How can I chain together groups of promises? - javascript

I am using the Q javascript promises library and am running in a browser, and I want to figure out how to chain together groups of promises so that each group gets executed sequentially. For example, if I have items A, B, C, and D, I want to group A and B together and then C and D together, so that both A and B must fulfill before C and D get executed. I created this simple jsfiddle to show my current attempt.
var work_items = [ 'A','B','C','D','E','F','G','H','I' ];
var n = 2; // group size
var wait = 1000;
var getWorkPromiseFn = function (item) {
log("Getting promise function for " + item);
return function () {
log("Starting " + item);
var deferred = Q.defer();
setTimeout(function () {
var status = "Finished " + item;
log(status);
deferred.resolve(status);
}, wait);
return deferred.promise;
};
};
var queue = Q();
//log('Getting sequentially'); // One-by-one in sequence works fine
//work_items.forEach(function (item) {
// queue = queue.then(getWorkPromiseFn(item));
//});
log('Getting ' + n + ' at a time'); // This section does not
while (work_items.length > 0) {
var unit = [];
for (var i=0; i<n; i++) {
var item = work_items.shift();
if (item) {
unit.push(getWorkPromiseFn(item));
}
}
queue.then(Q.all(unit));
}
var inspect = queue.inspect(); // already fulfilled, though no work is done
It looks like I am probably passing the wrong array to Q.all here, since I'm passing in an array of functions which return promises rather than an array of the promises themselves. When I tried to use promises directly there (with unit.push(Q().then(getWorkPromiseFn(item)); for example), the work for each was begun immediately and there was no sequential processing. I guess I'm basically unclear on a good way to represent the group in a way that appropriately defers execution of the group.
So, how can I defer execution of a group of promises like this?

This can be done by first pre-processing the array of items into groups, then applying the two patterns (not the anti-patterns) provided here under the heading "The Collection Kerfuffle".
The main routine can be coded as a single chain of array methods.
var work_items = [ 'A','B','C','D','E','F','G','H','I' ];
var wait = 3000;
//Async worker function
function getWorkPromise(item) {
console.log("Starting " + item);
var deferred = Q.defer();
setTimeout(function () {
var status = "Finished " + item;
console.log(status);
deferred.resolve(status);
}, wait);
return deferred.promise;
};
function doAsyncStuffInGroups(arr, n) {
/*
* Process original array into groups, then
* process the groups in series,
* progressing to the next group
* only after performing something asynchronous
* on all group members in parallel.
*/
return arr.map(function(currentValue, i) {
return (i % n === 0) ? arr.slice(i, i+n) : null;
}).filter(function(item) {
return item;
}).reduce(function(promise, group) {
return promise.then(function() {
return Q.all(group.map(function(item) {
return getWorkPromise(item);
}));
});
}, Q());
}
doAsyncStuffInGroups(work_items, 2).then(function() {
console.log("All done");
});
See fiddle. Delay of 3s gives you time to appreciate what's going on. I found 1s too quick.
Solutions like this are elegant and concise but pretty well unreadable. In production code I would provide more comments to help whoever came after me.
For the record:
The opening arr.map(...).filter(...) processes arr (non destructively) into an array of arrays, each inner array representing a group of length n (plus terminal remainders).
The chained .reduce(...) is an async "serializer" pattern.
The nested Q.all(group.map(...)) is an async "parallelizer" pattern.

The .then function of a promise does not mutate the promise, so when you do:
p.then(function(){
// stuff
});
You do not change the promise p at all, instead, you need to assign it to something:
p = p.then(....)
This is why your queue promise was always resolved, it never changed beyond Q().
In your case, something like changing:
queue.then(Q.all(unit));
Into:
queue = queue.then(function(){ return Q.all(unit); });
Or in ES6 promises and libraries that use their syntax like Bluebird the other answer mentioned:
queue = queue.then(function(){ return Promise.all(unit); });

The thing that confused me most is that the async function being chained needs to return a function that returns a promise. Here's an example:
function setTimeoutPromise(ms) {
return new Promise(function (resolve) {
setTimeout(resolve, ms);
});
}
function foo(item, ms) {
return function() {
return setTimeoutPromise(ms).then(function () {
console.log(item);
});
};
}
var items = ['one', 'two', 'three'];
function bar() {
var chain = Promise.resolve();
for (var i in items) {
chain = chain.then(foo(items[i], (items.length - i)*1000));
}
return chain.then();
}
bar().then(function () {
console.log('done');
});
Notice that foo returns a function that returns a promise. foo() does not return a promise directly.
See this Live Demo

i would suggest you use bluebird, its the best performance promise out there, https://github.com/petkaantonov/bluebird
the example to chain should also be here https://github.com/petkaantonov/bluebird#how-do-long-stack-traces-differ-from-eg-q

Related

What's the alternative to the reduce pattern with Promises when dealing with recursion?

Note: I cannot use async.
I like to use the reduce pattern in cases where I need to run over an array and execute the same function on its members and return a promise, like so:
function get_count() {
return new Promise(function(resolve, reject) {
resolve(3);
});
}
function recursively_execute(data) {
return new Promise(function(resolve, reject) {
resolve(data);
});
}
function reduce_promise_pattern() {
const get_batch_run_count = get_count();
const batch_process = get_batch_run_count.then((count_value) => {
const run_count = new Array(count_value).fill('batch');
function recursive_function(data) {
console.log('Running batch!');
return recursively_execute(data).then(() => {
return data;
});
}
return run_count.reduce((previous_promise) => {
return previous_promise.then((previous_response) => {
test_data = {
'test': 1
};
return recursive_function(test_data);
})
}, Promise.resolve())
});
return batch_process;
}
This will run 3 times because of the run_count which basically builds an array of 3 items. Although it works, this feels like a hack to me.
This approach works when my list is already pre-defined with unique items and these items, well, individually are used inside that reduce as data that is built upon for example, if I have 3 steps to go through, these 3 steps are all unique and each step's data will be used within that one run...but in my case? I'm just tricking the system to think these are different items.
What is the alternative to this?
You reached the limits of Promise chains, although they work they ain't readable. That's why async / await was introduced to handle exactly these usecases, with them you can just halt all kinds of (nested) loops without having to maintain promises for each:
async function reducePromisePattern() {
for(let i = await getCount(); i >= 0; i--) {
await recursiveFunction({'test': 1 });
}
}
If you can't use / transpile async, you could still write some small helpers to do the looping for you, e.g.:
function loopAsync(times, fn) {
function task() {
times--;
if(times <= 0) return;
return fn().then(task);
}
return Promise.resolve().then(task);
}
function reducePromisePattern() {
return getCount().then(function(count) {
return asyncLoop(count, function() {
return recursiveFunction({ test: 1 });
});
});
}
Here are two options without nesting functions in one another. The first one simply uses a for-loop while the second function uses a recursive solution. The last argument of both solutions is optional and should only be used if you want to pass the return data forward from one run to the next (similar to reduce).
const sleep = () => new Promise(resolve => setTimeout(resolve, Math.random() * 1500 + 500));
// solution #1 - for-loop
function times1(n, callback, init) {
var promise = Promise.resolve(init);
for (; n > 0; --n) {
promise = promise.then(val => callback(val));
}
return promise;
}
// example usage
times1(3, n => {
console.log("solution #1 -", n);
return sleep().then(() => n + 1);
}, 0);
// solution #2 - recursive
function times2(n, callback, init) {
var promise = Promise.resolve(init);
if (n <= 0) return promise;
return promise.then(val => times2(n - 1, callback, callback(val)));
}
// example usage
times2(3, n => {
console.log("solution #2 -", n);
return sleep().then(() => n + 1);
}, 0);

How to execute promises in series?

var promiseReturningFuncs = [];
for(var i = 0; i < 5; i++){
promiseReturningFuncs.push(askQuestion);
}
var programmers = [];
Promise.reduce(promiseReturningFuncs, function(resp, x) {
console.log(typeof resp);
if(typeof resp != "function") {
programmers.push(resp);
}
return x();
})
.then(function(resp) {
programmers.push(resp);
console.log(programmers);
});
My goal: execute the askQuestion function in series and resolve an array of objects created by that function. (this function must execute in series so that it can respond to user input)
So imagine that the askQuestion function returns a promise that resolves a object I want to add to an array.
This is my messy way of doing it.
I am looking to find a cleaner way of doing it, ideally, i wouldn't even need to push to an array, I would just have a final .then, where the response is an array.
Since you appear to be using the Bluebird promise library, you have a number of built-in options for sequencing your promise returning functions. You can use Promise.reduce(), Promise.map() with a concurrency value of 1, Promise.mapSeries or Promise.each(). If the iterator function returns a promise, all of these will wait for the next iteration until that promise resolves. Which to use depends more upon the mechanics of how your data is structured and what result you want (neither of which you actually show or describe).
Let's suppose you have an array of promise returning functions and you want to call them one at a time, waiting for the one to resolve before calling the next one. If you want all the results, then I'd suggest Promise.mapSeries():
let arrayOfPromiseReturningFunctions = [...];
// call all the promise returning functions in the array, one at a time
// wait for one to resolve before calling the next
Promise.mapSeries(arrayOfPromiseReturningFunctions, function(fn) {
return fn();
}).then(function(results) {
// results is an array of resolved results from all the promises
}).catch(function(err) {
// process error here
});
Promise.reduce() could also be used, but it would accumulate a single result, passing it from one to the next and end with one final result (like Array.prototype.reduce() does).
Promise.map() is a more general version of Promise.mapSeries() that lets you control the concurrency number (the number of async operations in flight at the same time).
Promise.each() will also sequence your functions, but does not accumulate a result. It assumes you either don't have a result or you are accumulating the result out-of-band or via side effects. I tend to not like to use Promise.each() because I don't like side effect programming.
You could solve this in pure JS using ES6 (ES2015) features:
function processArray(arr, fn) {
return arr.reduce(
(p, v) => p.then((a) => fn(v).then(r => a.concat([r]))),
Promise.resolve([])
);
}
It applies the function given to the array in series and resolves to an array of the results.
Usage:
const numbers = [0, 4, 20, 100];
const multiplyBy3 = (x) => new Promise(res => res(x * 3));
// Prints [ 0, 12, 60, 300 ]
processArray(numbers, multiplyBy3).then(console.log);
You'll want to double check browser compatibility but this works on reasonably current Chrome (v59), NodeJS (v8.1.2) and probably most others.
You can use recursion so that you can move to the next iteration in a then block.
function promiseToExecuteAllInOrder(promiseReturningFunctions /* array of functions */) {
var resolvedValues = [];
return new Promise(function(resolve, reject) {
function executeNextFunction() {
var nextFunction = promiseReturningFunctions.pop();
if(nextFunction) {
nextFunction().then(function(result) {
resolvedValues.push(result);
executeNextFunction();
});
} else {
resolve(resolvedValues);
}
}
executeNextFunction();
}
}
Executing one after another using a recursive function( in a non promise way):
(function iterate(i,result,callback){
if( i>5 ) callback(result);askQuestion().then(res=>iterate(i+1,result.concat([res]),callback);
})(0,[],console.log);
For shure this can be wrapped in a promise:
function askFive(){
return new Promise(function(callback){
(function iterate(i,result){
if( i>5 ) callback(result);askQuestion().then(res=>iterate(i+1,result.concat([res]),callback);
})(0,[],console.log);
});
}
askFive().then(console.log);
Or:
function afteranother(i,promise){
return new Promise(function(resolve){
if(!i) return resolve([]);
afteranother(i-1,promise).then(val=>promise().then(val2=>resolve(val.concat([val2])));
});
}
afteranother(5,askQuestion).then(console.log);

javascript loop promises iterating with array in arguments

I am trying to loop through an array of AsynWork to be done. And cant flood the system with async work done all at the time. so I am trying to do one by one with promises. My problem is that I need to go though an array of values so each async works on each value of the array. I managed to do it with this code, but it works for my specific case. Can't make it general. What would be the approach to make it reusable for other type of arrays? I have seen some solutions with array.reduce then promises but cant figure it out. Also have seen examples with Q but not using, if it can be done with simple javascript would be better.
My Code:
function doSomething(ObjIn1, ObjIn2) {
return new Promise(function(resolve, reject) {
console.log("doSomething: ObjIn1: " + ObjIn1 + " ObjIn2: " + ObjIn2);
setTimeout(function() {
console.log("doSomething Done: ObjIn1: " + ObjIn1 + " ObjIn2: " + ObjIn2);
resolve(ObjIn1, ObjIn2);
}, 500);
})
}
function LoopPromises(Function2Loop, functionOptions, Counter, Max) {
console.log("Counter: " + Counter);
if (Counter < Max) {
Function2Loop.apply(this, [functionOptions[0][Counter], functionOptions[1]]).then(function() {
Counter++;
LoopPromises(Function2Loop, functionOptions, Counter, Max);
});
}
}
LoopPromises(doSomething, [
["A1", "A2", "A3"], "ARG2TESTE"
], 0, 3)
You're overthinking this :) A function with arguments is the same as a function without arguments closing over a function with arguments so:
a(1,2,3,4);
Is the same as
(() => a(1,2,3,4))();
Except perhaps negligibly slower. I'm assuming you need to queue the work for an arbitrary amount of promises. If you need to do it for a fixed number - you can just then between them. Let's see how we can do this:
// runs fn on the array elements in sequence, but
function sequence(fns) { // fns - functions returning promises
return fns.reduce((prev, nextFn) => { // 'fold' the array
return prev.then(nextFn); // after the previous is done, execute the next
}, Promise.resolve()); // start with an empty promise
}
Make sure you understand reduce first. For convenience - let's see an example without it:
function sequence(fns) { // fns - functions returning promises
var queue = Promise.resolve();
fns.forEach(fn => queue = queue.then(fn));
return queue;
}
We're iterating through our array of work (functions) and executing them one after the other where we execute the next after the promise the previous returned resolved.
Where the values wait for each other based on the promise resolving (via then). This would let you do:
sequence([
() => new Promise(r => setTimeout(r, 500));
() => console.log("I only run after the previous work completed");
]);

Making async javascript task in a loop

function(obj){
for (property in obj) {
if (obj.hasOwnProperty(property)) {
// some code here
if(condition){
obj.children = example.getdata(base, obj.name);
}
// some more code releated to obj
}
}
if (obj.length == 10)
{
//some more function
}
}
Now i want to make example.getdata async but i dont want to execute if statement that is after for loop until all the sync tasks are done.
Its more of like i want all the example.getdata function calls to execute in parallel and after they finish work i execute if (obj.length).
I tried using promises and push all the promises and resolve them but i dont know how to handle the return value for each function call.
You can use Promise s.
Think of something like:
var jobs = get_jobs(data);
when_all(jobs).done(function (jobs_result) {
console.log(jobs_result);
});
Where get_jobs returns a list or Promises and when_all will resolve when all it's input jobs are resolved.
To run async tasks serially in a loop, you can't use a regular for loop because the for loop won't wait for your async operation to complete before executing the next cycle of the loop. Rather, you have to do your own custom iteration a slightly different way. Here's one way:
Assuming your getdata() function is actually asynchronous and has a completion function, you could structure things like this:
function myFunc(obj, callback) {
var keys = Object.keys(obj);
var cntr = 0;
var results = [];
function next() {
if (cntr < keys.length) {
example.getdata(obj[keys[cntr++]], function(result) {
// do something with the result of each async operation here
// and put it in the results array
// kick off the next iteration
next();
});
} else {
// call the final callback because we are done now with all async operations
callback(results);
}
}
// start the first iteration
next();
}
If your getData function returns a promise or can be made to return a promise, then you can use promises for this too:
function myFunc(obj) {
var keys = Object.keys(obj);
keys.reduce(function(p, item) {
return p.then(function(result) {
// do something with the result of each async operation here
// and put it in the results array
return example.getdata(obj[item]);
});
}, Promise.resolve());
}
myFunc.then(function(results) {
// all async operations done here, use the results argument
});
Here is a clean example of a for loop using promises. If you can pick a promise library libraries like Bluebird will make it even simpler:
function(obj){
var props = Object.keys(obj), p = Promise.resolve();
props.forEach(function(prop){
p = p.then(function(){
if(condition){ // can access obj[prop] and obj here
obj.children = example.getData(...); // getData returns a promise
return obj.children; // return the promise.
}
});
});
Promise.resolve(obj.children).then(function(children){
// here the async call to get `.children` is done.
// can wait for `p` too (the loop) if we care about it
if(obj.length === 10) // do stuff
});

jQuery Promise, $.when execute all deferreds in array [duplicate]

Here's an contrived example of what's going on: http://jsfiddle.net/adamjford/YNGcm/20/
HTML:
Click me!
<div></div>
JavaScript:
function getSomeDeferredStuff() {
var deferreds = [];
var i = 1;
for (i = 1; i <= 10; i++) {
var count = i;
deferreds.push(
$.post('/echo/html/', {
html: "<p>Task #" + count + " complete.",
delay: count
}).success(function(data) {
$("div").append(data);
}));
}
return deferreds;
}
$(function() {
$("a").click(function() {
var deferreds = getSomeDeferredStuff();
$.when(deferreds).done(function() {
$("div").append("<p>All done!</p>");
});
});
});
I want "All done!" to appear after all of the deferred tasks have completed, but $.when() doesn't appear to know how to handle an array of Deferred objects. "All done!" is happening first because the array is not a Deferred object, so jQuery goes ahead and assumes it's just done.
I know one could pass the objects into the function like $.when(deferred1, deferred2, ..., deferredX) but it's unknown how many Deferred objects there will be at execution in the actual problem I'm trying to solve.
To pass an array of values to any function that normally expects them to be separate parameters, use Function.prototype.apply, so in this case you need:
$.when.apply($, my_array).then( ___ );
See http://jsfiddle.net/YNGcm/21/
In ES6, you can use the ... spread operator instead:
$.when(...my_array).then( ___ );
In either case, since it's unlikely that you'll known in advance how many formal parameters the .then handler will require, that handler would need to process the arguments array in order to retrieve the result of each promise.
The workarounds above (thanks!) don't properly address the problem of getting back the objects provided to the deferred's resolve() method because jQuery calls the done() and fail() callbacks with individual parameters, not an array. That means we have to use the arguments pseudo-array to get all the resolved/rejected objects returned by the array of deferreds, which is ugly:
$.when.apply($,deferreds).then(function() {
var objects = arguments; // The array of resolved objects as a pseudo-array
...
};
Since we passed in an array of deferreds, it would be nice to get back an array of results. It would also be nice to get back an actual array instead of a pseudo-array so we can use methods like Array.sort().
Here is a solution inspired by when.js's when.all() method that addresses these problems:
// Put somewhere in your scripting environment
if (typeof jQuery.when.all === 'undefined') {
jQuery.when.all = function (deferreds) {
return $.Deferred(function (def) {
$.when.apply(jQuery, deferreds).then(
// the calling function will receive an array of length N, where N is the number of
// deferred objects passed to when.all that succeeded. each element in that array will
// itself be an array of 3 objects, corresponding to the arguments passed to jqXHR.done:
// ( data, textStatus, jqXHR )
function () {
var arrayThis, arrayArguments;
if (Array.isArray(this)) {
arrayThis = this;
arrayArguments = arguments;
}
else {
arrayThis = [this];
arrayArguments = [arguments];
}
def.resolveWith(arrayThis, [Array.prototype.slice.call(arrayArguments)]);
},
// the calling function will receive an array of length N, where N is the number of
// deferred objects passed to when.all that failed. each element in that array will
// itself be an array of 3 objects, corresponding to the arguments passed to jqXHR.fail:
// ( jqXHR, textStatus, errorThrown )
function () {
var arrayThis, arrayArguments;
if (Array.isArray(this)) {
arrayThis = this;
arrayArguments = arguments;
}
else {
arrayThis = [this];
arrayArguments = [arguments];
}
def.rejectWith(arrayThis, [Array.prototype.slice.call(arrayArguments)]);
});
});
}
}
Now you can simply pass in an array of deferreds/promises and get back an array of resolved/rejected objects in your callback, like so:
$.when.all(deferreds).then(function(objects) {
console.log("Resolved objects:", objects);
});
You can apply the when method to your array:
var arr = [ /* Deferred objects */ ];
$.when.apply($, arr);
How do you work with an array of jQuery Deferreds?
When calling multiple parallel AJAX calls, you have two options for handling the respective responses.
Use Synchronous AJAX call/ one after another/ not recommended
Use Promises' array and $.when which accepts promises and its callback .done gets called when all the promises are return successfully with respective responses.
Example
function ajaxRequest(capitalCity) {
return $.ajax({
url: 'https://restcountries.eu/rest/v1/capital/'+capitalCity,
success: function(response) {
},
error: function(response) {
console.log("Error")
}
});
}
$(function(){
var capitalCities = ['Delhi', 'Beijing', 'Washington', 'Tokyo', 'London'];
$('#capitals').text(capitalCities);
function getCountryCapitals(){ //do multiple parallel ajax requests
var promises = [];
for(var i=0,l=capitalCities.length; i<l; i++){
var promise = ajaxRequest(capitalCities[i]);
promises.push(promise);
}
$.when.apply($, promises)
.done(fillCountryCapitals);
}
function fillCountryCapitals(){
var countries = [];
var responses = arguments;
for(i in responses){
console.dir(responses[i]);
countries.push(responses[i][0][0].nativeName)
}
$('#countries').text(countries);
}
getCountryCapitals()
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<h4>Capital Cities : </h4> <span id="capitals"></span>
<h4>Respective Country's Native Names : </h4> <span id="countries"></span>
</div>
As a simple alternative, that does not require $.when.apply or an array, you can use the following pattern to generate a single promise for multiple parallel promises:
promise = $.when(promise, anotherPromise);
e.g.
function GetSomeDeferredStuff() {
// Start with an empty resolved promise (or undefined does the same!)
var promise;
var i = 1;
for (i = 1; i <= 5; i++) {
var count = i;
promise = $.when(promise,
$.ajax({
type: "POST",
url: '/echo/html/',
data: {
html: "<p>Task #" + count + " complete.",
delay: count / 2
},
success: function (data) {
$("div").append(data);
}
}));
}
return promise;
}
$(function () {
$("a").click(function () {
var promise = GetSomeDeferredStuff();
promise.then(function () {
$("div").append("<p>All done!</p>");
});
});
});
Notes:
I figured this one out after seeing someone chain promises sequentially, using promise = promise.then(newpromise)
The downside is it creates extra promise objects behind the scenes and any parameters passed at the end are not very useful (as they are nested inside additional objects). For what you want though it is short and simple.
The upside is it requires no array or array management.
I want to propose other one with using $.each:
We may to declare ajax function like:
function ajaxFn(someData) {
this.someData = someData;
var that = this;
return function () {
var promise = $.Deferred();
$.ajax({
method: "POST",
url: "url",
data: that.someData,
success: function(data) {
promise.resolve(data);
},
error: function(data) {
promise.reject(data);
}
})
return promise;
}
}
Part of code where we creating array of functions with ajax to send:
var arrayOfFn = [];
for (var i = 0; i < someDataArray.length; i++) {
var ajaxFnForArray = new ajaxFn(someDataArray[i]);
arrayOfFn.push(ajaxFnForArray);
}
And calling functions with sending ajax:
$.when(
$.each(arrayOfFn, function(index, value) {
value.call()
})
).then(function() {
alert("Cheer!");
}
)
If you're transpiling and have access to ES6, you can use spread syntax which specifically applies each iterable item of an object as a discrete argument, just the way $.when() needs it.
$.when(...deferreds).done(() => {
// do stuff
});
MDN Link - Spread Syntax
I had a case very similar where I was posting in an each loop and then setting the html markup in some fields from numbers received from the ajax. I then needed to do a sum of the (now-updated) values of these fields and place in a total field.
Thus the problem was that I was trying to do a sum on all of the numbers but no data had arrived back yet from the async ajax calls. I needed to complete this functionality in a few functions to be able to reuse the code. My outer function awaits the data before I then go and do some stuff with the fully updated DOM.
// 1st
function Outer() {
var deferreds = GetAllData();
$.when.apply($, deferreds).done(function () {
// now you can do whatever you want with the updated page
});
}
// 2nd
function GetAllData() {
var deferreds = [];
$('.calculatedField').each(function (data) {
deferreds.push(GetIndividualData($(this)));
});
return deferreds;
}
// 3rd
function GetIndividualData(item) {
var def = new $.Deferred();
$.post('#Url.Action("GetData")', function (data) {
item.html(data.valueFromAjax);
def.resolve(data);
});
return def;
}
If you're using angularJS or some variant of the Q promise library, then you have a .all() method that solves this exact problem.
var savePromises = [];
angular.forEach(models, function(model){
savePromises.push(
model.saveToServer()
)
});
$q.all(savePromises).then(
function success(results){...},
function failed(results){...}
);
see the full API:
https://github.com/kriskowal/q/wiki/API-Reference#promiseall
https://docs.angularjs.org/api/ng/service/$q

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