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Issue with nested ajax call in jQuery

I have a situation where I make an ajax call, on returning from which (successfully), I make an another ajax call with the returned data and submit the page. The pseudo code looks something like this:
$.ajax({
url: 'first_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
}).done(function(response) {
$.ajax({
url: '2nd_page.jsp',
type: 'POST',
dataType: 'JSON',
data: {...}
});
thisPage.submit();
});
The inner ajax call is not executed if I do not comment out the 'submit' line. I do not understand the behaviour. Can someone please help me with this.
Thanks

You need to execute submit on second ajax sucess.
For example
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
$.ajax({
url: '',
type: 'GET',
data: {
},
success: function (data) {
//do your stuff
}

$("input[type='submit']").click(function(event){
event.preventDefault();
$.ajax({
url:'abcd.php',
method:'post',
type:'json',
async:false,
success:function(response){
$.ajax({
url:'abcde.php',
method:'post',
type:'json',
data:{res:response},
success:function(response){
console.log(response);
}
});
$("form").submit();
}
});
});
Try this one.Its working correctly.

Repeating jQuery Ajax success function

I'm using Ajax to add an array of data to a database.
Currently when "#bookingbutton" is clicked on this returns a block of HTML with ".select-room-button" button.
I've added the ".select-room-button" code in the success function of the original Ajax call for "#bookingbutton" otherwise it doesn't work.
I want to be able to click on the ".select-room-button" unlimited times without having to repeat the code loads of times in each success function if that makes sense? I feel like there must be a smarter way to do this but I'm not sure how?
jQuery(document).ready(function($) {
$('#bookingbutton').click(function() {
$('.booking-main').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$('.booking-side-response').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$.ajax({
type: 'POST',
url: AJAX_URL,
data: $('#bookroom').serialize(),
dataType: 'json',
success: function(response) {
if (response.status == 'success') {
$('#bookroom')[0].reset();
}
$('.booking-main').html(response.content);
$('.booking-side-response').html(response.sidebar);
$('.select-room-button').click(function() {
$('.booking-main').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$('.booking-side-response').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$.ajax({
type: 'POST',
url: AJAX_URL,
data: $('#bookroom').serialize(),
dataType: 'json',
success: function(response) {
if (response.status == 'success') {
$('#bookroom')[0].reset();
}
$('.booking-main').html(response.content);
$('.booking-side-response').html(response.sidebar);
}
});
});
}
});
});
});

For this you can use various selector for a single event to trigger ajax calls.
So your code snippet will look like
jQuery(document).ready(function($) {
$(document).on("click",'#bookingbutton, .select-room-button', function() {
$('.booking-main').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$('.booking-side-response').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$.ajax({
type: 'POST',
url: AJAX_URL,
data: $('#bookroom').serialize(),
dataType: 'json',
success: function(response) {
if (response.status == 'success') {
$('#bookroom')[0].reset();
}
$('.booking-main').html(response.content);
$('.booking-side-response').html(response.sidebar);
}
});
});
});

You can try using .on like this on the document. It will bind events for dynamically generated HTML too.
jQuery(document).ready(function($) {
$(document).on("click",'#bookingbutton, .select-room-button').click(function() {
$('.booking-main').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$('.booking-side-response').html('<img src="http://mailgun.github.io/validator-demo/loading.gif" alt="Loading...">');
$.ajax({
type: 'POST',
url: AJAX_URL,
data: $('#bookroom').serialize(),
dataType: 'json',
success: function(response) {
if (response.status == 'success') {
$('#bookroom')[0].reset();
}
$('.booking-main').html(response.content);
$('.booking-side-response').html(response.sidebar);
});
});
});

You can make these change
use $(document).ready(function() instead of jQuery(document).ready(function($)
use $('body').on('click', '.select-room-button', function() instead of $('.select-room-button').click(function() and get it out $('#bookingbutton').click(function()

Ajax call to database not works

in my application I have to make an ajax call to php file.it works proper in all devices. but when I tried it on ipad mini it not calls the php, so that the functionality not works, I've seen so many question about this problem and edited my code like this.
jQuery.ajax({
type: "POST",
async: true,
cache: false,
url: "directory/phpfile.php",
data: data,
success: function(response) {
}
});
my old code is
jQuery.ajax({
type: "POST",
url: "wp-admin/admin-ajax.php",
data: data,
success: function(response) {
}
});
and the problem still cant resolve . so please any one tell me how to resolve this.

Please use this code
$("#ajaxform").submit(function(e)
{
var postData = $(this).serializeArray();
var formURL = $(this).attr("action");
$.ajax(
{
url : formURL,
type: "POST",
data : postData,
success:function(data, textStatus, jqXHR)
{
//data: return data from server
},
error: function(jqXHR, textStatus, errorThrown)
{
//if fails
}
});
e.preventDefault(); //STOP default action
e.unbind(); //unbind. to stop multiple form submit.
});
$("#ajaxform").submit(); //Submit the FORM

<script type='text/javascript'>
$(document).ready(function startAjax() {
$.ajax({
type: "POST",
url: "test.php",
data: "name=name&location=location",
success: function(msg){
alert( "Data Saved: " + msg );
}
});
});

jQuery - stop form submission from changing page using ajax

I am trying to submit a form without reloading the page. I have tried using this script with no success:
$('#formId').submit(function(e){
$.ajax({
type: "POST",
url: 'serverSide.php',
data: $('#formId').serialize(),
success: function(data){
alert(data);
}
});
e.preventDefault();
});
Does anyone know what I am doing wrong?

Using return false will usually do the trick
$('#formId').submit(function(e){
$.ajax({
type: "POST",
url: 'serverSide.php',
data: $('#formId').serialize(),
success: function(data){
alert(data);
}
});
e.preventDefault();
return false;
});

Try putting preventDefault before the AJAX. This way the default actions are prevented before the ajax-request is triggered
$('#formId').submit(function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: 'serverSide.php',
data: $('#formId').serialize(),
success: function(data){
alert(data);
}
});
});

Do something after window load

I'm doing a (simple) ajax call on window load:
$(window).load(function () {
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
...........
How can I do something, for instance a function or event after this ajax proces is finished. The problem is I have to append something to the data recieved by the ajax call. But I can't append on window load because the data is still being processed.

Put it in the success handler of the ajax call:
$(window).load(function () {
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
// do whatever you want with data
}
});
});

You can call that in the success callback function of Ajax request
success: function(data) {
myFunction() ; // If function
$('#elementID').click() // If you want to trigger a click event
}

You may use the
`$(document).ready`
So it will be similar to this:
$(document).ready(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
//Your code should be here

After
success: function(data) {
for (var ii = 0; ii < data.length; ii++){
building html here
}
your code here
}
you want to enter in your functions within the success function for the ajax call but before the call is complete.

You could also do
$.ajax({
url: someUrl,
type: "get",
dataType: "",
context: document.body
}).done(function() {
// do whatever when is done
onCompleteFunction();
});

this should execute your request when page is just loaded.
$(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
success: function(data) {
// do whatever you want with data
}
});
});
or you can do:
$(function(){
$.ajax({
url: someUrl,
type: "get",
dataType: "",
complete: function(data) {
// do whatever you want with data
}
});
});