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Calculation in retrieved JSON API data

Here is my code I need how to add a percentage or number to each value in total field I have tried a lot but nothing works.
<?php
$json=file_get_contents("http://www.upliftinghumanity.net/edd-api/sales/?key=75caa8cb60362c89e6ac2b62730cd516&token=6547d40b82cecb81cb7b0ec928554a9e&number=-1");
$data = json_decode($json);
extract(json_decode($json, true));
if (count($data->sales)) {
// Open the table
echo "<table>";
// Cycle through the array
foreach ($data->sales as $idx => $sales)
{
// Output a row
echo "<tr>";
echo "<td>$sales->total</td>";
echo "<td>$sales->total+3 </td>";
echo "<td>$sales->gateway</td>";
echo "<td>$sales->email</td>";
echo "<td>$sales->transaction_id</td>";
echo "</tr>";
}
// Close the table
echo "</table>";
}
?>
result image

You can add it before echoing it out as a string for example $somevar = $sales->data+1; echo "blahh $somevar"; or echo "blahh {$somevar}";
#Ezekiel the problem is solved what you suggest. i was missing some basic stuff . Thanks –

Hi you can't perform php arithmetic operations which its been qouted as a string, you can probably use the "{$sales->data+3}" but it is always advisable to do thr calculation outside the string as this is only a pseudo code "{$sales->data+3}" and may not work even if you include the curly braces

AJAX - Undefined PHP variable

I have the following problem, the following script sends a keyword a PHP file hosted in another domain (I already added the CROS headers), this PHP returns me some "echos of different variables" (title, thumbnail, url, etc.) And it works but randomly returns me "Undefined variables".
The first thing was to add an if (isset ()) to my variables in PHP and the error does not appear anymore but the results returned by my searches are much smaller (Before adding it averaged 10 to 20 results, Now I get 5 results).
Can this be a problem with my script?
My form.php
<form method="POST" action="" id="form-busqueda">
<input type="text" name="keyword">
<button id="search" name="search">Search</search>
<div id="results"></div>
<script>
jQuery(function($){
var pluginUrl = '<?php echo plugin_dir_url( __FILE__ ); ?>' ;
$('[id^="form-busqueda"]').on('submit', function(e) {
e.preventDefault();
$.ajax({
type : 'POST',
url : 'http://localhost/ladoserver/script.php',
data : $(this).serialize(),
beforeSend: function(){
$('#results').html('<img src="'+pluginUrl+'../../assets/img/loading.gif" />');
}
}).done(function(data) {
$('#results').html(data);
});
});
});
</script>
</form>
My script.php (dlPage is a function that create cURL connection):
<?php
if (isset($_POST['keyword'])) {
$search = $_POST['keyword'];
$html = dlPage("http://example.com/" . $search);
//where I search and get with simple_html_dom example:
$video = $videos->find('div.example2>a', 0);
$title = $video->innertext;
$url = $video->attr['href'];
$id = $video->attr['id'];
$thumbnail = $video->find('div.thumb', 0)->innertext;
echo $title;
echo $url;
echo $id;
echo $thumbnail[0];
}
?>
I've updated my code, I didn't put all the code because I thought that it isn't relevant, my script.php works fine with pure PHP. The problem appear when I use AJAX.
I'm getting the following error:
Notice: Undefined variable: title in C:\xampp\htdocs\webs\ladoserver\script.php on line 13
Notice: Undefined variable: title in C:\xampp\htdocs\webs\ladoserver\script.php on line 13
Notice: Undefined variable: url in C:\xampp\htdocs\webs\ladoserver\script.php on line 14

The undefined variable is coming from your PHP file (/ladoserver/script.php).
What generates the variables being returned? The most common "cause" of this, is by only setting the variables within a block of code that might not be executed (eg within an if block, or in a loop that iterates 0 times)
You could get around the error (assuming you're okay with blank values) by defining each of the variables at the top of your script.
<?php
$title = "";
$thumbnail = "";
$url = "";
$id = "";
?>
Edit: #snip1377 reminded me that you can also just use isset at the end of your script before the output as well.
Here's some sample code for your $thumbnail variable, which you could apply to all your variables being returned
<?php
if (isset($thumbnail))
{
echo $thumbnail;
}
else
{
echo "";
}
?>
Alternativaely, you can use a ternary operator:
<?php
echo (isset($thumbnail)) ? $thumbnail : '';
?>
Edit again: just to illustrate what I mean about how the variables might not get defined within a script, here is an example that could cause that undefined error:
<?php
if ($_POST['value'] == 1)
{
// This will never be reached unless $_POST['value'] is exactly 1
$return_val = 1;
}
echo $return_val;
?>
This will give the undefined warning, if $_POST['value'] is anything other than 1.
Similarly, if $_POST['value'] were 0 in the following code, it would have that undefined warning as well:
<?php
for ($i=0; $i<$_POST['value']; $i++)
{
// This will never be reached if $_POST['value'] is less than 1
$return_val = $i;
}
echo $return_val;
?>
In the examples above, you can simply define $return_val at the top of the script, and you won't get the error anymore.

You send this data as a post method.you shuld echo them with $_post['name'] but you just echo $name
Use this in script.php :
<?php
echo $_POST['title'];
echo $_POST['thumbnail'];
echo $_POST['url'];
?>

phpcoding special characters

When I load a php page, i put within a javascript function, a name. The problem comes when this string has special chars like '.
Here I paste the code of a click event:
showSocialShare(event, '<?php echo $object->slug; ?>', '<?php echo htmlspecialchars($object->title); ?>', '<?php echo $object->image; ?>')
I thought that the function htmlspecialchars code somehow the string but the result is:
showSocialShare(event, '4049269', 'collection-'Noun'', '/img/Original.jpg')
As can be seen, at the second parameter, the name contains characters like ' and arises an error.
How can I avoid this?

Never output text from PHP directly into a Javascript context. As you're finding out, it's VERY easy to generate JS syntax errors.
Always use json_encode: e.g. given this
<?php $foo = 'bar'; ?>
<script>
var badly_broken = <?php echo $foo ?>;
var working_fine = <?php echo json_encode($foo); ?>;
</script>
You'll end up with
<script>
var badly_broken = bar; // oops - undefined variable "bar"
var working_fine = "bar";
</script>
And note that if you're outputting JS into an HTML attribute, you not only have to generate valid Javascript, you have to output valid HTML AS WELL:
<?php $foo = array('bar' => 'baz'); ?>
<a onclick="brokenCall(<?echo json_encode($foo) ?>)">
<a onclick="workinCall(<? echo htmlspecialchars(json_encode($foo)) ?>)">
produces:
<a onclick="brokenCall({"bar":"baz"})">
^--start attribute
^--end attribute - ruhroh
<a onclick="workingCall({"bar":"baz"}")>

Array of Javascript in PHP

I was trying to get datas from the database and put them into the array in Javascript but Javascript is not working in PHP command area.
Here is the whole PHP codes;
<?php
mysql_connect("mysql.metropolia.fi","localhost","") or die("ERROR!!");
mysql_select_db("localhost") or die("COULDN'T FIND IT!!") or die("COULDN'T FIND DB");
$sql = mysql_query("SELECT * FROM METEKSAN_HABER_CUBUGU");
$haber = 'haber';
$list = array();
$i=0;
while($rows = mysql_fetch_assoc($sql)){
$list[] = $rows[$haber];
$i++;
}
echo $i;
echo '<script type="text/javascript">
var yazi=new Array();';
echo $i;
for ($k = 0 ; $k < $i ; $k++){
echo 'yazi['.$k.']="'.$list[$k].'';
}
echo '</script>';
?>
But when it comes to;
echo '<script type="text/javascript">
var yazi=new Array();';
this command line, the problem begins. Though I write 'echo $i;' after that command, I get nothing on the screen but I get the result if I write before that command. So, it means that everything works well before that command. What you think about the problem ? Why can't I starting the Javascript command ? Am I writing something wrong ?
Please give me a hand.
Thanks.
UPDATE;
I opened the web source and yeah it exactly seems there is a problem. So, I think it's better to ask that how can I write
<script type="text/javascript">
/*Example message arrays for the two demo scrollers*/
var yazi=new Array()
yazi[0]='METEKSAN Savunma, Yeni Dönemin Örnek Oyuncusu Olmaya Hazır'
yazi[1]='METEKSAN Savunma Bloomberg TVde'
</script>
this Javascript code in PHP ??
You can see my output at http://users.metropolia.fi/~buraku/Meteksan/index.php

try something like this
while($rows = mysql_fetch_assoc($sql)){
$list[] = ''.$rows[$haber].'';
}
$js_array = json_encode($list);
echo "<script>var yazi = ". $js_array . ";</script>";

It seems you are executing it currently in your browser? Then you should find your second output when opening page source, because your browser tries to executes the output as JS code. If you execute it on cli, everything should work as expected.
EDIT based on your comment:
Bullshit i wrote before, obviously. Viewing line 122 of your current html shows me a problem with your quotation marks. try the following:
for ($k = 0 ; $k < $i ; $k++){
echo 'yazi['.$k.']=\''.$list[$k].'\';';
}
In the end you should try to avoid using this kind of js rendering at all. The json_encode proposal of jeremy is the correct way to go.

You may have much more compact code:
....
$list = array()
while($rows = mysql_fetch_assoc($sql)) {
$list[] = $rows[$haber];
}
echo '<script type="text/javascript">' . "\n";
echo 'var yazi=';
echo json_encode($list,JSON_HEX_APOS | JSON_HEX_QUOT);
echo ";\n";
echo '</script>' . "\n";
What is this doing:
There's no need to count the added elements in $i, count($array) will give you the cutrrent number.. But it's not needed anyway.
Put some newlines behind the echo, better readable source
json_encode will format an JSON array from your php array, which can be directly used as source code.

using php _GET within javascript function

I have some javascript embedded into an html file that I am running in a browswer.
document.getElementById('home-search-text-inp').value = <?php echo htmlspecialchars($_GET['search_for']); ?>;
Why does this not fill the textbox?
Note that:
document.getElementById('home-search-text-inp').value = "hi";
puts "hi" into the textbox and:
<?php echo htmlspecialchars($_GET['search_for']); ?>
writes text just fine.
Thanks in advance

You're missing quotes around your string value:
document.getElementById('home-search-text-inp').value = <?php echo htmlspecialchars($_GET['search_for']); ?>;
^^^^ ^^^^
HERE HERE
should be:
document.getElementById('home-search-text-inp').value = "<?php echo htmlspecialchars($_GET['search_for']); ?>";