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Jquery, cannot access css properties of dynamically generated element

I am using jQuery to append elements to a div, and all works fine.
var new_div = $('<div>My stuff</div>');
new_div.appendTo("#container");
However, I'd like the div to appear by fading in, instead of abruptly.
I notice though that I get an error when I try to access graphic properties on my dynamically generated element. So this, for example fails:
new_div.hide().fadeIn();
The console reports the following error:
TypeError: jQuery.curCSS is not a function
Do I understand this correctly, that this fails because current css properties are not defined for the dynamically generated element? Or what else can be goingg wrong?
Important edit
Additional checking and working on this pointed out to a complete misunderstanding from my part. This has nothing to do with the fact that the element was dynamically generated. I got the same thing by calling fadeIn() on whatever element.
I sincerely apologize!
I still didn't get, though, why this happens

Adding elements to the DOM takes some time, miliseconds maybe, but it's still a reason for jquery not be able to find the element.
This process might be even slower if the DOM is a large html page.
Write your code like this:
var new_div = $('<div>My stuff</div>');
new_div.appendTo("#container");
setTimeout( function(){
new_div.hide().fadeIn();
} , 150); // 100 could be also good
It might be enough time for jquery to catch the element.

I would add an id to keep track of all elements I'm creating (just my preference, but it makes it easier to code it).
var new_div = '<div id="myNewDiv1" style="display:none;">My Styff</div>'
$('body').append(new_div);
$('#myNewDiv1').fadeIn();

It does seem to be a compatibility question, although I wasn't able to figure out exactly why and how to fix it.
Adding this code fixes the problem though:
jQuery.curCSS = function(element, prop, val) {
return jQuery(element).css(prop, val);
};

Cannot use css() on dynamically created div in custom plugin

I have recently taken up learning how to make a jQuery plugin. This is my first attempt at just creating something that is very simple. I am still relatively new to jQuery and have come into a bit of a bind when it comes to selecting dynamically created content. In this scenario I am attempting to select a div I created within the plugin.
I have made a jsFiddle here.
I have perused many posts about selecting dynamically created div's and most of them are solved either using on or a callback function. And I am not sure that those can be applied in this situation.
I think the issue occurs at this point in the code:
$element.append("<div class=\"gifLoader\"></div>");
$gifLoader = $element.find('.gifLoader');
$gifLoader.css("bacground-image", "url(\"" + plugin.settings.gifSrc + "\")");
plugin.settings.callback.call(this);
Is there some way I can use a callback function like you would with methods like fadeTo? Also, if anyone cares to comment. I would really appreciate some feedback on the layout of my plugins. I don't fully comprehend what it is I am doing when making a plugin, I am just hoping to learn how to use Javascript and jQuery without the coding looking so clunky. (Before I just had anonymous functions within anonymous functions)

You have one typo, and one error: bacground-image => background-image, and src() => url()
Change
$gifLoader.css("bacground-image", "src(\"" + plugin.settings.gifSrc + "\")");
To
$gifLoader.css("background-image", "url(\"" + plugin.settings.gifSrc + "\")");

When you are creating a dynamic element using javascript or jquery, that element does not reflect in your DOM straight away. If you take a look into the HTML that is generated using the developer tools you'd find before: and after: tags appended with your HTML.
The best way to realize the problem is to either specify the background-image when you are creating the div like:
$("#element").append("<div class='gifLoader' style='background-image: url('" + plugin.settings.gifSrc + "')'></div>");
Otherwise if you are looking to change the background-image on some kind of user interaction, you can go for this:
$("#element").append("<div class='gifLoader' id='someID' someEvent='transform(someID)'></div>");
And then have function transform() defined somewhat like:
function transform(elementID) {
$("#" + elementID).css("background-image", "some image URL");
}

Get return value from html dropdown appended from html.append

I am trying to generate a dynamic dropdown on a mouse over event over an object. I accomplished it like so,
canvas.on('mouse:move', function (e) {
$('body').append("<div id='imageDialog' style='position: absolute; top: 0; left: 0'><select id='mySelect' onchange='copy();'><option value='wipro' >wipro</option><option value='Hcl' >Hcl</option><option value='krystal kones' >krystal kones</option></select></div>");
});
This functionality works fine. But there is an issue in my next requirement where I need to capture the selected item when the user selectes an item from the drop down. I know its a long shot but I tried it by having onchange='copy();' in the drop down and alerting out the selection made like so,
function copy(){
alert(document.getElementById("imageDialog").value);
}
But as expected it gave the error Uncaught ReferenceError: copy is not defined.
I was at this for some time and had no luck whatsoever and I would really appreciate any help from you experts regarding this.
Thanks.

I'm not sure I understand some of these design decisions (generating select boxes is an odd way to do a dropdown menu) but we'll skip that part for now and get to the good stuff.
When you add new elements to the DOM after initial load, you need to think of event binding a little differently. Since these initial elements weren't around when you first said "Hey, all elements do this when I hover on you", the way you handle it is by telling a parent element instead. Sticking in jQuery-land:
$('.parent-element').on('click', '.child-element', function (){ });
This gives you the same result as assigning click directly to .child-element if it was around at initial render. You can read more about delegated events here: http://api.jquery.com/on/
Here's a fiddle that cleans up your stuff a bit: http://jsfiddle.net/g6r8k6dk/1/

without using pure javascript, use jQuery like the following code.
$('document').ready(function(){
$('#imageDialog').on('click',function(){
alert($('#imageDialog select').value);
})
})

carousel javascript several times

I wanna use this carousel :
[http://codepen.io/ScottMarshall/pen/FwxpH][1] on a forum, but when I repeat the code, it doesn't work well.
Can you help me ?
here, it's working, but the second container doesn't want and I don't want to change anything in the HTML...
JSFiddle

Here is working fiddle: http://jsfiddle.net/1x6251wc/2/
This is the key change to get the context "Front" instead of all of them:
var $front = $this.parent().find(".Front");
It's a poorly written plugin, but this change should get it to work across multiple instances.

jquery ui.slider: add click event to display/hide handle

I am completely new to javascript and jquery. My programming knowledge is... nonexistent, I just started some days ago with some simple tasks like replacing a CSS class or toggling a div. So I want to apologize if I'm treading on someones toes by asking newbie-questions in here. But I hope that someone can help me and solve my problem.
I need to implement some sort of visual analog scale for a survey; ui.slider is perfect for that one. But I need the handle to be hidden by default. When the user clicks on the slider, the handle shall appear in the proper position. That should be fairly simple - at least I hope so - by just hiding the handle with CSS and changing it by a click event on the slider.
I use the following piece of code to wrap a normal div (a div is needed in my understanding to apply the jquery slider.js) to my input elements (they should be - at least visually - replaced by the slider) and pass the value of the slider to the input elements (needed for passing the values to a form). that works properly. (I do that instead of just putting a div in my DOM by default because I cannot influence some PHP scripts that will generate form elements of the survey and so on)
$(function () {
$.each($('.slider'),
function () {
obj = $(this);
obj.wrap('<div></div>');
obj.parent().slider({
change: function (event, ui) {
$('input', this).val(ui.value);
}
});
});
});
Hiding the slider-handle can be done by CSS as described above by changing style properties of a.ui-slider-handle. but when I add a normal click event to the slider (.ui-slider) that changes CSS properties of the handle, nothing happens. As far as my basic knowledge goes it should have something to do with the click event not working on generated DOM elements. Am I right with that one? And if yes: how can I solve this problem? Could someone provide me a piece of code for my function and explain it so I might comprehend what's exactly going on?
I read a tutorial about events on learningjquery.com but I have not made enough progresses the last few days since I started working with JS/jquery to comprehend the steps and translate it into my example/problem. And I am running out of time (I need this for a survey I have to make asap, that's why I hope someone could give me a hint so I can solve this little issue somehow).

Any reason you can't just include the show on the change event rather than a click? It's a bit cleaner code-wise rather than including a whole new event.
$(function() {
$('.slider').wrap('<div></div>').parent().slider({
change: function(event, ui) {
$('input', this).val(ui.value);
$('.ui-slider-handle').show();
}
});
});
Also, there was a bit of redundancy in the code - most jQuery functions return the object itself, so you can chain them. And you don't need that each function, since most jQuery functions also, when applied to a collection, run on all of them :)