given string is
var strg = "RoomItemsQuantity[items][1][itemId]"
I'm having the above string value.How can i get itemId from the string.
var index = strg.lastIndexOf("[");
var fnstrg = strg.substr(index+1);
var fnstrg = fnstrg.replace("]","");
I've done like this is there any easiest way to do this?
thanks,
This code...
var arr = "RoomItemsQuantity[items][1][itemId]".replace(/]/g, "").split("[")
Will result in an array like this:
["RoomItemsQuantity", "items", "1", "itemId"]
Then...
arr[arr.length - 1]
Will give you what you want.
If the above pattern is fixed, then you could use the following trick :
var myString = "RoomItemsQuantity[items][1][itemId]";
var myItemId = (myString+"[").split("][")[2]
You can use a regular expression like:
('RoomItemsQuantity[items][1][itemId]'.match(/([^\[]+)\]$/) || [])[1] // itemId
You can also use lookahead or lookbehind but support may not be available.
Related
I have the following string:
var fileName = $(this).val();
this will give me a result:
C:\fakepath\audio_recording_47.wav
what I want is to obtain : audio_recording_47.wav
so, I need to trim it but I don't know how using javascript
please help
filename.split('\\').reverse()[0];
This will split the path by slashes, to obtain each part. Then to keep it simple, i reverse the array, so the last part that you need is now the first; and get the first part.
Or, even more simply: filename.split('\\').pop(), which will get the last item from the array.
You could write a little function to return the base name of the path:
function basename(fn) {
var x = fn.lastIndexOf("\\");
if (x >= 0) return fn.substr(x + 1);
return fn;
}
var filename = basename($(this).val());
You can do like this:
var fileName = $(this).val();
var path = fileName.split('\\');
var lastValue = path[path.length-1];
console.log(lastValue);//audio_recording_47.wav
Or, the shorter way you can do like this:
var fileName = $(this).val();
var path = fileName.split('\\').slice(-1);//audio_recording_47.wav
This should do it:
var trimmedFileName = fileName.match(/[^\\]*$/);
It matches everything that isn't a \ until the end of the string.
You could use a regular expression, like this:
var fileName = this.value.replace(/(?:[^\\\/]*[\\\/])*/, '');
Also, there is no need to use that snippet of jQuery, as this.value is both faster and simpler.
I have a string like
/abc/def/hij/lmn.o // just a raw string for example dont know what would be the content
I want only /abc/def/hij part of string how do I do that.
I tried using .split() but did not get any solution.
If you want to remove the particular string /lmn.o, you can use replace function, like this
console.log(data.replace("/lmn.o", ""));
# /abc/def/hij
If you want to remove the last part after the /, you can do this
console.log("/" + data.split("/").slice(1, -1).join("/"));
# /abc/def/hij
you can do
var str = "/abc/def/hij/lmn.o";
var dirname = str.replace(/\/[^/]+$/, "");
Alternatively:
var dirname = str.split("/").slice(0, -1).join("/");
See the benchmarks
Using javascript
var x = '/abc/def/hij/lmn.o';
var y = x.substring(0,x.lastIndexOf("/"));
console.log(y);
var s= "/abc/def/hij/lmn.o"
var arr= s.split("/");
after this, use
arr.pop();
to remove the last content of the array which would be lmn.o, after which you can use
var new_s= arr.join("/");
to get /abc/def/hij
So I have objects listed like favoriteImage1, favoriteImage2... favoriteImage22. How do I get the number at the end of word? I tried parseInt but it returns undefined. Is there an easy way to do this?
Use a regular expression:
var string = "favoriteImage1";
var num = +string.replace(/\D/g, "");
If the name will always have the prefix "favoriteImage", you could also do
var x = "favoriteImage1";
var num = parseInt(x.substring(13));
Can someone please help. I need to get the characters between two slashes e.g:
Car/Saloon/827365/1728374
I need to get the characters between the second and third slashes. i.e 827365
You can use the split() method of the String prototype, passing in the slash as the separator string:
const value = 'Car/Saloon/827365/1728374';
const parts = value.split('/');
// parts is now a string array, containing:
// [ "Car", "Saloon", "827365", "1728374" ]
// So you can get the requested part like this:
const interestingPart = parts[2];
It's also possible to achieve this as a one-liner:
const interestingPart = value.split('/')[2];
Documentation is here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split
This will simply alert 1728374, as you want
alert("Car/Saloon/827365/1728374".split('/')[3]);
or, a bit longer, but also more readable:
var str = "Car/Saloon/827365/1728374";
var exploded = str.split('/');
/**
* str[0] is Car
* str[1] is Saloon
* str[2] is 827365
* str[3] is 1728374
*/
Try the_string.split('/') - it gives you an array containing the substrings between the slashes.
try this:
var str = 'Car/Saloon/827365/1728374';
var arr = str.split('/'); // returns array, iterate through it to get the required element
Use split to divide the string in four parts:
'Car/Saloon/827365/1728374'.split('/')[2]
Gives "827365"
You will have to use the .split() function like this:
("Car/Saloon/827365/1728374").split("/")[2];
"Car/Saloon/827365/1728374".split("/")[2]
"Car/Saloon/827365/1728374".split("/")[3]
How many you want you take it.. :)
var str = "Car/Saloon/827365/1728374";
var items = str.split("/");
for (var i = 0; i < items.length; i++)
{
alert(items[i]);
}
OR
var lastItem = items[items.length - 1]; // yeilds 1728374
OR
var lastItem1728374 = items[2];
Javascript:
var string = '(37.961523, -79.40918)';
//remove brackets: replace or regex? + remove whitespaces
array = string.split(',');
var split_1 = array[0];
var split_2 = array[1];
Output:
var split_1 = '37.961523';
var split_2 = '-79.40918';
Should I just use string.replace('(', '').replace(')', '').replace(/\s/g, ''); or RegEx?
Use
string.slice(1, -1).split(", ");
You can use a regex to extract both numbers at once.
var string = '(37.961523, -79.40918)';
var matches = string.match(/-?\d*\.\d*/g);
You would probably like to use regular expressions in a case like this:
str.match(/-?\d+(\.\d+)?/g); // [ '37.961523', '-79.40918' ]
EDIT Fixed to address issue pointed out in comment below
Here is another approach:
If the () were [] you would have valid JSON. So what you could do is either change the code that is generating the coordinates to produce [] instead of (), or replace them with:
str = str.replace('(', '[').replace(')', ']')
Then you can use JSON.parse (also available as external library) to create an array containing these coordinates, already parsed as numbers:
var coordinates = JSON.parse(str);