I have a reason to use checkboxes instead of radio buttons so please don't suggest I use radio buttons but need to duplicate the functionality. However when I select the Yes checkbox, it disables the No checkbox for some reason. When no is selected I want to hide the div and deselect Yes, and the opposite when I select Yes I want to show the div and uncheck NO. The only way I can select NO when Yes is checked is to uncheck it.
Working demo Here
JS Fiddle not working Here
Javascript
function injure() {
if (document.getElementById("f2").checked == true) {
document.getElementById("LocFall").style.display="block";
document.getElementById("f1").checked = false;
} else {
if (document.getElementById("f1").checked == true) {
document.getElementById("LocFall").style.display="none";
document.getElementById("f2").checked = false;
}
}
}
CSS
#LocFall {
display:none;
}
HTML
<input type="checkbox" id="f1" name="" onclick="injure();">
<label for="f1"> No </label><BR>
<input type="checkbox" id="f2" name="" onclick="injure();">
<label for="f2"> Yes</label><BR>
<div id="LocFall">
Show some stuff
</div>
http://jsfiddle.net/6NN6s/14/
<input type="checkbox" id="f1" name="same" onclick="injure(this);" />
<label for="f1">No</label>
<BR>
<input type="checkbox" id="f2" name="same" onclick="injure(this);" />
<label for="f2">Yes</label>
<BR>
<div id="LocFall">Show some stuff</div>
function injure(cmb) {
if (cmb.checked) {
if(cmb.id==="f2")
{ document.getElementById("LocFall").style.display = "block";
document.getElementById("f1").checked = false;
}
else
{
document.getElementById("LocFall").style.display = "none";
document.getElementById("f2").checked = false;
}
}
}
try this out, may be what you need.
In Fiddle change on the left in second drop-down list 'onLoad' to 'no wrap - in <head>'.
Split injure into a different function for each; if you choose No, then you cannot choose Yes because of the way your function is set up - the first condition will always evaluate as true.
The problem stems from not knowing which checkbox was actually clicked inside the function. As it is there's only two different ways the function can respond: one if f1 is checked and one if f2 is checked. The problem is there's actually more possible states that you're trying to represent.
State 1: Nothing checked, user clicks f1 or f2
State 2: f1 checked, f2 clicked
State 3: f2 checked, f1 clicked
Your code handles the first state fine but it can't deal properly with the second ones. If you split your code into two seperate functions to handle each box then you'll have all the necessary information to write correct decision logic.
There's also the states of clicking the same box, but they are simple and your code handles them already.
Related
I need to know if a radio button has been selected to hide / show other options.
<input #r4 type="radio" name="x">
<span>Group</span>
<div class="subOption" *ngIf="r4.checked"></div>
div.subOption must be displayed when it has been selected.
it's correct?¿
I would just create a new boolean variable in the component, that you set as true when radio button has been checked. With that boolean you then display the div. So for example:
isChecked: boolean = false; // our new variable
<input type="radio" name="x" (click)="isChecked = true">
<div *ngIf="isChecked">
<!-- Your code here -->
</div>
EDIT: As to multiple radiobuttons... as mentioned in a comment, radio buttons seems at this point be kind of buggy with Angular. I have found the easiest way to deal with radio buttons seems to be using a form. So wrap your radio buttons in a form, like so:
<form #radioForm="ngForm">
<div *ngFor="let val of values">
<input (change)="changeValue(radioForm.value)" type="radio" [value]="val.id" name="name" ngModel />{{val.name}}
</div>
</form>
whereas on radio button would look like the following in this example:
{
id: 1,
name: 'value1'
}
In the form there is a change event, from which we pick up the chosen radio button value.
(change)="changeValue(radioForm.value)"
Then I would just play with boolean and the value chosen:
changeValue(val) {
this.valueChosen = true; // shows div
this.chosenVal = val.name; // here we have the value chosen
}
A plunker to play with: here
I have a checkbox on a form that does something dangerous. So, I want to make sure the user is really sure when they check this item, but I don't want to warn them if they're unchecking the checkbox.
My issue is this works fine if they click on the actual checkbox to uncheck it, but not the text of the label.
http://jsfiddle.net/j2ppzpdk/
function askApply() {
if (document.getElementById("apply").checked) {
var answer = confirm("Are you sure about that?");
if (!answer) {
document.getElementById("apply").checked = false;
}
}
}
<form>
<label onclick="askApply();">
<input type="checkbox" name="apply" id="apply" value="1" /> Apply
</label>
</form>
Some notes:
Better add the event listener to the element that changes (the checkbox), not its label.
Better listen to change event instead of click. For example, the checkbox could be changed using the keyboard.
Better avoid inline event listeners. You can use addEventListener instead.
document.getElementById('apply').addEventListener('change', function() {
if(this.checked) {
var answer = confirm("Are you sure about that?");
if (!answer) {
document.getElementById("apply").checked = false;
}
}
});
<form>
<label>
<input type="checkbox" name="apply" id="apply" value="1" />
Apply
</label>
</form>
I have seen other examples of this but have not successfully gotten this to function correctly. The examples I have seen also are just using regular checkboxes. I have used a class to stylize the checkbox with a sprite sheet so having a bit of trouble taking the ideas of these other examples and applying them to my case.
Here is the mark up:
<div id="showHideAll"">Show/Hide All<input type="checkbox" id="allCheck" name="pinSet" class="pinToggles" onclick="checkAllLinks()">
<label for="allCheck" class="css-label"></label></div>
</div>
<div>Opt1<input type="checkbox" id="opt1Check" name="pinSet" class="pinToggles" onclick="checkOpt1Links()">
<label for="opt1Check" class="css-label"></label>
</div>
<div>Opt2<input type="checkbox" id="opt2Check" name="pinSet" class="pinToggles" onclick="checkOpt2Links()">
<label for="opt2Check" class="css-label"></label>
</div>
<div>Opt3<input type="checkbox" id="opt3Check" name="pinSet" class="pinToggles" onclick="checkOpt3Links()">
<label for="dinShopCheck" class="css-label"></label>
</div>
The checked property is what changes the sprite using a css class.
input[type=checkbox].pinToggles:checked + label.css-label {
background-position: 0 -16px;
}
Most of this is for other functionality but thought I would show it just in case.
This is how I set up the individual checkboxes:
function checkOpt1Links(){
$('#opt1 li a').toggleClass("inactive");
if(opt1.getVisible() == true)
{
opt1.setOptions({visible:false});
}
else
{
opt1.setOptions({visible:true});
}
}
What I am looking for is the typical select all checkbox functionality, where if you check it the boxes all check, if you uncheck they all uncheck but also if you click a box when select all is checked the select all and the clicked checkbox uncheck and vice versa. I did look at this example: Jquery "select all" checkbox but just having difficult time making it work. Thanks for the help!
1) Use change event handler instead of click for checkbox and radio buttons.
You can make it simple like this
$('#showHideAll').on('change', 'input[type=checkbox]', function () {
if ($('.pinToggles').is(':checked')) {
$('.pinToggles').prop('checked', false)
}
else {
$('.pinToggles').prop('checked', true)
}
});
2) I have removed the class and onclick event handler in the below checkbox only.
HTML:
<div id="showHideAll">Show/Hide All<input type="checkbox" id="allCheck" name="pinSet" >
<label for="allCheck" class="css-label"></label></div>
</div>
Check this JSFiddle
I am trying to toggle the value of a checkbox using the following code:
<div class="control-group">
<label class="control-label checkbox" for="IsViewAsWebpage">
{{#if this.IsViewAsWebpage}}
<input type="hidden" id="IsViewAsWebpage" name="IsViewAsWebpage" value="true"/>
<input type="checkbox" class="enable-checkbox" checked />
{{else}}
<input type="hidden" id="IsViewAsWebpage" name="IsViewAsWebpage" value="false"/>
<input type="checkbox" class="enable-checkbox" />
{{/if}}
<span>View as Webpage</span>
</label>
</div>
'click .enable-checkbox': function (e) {
if (e.currentTarget.parentElement.htmlFor == "IsViewAsWebpage") {
this.$('#IsViewAsWebpage').is(':checked');
}
}
I know I am misssing something in the click function. I would basically want to toggle the checkbox value when the user clicks on it. Can someone point me to the right directions pls. Thank you.
When your checkbox gets clicked, it's going to toggle. That's the way checkboxes work.
If you want the hidden input to change value when the checkbox is toggled, I think what you want is this:
$(".enable-checkbox").change(function (e) {
if($(this).parent().attr("for") == "IsViewAsWebpage") {
var checked = $(this).is(":checked"); // Returns true/false.
$('#IsViewAsWebpage').attr("value", checked); // Sets true/false.
}
});
If you want to use handlebars.js to switch content when you click an check box, you will need to replace your content by calling handlebars each time you make a modification to your checkbox
$(".enable-checkbox").change(function (e) {
if($(this).parent().attr("for") == "IsViewAsWebpage") {
var checked = $(this).is(":checked");
IsViewAsWebpage = checked;
$("#yourcontainer").html(Handlebars.compile(yourtemplatesource));
}
}
then your IsViewAsWebpage variable should be global and your mustache condition should only be :
{{#if IsViewAsWebpage}}
But this is complicated for nothing... just use Aesthete solution, it will save you a lot of time.
I am using the script below to show and hide a div based on whether or not the checkbox is checked, this if so I can show/hide a paypal button until they accept the terms.
But we now want of offer three payment option so it will need to open/close 3 divs, I tried just copying the div 3 times but it still only opened one. Can any body help me with this please?
<script type="text/javascript">
function doInputs(obj){
var checkboxs = obj.form.c1;
var i =0, box;
document.getElementById('mydiv').style.display = 'none';
while(box = checkboxs[i++]){
if(!box.checked)continue;
document.getElementById('mydiv').style.display = '';
break;
}
}
</script>
<form>
<input type="checkbox" name="c1" onclick="doInputs(this)">
</form>
<div id="mydiv" style="display:none">
<input type="text">
</div>
Also it would be amazing if someone could help me add in another checkbox, and make the paypal buttons (divs) only show when BOTH are checked?
Thanks very much!
I also stole Marcus's answer but with the following improvements:
I use the jQuery document ready event so the code fires after the page loads
I simplified the logic
It works for multiple types of payment
http://jsfiddle.net/5Byes/3/
Using jQuery you can have an array or just two variables that are set to false. When a button is checked you set that equivalent value to the opposite of the current value (so if it was false, it would become true and vice-versa).
Here's a simple example of how you could accomplish this: http://jsfiddle.net/5Byes/
Only one element with particular ID is allowed on the page. If you want more — use class attribute.
On the other hand, you could wrap all divs with payments method in one div with ID, let's say, paymentsMethods and then show/hide it.
var paymentsDiv = document.getElementById('paymentsMethods');
if (box.checked) paymentsDiv.show(); else paymentsDiv.hide();
If you want 2 checkboxes — set onclick of both to same handler and change condition to box1.checked && box2.checked.
With jQuery (which is in your question tags) you could do $('#paymentsMethods').toogle() on checkbox click (see also $.hide() and $.show()).
If I understand correctly what you're looking for, you can do it like this:
HTML:
<input id="opt1cb" type="checkbox" value="Option 1" />Option 1<br />
<input id="opt2cb" type="checkbox" value="Option 2" />Option 2<br />
<input id="opt3cb" type="checkbox" value="Option 3" />Option 3<br />
<div class="option" id="opt1">Option 1</div>
<div class="option" id="opt2">Option 2</div>
<div class="option" id="opt3">Option 3</div>
<div class="option" id="opt23">Option 2 & 3</div>
jQuery:
$('.option').hide();
$('#opt1cb').click( function() {
if( $(this).prop("checked") ) {
$('#opt1').show();
} else {
$('#opt1').hide();
}
});
$('#opt2cb').click( function() {
if( $(this).prop("checked") ) {
$('#opt2').show();
if( $('#opt3cb').prop("checked") )
$('#opt23').show();
} else {
$('#opt2').hide();
$('#opt23').hide();
}
});
$('#opt3cb').click( function() {
if( $(this).prop("checked") ) {
$('#opt3').show();
if( $('#opt2cb').prop("checked") )
$('#opt23').show();
} else {
$('#opt3').hide();
$('#opt23').hide();
}
});
Working jsfiddle here: http://jsfiddle.net/bCDqa/
http://jsfiddle.net/5Byes/4/
I stole Marcus' fiddle and updated it to do what you want.