I've a Float32Array of 10659503 elements in length. I want to chunk (split) it into small arrays of fixed length. How to do that? I've tried the method bellow it's not working:
var LENGTH = 4096;
var chunking = function(data) {
var chunks = [];
for (var i = 0; i < data.length; i += LENGTH) {
var index = ~~(i/LENGTH);
var offset = i%LENGTH;
if (offset === 0) {
chunks[i] = data.subarray(i, LENGTH);
}
}
console.log(chunks);
}
Thank you,
You can use Float32Array.subarray() get the sliced view of the original array.
function chunking(data, length) {
var result = [];
for (var i = 0; i < data.length; i += length) {
result.push(data.subarray(i, i + length));
}
return result;
}
console.log(chunking(new Float32Array(100), 12));
In general case I would do it using splice
function chunk(data, LENGTH) {
var ret = []
while (data.length) {
ret.push(data.splice(0,LENGTH))
}
return ret
}
But since Float32Array doesn't have this method in prototype (thanks #Felix Kling), it is going to be little bit more complicated:
function chunk(data, LENGTH) {
var ret = []
while (data.length) {
ret.push([].splice.call(data, 0, LENGTH))
}
return ret
}
However, since you probably want to avoid coping data back and forth in memory, you have to use methods that just create new ArrayBufferView without moving actual data. And that is exactly what subarray method is doing. So #thefourtheye answer is the right way to go.
Try this:
newArray = (function(array, chunk) {
retArr = [];
for (var i = 0; i < array.length; i+=chunk)
retArr.push(array.slice(i,i+chunk));
return retArr;
}(oldArray, chunkSize))
http://jsfiddle.net/R3Ume/7/
Related
I have a combinatoric script that's working fine, actually got most of it from the IBM dev website. But I want to be able to not just show the possible combinations, but also extract the numbers on each combination and get the product of the entire numbers. The project am working on mixes numbers (quantity) with strings (codename). So after combining them, i extract the number from each string and get the product of all the numbers in each combination. As shown;
[A2,B4,C5] = 2*4*5 = 40
Here is my javascript code that gets the combination, not to worry, I ran it with a test array of numbers 1-6, without the characters as shown above.
var Util = function() {
};
Util.getCombinations = function(array, size, start, initialStuff, output) {
if (initialStuff.length >= size) {
output.push(initialStuff);
} else {
var i;
for (i = start; i < array.length; ++i) {
Util.getCombinations(array, size, i + 1, initialStuff.concat(array[i]), output);
}
}
}
Util.getAllPossibleCombinations = function(array, size, output) {
Util.getCombinations(array, size, 0, [], output);
}
// Create an array that holds numbers from 1 ... 6.
var array = [];
for (var i = 1; i <= 6; ++i) {
array[i - 1] = i;
}
var output = [];
var resultArray = [];
Util.getAllPossibleCombinations(array, 4, output);
for(var j=0; j<output.length; j++) {
resultArray += output[j] + "=" + "<br />";
}
document.getElementById("test").innerHTML = resultArray;
});
I tried running this code inside the last for loop to get my multiplication, but it's just not executing, i must be doing something wrong. Here is the code;
var inputval = output[j].replace(/[^,.0-9]/g, '');
inputval = inputval.slice(0, -1);
var hoArray = inputval.split(',');
var cunt= hoArray.length;
var ans=1;
for(var m=0; m<cunt; m++)
{
ans *= hoArray[m];
}
Thanks for your assistance in advance.
walk the array then walk the string, then cast and see if it is an integer then tally and sum the product.
let array = ['A20', 'B11', 'C5'];
function getProduct(ar) {
let product = 1;
for (let x of ar) {
let semiProduct = [];
for (let i of x) {
if (Number.isInteger(+i)) {
semiProduct.push(i);
}
}
product *= semiProduct.join('');
}
return product;
}
console.log(getProduct(array))
You could also use a regular expression.
let array = ['A20', 'B11', 'C5'];
function getProduct(ar) {
let product = 1;
for (let x of ar) {
product *= x.match(/\d+/)[0];
}
return product;
}
console.log(getProduct(array))
If you want a way to generate permutations, you can utilize a generator to make things more concise.
let array = ['A20', 'B11', 'C5'];
function* permu(arr, l = arr.length) {
if (l <= 0) yield arr.slice();
else
for (var i = 0; i < l; i++) {
yield* permu(arr, l - 1);
const j = l % 2 ? 0 : i;
[arr[l - 1], arr[j]] = [arr[j], arr[l - 1]];
}
}
console.log(
Array.from(permu(array))
);
When I run that code in the console it throws an error because output[j] is an array [1,2,3,4] and it looks like you're expecting it to be a string. Arrays do not have a replace method in JS.
You should run this:
var count= hoArray.length;
var ans=1;
for(var m=0; m<count; m++)
{
ans *= hoArray[m];
}
And put output[j] instead of hoArray. And don't do any of this:
var inputval = output[j].replace(/[^,.0-9]/g, '');
inputval = inputval.slice(0, -1);
var hoArray = inputval.split(',');
I'm pretty sure this is a basic question but my PHP background is making me unable to solve this. I was also unable to find a solution that came even close in SO.
I have an array of objects containing a value I want to loop and sum. Everything works well but I would like to directly sum those values to another array in the output.
So this is the working function:
function postsCalc(arrayEntry) {
var postsOutput = [];
var postLikes = 0;
for (var i = 0, len = arrayEntry.length; i < len; i++) {
postLikes += arrayEntry[i].likes.summary.total_count;
}
postsOutput.likes = postLikes;
return postsOutput;
}
Output:
likes : 55555;
Which works well, but can't I push it directly to the array key and avoid having to do the postsOutput.likes = postLikes?
Like this:
function postsCalc(arrayEntry) {
var postsOutput = [];
for (var i = 0, len = arrayEntry.length; i < len; i++) {
postsOutput.likes += arrayEntry[i].likes.summary.total_count;
// or even a multidimensional:
postsOutput.totals.likes += arrayEntry[i].likes.summary.total_count;
}
return postsOutput;
}
and that would output the same as above but avoiding the extra step, is this possible in Javascript?
Thanks in advance
You can use the reduce function on a list to do this:
function postsCalc(arrayEntry) {
var postLikes = arrayEntry.reduce(function(a, b) {return a + b.likes.summary.total_count}, 0);
return {likes: postLikes};
}
It works like this: Array.reduce(callback, initialValue) where callback = function(a, b) where a is the accumulator (e.g. tracks the sum, etc) and b is a representation of the item you're iterating over on the list. initialValue is the starting point for the function (e.g. on the first iteration).
Idiomatic javascript would look like (for your first function):
function postsCalc(arrayEntry) {
var postsOutput = {
postLikes: 0
};
for (var i = 0, len = arrayEntry.length; i < len; i++) {
postsOutput.postLikes += arrayEntry[i].likes.summary.total_count;
}
return postsOutput;
}
or, now that we can assume .forEach exists:
function postsCalc(arrayEntry) {
var postsOutput = {
postLikes: 0
};
arrayEntry.forEach(function(entry) {
postsOutput.postLikes += entry.likes.summary.total_count;
}
return postsOutput;
}
I am working on solving an algorithm (do not want to explain my approach, as I am still trying to solve it on my own). However I am having difficulty with a particular part.
function smallestCommons(arr)
{
var rangeArray = [];
var outterArray = [];
var testArray = [];
arr = arr.sort(function(a,b){return a>b});
for(var i=arr[0];i<=arr[1];i++)
{
rangeArray.push(i);
}
for(var j=0;j<rangeArray.length;j++)
{
for(var k=1;k<=100;k++)
{
if(k%rangeArray[j] === 0)
{
outterArray.push([k]);
}
}
}
console.log(outterArray);
}
smallestCommons([1,5]);
The second part of the code I am looping through the items in rangeArray [1,2,3,4,5] and trying to insert all the multiples (from 1 to 100) of EACH index into a DIFFERENT array. But my code currently is pushing EACH individual number which is a multiple into its own array per each digit. I need it to push all the multiples of each index of rangeArray into outer array. So that I end up with a 2D array of all the multiples of rangeArray in different array for every iteration of j.
So for example instead of ending up with
outerArray == [[1],[2],[3]...]
I would end up with all the multiples of 1 (up to 100) into one array and then all the multiples of 2 into another array and so on and so forth so it looks like this.
outerArray == [[1,2,3,4...] [2,4,6,8...] [3,6,9,12...]]
Its very hard to explain, hopefully I have been clear. Thanks.
It's quite impossible to understand your question, but wisely you've described the output you're trying to generate...
Turns out, that's quite simple:
let arr = [];
for(let i = 1; i <= 100; i++) {
let innerArr = [];
for(let j = i; j <= 100; j += i) {
innerArr.push(j);
}
arr.push(innerArr);
}
console.log(arr);
how many elements should be in each multiple array? I guessed 100 but you can adjust that accordingly...
function smallestCommons(arr)
{
var rangeArray = [];
var outterArray = [];
var testArray = [];
arr = arr.sort(function(a,b){return a>b});
for(var i=arr[0];i<=arr[1];i++)
{
rangeArray.push(i);
}
for(var j=0;j<rangeArray.length;j++)
{
for(var k=1;k<=100;k++)
{
if(k%rangeArray[j] === 0)
{
var multipleArray = [];
for(var z=1;z<100;z++) {
multipleArray.push(z*k);
}
outterArray.push(multipleArray);
}
}
}
console.log(outterArray);
}
smallestCommons([1,5]);
Guys I need your opinion; I've encountered this earlier during my interview, I just want to confirm I understood the question right and I got the answer correctly. Thank you. Please check the question and my answer below:
Take an input single dimensional array [1,2,3,4] and output the product of the integers excluding the current index [24,12,8,6];
//My answer
function calculate(values:Array):Array {
var resultArray:Array = new Array();
for(var i:int = 0; i < values.length; i++) {
var getVal1:Number = 1;
for(var k:int = 0; k <= values.length; k++) {
if(i != k) {
var getVal2:Number = values[k];
getVal1 *= getVal2;
}
}
resultArray.push(getVal1);
}
return resultArray;
}
Nested loops seems like a very messy way to go.
Assuming relatively up-to-date browser (IE 8 and below are out) or suitable shim:
var resultArray = sourceArray.map(function(val,ind,arr) {
arr = arr.slice(0); // create copy of array to work on here
arr.splice(ind,1); // remove current item from array
return arr.reduce(function(prev,curr) {return prev*curr;},1);
});
Array.prototype.map
Array.prototype.reduce
EDIT Here's another way that should be more efficient:
var product = sourceArray.reduce(function(prev,curr) {return prev*curr;},1);
var resultArray = sourceArray.map(function(val) {return product/val;});
Your solution gives the correct answer, but there is a much more efficient method to calculate the new array:
function calculate(values:Array):Array {
var resultArray:Array = new Array();
var product:int = 1;
for(var i:int = 0; i < values.length; i++) {
product *= values[i];
}
for(var i:int = 0; i < values.length; i++) {
resultArray.push(product / values[i]);
}
return resultArray;
}
This solution has O(n) execution time, while your code has O(n²) execution time.
That should work. You can do it easier and more efficiently by multiplying all items first:
function calculate(values) {
var prod = 1;
for (var i = 0; i < values.length; i++) prod *= values[i];
var result = [];
for (i = 0; i < values.length; i++) result.push(prod / values[i]);
return result;
}
I believe that my code below is very easy to read. And has no nested loops, but two consecutives. My answer would be:
function calculate(array){
var total = array.reduce(function(a, b){
return a * b;
});
return array.map(function(element){
return total / element;
});
}
Though I like #Kolink's short-and-efficient solution best, here's another way to solve the task - not using division but still being in O(n):
function calculate(values) {
var acc = 1,
l = values.length,
result = new Array(l);
for (var i=0; i<l; i++) {
result[i] = acc;
acc *= values[i];
}
acc = 1;
while(i--) {
result[i] *= acc;
acc *= values[i]
}
return result;
}
Or, the same thing but a little obfuscated*:
function calculate(values) {
var acc = 1,
i = 0,
l = values.length,
result = new Array(l);
if (l)
result[i] = 1;
while( ++i < l)
result[i] = acc *= values[i-1];
i -= acc = 1;
while (i--)
result[i] *= acc *= values[i+1];
return result;
}
*: I like shorthand operators!
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Array value count javascript
I have an array which contains several duplicates, what I'm trying to achieve is to count how many duplicates each unique string has in this one array.
The array looks something like this
array = ['aa','bb','cc','aa','ss','aa','bb'];
Thus I would like to do something like this
if (xWordOccurrences >= 5) {
// do something
}
But I'm not sure how I would code this.
I was thinking, create an object with each unique string, then loop through the original array, match each string with it's object and increment it's number by 1, then loop over the object to see which words had the most duplicates...
But this seems like an over complexe way to do it.
You can use an object which has keys of the Array's values and do something like this
// count everything
function getCounts(arr) {
var i = arr.length, // var to loop over
obj = {}; // obj to store results
while (i) obj[arr[--i]] = (obj[arr[i]] || 0) + 1; // count occurrences
return obj;
}
// get specific from everything
function getCount(word, arr) {
return getCounts(arr)[word] || 0;
}
getCount('aa', ['aa','bb','cc','aa','ss','aa','bb']);
// 3
If you only ever want to get one, then it'd be more a bit more efficient to use a modified version of getCounts which looks similar to getCount, I'll call it getCount2
function getCount2(word, arr) {
var i = arr.length, // var to loop over
j = 0; // number of hits
while (i) if (arr[--i] === word) ++j; // count occurance
return j;
}
getCount2('aa', ['aa','bb','cc','aa','ss','aa','bb']);
// 3
Try this function:
var countOccurrences = function(arr,value){
var len = arr.length;
var occur = 0;
for(var i=0;i<len;i++){
if(arr[i]===value){
occur++;
}
}
return occur;
}
var count = countOccurrences(['aaa','bbb','ccc','bbb','ddd'],'bbb'); //2
If you want, you can also add this function to the Array prototype:
Array.prototype.countOccurrences = function(value){
var len = this.length;
var occur = 0;
for(var i=0;i<len;i++){
if(this[i]===value){
occur++;
}
}
return occur;
}
How about you build an object with named property?
var array = ['aa','bb','cc','aa','ss','aa','bb'];
var summary = {};
var item = '';
for ( i in array){
item = array[i];
if(summary[item]){
summary[item] += 1;
}
else{
summary[item] = 1;
}
}
console.log( summary );
summary will contain like this
{aa: 3, bb: 2, cc: 1, ss: 1}
which you could then iterate on and then sort them later on if needed.
finally to get your count, you could use this summary['aa']
<script type="text/javascript">
var array = ['aa','bb','cc','aa','ss','aa','bb'];
var myMap = {};
for(i = 0; i < array.length; i++) {
var count = myMap[array[i]];
if(count != null) {
count++;
} else {
count = 1;
}
myMap[array[i]] = count;
}
// at this point in the script, the map now contains each unique array item and a count of its entries
</script>
Hope this solves your problem
var array = ['aa','bb','cc','aa','ss','aa','bb'];
var dups = {};
for (var i = 0, l = array.length; i < l; i++ ) {
dups[array[i]] = [];
}
for (str in dups) {
for (var i = 0, l = array.length; i < l; i++ ) {
if (str === array[i]) {
dups[str].push(str);
}
}
}
for (str in dups) {
console.log(str + ' has ' + (dups[str].length - 1) + ' duplicate(s)');
}
This function may do everything you need.
function countDupStr(arr, specifier) {
var count = {}, total = 0;
arr.forEach(function (v) {
count[v] = (count[v] || 0) + 1;
});
if(typeof specifier !== 'undefined') {
return count[specifier] - 1;
}
Object.keys(count).forEach(function (k) {
total += count[k] - 1;
});
return total;
}
Each value in the array is assigned and incremented to the count object. Whether or not a specifier was passed, the function will return duplicates of that specific string or the total number of duplicates. Note that this particular technique will only work on string-coercible values inside your arrays, as Javascript can only index objects by string.
What this means is that during object assignment, the keys will normalize down to strings and cannot be relied upon for uniqueness. That is to say, this function wouldn't be able to discern the difference between duplicates of 3 and '3'. To give an example, if I were to perform:
var o = {}, t = {};
o[t] = 1;
console.log(o);
The key used in place of t would eventually be t.toString(), thus resulting in the perhaps surprising object of {'[object Object]': 1}. Just something to keep in mind when working with Javascript properties.
I saw this post about it, perhaps it can help:
http://ryanbosinger.com/blog/2011/javascript-count-duplicates-in-an-array/