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How to select and deselect multiple check box with a button click in javascript

In my project, i have multiple check box (total 27).I am trying to select all the check box with a single button click and i am able to do it.But i want to deselect the same check box with the same button click.So the button should act like a selector and a de-selector.I can not use a check box instead of the button.
My html code is:
<div class="countryAll">
<span class="countrySelect_lngTrans_Translatable" title="Select All">
<input type="button" class="selectAllcountry" />
</span>
<span class="displayData">Select whole country</span>
</div>
In js:
$(self.element).on('click', '.selectAllcountry', function(e) {
debugger;
$('.chkCountry').trigger('click')
e.stopPropagation();
});

Using trigger will always toggle the state, so if some elements are checked and some aren't then it won't work fine.
Instead you can try something like
$(document).on('click', '.selectAllcountry', function(e) {
var $checks = $('.chkCountry');
$checks.prop('checked', !$checks.is(':checked'))
e.stopPropagation();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="countryAll">
<span class="countrySelect_lngTrans_Translatable" title="Select All">
<input type="button" class="selectAllcountry" />
</span>
<span class="displayData">Select whole country</span>
</div>
<input class="chkCountry" type="checkbox" />
<input class="chkCountry" type="checkbox" />
<input class="chkCountry" type="checkbox" />
<input class="chkCountry" type="checkbox" />

Try this
$('.selectAllcountry').on('click', function(){
if ($('.selectAllcountry').is(':checked')) {
$('.chkCountry').find(':checkbox').prop('checked', true);
} else {
$('.chkCountry').find(':checkbox').prop('checked', false);
}
});

try this....
$(document).on('click', 'input.selectAllcountry', function(e) {
if ($('input.selectAllcountry').is(':checked'))
{
$('.chkCountry').prop('checked',true);
}
else
$('.chkCountry').prop('checked',false);
});

var chkStatus = true;
$('.selectAllcountry').click(function() {
$('.countryAll').find(':checkbox').prop('checked', chkStatus);
chkStatus = !chkStatus;
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="countryAll">
<span class="countrySelect_lngTrans_Translatable" title="Select All">
<input type="button" class="selectAllcountry" />
</span>
<span class="displayData">Select whole country</span>
<br>
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
<input type="checkbox" name="vehicle" value="Bike">I have a bike
<br>
</div>

as you have done the portion of selection, now focus on Deselecting.
to remove all checkbox inputs at once
$('input:checkbox').removeAttr('checked');
or you can add class as identifier and then remove checked element on the basis of class.
for exa.
$('.chkCountry').removeAttr('checked');

I think you have made one mistake in your code you have used class attribute twise in html tag.I think that's why it take first class attribute and other are ignored.
<div class="countryAll">
<span class="countrySelect_lngTrans_Translatable" title="Select All">
<input type="button" class="selectAllcountry" />
</span>
<span class="displayData">Select whole country</span>
</div>
please combine all class in single class attribute.
I think it will be helpful.

HTML FORMS - Passing values to two different forms on the same page

I am having problems trying to pass values to two different forms on the same page. The page is populated with 16 radio buttons (which I’ve turned into boxes for display reasons) and they all hold a value (e.g. 001). Both of the forms jobs are to somehow grab the active/selected radio button value and post it to a PHP file so database changes can be made. Instead of a submit button, I am using an anchor to pass a JavaScript submit function. I have tried having
both forms cover the whole page but still didn't have any luck.
I’ll post some code below to help you understand.
PS. If you need more code to understand, I can post it to pastebin.
<li>
<form id="form_ready" method="post" action="../backend/screen.php">
<input type="hidden" name="screenid" value="" />
<input type="hidden" name="status" value="" />
<input type="hidden" name="pickupid" value="document.activeElement.value;" />
<a onclick="document.getElementById('form_ready').submit();">READY</a>
</form>
</li>
<li>
<form id="form_c" method="post" action="../backend/screen.php">
<input type="hidden" name="status" value="" />
<input type="hidden" name="pickupid" value="document.activeElement.value;" />
<a onclick="document.getElementById('form_c').submit();">COLLECTED</a>
</form>
</li>
</ul>
<div id="content">
<div id="container">
<div id="table">
<div id="tr1">
<div id="td1">
<input type="radio" name="pickup" id="1" value="001" />
<label for="1"> <span>001</span> </label>
</div>
<div id="td2">
<input type="radio" name="pickup" id="2" value="002" />
<label for="2"> <span>002</span> </label>
</div>
<div id="td3">
<input type="radio" name="pickup" id="3" value="003" />
<label for="3"> <span>003</span> </label>
</div>
<div id="td4">
<input type="radio" name="pickup" id="4" value="004" />
<label for="4"> <span>004</span> </label>
</div>

To answer the suggestion in the comments and use only one form, here's how to grab the value from the selected radio button:
var inputs = document.getElementsByTagName('input');
var valueSelected;
for (var i = 0; i < inputs.length; i++) {
if (inputs[i].checked) valueSelected = inputs[i].value;
}
valueSelected will contain the value of the selected radio.
If you ever need to reduce the type to "radio" only for some reason, you can check an input type with inputs[i]['type'] === 'radio' in the for loop.
The best would probably still be to set a class for your "radio" inputs, it will allow the loop to be more specific, hence a more efficient code, for example:
<input type="radio" class="myRadio">
and in JS: var inputs = document.getElementsByClassName('myRadio');

PrintThis Not Capturing Checked Checkboxes

So I am using the PrintThis JQuery plugin in order to print a form field, but for some reason I am unable to have the plugin print out any changes made to the checkboxes. When I click "Print", the only checkbox that appears to change is one that has a "checked" property by default. Any ideas on how to fix this?
HTML:
<body>
<div id="print">
<form>
<input id="option" type="checkbox" checked>
<label class="checkbox" for="option"> You are 18 years or older</label>
<br><br>
<input id="option2" type="checkbox">
<label class="checkbox" for="option2"> You have tested positive for something in your blood</label>
<br><br>
<input id="option3" type="checkbox">
<label class="checkbox" for="option3"> You have health-related kidney problems</label>
<br><br>
<input id="option4" type="checkbox">
<label class="checkbox" for="option4"> You have health-related skin problems</label>
<br><br>
<input id="option5" type="checkbox">
<label class="checkbox" for="option5"> You have a low platelet count</label>
</form>
</div>
<br>
<br>
<input id="printButton" type="button" value="Click here to download and print this checklist to review with your doctor." />
</body>
JSFiddle: http://jsfiddle.net/Hybridx24/bxtpv26x/

Not sure what the problem might be here, but you can get around it by explicitly setting the checked attribute for the checkboxes that are checked.
$("input:button").click(function () {
$('input[type="checkbox"]').each(function() {
var $this = $(this);
if($this.is(':checked')) {
$this.attr('checked', true);
} else {
$this.removeAttr('checked');
}
});
$("#print").printThis({'importStyle': true});
});
Check Fiddle

So after skimming through the plugin's source. Looks like there's a property for form values. I added it in and it seems to work.
$('#selector').printThis({formValues:true});
http://jsfiddle.net/wzp0e9r9/

Usage of radio value in ID selector

Given this html:
<form action="">
<div id="choices">
<input type="radio" name="stype" id="opt1" value="input1_div" checked=""/> Opt1
<input type="radio" name="stype" id="opt2" value="input2_div"/> Opt2
</div>
<div id="stypes">
<div id="input1_div">
<input type="text" id="input1" name="input1" placeholder="input1"/>
</div>
<div id="input2_div" style="display: none;">
<input type="text" id="input2" name="input2" placeholder="input2" disabled=""/>
</div>
</div>
<div id="#sbutton">
<input type="submit" id="input3" value="Submit"/>
</div>
</form>
I use following jQuery to hide/disable input fields based on selected radio buttons:
jQuery('#choices input').each(function() {
var item = this;
$(this).click(function() {
if($('input[type=radio][name=stype]').is(':checked')) {
$('#stypes > div').hide();
$('#stypes input').not("#sbutton").prop('disabled', true);
$('#' + $(item).val()).fadeIn();
$('#' + $(item).val() + ' input').prop('disabled', false);
}
});
});
All-in-One in this jsfiddle.
I'm particularly unsure about my technique to incorporate radio value into the id selector:
$('#' + $(item).val()).fadeIn();
$('#' + $(item).val() + ' input').prop('disabled', false);
What is the correct way to do it? Other tips regarding my jQuery?

First of all, you don't need a sophisticated jQuery.each loop to bind the click and to define this. In each event handler this will be the caller of the function. In your case it is enough to have click function for all of them.
As you said in comments, it's only matter of presentation. I prefer to have one field instead of two fields. Even I prefer to have a fixed name for this text input, though in order to make it very similar to your example I change the name and placeholder accordingly.
$(function(){
$('#choices input').click(function() {
var newName = $(this).val(),
newPlaceholder = $(this).attr("data-placeholder");
$('#interchangable_input[name!='+newName+']').hide()
.attr("name", newName)
.attr("placeholder", newPlaceholder)
.fadeIn();
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="">
<div id="choices">
<input type="radio" name="stype" id="opt1" data-placeholder="Input one" value="input1" checked=""/> <label for="opt1">Opt1</label>
<input type="radio" name="stype" id="opt2" data-placeholder="Input two" value="input2"/> <label for="opt2">Opt2</label>
</div>
<div id="stypes">
<input type="text" id="interchangable_input" name="input1" placeholder="Input one"/>
</div>
<div id="#sbutton">
<input type="submit" id="input3" value="Submit"/>
</div>
</form>
Few more suggestions:
You can use <label for="target id"> for each option label in radio buttons or checkboxes. It will work fine with click event handler, even if the user clicks on the label instead of the button itself.
You can hid some information as data-* attribute in html5. You don't need to necessarily use value.
Update for multiple items
In case of group of multiple items in form, I can imagine a form with different sections or pages. The <fieldset> can be use to group these items. In HTML5 you could just disable the fieldset tag by <fieldset disabled> when you change the form page with jquery. (With exception of IE browsers). Because of this exception we need to disable all items in subforms. In order to handle this part, I defined a class .form-element which applies for all form inputs. You can also use <div> instead of <fieldset>, then you will need to track their enable/disable status.
$(function(){
// initialization by disabling form-elements and hiding them
$("#subforms fieldset[disabled]").hide();
$("#subforms fieldset[disabled] .form-element").attr('disabled','disabled');
// choice tracker
$('#choices input').click(function() {
var $target = $($(this).attr("data-subform")),
$oldElement = $("#subforms fieldset:not([disabled])");
$oldElement.attr('disabled','disabled').hide();
$oldElement.find(".form-element").attr('disabled','disabled');
$target.removeAttr("disabled");
$target.find(".form-element").removeAttr("disabled");
$target.fadeIn();
});
});
fieldset {
border: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="">
<div id="choices">
<input type="radio" name="stype" id="opt1" data-subform="#subform1" value="subform1" checked=""/> <label for="opt1">Opt1</label>
<input type="radio" name="stype" id="opt2" data-subform="#subform2" value="subform2"/> <label for="opt2">Opt2</label>
</div>
<div id="subforms">
<fieldset id="subform1" >
<input class="form-element" type="text" name="input1_1" placeholder="Input one"/>
<input class="form-element" type="text" name="input1_2" placeholder="Input two"/>
</fieldset>
<fieldset id="subform2" disabled>
<input class="form-element" type="text" name="input2_1" placeholder="Input one"/><br />
<textarea class="form-element" name="input2_2" placeholder="Input two"></textarea><br />
<input class="form-element" type="checkbox" name="input2_3" id="input2_3" /> <label for="input2_3">check this first</label>
</fieldset>
</div>
<div id="#sbutton">
<input type="submit" id="input3" value="Submit"/>
</div>
</form>

jQuery - Uncheck other checkboxes if a specific checkbox is selected by user

I would like to uncheck all the checkboxes that are presently selected if a specific checkbox is selected by the user.
Example:
<div>
<label for="foo">
<input type="checkbox" name="meh" id="foo" checked> foo
</label>
</div>
<div>
<label for="bar">
<input type="checkbox" name="meh" id="bar" checked> bar
</label>
</div>
<div>
<label for="foobar">
<input type="checkbox" name="meh" id="foobar"> foobar
</label>
</div>
<div>
<label for="barfoo">
<input type="checkbox" name="meh" id="barfoo" checked> barfoo
</label>
</div>
<div>
<label for="omgwtfbbq">
<input type="checkbox" name="meh" id="omgwtfbbq"> omgwtfbbq
</label>
</div>
If the user selects "omgwtfbbq" checkbox, I would like all the other boxes that might be checked to be unchecked and have the "omgwtfbbq" be the only one checked.

for the label instead of id I think you need for
<div>
<label for="foo">
<input type="checkbox" name="foo" id="foo" checked /> foo
</label>
</div>
<div>
<label for="bar">
<input type="checkbox" name="bar" id="bar" checked /> bar
</label>
</div>
<div>
<label for="foobar">
<input type="checkbox" name="foobar" id="foobar" /> foobar
</label>
</div>
<div>
<label for="barfoo">
<input type="checkbox" name="barfoo" id="barfoo" checked /> barfoo
</label>
</div>
<div>
<label for="omgwtfbbq">
<input type="checkbox" name="omgwtfbbq" id="omgwtfbbq" /> omgwtfbbq
</label>
</div>
then
var $others = $('input[type="checkbox"][name="meh"]').not('#omgwtfbbq')
$('#omgwtfbbq').change(function () {
if (this.checked) {
$others.prop('checked', false)
}
});
$others.change(function () {
if (this.checked) {
$('#omgwtfbbq').prop('checked', false)
}
})
Demo: Fiddle
Note: I'll add a common class to all the input elements which has to be affected by omgwtfbbq and change var $others = $('#foo, #bar, #foobar, #barfoo') to var $others = $('.myclassoninput')

Live demo (click).
$('#omgwtfbbq').click(function() {
$('input:checkbox').not(this).attr('checked', false);
});
Also note that you're re-using id's. Id's should only be used once in a document.

If you choose not to give each checkbox a sequential IDs so that you can use an array, here's a solution:
Place all your controls in a div, with an ID "checkgroup".
Then the JavaScript function goes:
function checkone(d){
if (!d.checked) return; //if it's unchecked, then do nothing
var group=document.getElementById('checkgroup');
var os=group.getElementsByTagName('input');
for (var i=0;i<os.length;i++){
if (os[i].checked&&os[i]!=d) os[i].checked=false;
}
}
Now you can call this function in each checkbox
<div id="checkgroup">
<input id="abcd" onclick="checkone(this);">
<input id="xyz" onclick="checkone(this);">
...
</div>
Note how you don't even need to bother with the name, because the object passes in itself.