Is there a way to get a next element from a current sister element? Sorry if confusing.
<div class="wrapper">
<div class="paDiv">
<div class="saDivOne">
</div>
</div>
<div class="paDivTwo">
<div class="saDivTwo">
</div>
</div>
</div>
<script>
$('.paDiv').each(function(){
htmlContent = $(this).children().html();
SisterDivContent = $(this).next('.paDivTwo').children().html();
console.log(SisterDivContent);
})
</script>
$('.paDiv').each(function(){
var SisterDivContent = $(this).parent().find('.saDivTwo').html();
alert(SisterDivContent);
});
You have to add some contents inside div class 'saDivTwo'. Otherwise you will get empty content only.
Demo:
http://jsfiddle.net/U8n7g/
Try using .sibling:
$('.paDiv').sibling('paDivTwo').html()
Related
Lets say I have this...
<div class="container" id="continingStuff">
<div class="someClass" id="notLookingForThis" data="dataValue1">
Stuff
</div>
<div class="someClass" id="lookingForThis" data="dataValue2">
Stuff
</div>
</div>
and I want to get the id of the div thats data value is dataValue2, how can I do that with jQuery or Javascript?
You can use Attribute Equals Selector to get element, then you can use attr() method to get id of the element.
Example:
$(document).ready(function() {
var id = $('div[data=“dataValue2”]').attr('id');
console.log(id);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class=“container” id=“continingStuff”>
<div class=“someClass” id=“notLookingForThis” data=“dataValue1”>
Stuff
</div>
<div class=“someClass” id=“lookingForThis” data=“dataValue2”>
Stuff
</div>
</div>
Using jQuery, you can use this selector:
var id = $("div[data='dataValue2']").attr('id');
Here's working a code snippet:
var id = $("div[data='dataValue2']").attr('id');
console.log(id);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container" id="continingStuff">
<div class="someClass" id="notLookingForThis" data="dataValue1">
Stuff
</div>
<div class="someClass" id="lookingForThis" data="dataValue2">
Stuff
</div>
</div>
you can use this for your code
var id = $('*[data="dataValue2"]').attr('id');
i have 2 divisoin
<div id="details">
<div id="feature">
</div>
</div>
I need to put the content using $("#details").html(content); (it is working correctly) like that way i need to put the content inside feature div i am using following way:
$("#details #feature").html(content);
but it is not working..how to solve?
When you use $("#details").html(content); you override the content of the div. So you're inner div with the id feature gets removed. Maybe you use $("#details").prepend(content); or you add another div for the main content and replace that content.
Look here is an example:
https://jsfiddle.net/morrisjdev/s9u7rfcu/
ID is a unique attribute so you can directly use id like below.
$(function() {
var content = "Some text here";
$('#feature').html(content);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="details">
<div id="feature">
</div>
</div>
OR
$(function() {
var content = "Some text here";
$('#details').find('#feature').html(content);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="details">
<div id="feature">
</div>
</div>
$(document).ready(function(){
var htmldetail ="Hello! I am Here";
var details = $("#details").html(htmldetail);
$("#userfeature").html(details);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<div id="details">
<div id="userfeature">
</div>
</div>
The second is #feature and not #userfeature. And also add the jQuery Library as well. You can replace test with content variable.
$("#feature").html("test");
<div id="details">
<div id="feature">
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
And also remember Id is unique and hence no need to mention its parent.
Run the following snippet and you can get the output.
Simple way..Go Through this
HTML
<div id="details">
<div id="feature">
</div>
</div>
JQUERY
$(document).ready(function()
{
var content="contain sample data";
// $("#details").html(content); if you wrote like this,
this will replace all content, so the inner div will be replaced
$("#details").append(content); // outer div
$("#feature").html(content);
});
Or you can use css-like selector method:
$(document).ready(function() {
$('#details > #feature').html('Hello <strong>World!!!</strong>');
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="details">
<div id="feature">
</div>
</div>
I have created a plunk for it and it is working.
Try including the action inside
$( document ).ready(function() {
console.log( "ready!" );
var content = 'Hey there';
$("#details #feature").html(content);
});
Plunk :- http://plnkr.co/edit/63GsIoGmprnKs7oe77cF?p=preview
I have two divs on my website. They both share the same css properties, but one of them holds 24 other divs. I want all of these 24 divs to be copied into the other div.
This is how it looks like:
<div id="mydiv1">
<div id="div1">
</div>
</div id="div2>
</div>
//and all the way up to div 24.
</div>
<div id="mydiv2">
</div>
I want all of the 24 divs within mydiv1 to be copied into mydiv2 when the page loads.
Thanks in advance
Firstly we are assigning divs into variables (optional)
var firstDivContent = document.getElementById('mydiv1');
var secondDivContent = document.getElementById('mydiv2');
Now just assign mydiv1's content to mydiv2.
secondDivContent.innerHTML = firstDivContent.innerHTML;
DEMO
http://jsfiddle.net/GCn8j/
COMPLETE CODE
<html>
<head>
<script type="text/javascript">
function copyDiv(){
var firstDivContent = document.getElementById('mydiv1');
var secondDivContent = document.getElementById('mydiv2');
secondDivContent.innerHTML = firstDivContent.innerHTML;
}
</script>
</head>
<body onload="copyDiv();">
<div id="mydiv1">
<div id="div1">
</div>
<div id="div2">
</div>
</div>
<div id="mydiv2">
</div>
</body>
</html>
You can use the .ready() event of jquery
jQuery(document).ready(function() {
jQuery('.div1').html(jQuery("#div2").html());
}
Also a working DEMO.
var divs = document.getElementById('mydiv1').innerHTML;
document.getElementById('mydiv2').innerHTML= divs;
Alternative in jquery You can use clone and put it in your target div. Example:
$('#mydiv1').clone().appendTo('#mydiv2');
Copy #mydiv1 into #mydiv2
Try this one in 2022.
let clonedDiv = document.getElementById('myDiv').cloneNode(true);
document.body.appendChild(clonedDiv);
I have created a document with html. I want to retrieve child node from the root node for that I am using following code...
That is HTML.
<a id="Main1" onclick="RetrieveElement(this);">Test1
<div name="Top1">
</div>
<div name="Middle1">
I'm Middle.
</div>
<div name="Bottom1">
</div>
</a>
<a id="Main2" onclick="RetrieveElement(this);">Test2
<div name="Top1">
</div>
<div name="Middle1">
I'm Middle.
</div>
<div name="Bottom1">
</div>
</a>
javascript.
function RetrieveElement(element){
alert(this.getElementByName("Middle1").innerHTML);
}
However, That is not working. I have tried finding the problem but cant solve it... Any help ?
If you want to get the first child element only:
var element = document.getElementById('Main1').children[0];
If you want to get the first anchor element:
var element = document.getElementById('Main1').getElementById('Middle1');
getElementById is a method of Document, not Element. Try this:
<script type="text/javascript">
function RetrieveElement(element){
window.alert(document.getElementById("Middle1").innerHTML);
}
</script>
<a id="Main1" href="#" onclick="RetrieveElement(this);">Test1</a>
<div id="Top1">
</div>
<div id="Middle1">
I'm Middle.
</div>
<div id="Bottom1">
</div>
Can you use jQuery?
It would be as easy as this
<div class="full_widget">
<div class="connect_top clearfix">
</div>
<div id="stream_content" class="page_stream_short">
</div>
<div class="connections">
</div>
</div>
what i whant to do is to move connections class in the first place juste after
<div class="full_widget">
just like this :
<div class="full_widget">
<div class="connections">
</div>
<div class="connect_top clearfix">
</div>
<div id="stream_content" class="page_stream_short">
</div>
</div>
thanks
$(".connections").prependTo(".full_widget");
This will always move .connections to the inner top of .full_widget.
$(".connections").insertBefore(".connect_top");
If you added in another element to the top, using insertBefore() will insure it's displayed right above .connect_top, instead of moving it directly to the top.
If you have more than one of those, simply do:
$(".connections").prepend(function() {
var ele = $(this);
ele.prependTo(ele.parent());
});
You can use the jquery prepend function:
$('.full_widget').prepend( $('.connections') );
$('.full_widget').prepend($('.connections'));