Here I am getting values from textarea in array variable.
After that I convert javascript variable to PHP variable and perform some processing over it.
After process completed again I convert PHP to JS and alert. But when I alert, it gives empty result.
<script>
$( "#convert" ).click(function() {
var arabic = document.getElementById("ar").value; // ar is id of text area
<?php $ar_terms = "<script>document.write(arabic)</script>"?>
<?php
$string=implode(",",$ar_terms);
$result = array();
foreach ($ar_terms as $term) {
// echo $Arabic->ar2en($term);
array_push($result, $Arabic->ar2en($term));
}
$result=implode(",",$result);
?>
var arabic = new Array();
arabic='<?php echo $result; ?>';
alert(arabic);
});
</script>
Entire code is here : https://gist.github.com/karimkhanp/d4ac41fa864fd8ae0521
You can do one thing in this scenario to pass the variable from PHP to js. You can convert the array using json_encode() before echoing:
$result=json_encode( implode(",",$result) );
As a result, when you assign this variable to js in the <?= ?> block, it will read the json string and thus the array will be assigned:
arabic='<?php echo $result; ?>';
Related
I am trying to call JavaScript function in php and pass it value of a php json array type variable as an argument. I found from search on SO forum one way to do this is to echo/print_r the variable value to a js var inside a js script within php code. I am trying do it this way but I am not able to recover from 'unexpected token: identifier error ' while doing so.
I am trying to figure out the reason of syntax error but couldn't. I tried different ways what I found; by putting quotes single/double around php part within the script, without quotes as some places I found solution with quotes some places without but no one seems working.
Here is my code. It will be very helpful if someone sees it and point what is causing this error.
<script>
dspChrt(WData);
.......
</script>
<HTML>
<?php
$WData;
require("Connection.php");
try {
$stmt = $conn->prepare("Select humidity, temperature FROM weatherdata");
$stmt->execute();
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach($stmt->fetchAll() as $k=>$v) {
$WData = json_encode($v);
//print_r($WData);
}?>
<script>
var Wdata = <?php print_r($WData);?>
dspChrt(WData);
consol.log(WData);
</script>
<?php
}
catch(PDOException $e) {
echo "Error: " . $e->getMessage();
}
?>
</HTML>
First of all you need to parse the JSON using JSON.parse.
Also you need to change the sequence of php and javascript code.
If you want to assign php data to Javascript variable, please retrieve data using php first and write javascript code below it.
For example :
<?php
$v = array(1,2,3);
$data = json_encode($v);
?>
<script>
var WData = JSON.parse('<?php echo $data; ?>');
dspChrt(WData);
</script>
You should encode your PHP into JSON to pass it to JavaScript.
And you should prepare your data first.
<?php
$data = array('xxx'=>'yyy');
?>
<script>
var data = <?php echo json_encode($data); ?>;
//then in js, use the data
</script>
for your code, there are too many errors to be fixed:
<HTML>
<?php
require("Connection.php");
$stmt = $conn->prepare("Select humidity, temperature FROM weatherdata");
$stmt->execute();
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
$WData = array();
foreach($stmt->fetchAll() as $k=>$v) {
$WData[] = $v;
}
?>
<script>
var WData = <?php echo json_encode($WData);?>;
console.log(WData);
dspChrt(WData);
</script>
</HTML>
Here is my code to call AJAX and get the response from another PHP file:
$.post('<?php echo get_site_url(); ?>/ajax-script/',{pickup:pickup,dropoff:dropoff,km:km},
function(data){
$('#fare').html(data);
$('#loading_spinner').hide();
});
ajaxscript.php file
$jsonData = '{"fare":30580,"actual_distance":1519,"city":"Islamabad","status":true}';
$json = json_decode($jsonData,true);
echo $json['fare'];
This code gives me the fare at the time of $('#fare').html(data);
But I need to extract the city from JSON, too, and for this I added an extra line in ajaxscript.php:
echo $json['city'];
After doing this, it gives me 30580Islamabad
How can I store these two values separately in JavaScript? I need them for future work.
You are doing everything backwards
Your PHP should be
$jsonData = '{"fare":30580,"actual_distance":1519,"city":"Islamabad","status":true}';
//$json = json_decode($jsonData,true);
echo $jsonData;
As you already have a JSONString to send to your javascript.
Then your javascript will recieve a javascript object in the data parameter of
$.post( '<?php echo get_site_url(); ?>/ajax-script/',
{pickup:pickup,dropoff:dropoff,km:km},
function( data ) {
$('#fare').html(data.fare);
$('#city').html(data.city);
$('#loading_spinner').hide();
}, "json");
Note the "JSON" at the end of the javascript to tell it to expect a JSON Object, it will then convert the JSONString to a javascript Object automatically for you so the data parameter will be an onbect
Add Special characters at the end of each value and in jquery, using jquery split, cut the variable and display
like below;
$jsonData = '{"fare":30580^^,"actual_distance":1519^^,"city":"Islamabad^^","status":true}';
$json = json_decode($jsonData,true);
echo $json['fare'];
in jquery
function(data){
var tdata = data.split("^^");
$('#fare').html(tdata[0]);
$('#loading_spinner').hide();
});
php file
$querySelectWordFilter = "SELECT * FROM badwordfilter";
$stmtSelectWordFilter = $conn->prepare($querySelectWordFilter);
$stmtSelectWordFilter->execute();
while($rowSelectWordFilter = $stmtSelectWordFilter->fetch()){
$Array[] = $rowSelectWordFilter["filterWord"];
}
foreach($Array as $val){
echo $val;
}
Javascript file
<script>
var filter = ['ass', 'evil','ugly'];
</script>
Question : Firstly,I select all the value from database and store it into array.But how can i pass the PHP array variable into JavaScript filter variable?
No need of foreach loop just create your array
while($rowSelectWordFilter = $stmtSelectWordFilter->fetch()){
$Array[] = $rowSelectWordFilter["filterWord"];
}
And in JavaScript use json_encode as
<script>
var filter = <?php echo json_encode($Array); ?>;
</script>
I understand that the format for passing a PHP array to Javascript is:
<script type="text/javascript">
var obj = <?php echo json_encode($php_variable); ?>;
</script>
I have a php function that stores some values in a longitude and latitude array. These array do hold the right values within php since print_r() within php shows me that the array is correct.
print_r($latitude_array);
print_r($longitude_array);
Now, I pass on this array to JS in this manner:
<script>
var lati_array = "<?php echo json_encode($latitude_array); ?>";
var longi_array = "<?php echo json_encode($longitude_array); ?>";
alert(lati_array[0]);
</script>
In the beginning, when I open the HTML file, it shows me an empty array (which is expected because the PHP arrays aren't filled yet). Then user enters something, the php arrays are filled up with longitudes and latitudes. These values should now be passed to JS. However, it doesn't alert anything after that. I can't be sure if array is successfully passed to JS. What am I missing?
Try this:
<script>
var data = <?php echo json_encode( $data ); ?>;
</script>
Try like below:
<?php
$array_var = array(111, 222, 333, 444);
?>
<script>
var array_var = "<?php echo json_encode($array_var); ?>";
console.log(array_var);
array_var = JSON.parse(array_var);
console.log(array_var);
alert(array_var[0]);
</script>
You are getting a string in lati_array , Try to convert it into json like this:
<script>
var lati_array = "<?php echo !empty($latitude_array) ? json_encode($latitude_array) : ''; ?>";
var longi_array = "<?php echo !empty($longitude_array) ? json_encode($longitude_array) : ''; ?>";
lati_array = JSON.parse(lati_array);
alert(lati_array[0]);
</script>
I'm trying to make a very simple autocomplete function on a private website using a trie in JavaScript. Problem is the examples I have seen and trying are just using a predefined list in a JavaScript array.
e.g. var arrayObjects = ["Dog","Cat","House","Mouse"];
What I want to do is retrieve MySQL results using PHP and put them into a JavaScript array.
This is what I have so far for the PHP (the JavaScript is fine just need to populate the array):
<?php
$mysqli = new mysqli('SERVER', 'U/NAME', 'P/WORD', 'DB');
if (!$mysqli)
{
die('Could not connect: ' . mysqli_error($mysqli));
}
if ($stmt = $mysqli->prepare("SELECT category.name FROM category")) {
$stmt->bind_result($name);
$OK = $stmt->execute();
}
while($stmt->fetch())
{
printf("%s, ", $name);
}
?>
Then I want to insert essentially each value using something like mysql_fetch_array ($name); (I know this is incorrect but just to show you guys what's going on in my head)
<script> -- this is the javascript part
(function() {
<?php while $stmt=mysql_fetch_array($name))
{
?>
var arrayObjects = [<?php stmt($name) ?>];
<?php }
?>
I can retrieve the results echoing out fine, I can manipulate the trie fine without MYSQL results, I just can't put them together.
In this case, what you're doing is looping through your result array, and each time you're printing out the line var arrayObjects = [<?php stmt($name) ?>];. However this doesn't convert between the PHP array you're getting as a result, and a javascript array.
Since you started doing it this way, you can do:
<?php
//bind to $name
if ($stmt = $mysqli->prepare("SELECT category.name FROM category")) {
$stmt->bind_result($name);
$OK = $stmt->execute();
}
//put all of the resulting names into a PHP array
$result_array = Array();
while($stmt->fetch()) {
$result_array[] = $name;
}
//convert the PHP array into JSON format, so it works with javascript
$json_array = json_encode($result_array);
?>
<script>
//now put it into the javascript
var arrayObjects = <?php echo $json_array; ?>
</script>
Use json_encode to turn your PHP array into a valid javascript object. For example, if you've got the results from your database in a php array called $array:
var obj = "<?php echo json_encode($array); ?>";
You can now use obj in your javascript code
For the auto-completion you can use the <datalist> tag. This is a relatively new feature in HTML5 (see support table) but the polyfill exists.
Fill the <option> tags in php when building the page and you a are done.