);
//hidden_ctx is hidden behind a background layer
var g1=hidden_ctx.createRadialGradient(500,500,550,500,500,650);
g1.addColorStop(0.00,"rgba(0,0,0,0.7)");
g1.addColorStop(0.30,"rgba(0,0,0,0.35)");
g1.addColorStop(1.00,"rgba(0,0,0,0.00)");
hidden_ctx.fillStyle=g1;
hidden_ctx.fillRect(0, 0, img_width, img_height);
hidden_ctx.globalCompositeOperation="source-in";
//custom drawImage method where selected[num] contains
//contains images & metadata
drawIt(hidden_ctx, selected[num].image[0], 0, 0, img_width, img_height);
imgData=hidden_ctx.getImageData(0, 0, img_width, img_height);
// invert colors
for (var i=0;i<imgData.data.length;i+=4)
{
grayscaled = 0.34 * imgData.data[i] + 0.5 * imgData.data[i + 1] + 0.16 * imgData.data[i + 2];
imgData.data[i]=grayscaled;
imgData.data[i+1]=grayscaled;
imgData.data[i+2]=grayscaled;
}
//places the converted image in the lower right corner where
//WIDTH/HEIGHT is window.innerWidth/window.innerHeight
ctx.putImageData(imgData, WIDTH-img_width, HEIGHT-img_height);
You can use compositing to achieve a fade effect more efficiently.
draw a radial gradient that fades to transparent in the top-left corner.
Adjust the radial gradient to meet your design needs.
set compositing to source-in which causes any subsequent draws to only appear over existing non-transparent pixels.
draw your image (the image will fade the same way your radial gradient did)
Using compositing is especially efficient if the device has a GPU because compositing will use it.
Example code and a Demo: http://jsfiddle.net/m1erickson/thqamsLk/
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" media="all" href="css/reset.css" /> <!-- reset css -->
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<style>
canvas{ background-color: lightgray; }
canvas{border:1px solid red;}
</style>
<script>
$(function(){
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var cw=canvas.width;
var ch=canvas.height;
var img=new Image();
img.onload=start;
img.src="https://dl.dropboxusercontent.com/u/139992952/multple/reef.jpg";
function start(){
canvas.width=img.width;
canvas.height=img.height;
var g1=ctx.createRadialGradient(500,500,550,500,500,650);
g1.addColorStop(0.00,"rgba(0,0,0,1.00)");
g1.addColorStop(0.30,"rgba(0,0,0,0.75)");
g1.addColorStop(1.00,"rgba(0,0,0,0.00)");
ctx.fillStyle=g1;
ctx.fillRect(0,0,cw,ch);
ctx.globalCompositeOperation="source-in";
ctx.drawImage(img,0,0);
}
}); // end $(function(){});
</script>
</head>
<body>
<h4>Fading an image using compositing</h4>
<canvas id="canvas" width=300 height=300></canvas>
</body>
</html>
Related
I need to rotate an image in a canvas and simultaneously resize it to make sure that the corners of the canvas does not remain empty. The solution should be something similar to what do aviary in the "Crop, Resize & Rotate" example.
I think the solution is to combine the functions of rotation and resize of canvas, but I can not find any concrete solution to the problem and I didn't find any exaustive example on the web.
Any advice would be helpful
Thanks
I have not had a look at the example you have given but I gave a detailed answer on the problem of fitting a rotated image onto a canvas so that there is no blank spaces.
There is some math involved (go figure) but it is just basic trigonometry and I provided an explanation of how its all done. There are two solutions, one that finds the min scale that will fit the canvas for any rotation and the other the will find the min scale to fit the canvas for a particular rotation.
It is assumed that the image is centered, if not there is an easy way to adapt the code provided by supplying an abstract canvas size so that the rotated image is centered on that abstract canvas.
So if your center of image is at x = 100, y = 100 and the canvas is canvasWidth = 300, canvasHeight = 300 then just use an abstract size of absCanvasWidth = (canvasWidth - x) * 2; and then the image at x = absCanvasWidth/2 do the same for height. That will fit the rotated, translated image to fill the canvas.
The answer with the code can be found for the question After rotate, draw Image at correct position
Here's some code that might help you. This shows how to rotate an image 90 degrees clockwise, then scale it to fit in the original canvas space.
window.onload = function() {
var img = document.getElementById("myImage");
var rotatedCanvas = document.getElementById("myRotatedCanvas");
var width = rotatedCanvas.offsetWidth;
var height = rotatedCanvas.offsetHeight;
// draw the original image
var ctx = document.getElementById("myCanvas").getContext("2d");
ctx.drawImage(img, 0, 0);
// draw the rotated image
ctx = rotatedCanvas.getContext("2d");
ctx.rotate(90 * Math.PI / 180);
// the last two parameters scale the image
ctx.drawImage(img, 0, -width, height, width);
};
img {
display: none;
}
canvas {
border: 1px black solid;
}
<img src="http://imgur.com/UeMOrix.gif" id="myImage"/>
<canvas id="myCanvas" width="400" height="150"></canvas>
<br>
<canvas id="myRotatedCanvas" width="400" height="150"></canvas>
I have been trying to print arc in the html page. How can i remove the already drawn arch from the page?. i have written the below code.
<!DOCTYPE html>
<html>
<body>
<canvas id="myCanvas" width="1200" height="1000"
style="border:1px solid #d3d3d3;">
Your browser does not support the HTML5 canvas tag.</canvas>
<script>
var c = document.getElementById("myCanvas");
var ctx = c.getContext("2d");
/*ctx.beginPath();
ctx.arc(600,500,20, 0.5*Math.PI,2*Math.PI);
ctx.stroke();
ctx.beginPath();
ctx.arc(600,500,40, 0.5*Math.PI,2*Math.PI);
ctx.stroke();
*/
var radius=20;
for (i=0; i<10; i++)
{
var ctx = c.getContext("2d");
ctx.beginPath();
ctx.arc(600,500,radius, 0.5*Math.PI, 2*Math.PI);
ctx.stroke();
radius= radius+30;
}
</script>
</body>
</html>
How can i achieve this?.
Call clearRect method:
ctx.clearRect(0, 0, 1200, 1000)
The four arguments are:
axis-X of left top corner of the area to wipe
axis-Y of left top corner of the area to wipe
width of the area to wipe
height of the area to wipe
So with this method, you could wipe either the whole canvas or just a certain part of it.
If you want to remove the whole previously drawn image please take a look at the other anwers. In the comments OP made it clear that this is not what he was trying to achieve. So instead I will answer the intended question:
How do I un-stroke a path?
A bitmap is not a vector graphic. You cannot simply remove or modify things you've drawn previously. By drawing on a canvas you modify the pixel color values of its image data. If you need to undo things you have to maintain a separate data structure with the relevant data yourself.
For example you could create a copy of the image data before drawing something. Then you could return to this snapshot afterwards. HTMLCanvasElement#toDataURL returns the complete image as an url which you can use as the src of an image. Later you can draw this image on the canvas to revert all subsequent changes. HTMLCanvasElement#toBlob does about the same but it returns a blob. This might consume less memory but it's a little more inconvenient to use. The most convenient method is CanvasRenderingContext2D#getImageData. You can even use it to copy only a small part of the image. This is useful if you have a big canvas but only modify pixels in a small region.
Another way to make modifications undoable is by maintaining a detailed list of your steps. For example whenever you draw an arc you store the exact parameters as one entry in the list. steps.push({type: 'stroke', style: 'rgb(0,0,0)', shapes: [{type: 'arc', x: 600, y: 500, radius: radius, from: 0.5 * Math.PI, to: 2 * Math.PI}]}) You can remove, rearrange or modify the elements in this list any way you like and have all necessary information to draw the resulting image from scratch. Basically you've implemented just another vector graphic library.
I'm working on some code which is drawing to a canvas. One part of the code draws some lines onto the canvas. The position and colour of those lines don't change, but they often need to be redrawn because other code may have affected it (eg: drawn over the top of it).
There can be several hundred lines to draw, and in these cases, profiling shows me that it's taking ~200ms to draw, so I'm looking to optimise this somewhat.
One thing I noticed was that when drawing to the canvas, you basically are adding points to a path and then once ready, you can fill or stroke that path. Though the pixels on the canvas are out of date, if I were able to keep a reference to the path, then updating would be as simple as re-stroking the previously constructed path.
My question is: how on earth do you get a Path object?
The fill and stroke methods appear to accept a path object, and the spec defines the methods for Path, but I can't seem to find the actual Path class anywhere...
So, just to recap:
I have something like this:
function update() {
context.beginPath();
// lots of lines added to the default path...
context.moveTo(x1, y1); context.lineTo(somewhere, else);
context.moveTo(x2, y2); context.lineTo(somewhere, else);
context.stroke();
}
What I'd like is something like this:
function update() {
if (!this.path) {
this.path = new Path(); // <-- here's the magic
this.path.moveTo(x1, y2); this.path.lineTo(somewhere, else); // etc
}
this.path.stroke();
}
The canvas spec calls for a Path object that is not implemented in browsers yet.
BTW, when implemented, the Path object will be useful in hit-testing when combined with context.isPointInPath(myPath); Someday...
Here's how you could create your own Path object until the browsers catch up:
Create a JS object that contains a canvas where your path strokes are drawn.
When you want to do myPath.stroke(), use myVisibleContext.drawImage(myPath.context,0,0) to "blit" the path's canvas onto your drawing canvas.
Demo: http://jsfiddle.net/m1erickson/QLJv8/
Code:
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" media="all" href="css/reset.css" /> <!-- reset css -->
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<style>
body{ background-color: ivory; }
#canvas{border:1px solid red;}
</style>
<script>
$(function(){
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
function Path(maxWidth,maxHeight,color,linewidth,drawingContext){
this.width=maxWidth;
this.height=maxHeight;
this.drawingCtx=drawingContext;
this.points=[]
this.canvas=document.createElement("canvas");
this.canvas.width=maxWidth;
this.canvas.height=maxHeight;
this.ctx=this.canvas.getContext("2d");
this.ctx.strokeStyle=color;
this.ctx.lineWidth=linewidth;
this.lastX;
this.lastY;
}
Path.prototype.moveTo=function(x,y){
this.lastX=x;
this.lastY=y;
}
Path.prototype.lineTo=function(x,y){
this.ctx.moveTo(this.lastX,this.lastY);
this.ctx.lineTo(x,y);
this.ctx.stroke();
this.lastX=x;
this.lastY=y;
}
Path.prototype.stroke=function(){
this.drawingCtx.drawImage(this.canvas,0,0);
}
// create a new path object
var p=new Path(300,300,"blue",2,ctx);
// set the Path's drawing commands
p.moveTo(69,91);
p.lineTo(250,150);
p.moveTo(69,208);
p.lineTo(180,54);
p.lineTo(180,245);
p.lineTo(69,91);
p.moveTo(69,208);
p.lineTo(250,150);
// draw the Path.canvas to the drawing canvas
p.stroke();
// tests...
$("#stroke").click(function(){
p.stroke();
});
$("#erase").click(function(){
ctx.clearRect(0,0,canvas.width,canvas.height);
});
}); // end $(function(){});
</script>
</head>
<body>
<button id="stroke">Path.stroke</button><br>
<button id="erase">Erase main canvas</button><br>
<canvas id="canvas" width=300 height=300></canvas>
</body>
</html>
Turns out, it's just that no browser supports it yet, according to this blog (dated 24th January 2013) http://www.rgraph.net/blog/2013/january/html5-canvas-path-objects.html
Their is no path support in canvas, but why don't use svg line and set its zIndex to be on top of others.
None of the canvas drawing API let you hold references to objects.
Canvas lets you draw pixels in a bitmap, not create and manipulate objects like SVG does.
If you're looking to optimize performance and you want to reuse the same path over and over again, you might want to draw it once in a separate canvas oject, and then draw that canvas into your other canvas using drawImage (which can take a canvas as argument).
How can I vertically rotate an image using only Canvas (without WebGL etc.)?
I'm looking at something like -webkit-transform: rotateY(); in CSS3.
[Edit: Oops! I think I misunderstood your question. You want to flip with 3D effect, just without webGL.]
Yes, you can do 3D rotations in canvas without webGL.
Several canvas libraries offer 3D canvas rotation...
Take a look and K3D (NICE effects!): http://www.kevs3d.co.uk/dev/canvask3d/k3d_test.html
Take a look at GreenSock: http://www.greensock.com/css3/
If you don't want any libraries at all, check out K3D. It's license is liberal enough to allow you to pull out the rotating code you need.
.
.
[My original answer below is probably off-track of what you want--but I'll leave it here anyway]
Here's how to vertically flip a canvas image
When you want to flip vertically, you ironically are flipping on the horizontal axis.
To flip on the horizontal axis you use context.scale like this:
context.scale(1,-1); // flip vertically--using the HORIZONTAL axis !
Here's code and a Fiddle: http://jsfiddle.net/m1erickson/JBCGC/
<!doctype html>
<html>
<head>
<link rel="stylesheet" type="text/css" media="all" href="css/reset.css" /> <!-- reset css -->
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<style>
body{ background-color: ivory; }
canvas{border:1px solid red;}
</style>
<script>
$(function(){
var canvasH=document.getElementById("canvasH");
var ctxH=canvasH.getContext("2d");
var img=new Image();
img.onload=function(){
// flip on the horizontal axis
// (causes upside down)
canvasH.width=img.width;
canvasH.height=img.height;
ctxH.save();
ctxH.scale(1,-1);
ctxH.translate(0,-img.height);
ctxH.drawImage(img,0,0);
ctxH.restore();
}
img.src="http://dl.dropbox.com/u/139992952/houseIcon.png";
}); // end $(function(){});
</script>
</head>
<body>
<canvas id="canvasH" width=300 height=300></canvas>
</body>
</html>
You can try this -
// translate context to center of canvas
context.translate(canvas.width / 2, canvas.height / 2);
// rotate 45 degrees clockwise
context.rotate(Math.PI / 4);
The rotate transformation requires an angle in radians.
Reference
I like #markE answer, just figured I would post this one as well. It allows you to rotate the image to whatever angle you need.
function rotate(angle) {
ctxH.clearRect(0, 0, width, height);
ctxH.save();
ctxH.translate(width / 2, height / 2);
ctxH.rotate(angle * Math.PI / 180);
ctxH.drawImage(img, -width / 2, -height / 2);
ctxH.restore();
}
markE's Modified Demo (with animation)
I am targeting google chrome. Is it possible to draw transparent images on a canvas? By transparent I mean the drawing the entire image at something like 50% opacity.
You can do this using the globalAlpha property, like this:
<!DOCTYPE HTML>
<html>
<body>
<canvas height="100" width="100" id="myCanvas"></canvas>
<script>
var canvas = document.getElementById("myCanvas");
var context = canvas.getContext("2d");
context.globalAlpha = 0.5;
var myImage = new Image();
myImage.src = "someImage.jpg";
myImage.onload = function()
{
context.drawImage(myImage, 0, 0, 100, 100);
};
</script>
</body>
</html>
And yes, it does work with images. Verified with IE 9, FF 5, Safari 5, and Chrome 12 on Win 7.
The canvas element has a global alpha attribute that lets you apply partial transparency to anything you draw.
It's possible if you iterate thru the canvas' image-data and set the alpha value manually, then export the transparent image with the canvas.toDataURL method and insert it into another canvas.