il8n = {
'en-us':{
hello:"Hello Everyone",
goodbye:"See ya later",
welcome:"Hello how are you?",
design:"Kandi Designs"
}
};
function translate(){
var userLang = navigator.language || navigator.userLanguage;
var body = document.body || document.getElementsByTagName('body')[0];
var html = body.innerHTML;
body.innerHTML = body.innerHTML.replace(/({T_(.*?)})/g, il8n[userLang.toLowerCase()][$1.replace(/{T_|},'').toLowerCase()]);
}
translate();
Basically what I want to do is get rid of {T_Hello} to Hello Everyone but since I suck at regex my capture groups and using $1 I can't get this correctly. Can anyone assist in this a wee bit?
You have the right idea. $1, however, is not a variable where you use it. Change the second argument to replace to this:
function (match, $1) {
return il8n[userLang.toLowerCase()][$1.toLowerCase()];
}
replace can take a function as an argument. Then, shorten the capture group in the regex to this:
/{T_(.*?)}/g
This saves you some unnecessary string processing inside the replace function. On an unrelated note, regarding performance, you might want the server to send the appropriate il8n object based on the Accept-Language header, or, even better, do the insertions itself instead of relying on flaky and slow client-side code (making it cacheable).
Based on your il8n object keys you could do this to check for T_ followed by any uppercase letters.
/T_([A-Z]+)/
You could add lowercase or numbers to it too:
/T_([A-Za-z0-9]+)/
This should work:
body.innerHTML = body.innerHTML.replace(
/({T_(.*?)})/g,
function (s) { return il8n [userLang.toLowerCase()] [s.replace(/{T_|}/g,'').toLowerCase()]; }
);
The second argument of replace() can be a string or a function that takes so many arguments as there are ()-groups in the regular expression, which in your case is one.
Indeed, if you write
s.replace (/a/g, 'b')
then, obviously, replace() receives two strings. However, if you write
s.replace (/a/g, f(x))
then again, replace() receives two strings, the second being the string returned from f(x), so if f(x) returns 'b', then the two expressions above are equivalent. Since f(x) is executed before replace() has a chance to see it, it cannot use the special variables like $1, since at the point of call they are not defined.
If you want the code to be executed by replace(), then it should be executable code:
replace (/a/g, function (x) { return ' [' + x + '] found! '; } )
so that at the point of call, the function object is formed and this function is called inside replace with the argument $1 each time (note the global modifier g in the regex).
Note that your code will only work if placed below the text or called onload(), not above the text:
<body>
{T_hello} reader!
<script>
your code
</script>
<body>
works, but
<body>
<script>
your code
</script>
{T_hello} reader!
<body>
doesn't, because when it is executed, there is nothing still in <body>. The best place to call it is in <body onload='translate()'>.
I also corrected a typo in your code: s.replace(/{T_|} should be s.replace(/{T_|}/.
And another error in your code is: s.replace(/{T_|}/ should be s.replace(/{T_|}/g, because it is supposed to make two replacements, not one.
Related
I'd like to know how to replace a capture group with its uppercase in JavaScript. Here's a simplified version of what I've tried so far that's not working:
> a="foobar"
'foobar'
> a.replace( /(f)/, "$1".toUpperCase() )
'foobar'
> a.replace( /(f)/, String.prototype.toUpperCase.apply("$1") )
'foobar'
Would you explain what's wrong with this code?
You can pass a function to replace.
var r = a.replace(/(f)/, function(v) { return v.toUpperCase(); });
Explanation
a.replace( /(f)/, "$1".toUpperCase())
In this example you pass a string to the replace function. Since you are using the special replace syntax ($N grabs the Nth capture) you are simply giving the same value. The toUpperCase is actually deceiving because you are only making the replace string upper case (Which is somewhat pointless because the $ and one 1 characters have no upper case so the return value will still be "$1").
a.replace( /(f)/, String.prototype.toUpperCase.apply("$1"))
Believe it or not the semantics of this expression are exactly the same.
I know I'm late to the party but here is a shorter method that is more along the lines of your initial attempts.
a.replace('f', String.call.bind(a.toUpperCase));
So where did you go wrong and what is this new voodoo?
Problem 1
As stated before, you were attempting to pass the results of a called method as the second parameter of String.prototype.replace(), when instead you ought to be passing a reference to a function
Solution 1
That's easy enough to solve. Simply removing the parameters and parentheses will give us a reference rather than executing the function.
a.replace('f', String.prototype.toUpperCase.apply)
Problem 2
If you attempt to run the code now you will get an error stating that undefined is not a function and therefore cannot be called. This is because String.prototype.toUpperCase.apply is actually a reference to Function.prototype.apply() via JavaScript's prototypical inheritance. So what we are actually doing looks more like this
a.replace('f', Function.prototype.apply)
Which is obviously not what we have intended. How does it know to run Function.prototype.apply() on String.prototype.toUpperCase()?
Solution 2
Using Function.prototype.bind() we can create a copy of Function.prototype.call with its context specifically set to String.prototype.toUpperCase. We now have the following
a.replace('f', Function.prototype.apply.bind(String.prototype.toUpperCase))
Problem 3
The last issue is that String.prototype.replace() will pass several arguments to its replacement function. However, Function.prototype.apply() expects the second parameter to be an array but instead gets either a string or number (depending on if you use capture groups or not). This would cause an invalid argument list error.
Solution 3
Luckily, we can simply substitute in Function.prototype.call() (which accepts any number of arguments, none of which have type restrictions) for Function.prototype.apply(). We have now arrived at working code!
a.replace(/f/, Function.prototype.call.bind(String.prototype.toUpperCase))
Shedding bytes!
Nobody wants to type prototype a bunch of times. Instead we'll leverage the fact that we have objects that reference the same methods via inheritance. The String constructor, being a function, inherits from Function's prototype. This means that we can substitute in String.call for Function.prototype.call (actually we can use Date.call to save even more bytes but that's less semantic).
We can also leverage our variable 'a' since it's prototype includes a reference to String.prototype.toUpperCase we can swap that out with a.toUpperCase. It is the combination of the 3 solutions above and these byte saving measures that is how we get the code at the top of this post.
Why don't we just look up the definition?
If we write:
a.replace(/(f)/, x => x.toUpperCase())
we might as well just say:
a.replace('f','F')
Worse, I suspect nobody realises that their examples have been working only because they were capturing the whole regex with parentheses. If you look at the definition, the first parameter passed to the replacer function is actually the whole matched pattern and not the pattern you captured with parentheses:
function replacer(match, p1, p2, p3, offset, string)
If you want to use the arrow function notation:
a.replace(/xxx(yyy)zzz/, (match, p1) => p1.toUpperCase()
Old post but it worth to extend #ChaosPandion answer for other use cases with more restricted RegEx. E.g. ensure the (f) or capturing group surround with a specific format /z(f)oo/:
> a="foobazfoobar"
'foobazfoobar'
> a.replace(/z(f)oo/, function($0,$1) {return $0.replace($1, $1.toUpperCase());})
'foobazFoobar'
// Improve the RegEx so `(f)` will only get replaced when it begins with a dot or new line, etc.
I just want to highlight the two parameters of function makes finding a specific format and replacing a capturing group within the format possible.
SOLUTION
a.replace(/(f)/,(m,g)=>g.toUpperCase())
for replace all grup occurrences use /(f)/g regexp. The problem in your code: String.prototype.toUpperCase.apply("$1") and "$1".toUpperCase() gives "$1" (try in console by yourself) - so it not change anything and in fact you call twice a.replace( /(f)/, "$1") (which also change nothing).
let a= "foobar";
let b= a.replace(/(f)/,(m,g)=>g.toUpperCase());
let c= a.replace(/(o)/g,(m,g)=>g.toUpperCase());
console.log("/(f)/ ", b);
console.log("/(o)/g", c);
Given a dictionary (object, in this case, a Map) of property, values, and using .bind() as described at answers
const regex = /([A-z0-9]+)/;
const dictionary = new Map([["hello", 123]]);
let str = "hello";
str = str.replace(regex, dictionary.get.bind(dictionary));
console.log(str);
Using a JavaScript plain object and with a function defined to get return matched property value of the object, or original string if no match is found
const regex = /([A-z0-9]+)/;
const dictionary = {
"hello": 123,
[Symbol("dictionary")](prop) {
return this[prop] || prop
}
};
let str = "hello";
str = str.replace(regex, dictionary[Object.getOwnPropertySymbols(dictionary)[0]].bind(dictionary));
console.log(str);
In the case of string conversion from CamelCase to bash_case (ie: for filenames), use a callback with ternary operator.
The captured group selected with a regexp () in the first (left) replace arg is sent to the second (right) arg that is a callback function.
x and y give the captured string (don't know why 2 times!) and index (the third one) gives the index of the beginning of the captured group in the reference string.
Therefor a ternary operator can be used not to place _ at first occurence.
let str = 'MyStringName';
str = str.replace(/([^a-z0-9])/g, (x,y,index) => {
return index != 0 ? '_' + x.toLowerCase() : x.toLowerCase();
});
console.log(str);
I have a Javascript application where I need to escape characters like "<" and ">" in a string.
This looks like an ideal solution:
How to escape HTML
function escapeHTML(str){
var p = document.createElement("p");
p.appendChild(document.createTextNode(str));
return p.innerHTML;
}
or a short alternative using the
Option()
constructor
function escapeHTML(str){
return new Option(str).innerHTML;
}
Q: Does this actually add "p" (and the associated text) to my DOM?
Q: Do I need a "removeChild()" or any other "cleanup" if all I want to save is the escaped string?
A1: No, that would be if the function also called document.body.appendChild(p);
A2: No, as you can probably guess from A1. After the function returns, its local variables are discarded, the p becomes unreachable, and will eventually be garbage-collected.
I have a basic replace function, but I need it to perform a global replace, as it seems to be stopping on the first instance. I do not want to do it with a Regex. Applying the global attribute seems easy enough in most examples, but I am passing in a variable as the value to be replaced, and /g is having no impact. What am I doing wrong? Here is the example without the /g:
test string
"Why is my ^%friend so ^%? Maybe I need a ^!% one, abrand^!% one"
Simple replace function
function translate(oddStr) {
var tagDictionary = {};
tagDictionary['^%'] = 'odd';
tagDictionary['^!%'] = 'new';
Object.keys(tagDictionary).forEach( function (tag) {
oddStr = oddStr.replace(tag, tagDictionary[tag]);
});
return oddStr;
};
This function returns the first instance of each replaced, as expected. How can I apply /g to the tag variable in the forEach?
Use a split-join combo like this:
oddStr = oddStr.split(tag).join(tagDictionary[tag]);
"Why is my ^% friend so ^%? Maybe I need a ^!% one, abrand ^!% one".replace(/\^%/g, 'odd').replace(/\^!%/g, 'new')
"Why is my odd friend so odd? Maybe I need a new one, abrand new one"
If you need to create the regular expression from string, you can use RegExp constructor: new RegExp('\\^%', 'g').
If you don't have control over the tag-dictionary and it is coming from some external resource, then you will have to properly escape the tags.
Instead of using adhoc symbols for templating you should ideally use something like lodash.template
You need to escape your regex special characters (^=Start of string)
function translate(oddStr) {
var tagDictionary = {
'\\^%' : "odd",
'\\^!%' : 'new'
};
Object.keys(tagDictionary).forEach( function (tag) {
var r = new RegExp(tag, "g");
oddStr = oddStr.replace(r, tagDictionary[tag]);
});
return oddStr;
};
console.log(translate("Why is my ^%friend so ^%? Maybe I need a ^!% one, a brand ^!% one"));
I'm trying to alert any JavaScript object as a string, in a function. This means if the parameter given to the function is window.document, the actual object, it should alert "window.document" (without quotes) as a literal string.
The following calls...
example(window);
example(window.document);
example(document.getElementById('something'));
...calling this function...
function example(o) {/* A little help here please? */}
...should output the following strings...
window
window.document
document.getElementById('something')
I've attempted to do this with combinations of toString() and eval() among some more miscellaneous shots in the dark without success.
No need insane backwards compatibility, newer ECMAScript / JavaScript features/functions are fine. Feel free to inquire for clarifications though the goal should be pretty straight forward.
This is not possible to do in a self contained script.
If using a preprocessor would be an option, then you could write one which converts example(whatever) into example('whatever'). Other than that I'm afraid you're out of luck.
The first problem is that objects don't have names.
The second problem is that from your examples, you're not really wanting to print the (nonexistent) name of an object, you want to print the expression that evaluated into a reference to an object. That's what you're trying to do in this example:
example(document.getElementById('something'));
For that to print document.getElementById('something'), JavaScript would have had to keep the actual text of that expression somewhere that it would make available to you. But it doesn't do that. It merely evaluates the parsed and compiled expression without reference to the original text of the expression.
If you were willing to quote the argument to example(), then of course it would be trivial:
example( "document.getElementById('something')" );
Obviously in this case you could either print the string directly, or eval() it to get the result of the expression.
OTOH, if you want to try a real hack, here's a trick you could use in some very limited circumstances:
function example( value ) {
var code = arguments.callee.caller.toString();
var match = code.match( /example\s*\(\s*(.*)\s*\)/ );
console.log( match && match[1] );
}
function test() {
var a = (1);
example( document.getElementById('body') );
var b = (2);
}
test();
This will print what you wanted:
document.getElementById('body')
(The assignments to a and b in the test() function are just there to verify that the regular expression isn't picking up too much code.)
But this will fail if there's more than one call to example() in the calling function, or if that call is split across more than one line. Also, arguments.callee.caller has been deprecated for some time but is still supported by most browsers as long as you're not in strict mode. I suppose this hack could be useful for some kind of debugging purposes though.
Don't know why you need this, but you can try walking the object tree recursively and compare its nodes with your argument:
function objectName(x) {
function search(x, context, path) {
if(x === context)
return path;
if(typeof context != "object" || seen.indexOf(context) >= 0)
return;
seen.push(context);
for(var p in context) {
var q = search(x, context[p], path + "." + p);
if(q)
return q;
}
}
var seen = [];
return search(x, window, "window");
}
Example:
console.log(objectName(document.body))
prints for me
window.document.activeElement
When I want to replace some parts of a string, should I call replace directly like this?
var r1 = /"\+((:?[\w\.]+)(:?(:?\()(:?.*?)(:?\))|$){0,1})\+"/g;
arg = arg.replace(r1, function(outer, inner){
return eval(inner);
});
Or test for a match first, and then replace if it's a hit, like this?
var r1 = /"\+((:?[\w\.]+)(:?(:?\()(:?.*?)(:?\))|$){0,1})\+"/g;
if (r1.test(arg)) {
arg = arg.replace(r1, function(outer, inner){
return eval(inner);
});
}
I guess this boils down to how the string.replace(regex, string) function works. Will it go into my callback even if there is no match, or will it then simply return arg? In that case I assume the calling replace directly is the right way to go to avoid having the regex engine match the string twice?
You don have to use test. The function in replace only executed when a match occurs.
No matches: No function (eval) call
1 match: 1 call
2 matches: 2 calls
etc.
Also, why are you using eval? eval executes the parameter, as if it's a JavaScript expression. Since you know the input format, it's likely that you're able to achieve the same behaviour without eval.