I am trying to inject a banner div
<div id='banner'></div>
on top of an existing webpage in such a manner so that when a person scrolls the webpage the banner remains on top. Also the webpage should be pushed down by the banner so that every part of the page remains accessible.
Here is my CSS:
#banner {
position:fixed;
display:block;
top:0px;
background-color:#FFFFFF;
width:100%; height:250px;
border:2px solid;
}
Here is my jquery:
$("body").prepend("<div id='banner'></div>");
I tried using jquery to find all divs that were fixed and changing them to relative before executing the above line but still the banner does not work. The error is shown in the following picture https://drive.google.com/file/d/0B0sCu8aj8zu2akhtcEdtajJJZEU/edit?usp=sharing
Please Help.
And I am not looking for ad revenue here this is just a practice task.
Here is a jsFiddle I have created. The banner div is at the top of the page.
It stays at the top while scrolling.
The HTML:
<div class="page">
</div>
The css:
.oldBody
{
width:100%;
height: 3000px;
background-color: navy;
margin-top:250px;
}
#banner
{
position:fixed;
top:0px;
background-color:#FFFFFF;
width:100%;
height:250px;
border:2px solid;
z-index:10000;
}
The JS:
$("body").wrapAll("<div class='oldBody'></div>");
$("body").prepend("<div id='banner'></div>");
Please maintain z-index of banner div.Z-index should be grater then other div on that page.
#banner {
position:fixed;
display:block;
top:0px;
background-color:#FFFFFF;
width:100%; height:250px;
border:2px solid;
z-index : 99999
}
i'd just like to present a different way to create the element:
var $banner = $('<div/>', { 'id' : 'banner' });
$('body').prepend($banner);
this technique for creating elements with jquery comes in handy when you have several different element to create. as a note, you can also create the element like so:
var $banner = $('<div/>').attr('id', 'banner');
I think the best way is first keep your ad on top in relative position when a person scroll page your function check the page-scroll .scrollTop() and then add fixed position on banner ad container just like freeze header, if you need further help in this regard let me know, I will provide you code. thanks I hope this technique will help you
Related
I want to make a gallery in HTML/CSS/jQuery. I have a bunch of thumbnails that all represent different images of varying sizes and orientations. When the thumbnail is clicked, I want the image to slide down from the top of the screen. The image should be as large as possible but still fitting in the window, taking into account margins and the like.
I have gotten all this to work properly in the past. However, now I want to add a caption below the image.
My solution was this. I have a div container that is fixed and is positioned with top:-96% and bottom:100% When a thumbnail is clicked, jQuery moves that to top:2% and bottom:2%
Previously I had a border that surrounded the image. Now I want to make that border actually part of a div instead, so that the border can go around the caption which should be below the image and centered, and said image.
Nothing I am doing is working, however. The image will not fit into the viewport, and will always be its max size no matter what I change the percent to.
I'm completely lost, I have no idea how to make this all work out. If you need code, I can give it to you, but as I said, it doesn't work. Thank you all in advance.
EDIT: Added code
HTML:
<div id=imgHoverCont>
<div id=imgBg>
<img id=imgHover src="" alt="">
<div id=commentHover></div>
</div>
</div>
CSS:
#imgHoverCont{
text-align:center;
position:fixed;
left:2%;
right:2%;
top:-96%;
bottom:100%;
}
#imgHover{
display:block;
height:100%;
width:auto;
}
#imgBg{
position: relative;
display: inline-block;
max-width:100%;
max-height:100%;
}
#commentHover{
position:absolute;
left:0;
bottom:0;
width:100%;
color:black;
background-color:white;
}
JS: Thumbnails are stored in an array of objects with their ID and their source.
for(let i in thumbnails){
$(thumbnails[i].id).on("click",function(livingHell){
return function(){
$("#imgHover").attr("src",thumbnails[livingHell].src)
$("#imgHoverCont").css("display","block");
$("#commentHover").html(thumbnails[livingHell].comment);
$("#imgHoverCont").animate({bottom:"2%",top:"2%"},1000);
}
}(i));
};
I've made some changes to your CSS
if I understood your question it works like expected, look here: https://jsfiddle.net/cratgjks/
#imgHoverCont{
text-align:center;
position:fixed;
left:2%;
right:2%;
top:-96%;
bottom:100%;
width:100%; /*new rule*/
}
#imgHover{
display:block;
height:100%;
width:100%;/*changed rule*/
}
#imgBg{
position: relative;
display: inline-block;
max-width:100%;/*changed rule*/
max-height:100%;
width:1500px
}
#commentHover{
position:absolute;
left:0;
bottom:0;
width:100%;
color:black;
background-color:white;
}
I'm trying to make a fullscreen site, also responsive, but on smaller screens the elements in the container overflow making it not 100% it varies depending on how many items are in it. Using:
top:100%;
position:relative;
width:100%;
height:100%
works, only if the screen is a certain size, on mobile devices using that it doest work, and appears half on the previous container.
Is there a way to position from the bottom of the element rather than top?
http://jsfiddle.net/q8tvwm2k/2/
Update:
Never minds found a pretty bad but working solution.
I'm pretty sure you really want a position:absolute to have another div relative to it. You just didn't word the question correctly. position:relative sets the point to which its children can be position:absolute, which is where you want to use top and the like. This is the structure you need to see:
HTML
<div class='surround'>
<div class='inside'>
<div class='outer'>
<div class='inner'>
</div>
</div>
</div>
</div>
CSS
.surround{
position:relative;
}
.inside{
height:100px; width:100px; position:absolute; top:100px; left:100px;
}
.outer{
height:100px; width:100px; position:relative;
}
.inner{
position:absolute; top:30px; left:10px;
}
So I have a simple lightbox with code like this:
jquery code:
var $overlay =$('<div class="overlay"></div>');
$('body').append($overlay);
$('img').click(function(){
$overlay.show();
});
css:
.overlay {
width: 100%;
height:100%;
background:grey;
display:none;
position: absolute;
top:0;
}
This is obviously very simple I haven't wrote much code except the overlay that will appear when the image is clicked and triggers the lightbox.
Here are my questions:
My webpage is longer than the screen, what code could I use to stop the screen scrolling when my lightbox is triggered.
Is it possible to set the lightbox $overlay to only fill the screen in view. So only take up the part of the webpage in the current screen view. I have images spread out over webpages and I when are a lightbox is triggered I would like it to fill only that part of the screen.
Well, I decided to post an answer hopefully it will help you.
First things first, your JavaScript. From the JS you posted, it looks like you are using a different .overlay for each image. Not needed.
Simply make one overlay like so:
<div class="overlay"><img src="#" width="500"/></div>
Then, set the images src when you click on an image on your webpage:
$('img').click(function(){
var src = $(this).attr('src');//Gets the image you clicked on src
$('.overlay').fadeIn();//Fades in the overlay
$('.overlay img').attr('src',src).css('margin-top',($(window).height() - $('.overlay img').height()-20)/2);//Sets the overlay image to the correct source, and centers the image. -20 is for the border
});
$('.overlay').click(function(){
$(this).fadeOut();// And fades out the overlay on click
});
Simple and easy. Now to your actual question.
How you are going to achieve what you want is with CSS.
First, set the body and html's height and width to 100%, and remove the margin. This stops overlay from making scroll bars:
body, html{
width:100%;
height:100%;
margin:auto;
}
Then, to make overlay appear over the image you clicked, change position:absolute; to position:fixed;:
.overlay {
width: 100%;
height:100%;
background:grey;
display:none;
position: fixed;
top:0;
text-align:center;
cursor:pointer;
}
Add a little more CSS to make it look pretty:
.overlay img{
border-radius:5px;
border:10px solid white;
box-shadow: 0 0 5px black;
}
And Bang!
JSFiddle Demo
Make sure you check out the coding in this JSFiddle
I've got to (unfortunately) put our ads onto our website. They're positioned down the right hand side of the page, outside of the content area.
When the screen width gets smaller, because it's positioned outside of the content they get cut off by the browser. I can offset everything by putting left: -someValuepx, which moves everything over.
Rather than having to put in lots and lots of media queries to keep slightly moving it over, is this something I can do in Javascript, to automatically keep them in the view? Ideally I'd like a function that I can run on page load, and then on the window resize event.
Here's a jsfiddle of the CSS at the moment. Edit the #container left attr to move the content.
And here's the code (as I believe it's required if you link to jsfiddle?)
HTML
<div id="container">
<div id="ads">
</div>
<div id="content">
</div>
</div>
CSS
#container {
width:500px;
min-height:100px;
background-color: firebrick;
margin:0px auto;
position:relative;
left:-50px;
}
#ads {
background-color:red;
position:absolute;
top:0;
right:-170px;
width:160px;
min-height:100px;
}
#content {
width:100%;
background-color:green;
min-height:100px;
}
I have a pure css solution, if you change your div structure to the following:
<div id="container">
<div class="padding">
<div id="ads"></div>
<div id="content"></div>
</div>
</div>
You are able to use the following styles:
#container {
width:670px;
min-height:100px;
margin:0px auto;
position:relative;
}
#container > .padding {
margin-right:170px;
background-color: firebrick;
}
#ads {
background-color:red;
position:absolute;
top:0;
right:0;
width:160px;
min-height:100px;
}
#content {
width:100%;
background-color:green;
min-height:100px;
}
#media (max-width:670px) /*this is the width of the container*/
{
#container {float:right;}
}
And this will keep your adds in view when the viewport is resized
Example
What you can do, is to create a function in JS that gets executed one time when the document is loaded and also when you resize.
This function should add a class (ie: hidden) to the the ads. you want to hide, and with CSS, give the right properties. Just addClass and removeClass, depending on the situation, should make the trick.
Example:
#ads { // normal values that makes the content of the ads visible }
#ads .hide { // offset values to hide the ads }
This way, you keep behavior & presentation separated.
Hope it helps !
In your html markup, you have both content and the ads inside a container. The problem is that the content takes all space of the container, and the ads are positioned outside of it.
Just make the container wide enaugh to hold both content and the ads, then position them appropriately. Make one break point on the width of content+ads (660px), where you would position the ads below the content, and give the container its current width (500px).
I was curious if there was a way to remove an element from the page flow similar to position:fixed;, such that the page won't scroll.
Example - currently even though it goes beyond the screen it doesn't increase the size of the document, but if position is changed to absolute / relative it will.
I would like for the position to be absolute (although relative will work), yet not increase the document size.
I'm looking for ways to do this be it html/css work around, JavaScript, or jquery (even browser-specific solutions).
Depending what else you have on the page, this might do the trick.
body {
height:100%;
width:100%;
overflow:hidden;
}
nav{
width:98px;
height:750px;
background:blue;
position:absolute;
}
If you want other elements to overflow the body, use this code.
<div class="wrapper">
<nav></nav>
</div>
body {
height:100%;
}
.wrapper {
position:absolute;
top:0;
bottom:0;
width:100%;
overflow:hidden;
}
nav{
width:98px;
height:750px;
background:blue;
position:absolute;
}