Not sure how to word this, so a little jsfiddle work:
http://jsfiddle.net/UwEe2/
That's the basic idea for what I need done, except that I am in need of the image to be centered (so that the very center, horizontally and vertically, of this image, appears in the little 250x250 window and is capable of being scrolled in all four directions to the edges of the image.
What I have, which would work if I would get the exact height and width of the image halved, http://jsfiddle.net/UwEe2/599/, which uses a second div inside the first with style="position:relative; top:-330px; left:-330px;", which shifts the image more to where I need it, but disallows the scrolling of the image left and up any further than the initial screen.
Hopefully this makes sense...I'm rather at a loss right now.
All you need to do is set the initial scrollTop and scrollLeft to the size of the image minus the container divided by two.
$('#container').scrollTop(($('#container img').height()-$('#container').height())/2).scrollLeft(($('#container img').width()-$('#container').width())/2);
http://jsfiddle.net/UwEe2/600/
Related
I am trying to develop a carousel similar to Netflix, but I cannot make it responsive. I have been using a codepen example:
Link to example
In this example, it has a hardcoded width and height. I would like to make it use a responsive measure (percentages). I wanted to use the vw viewport width units, but this doesn't work for me because it does not exclude the scrollbar. So, when I want every carousel item to have a width of 20vw (so that each one is 20% of the viewport size), they are always wider than I want because the viewport does not exclude the scrollbar.
How can I fix that problem?
I have made an example: Link
In this example, I want to show five items and showing an arrow on the right. The 6th item should be hidden behind the arrow, but the arrow width is not correct.
The width of every item is 18.4vw ( (100-8)/5=18.4). As you can see, I have put a padding on left and right with 4vw(so, I am subtracting 8 for total width), so, I have made the arrow layer with:
position:absolute;
right:0;
width:4vw;
In this manner, the arrow always is fixed to right.
The problem is that 18.4vw is the measure respect the viewport, and as there is a scrollbar, the width is not correct, because the scrollbar width is breaking the correct measure.
I dont know if you understand what I want to make.
BR.
I'm trying to create a spot the difference game with jQuery.
Basically, several images stacked, positioned absolutely in a container. Above the container there is the page header with a logo and a menu, which takes altogather about 120px above the images container.
When someone clicks an area inside the image, I put there a new div, with either a correct (V) mark, or a wrong (red X).
I'm trying to get the position of the click inside the element, using the following code (the following used event variable e is returned in the click event just to be clear):
var parentOffset = $(this).parent().offset();
var topOffset = e.clientY - offset.top;
My problem is that the offset from the top changes when I scroll the page down a little to the footer area, and then I do not position the new marker div in the correct height.
When I'm scrolled to the top of the page, the mark is position correctly.
I've created such a game before, but can't understand why suddenly the calculation is wrong :\
Seems that I get the distance minus the scroll height, but not sure.
Thanks for your insight,
Yanipan
I played around with Firebug a little and it looks like e.originalEvent.layerY is exactly what you're looking for.
It always shows the absolute coordinates of your click within the clicked object, no matter where the screen is scrolled.
Lets assume I have 10 blocks for jQuery Masonry, each block(div) width 200px, so at 1024x768, will look like this after Masonry
[000] [111] [222] [333] [444]
[555] [666] [777] [888] [999]
So, if I change screen resolution to 640x480, it will look like this
[000] [111] [222]
[333] [444] [555]
[666] [777] [888]
[999]
If I change screen resolution to 1600x190, it will look like
[000] [111] [222] [333] [444] [555] [666] [777]
[888] [999]
What I to achieve is: to make the first block([000]) always positioned in the center of the screen.
How?
PRTFM: "Whereas floating arranges elements horizontally then vertically, Masonry arranges elements vertically, positioning each element in the next open spot in the grid. The result minimizes vertical gaps between elements of varying height, just like a mason fitting stones in a wall". You can not fix one Masonry element in the center of a browser's window with all other elements arranging fluidly around it - you can have a fixed element top right or top left, called a "corner stamp".
you need to use:
$('.container').css('width','1024px');
$('.container').css('height','768px');
or
$('.container').css('width','640px');
$('.container').css('height','480px');
or
$('.container').css('width','1600px');
$('.container').css('height','190px');
to change the area of the boxes then the boxes will appears like what you want.
I have two divs. One should be positioned 5% from the left window border, the other should be to the right of the previously mentioned div and centred relative to window width. If the window is made too narrow it should not overlap the first div, and it should not move below either.
Whatever comes after should be positioned below the tallest of the first two divs.
How can I do this?
The closest I've come is to use a float for the first div. http://jsfiddle.net/7qVLm/
edit: Here's the final result that I'm happy with: http://jsfiddle.net/ATHpg/
Thanks to both #Christopher Smithson and #gmebeh whose answers helped me to get to this solution.
Here's a fiddle to consider for your solution.
http://jsfiddle.net/f2Muj/5/
With percentage-based width's you can make this happen:
jsFiddle
#d1 is 5% from the left, center-aligned content
#d2 is centered relative to the browser window, and will never overlap #d1
Both use fixed heights to accomodate fixed amounts of content
Play around with the percentages to get the exact width you you want.
I have a 700x300 background repeating seamlessly inside of the main content-div. Now I'd like to attach a div at the bottom of the content-div, containing a different background image that isn't repeatable, connecting seamlessly with the repeatable background above it. Essentially, the non-repeatable image will look like the end piece of the repeatable image.
Due to the nature of the pattern, unless the full 300px height of the background image is visible in the last repeat of the content-div's backround, the background in the div below won't seamlessly connect. Basically, I need the content div's height to be a multiple of 300px under all circumstances. What's a good approach to this sort of problem?
I've tried resizing the content-div on loading the page, but this only works as long as the content div doesn't contain any resizing, dynamic content, which is not my case:
function adjustContentHeight()
{
// Setting content div's height to nearest upper multiple of column backgrounds height,
// forcing it not to be cut-off when repeated.
var contentBgHeight = 300;
var contentHeight = $("#content").height();
var adjustedHeight = Math.ceil(contentHeight / contentBgHeight);
$("#content").height(adjustedHeight * contentBgHeight);
}
$(document).ready(adjustContentHeight);
What I'm looking for there is a way to respond to a div resizing event, but there doesn't seem to be such a thing. Also, please assume I have no access to the JS controlling the resizing of content in the content-div, though this is potentially a way of solving the problem.
Another potential solution I was thinking off was to offset the background image in the bottom div by a certain amount depending on the height of the content-div. Again, the missing piece seems to be the ability to respond to a resize event.
Another approach is to calculate the background-position style for the bottom and top DIVs based on the size of the content DIV. You can use negative positions to align the bottom of one to the top of another.
Yet another approach is to use a layered DIV approach in which the top, content and bottom are all children of a parent DIV that contains the background.
The benefit of these approaches is that it doesn't change the natural rendering of the content DIV simply for managing the background.
Example: http://bin.googlecode.com/svn/trunk/css/repeating-bg-content.html
Could setting background-position: fixed in your css help? Then your bottom div could move, but its background image would remain fixed in relation to the top of the page. As more of your repeating image was revealed, so more of your bottom image would be hidden.
This would comes under the heading of "offset the background image in the bottom div by a certain amount depending on the height of the content-div", rather than "the content div's height to be a multiple of 300px under all circumstances".
You could try adding an event listener to the div:
var div = document.getElementById("content");
div.addEventListener("resize", adjustContentHeight, false);
If nothing needs to match up at the top, position the repeating image at the bottom of the div (so the overflow will spill over the top). Like this:
div#repeating { background: transparent url('/path/to/image') repeat left bottom; }