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how to create a javascript rusable class to pass parameters to ajax

im new in JS,im looking for a way to create a class or function,reusable everywhere in my code,just pass it parameters and get the result,because currently I am doing like this:
$.ajax({
dataType: "json",
type: "POST",
url: "#Url.Action("power","Ranking")",
contentType: "application/json; charset=utf-8",
data: JSON.stringify({ "regionalManager": tmpString }),
success: function (result) {
})}
I write this every time I need, and im sick of it,

function sendAjaxCustom(DataType,Type,Url,Ctype,Data){
$.ajax({
dataType: DataType,
type: Type,
url: Url,
contentType: Ctype,
data: Data,
success: function (result) {
return result;
})}
}
You can call this function in JS like
var result = sendAjaxCustom("json","POST",'#Url.Action("power","Ranking")',"application/json; charset=utf-8",JSON.stringify({ "regionalManager": tmpString }));
you will have the result in result variable.

You can create a function like this
function ajax(url, data) {
$.ajax({
dataType: "json",
type: "POST",
url: url,
contentType: "application/json; charset=utf-8",
data: data,
success: function (result) {
})}
}
Pass the url if it's dynamic and the object data on the second parameter.

Just create a simple function with your variables that need to change between calls and return the $.ajax result from there.
function ajaxWrapper(url, data, callback) {
return $.ajax({
dataType: 'json',
type: 'POST',
url: url,
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(data),
success: callback
});
}
When you want to call it:
ajaxWrapper('http://www.google.com/', { hello: 'world' }, function(result) {
console.log(result);
});
With the callback it's much more reusable, since you can use this anywhere and change what you do on completion of the function wherever you use it.

A simple solution is to return an object and pass it to the ajax and if some change is required then you can update the properties of the object before calling the ajax service
function commonAjaxParams() {
return {
dataType: "json",
type: "POST",
url: "#Url.Action("power","Ranking")",
contentType: "application/json; charset=utf-8",
//and so on that are common properties
}
}
//now in your application first call the function to get the common props
var commonParams = commonAjaxParams();
//change or add an parameter to your liking
commonParams.type = 'GET';
commonParams.success = function(){...} //if this action is need
commonPramss.error = function(){...}
//now call you ajax action
$.ajax(commonParams)

There is another way in which you may call the ajax function and you may get success, fail response return.
The benefit is you manage success or fail response independently for each ajax request.
$(document).ready(function() {
function ajaxRequest(dataType, requestMethod, dataURL, jsonData) {
return $.ajax({
dataType: dataType,
type: requestMethod,
url: dataURL,
contentType: "application/json; charset=utf-8",
data: JSON.stringify(jsonData)
});
}
var jsonData = {
"regionalManager": "jason bourne"
};
ajaxRequest(
"json",
"POST"
"#Url.Action('power','Ranking')",
jsonData)
.success((data) {
console.log("success");
}).error((err) {
console.log("error");
}).done(() {
console.log("done");
});
});

how to get the json string in a variable

i got my json string inside the ajax as function like this way
$.ajax({
type: "POST",
url: "http://localhost/./Service/GetPageInfo",
dataType: "json",
contentType: 'application/json',
data: JSON.stringify({
filename: filename
}),
success: function (data) {
alert('Success');
},
error: function () {
alert('Error');
}
});
here i get data like
[{"main":{"sub":[],"tittle":"manu","startvalue":"","stopvalue":"","status":"","accumalated":"","comment":""}}]
i want it in a variable like
var myjsonobject =[{"main":{"sub":[],"tittle":"manu","startvalue":"","stopvalue":"","status":"","accumalated":"","comment":""}}]

There you go :
$.ajax({
type: "POST",
url: "http://localhost/./Service/GetPageInfo",
dataType: "json",
contentType: 'application/json',
data: JSON.stringify({
filename: filename
}),
success: function (data) {
alert('Success');
var jsonobject = data;
},
error: function () {
alert('Error');
}
});
Also I strongly advise you to use promises to make API calls: https://developer.mozilla.org/fr/docs/Web/JavaScript/Reference/Objets_globaux/Promise

var jsonobject= null;
$.ajax({
type: "POST",
url: "http://localhost/./Service/GetPageInfo",
dataType: "json",
contentType: 'application/json',
data: JSON.stringify({
filename: filename
}),
success: function (data) {
jsonobject=data;
alert('Success');
},
error: function () {
alert('Error');
}
});
If you want wait for ajax response and fill up variable then pass async: false in ajax request options.

Based on your comment, you need to parse the JSON in your success handler,
success: function (data) {
alert('Success');
var myjsonobject = JSON.parse( data );
},

Converting $.post into $.ajax

I have a post statement,
$.post("panel.php", 'data=[{"action":"UserInfo"}]', function (userInfo){
//processing
});
I need it to be converted to $.ajax so made it thus,
$.ajax({
type: "POST",
url: "panel.php",
data: { data: [{"action":"UserInfo"}]},
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(userInfo) {
//processing
}
});
But the post variable isn't being sent. Is this not the correct way?

Can you try something like this:
$.ajax({
type: "POST",
url: "panel.php",
data: {"action":"UserInfo"},
success: function(userInfo) {
//processing
}
});

Try this
$.ajax({
type: "POST",
url: "panel.php",
data: "action="+"UserInfo",
success: function(userInfo) {
//processing
}
});

Remove data from your data and keep it in a variable, stringify before your send as below
var data={"action":"UserInfo"};
$.ajax({
type: "POST",
url: "panel.php",
data: JSON.stringify(data),
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(userInfo) {
//processing
}
});

Your data attribute was not written as correct JSON:
data: { "data": [{"action":"UserInfo"}]},
You need quotation marks around the items inside your JSON object. You can use JSONLint to check if your JSON object is valid.

$.ajax({
type: "POST",
url: "panel.php",
data: {"action":"UserInfo"},
dataType: "json",
success: function(userInfo) {
//processing
}
});
Need a small change. there is a predefined format to send data in ajax,
data: {status: status, name: name},
data: "status="+status+"&name="+name.
Follow any one of the approach.

try like this,
$.ajax({
type: "POST",
url: "panel.php",
data: {"action":"UserInfo"},
success: function(userInfo) {
}
});

AJAX POST JSON value

I have AJAX POST, the result is JSON:
$.ajax({
type: "POST",
url: "../../api/test",
data: JSON.stringify(source),
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (result) {
var upload = JSON.stringify(result);
console.log(upload);
}
});
The upload result is:
{"Link":0,"Title":"d","Description":"dada","Keywords":"dad"}
How can I get the value of Title?

Do not stringify the result, just use result.Title.

As you already have JSON string, It's simple as a pie!
All you need to do is to call the property you want from the variable you assigned your result to.
for example:
var post_response;
$.ajax({
type: "POST",
url: "../../api/test",
data: JSON.stringify(source),
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (result) {
post_response = JSON.stringify(result);
console.log("Title: "+post_response.Title);
}
});
hope this helps.

Jquery set HTML via ajax

I have the following span:
<span class='username'> </span>
to populate this i have to get a value from PHP therefor i use Ajax:
$('.username').html(getUsername());
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
document.write(data);
}
})
}
Now when i debug i see that the returned data (data) is the correct value but the html between the span tags stay the same.
What am i doing wrong?
Little update
I have tried the following:
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
$('.username').html('RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRr');
}
})
}
getUsername();
Still there is no html between the tags (no text) but when i look at the console the method is completed and has been executed.
Answer to the little update
The error was in my Ajax function i forgot to print the actual response! Thank you for all of your answers, for those of you who are searching for this question here is my Ajax function:
public function ajax_getUsername(){
if ($this->RequestHandler->isAjax())
{
$this->autoLayout = false;
$this->autoRender = false;
$this->layout = 'ajax';
}
print json_encode($this->currentClient['username']);
}
Do note that i am using CakePHP which is why there are some buildin methods. All in all just remember print json_encode($this->currentClient['username']);

The logic flow of your code is not quite correct. An asynchronous function cannot return anything as execution will have moved to the next statement by the time the response is received. Instead, all processing required on the response must be done in the success handler. Try this:
function getUsername() {
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: { },
success: function(data){
$('.username').html(data); // update the HTML here
}
})
}
getUsername();

Replace with this
success: function(data){
$('.username').text(data);
}

In success method you should use something like this:
$(".username").text(data);

You should set the html in callback
function getUsername() {
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
$('.username').html(data);
}
})
}

Add a return statement for the function getUsername
var result = "";
$('.username').html(getUsername());
function getUsername(){
$.ajax({
type: 'POST',
url: myBaseUrl + 'Profiles/ajax_getUsername',
dataType: 'json',
data: {
},
success: function(data){
document.write(data);
result = data;
}
})
return result;
}

You can use .load()
Api docs: http://api.jquery.com/load/
In your case:
$('.username').load(myBaseUrl + 'Profiles/ajax_getUsername',
{param1: value1, param2: value2});