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How to get the value of title image and content in ajax php

How to display the data title, image and content?
Here's the code:
view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$dataArr = array();
$responseArr = array();
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
array_push($dataArr, $data);
}
echo json_encode($dataArr);
}
mysqli_free_result($result);
} else {
echo "No Record";
}
}
index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
alert(data)
}
});
});
});
What I'm trying to do is to get the title, image and content.
How to get the value of title, image and content?
How to call the "title", "name" and "content" from the php?
console.log('DATA: ' + data);

No need to use while loop for result. Also remove extra $dataArr and $responseArr
Update your code to:
in view.php
$id = $_REQUEST['edit_literature_id'];
$literature = $_REQUEST['literatureID'];
$module = $_REQUEST['edit_moduleId'];
if (isset($id)) {
$sql = "SELECT * FROM $literature WHERE `id`='".$id."'";
if ($result = mysqli_query($conn, $sql)) {
if (mysqli_num_rows($result) > 0) {
$row = mysqli_fetch_array($result);
$data['title'] = $row['title'];
$data['name'] = 'data:image/jpeg;base64,' . base64_encode($row['name']);
$data['content'] = $row['content'];
echo json_encode($data); exit;
}
mysqli_free_result($result);
}
}
$data['error'] = "No Record";
echo json_encode($data); exit;
Index.php
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
rowId = $(this).attr('data-id');
moduleData = $(this).attr('data-module');
literatureData = $(this).attr('data-literature');
$('#edit_id').val(rowId);
$('#edit_module').val(moduleData);
$('#edit_literature').val(literatureData);
$('#edit_imageId').val(rowId);
$('#update').val('update');
$.ajax({
type: 'POST',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (data) {
var response = jQuery.parseJSON(data);
var title = response.title;
var name = response.name;
var content = response.content;
alert(title);
alert(name);
alert(content);
}
});
});
});
After taking data from jQuery side, you can set value in html side using id or class attribute in jQuery.

How your ajax receiving .php file should look:
$validLiteratureIds = ['yourTable1', 'yourTable2'];
if (!isset($_GET['edit_literature_id'], $_GET['literatureID']) || !in_array($_GET['literatureID'], $validLiteratureIds)) {
$response = ['error' => 'Missing/Invalid Data Submitted'];
} else {
$conn = new mysqli('localhost', 'root', '', 'dbname');
$sql = "SELECT title, name, content
FROM `{$_GET['literatureID']}`
WHERE `id` = ?";
$stmt = $conn->prepare($sql);
$stmt->bind_param("s", $_GET['edit_literature_id']);
$stmt->execute();
$stmt->bind_result($title, $name, $content);
if (!$stmt->fetch()) {
$response = ['error' => 'No Record'];
} else {
$response = [
'title'=> $title,
'name' => 'data:image/jpeg;base64,' . base64_encode($name),
'content' => $content
];
}
}
echo json_encode($response);
Important practices:
Validate the user input so that only qualifying submissions have the privilege of accessing your database.
Write the failure outcomes before success outcomes consistently throughout your project, this will make your scripts easier to read/follow.
Always use prepared statements and bind user-supplied data to placeholders into your query for stability/security.
The tablename cannot be bound like the id value; it must be written directly into your sql string -- this is why it is critical that you validate the value against a whitelist array of literature ids.
There is no need to declare new variables to receive the $_GET values; just access the values directly from the superglobal array.
I am going to assume that your id is a primary/unique key in your table(s), so you don't need to loop over your result set. Attempt to fetch one row -- it will either contain data or the result set was empty.
Call json_encode() only once and at the end of your script.
It is not worth clearing any results or closing a prepared statement or a connection, because those tasks are automatically done when the script execution is finished anyhow -- avoid the script bloat.
As for your jquery script:
$(document).ready(function () {
$(document).on('click', '#btnModalUpdate', function (e) {
e.preventDefault();
$.ajax({
type: 'GET',
url: '../../crud/read/view.php',
data: $('#modalFormUpdate').serialize(),
dataType: 'json',
success: function (response) {
if (response.hasOwnProperty('error')) {
console.log(response.error);
} else {
console.log(response.title, response.name, response.content);
}
}
});
});
});
I've trim away all of the irrelevant lines
changed POST to GET -- because you are merely reading data from the database, not writing
parseJSON() is not necessary -- response is a ready-to-use object.
I am checking for an error property in the response object so that the appropriate data is accessed.
Both scripts above are untested (and completely written from my phone). If I have made any typos, please leave me a comment and I'll fix it up.

How to use AJAX to call php file from javascript file

I want to call php file from javascript, and this php file will update id=1
like this way:
javascript:
if(lastTemp >= document.getElementById("TempSet").value){
var jsonData2 =$.ajax({
url: "setpp.php",
dataType: "json",
async: false
}).responseText;
var obj2 = JSON.parse(jsonData2);
console.log(obj2);
}
else {
}
php file:
<?php
$DATABASE_HOST = 'localhost';
$DATABASE_USER = 'use';
$DATABASE_PASS = 'pass';
$DATABASE_NAME = 'database';
// Try and connect using the info above.
$db = mysqli_connect($DATABASE_HOST, $DATABASE_USER, $DATABASE_PASS,
$DATABASE_NAME);
if (!$db){
die("Connection Failed: ". mysqli_connect_error());
}
$db_update = "UPDATE setpoint_control SET status='ON' WHERE id=1";
$result = mysqli_query($db, $db_update);
?>
<?php
$data = array();
if(mysqli_num_rows($result)>0){
while($row = mysqli_fetch_array($result)){
array_push($data, $row['status']);
}
}
echo json_encode($data);
?>
the code is executed and the status in database table is changed but I got error in console : SyntaxError: JSON.parse: unexpected character at line 4 column 2 of the JSON data
How can I solve this issue which I think I need to rewrite json_encode but I don't know how?

$.ajax({
type: 'post',
dataType: 'json',
cache: false,
url: 'setpp.php',
success: function (response) {
$.each(response, function(i, item) {
alert(item);
});
},
error: function () {
alert("error");
},
});
example php answer setpp.php
if (mysqli_num_rows($result) > 0) {
while ($row = mysqli_fetch_array($result)) {
array_push($data, $row['status']);
}
die(json_encode($data));
} else {
$answer = array(
'No Records'
);
die(json_encode($answer));
}
I think the problem is the value returned by setpp.php.
remember to die(), otherwise the php answer will not be correct

Handling ajax response exceptions

I am currently handling a form with php and calling it via an ajax request, i want to handle exceptions showing a small div instead of the basic popup
so i did multiple if conditions based on the responsetext, however one of the exceptions doesnt get handled
This exception is the empty fields exception it always shows the wrong username or pw instead
here is the ajax call
function sendLogin(){
username = $('#loginEmail').val();
password = $('#loginPassword').val();
a = $.ajax({
type: 'post',
data: 'username='+username+'&password='+password,
url: '/account/login.php',
async: false,
});
if(a.responseText == "LoggedIn"){
$("#WrongPW_Error").fadeOut("fast");
$("#Empty_Error").fadeOut("fast");
$("#LoggedIn").fadeIn("fast");
setTimeout(location.reload(),2200);
}
else if(a.responseText == "Empty_Fields") {
//alert(a.responseText);
$("#WrongPW_Error").fadeOut("fast");
$("#Empty_Error").fadeIn("fast");
}
else if(a.responseText == "Wrong_Credentials") {
//alert(a.responseText);
$("#Empty_Error").fadeOut("fast");
$("#WrongPW_Error").fadeIn("fast");
}
}
and here is the php file
<?php
if(!isset($_POST['username']) || !isset($_POST['password'])){
echo "Empty_Fields";
die();
}
$username = $_POST['username'];
$password = $_POST['password'];
$hashed_pass = hash("sha512", $password);
$stmt = $dbh->prepare("SELECT Count(email)as total, username from Users where email = :username and password= :password");
$stmt->bindParam(':username', $username, PDO::PARAM_STR);
$stmt->bindParam(':password', $hashed_pass, PDO::PARAM_STR);
$stmt->execute();
$row = $stmt->fetch(PDO::FETCH_ASSOC);
$total = $row['total'];
if($total == 1){
session_start();
$_SESSION['user'] = $username;
$_SESSION['user_name'] = $row['username'];
echo "LoggedIn";
die();
}
else{
echo "Wrong_Credentials";
die();
}
?>

You are not performing the correct check in PHP to see if the POST variables are empty.
Read: What's the difference between 'isset()' and '!empty()' in PHP?
isset($_POST['username'])
will return true if the POST parameter exists, even if its content is an empty string. You need both tests: isset AND empty.
if(!isset($_POST['username']) || !isset($_POST['password'])){
echo "Missing_Param";
die();
}
if(empty($_POST['username']) || empty($_POST['password'])){
echo "Empty_Fields";
die();
}

Edit: I did not notice that you're using async: false; leaving this answer for reference. In general it's a good idea to use non-blocking calls in JS so other UI elements aren't affected.
$.ajax does not return anything; it's an asynchronous call that will call a function when it completes. You'll need to do something like this:
$.ajax({
// other arguments here
success: function(data) {
// handle success
},
error: function() {
// handle error
}
});
More examples available here and here.

Instead of calling die() on your PHP code, send an error response. Call http_response_code(401) (not authorized response). Second issue is that $.ajax doesn't return a response and async = false has been deprecated and should not be used. Instead, define two functions for success and failure and just set those as the success and error parameters of your AJAX request.
$.ajax({
type: 'post',
data: 'username='+username+'&password='+password,
url: '/account/login.php',
async: false,
success: successFunction,
error: errorFunction
});
function successFunction(response){
$("#WrongPW_Error").fadeOut("fast");
$("#Empty_Error").fadeOut("fast");
$("#LoggedIn").fadeIn("fast");
setTimeout(location.reload(),2200);
}
function errorFunction(response){
$("#WrongPW_Error").fadeOut("fast");
$("#Empty_Error").fadeIn("fast");
}

Unable to read key value pair of Json_encode in javascript

I am having issues with reading Json_encode response in a java script.
The PHP file reads values from database and sends the results as Json_encode array to html.
<?php
include("connect.php");
try {
$conn = new PDO("mysql:host=$servername;dbname=mydb", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "Call print_awb (#output1,#output2,:input_awb_ref_id)";
if (isset($_POST)) {
$p_in_awb_ref_id =reset($_POST["var_p_in_awb_ref_id"]);
}
$stmt = $conn->prepare($sql);
$stmt->bindParam(':input_awb_ref_id',$p_in_awb_ref_id, PDO::PARAM_INT);
$stmt->execute();
$out_awb_ref_id = $conn->query("SELECT #output1")->fetch(PDO::FETCH_ASSOC);
$out_agent_id = $conn->query("SELECT #output2")->fetch(PDO::FETCH_ASSOC);
$output = array(
"out_awb_ref_id" => $out_awb_ref_id,
"out_agent_id" => $out_agent_id,
);
echo json_encode($output);
$stmt->closeCursor();
}
catch(PDOException $e)
{
echo $sql . "<br>" . $e->getMessage();
}
?>
The HTML CODE
<script type="text/javascript">
function get_parameters(){
var quote = ABCD1234;
quote.toString();
window.alert(quote);
$.ajax({
type: "POST",
url: "printawb.php",
data: {var_p_in_awb_ref_id:quote},
dataType: "text",
success: function (result) {
alert(result);
var a = result.out_awb_ref_id;
alert (a);
alert(result['out_awb_ref_id']);
alert(result['out_agent_id'])
},
error:function (jqXHR, status, err){
//Fail
layer_1.html(html);
}
});
return vars;
};
</script>
The response I have is
HVP000062
{"out_awb_ref_id":{"#output1":"MIR"},"out_agent_id":{"#output2":"rtPreston"}}
undefined
undefined
All Need is the values in the 2nd line of the result ie. "MIR" and "rtPreston"
I have tried couple of things:
1. changed the calling function type as 'JSON' but the response was 'Object' without values
2. Tried converting to jsonString
3. tried reading values using JSON.parse(jsonString);
4. result['out_ref_awb_id']
None of them work. Can someone help me how I can get values of these? I can then use them to populate on a html page.
Many thanks

Add this as a first line in the HEAD section of your HTML template
<meta content="text/html;charset=utf-8" http-equiv="Content-Type">
<meta content="utf-8" http-equiv="encoding">
Then try this code:
<script type="text/javascript">
function get_parameters(){
var quote = ABCD1234;
quote.toString();
window.alert(quote);
$.ajax({
type: "POST",
url: "printawb.php",
data: {var_p_in_awb_ref_id:quote},
dataType: "text",
success: function (result) {
var data = jQuery.parseJSON(result);
var param1 = data.out_agent_id;
var param2 = data.out_awb_ref_id;
alert(param1["#output2"]);
alert(param2["#output1"])
},
error:function (jqXHR, status, err){
//Fail
layer_1.html(html);
}
});
return vars;
};
</script>

Ajax separate data which came from mysql

I am doing an ajax call like this:
function myCall() {
var request = $.ajax({
url: "ajax.php",
type: "GET",
dataType: "html"
});
request.done(function(data) {
$("image").attr('src',data);
});
request.fail(function(jqXHR, textStatus) {
alert( "Request failed: " + textStatus );
});
}
This is my ajax.php:
<?php
$connection = mysql_connect ("",
"", "");
mysql_select_db("");
// QUERY NEW ONE
$myquery = "SELECT * FROM mytable ORDER BY rand() LIMIT 1";
$result = mysql_query($myquery);
while($row = mysql_fetch_object($result))
{
$currentid = "$row->id";
$currentname = "$row->name";
$currenturl = "$row->url";
$currentimage = "$row->image";
echo $currenturl,$currentnam, $currenturl,$currentimage;
}
mysql_close($connection);
?>
My data variable from the ajax call now contains all variables at once:
($currenturl,$currentnam, $currenturl,$currentimage)
How can I separate them so I can do something like:
request.done(function(data) {
$("id").attr('src',data1);
$("name").attr('src',data2);
$("url").attr('src',data3);
$("image").attr('src',data4);
});

jQuery :
$.ajax({
type:"POST",
url:"ajax.php",
dataType:"json",
success:function(response){
var url = response['url'];
var name = response['name'];
var image = response['image'];
// Now do with the three variables
// $("id").attr('src',data1);
// $("name").attr('src',data2);
// $("url").attr('src',data3);
// $("image").attr('src',data4);
},
error:function(response){
alert("error occurred");
}
});
From your code:
echo $currenturl,$currentnam, $currenturl,$currentimage;
Replace the above line with the code below:
$array = array('url'=>$currenturl, 'name'=>$currentname, 'image'=>$currentimage);
echo json_encode($array);

instead of string return an array i.e. use json type for returning value
i.e instead of
echo $currenturl,$currentnam, $currenturl,$currentimage;
use
echo json_encode array('current' => $currenturl,'currentnam' => $currentnam, 'currenturl' => $currenturl,'currentimage' => $currentimage);
and also write 'dataType' as 'json' in ajax