Pop up if values are under -5 - javascript

I have a database with a table called "quote". It stores a margin field which is updated by users using an ajax table. This is in "process2.php" file.
I want a pop-up message saying "are you sure you want to put this margin" when the user clicks on the submit button if a margin value is below 5".
This is my submit form.
<form action="process3.php" method="POST" enctype="multipart/form-data">
<input type="submit" name="submit" value="Generate Quote"/>
</form>

You could do this with JavaScript (and jQuery, in this example). Your form would need an ID, as below:
<form action="process3.php" method="POST" id="myForm">
<input type="text" name="checkMargin1" />
<input type="text" name="checkMargin2" />
<input type="submit" value="Send" />
</form>
And then this would go into the head of your document:
<script type="text/javascript">
$('#myForm').onSubmit(function() {
var check1 = $('input[name="checkMargin1"]').val();
var check2 = $('input[name="checkMargin2"]').val();
if (check1 <= 5 || check2 <= -5) {
var answer = confirm("Are you sure you want to submit?");
return answer;
} else {
return true;
}
});
</script>
That function is fired when your form is submitted. It gets the values of the two margin fields (adding more should be easy) and checks if they are over -5. If they are, then return true allows the form to submit. If they are not, then a prompt dialog asks the user, which returns true when they click "Okay" and false when they click "Cancel", thus allowing or stopping the form from being sent.
Hope this helps :)

Related

disable button after form submission using plain javascript

Greeting developers, I search in all previous question from stackoverflow. There is no proper answer for this.I create two buttons inside form.One is addfriend and another one is unfriend which is disable. If the user click add , it direct to prompt box.After click ok for that,the unfriend button will able to click. Now my problem is it can submit my form but button is not work as expected until user logout. In all tutorial they show how to disable button only. Whenever i try, it work but not submit my form.I want my form submit and button disable until the user logout.Thanks in advance.
<script>
function myFunction(form){
var subject = prompt("Please enter Subject that want to study");
var btn = document.getElementById("btn");
var add = document.getElementById("add");
btn.disabled=false;
add.disabled=true;
if (subject == null){
form['subject'].value= subject;
add.value="request sent";
form.submit();
return false;
}
else if(subject != null) {
form['subject'].value= subject;
add.value="request sent";
btn.disabled=false;
add.disabled=true;
form.submit();
return true;
}
}
function unfriend(form){
var btn = document.getElementById("btn");
var add = document.getElementById("add");
add.disabled=false;
btn.disabled=true;
add.value="request sent";
return true;
}
</script>
<form method="post" id="form" enctype="multipart/form-data" autocomplete="off" >
<input type="hidden" name="id" value="<?php echo $row['register_ID'];?>" />
<input type="hidden" id="subject" name="subject" data-uid=<?php echo $_SESSION['sid'] ;?>/>
<td>
<input type="submit" onclick="return myFunction(form)"name="addfriend" data-type='addfriend' id="add" class="btn" value="add" />
</form>
<form>
<input type="submit" value="unfriend" id="btn" onclick="unfriend(form);" disabled="" />
</td>
</form>
I am not an expert in javaScript but seem to understand the problem.
Two possible scenarios are:
1 - if you have input type="submit" then it will submit the form but your javascript method will not be invoked because after submitting the form you will be redirected to some web page either the same page or different page and so it is a new get request all together.
2 - If you have type="button" then it will not submit the form but your javascript method will be invoked as you will remain on the same web page.
check this for difference : Difference between <input type='button' /> and <input type='submit' />
Solution:
Keep input type=button and do an ajax call to the post method and in the success of the ajax call, enable/disable your add and unfriend buttons.
Don't have the code handy so unable to share code.
Hope it helps.

cancel in confirm function submitting form in javascript

Got a form that requires users to input an amount to donate. On clicking submit, a function is called and the function is meant to display the amount specified and prompt the user to confirm if the amount typed is the actual amount or not.
The Cancel option in the Confirm() keeps submitting the form instead of returning false.
function donationFormSend(){
get_donation_amount = document.getElementById("get_donation_amt").value;
if(get_donation_amount != ''){
return confirm("You have specified "+get_donation_amount+" as the amount you wish to donate. \n\n Are you sure you want to proceed with the donation?");
}
else{
alert("Amount must be specified to process your donation.");
return false;
}
}
<form method="post" action="">
<div>
<div>Donation Amount:</div>
<input name="amount" type="text" id="get_donation_amt" required="required" />
</div>
<input name="donation_submit" type="submit" id="Submit" value="Proceed" onclick="return donationFormSend();" />
</form>
Jsfiddle link
Would be pleased getting help with this.
I updated your jsfiddle so it's in the expected format (loading the js in the head) and returning the confirm result
return confirm('blah blah')
works perfectly well for me in FF! Just make sure you clear your cache and reload your page.
A way to do do it might be:
form :
<form id='test' method="post" action="">
<div>
<div>Donation Amount:</div>
<input name="amount" type="text" id="get_donation_amt" required="required" />
</div>
<input type="submit" value="submit" onClick="form_submit(this.value)">
<input type="submit" value="cancel" onClick="form_submit(this.value)">
</form>
javascript:
document.getElementById('test').addEventListener('submit',function (event) {
if (event.preventDefault) {
event.preventDefault();
} else {
event.returnValue = false;
}
})
form_submit= function (submited_by) {
if(submited_by == 'submit'){
alert('Submited')
}else if (submited_by == 'cancel'){
alert('cancelled')
}
}
I'd rather use a switch statement to make it expandable in the future but this should work.
Also I'm using jquery mostly because I'm not sure how to stop default action without it.
here's a JSFiddle with the code running.
EDIT: Updated to not use Jquery.
EDIT: well, I feel stupid now, realised it wasn't cancel button in a submit form but in a confirmation form.
In your HTML use : onclick="return donationFormSend();"
In Your Javascript: return confirm("Are you sure ....blah blah blah")

JS validation false, form still submitting

I've got a JS problem. My validation seems to be working, checking that the user inputs a valid number which isn't zero, but the form is still submitting. I have seen this question asked many times but I can't find a solution that works for me. Any ideas would be great.
My Javascript
function checkNotZero()
{
var theNumber = document.getElementById("theNumber").value;
var str = /^\+?[1-9]\d*$/.test(theNumber);
if ( str == false ) {
alert('You have not entered a valid number');
return false;
} else {
document.getElementById('numberCheck').submit();
}
}
My HTML
<form action="/next.php" method="post" id="numberCheck">
<input type="text" id="theNumber" value="0">
<button id="submitButton" OnClick="checkNotZero();">Add to Basket</button>
</form>
Use an <input type="submit"> for the submit button.
Validate on the form's submit event rather than some onclick. Forms can get submitted in other ways than just clicking a button (for instance, pressing "enter", or procedurally through code).
Prefer .addEventListener to attributes for attaching events to elements. Use preventDefault() to prevent form submission.
Hi for the above requirement of 'validating form' java script validation should be done
when the form gets submitted. follow the below approach, form will not get submitted
until and unless the validation is correct.
<html>
<head>
<script type="text/javascript">
function checkNotZero()
{
var theNumber = document.getElementById("theNumber").value;
var str = /^\+?[1-9]\d*$/.test(theNumber);
if ( str == false ) {
alert('in');
alert('You have not entered a valid number');
return false;
} else {
document.getElementById('numberCheck').submit();
}
}
</script>
</head>
<body>
<form action="/next.php" method="post" id="numberCheck" onsubmit="return
checkNotZero()">
<input type="text" id="theNumber" value="0">
<button id="submitButton">Add to Basket</button>
</form>
</body>
</html>
the only change is <form action="/next.php" method="post" id="numberCheck"
onsubmit="return checkNotZero()">
do not use onclick event in submit button.

Submitting forms using JavaScript

I have been battling for the past two days with the evil onbeforeunload function in JavaScript. I have a function that warns the user when they are about to close a page.
However before the page close I would like to submit the form using JavaScript's .submit().
This is my code:
function setPopUpWindow(submitForm){
window.onbeforeunload = function () {
if (submitForm == false ) {
//alert("It worked"); --This code gets called so I know it works
document.getElementById("CancelScripting").submit();
//return "Unsaved Data would be lost";
}
}
}
In my html I have two buttons, one is (supposed to) trigger the .submit() and the other will just ignore it.
<body>
<form action=tett.html id="popUpForm" method=POST>
<script>setPopUpWindow();</script>
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
<input class=b1 type=submit id="CancelScripting" style="visibility:hidden" value="CancelScripting" >
</body>
The `setPopWindow value for the second input is not defined so it would be false.
For some reason the submit is not working well.
------------------------Edit to my question-----------------------------------------------
I would like to submit the form even if the user leaves the page by closing the X button on their window. This is the reason why I have the hidden button... Looks like people misunderstood my question.
The only thing you can do is to ask the user if they really want to leave the page:
<head>
<script type="text/javascript">
var submitForm = false;
window.onbeforeunload = function () {
if(submitForm == false){
return 'You have an unfinished form ...';
}
}
function setPopUpWindow(type){
submitForm = true;
}
</script>
</head>
<body>
<form action="" method="post" name="SubmitForm" id="SubmitForm">
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
</form>
</body>
I think that what you want to do is submit the form rather than the button by doing something like:
document.forms["formId"].submit();
where formId is the id of the form.
Also, I dont see anywhere in your code where your form is but your buttons should be inside of form tags.
For example, it should look like this:
<body>
<script>setPopUpWindow();</script>
<form id="formId" action="" method="post">
<input type="submit" id="submit_button" onclick="setPopUpWindow(true);">
<input class=b1 type=submit id="CancelScripting" style="visibility:hidden" value="CancelScripting" >
</form>
</body>

html form submission - javascript does not submit input button

Here's the problem: I have a simple form with three buttons and some hidden input fields. Depending on the button pressed (different name="" values), the action does something different.
I am now trying to add a confirmation dialog box to this form by doing this:
<form method="POST" action="/action" onsubmit="return confirmFormSubmit(this);">
<input type="submit" name="one" value="This">
<input type="submit" name="two" value="That">
<input type="submit" name="three" value="Something else">
</form>
<script type="text/javascript">
function confirmFormSubmit(obj)
{
window.event.preventDefault();
jConfirm('Are you sure you want to do this?', 'Awaiting confirmation', function(r) {
if (r == true) {
obj.form.submit();
} else {
return false;
}
});
}
</script>
When I click OK, the action happens, but the input button is not submitted.
Doing 'document.location = obj.form.action;' is not an option because that will not submit the POST parameters.
How can I make the damn thing submit the input fields and not just call the action?
I think that it is because the onsumit method overrides the action in your form declaration.
I would actually change the button of the form and make it a button linked to a javascript method that performs required tests and submit values to the right action.
<form method="POST" action="/action">
<a href="javascript: confirmFormSubmit(this)">
<input type="button" name="three" value="Something else">
</a>
</form>
something like this should be working

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