I'm creating a div dynamically using the following code:
$('#pageTabContent').append($('\
<div class="tab-pane" id="'+user_id+'">\
<div class="extras_area">\
<div class="expand_heading">Header to be clicked</div>\
<div class="expandable_content">this should be expanded.</div>\
</div>\
</div>'));
This is expanded within this HTML:
<div id="right_column">
<ul id="pageTab" class="nav nav-tabs"></ul>
<div id="pageTabContent" class="tab-content"></div>
</div>
I now want to expand the .expandable_content when I click the .expand_heading. To do this, I'm trying something like this in my javascript:
$("#right-column").on("load", ".expand_heading", hide);
$("#right-column").on("click", ".expand_heading", function(){
$(this).next(".expandable_content").slideToggle(100);
});
Unfortunately, that doesn't work. I don't know how to hide the div correctly when it is dynamically created. Can anybody help me out here?
Working Demo http://jsfiddle.net/t3WVs/
$('#pageTabContent').append($('\
<div class="tab-pane" id="'+Math.random()+'">\
<div class="extras_area">\
<div class="expand_heading">Header to be clicked</div>\
<div class="expandable_content">this should be expanded.</div>\
</div>\
</div>'));
//$(document).on("load", ".expand_heading", hide);
$(document).on("click", ".expand_heading", function(){
$(this).next(".expandable_content").slideToggle(100);
});
// if needed default close expand
// $('.expand_heading').click();
Why don't just use display:none rule:
$('#pageTabContent').append($('\
<div style="display:none;" class="tab-pane" id="'+user_id+'">\
<div class="extras_area">\
<div class="expand_heading">Header to be clicked</div>\
<div class="expandable_content">this should be expanded.</div>\
</div>\
</div>'));
Related
I have a div which I want to surround with an <a href>. I have the jQuery to add the <a href> after the div but I struggle to set it before and close it after the div.
This is the jQuery code I have:
$('.box_service').each(function() {
var link = $(this).html();
$(this).contents().wrap('');
});
It results in this HTML:
<div class="row">
<div class="box_service">
<a href="example.com">
<div class="inner-row"></div>
</a>
</div>
</div>
However my goal is this structure:
<div class="row">
<a href="example.com">
<div class="box_service">
<div class="inner-row"></div>
</div>
</a>
</div>
I can't enter the div before because there are more boxes in this row so I would add the <a href> to everything in there
The issue is due to your call to contents() which means you're wrapping the elements inside .box_service, not that element itself. Remove that method call.
Also note that each() is redundant, you can do what you require in a single line:
$('.box_service').wrap('');
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
Box service #1
<div class="inner-row">Inner row #1</div>
</div>
</div>
<div class="row">
<div class="box_service">
Box service #2
<div class="inner-row">Inner row #2</div>
</div>
</div>
.content will wrap the contents of your div, you want to wrap the div with <a> so call wrap on the div not on contents.
$('.box_service').each(function() {
var link = $(this).html();
$(this).wrap('');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
<div class="inner-row"></div>
</div>
</div>
$('.box_service').each(function() {
var link = $(this).html();
$(this).wrap('');
});
You just need to remove contents() in between $(this).wrap() because contents() mean that you are wrapping the children of $(this).
Remove .contents() in order to wrap around each element with the class box-service:
$('.box_service').each(function() {
$(this).wrap('');
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="row">
<div class="box_service">
<a href="example.com">
<div class="inner-row"></div>
</a>
</div>
</div>
$('.box_service').wrap('');
I have a container div with two divs inside of it, like such:
<div class="container">
<div class="child1"></div>
<div class="child2"></div>
</div>
I have wrapped another div around 'child1' and 'child2' but it's appearing twice which I haven't been able to fix:
$(".child1, .child2").wrapAll('<div class="style"></div>');
Which is rendering out as the following:
<div class="container">
<div class="style">
<div class="style">
<div class="child1"></div>
<div class="child2"></div>
</div>
</div>
</div>
But what I actually want is the following:
<div class="container">
<div class="style">
<div class="child1"></div>
<div class="child2"></div>
</div>
</div>
How do I go about fixing this? I have tried numerous other methods of trying to sort the double-append.
EDIT: The issue was jquery was firing twice, I moved the code out of the existing file and into a new file. Once I did this the answers below all worked.
Try:
$(".container > div").wrapAll('<div class="style"></div>');
Change you markup little bit, (just add common class)
<div class="container">
<div class="child1 child"></div>
<div class="child2 child"></div>
</div>
now use below code:
$( ".child" ).wrapAll( "<div class='style' />");
$(".child1").next().andSelf().wrapAll("<div class='style'/>");
Try it...
I ran this in fiddle and it seems to work fine... ??????
You can do this though...
$(".container").each(function() {
var ch1 = $(this).find('.child1');
var ch2 = $(this).find('.child2');
var st = $('<div class="style">');
st.append(ch1);
st.append(ch2);
$(this).html('').append(st);
});
I have something like this, and i need to show every div called "plink" just in the main div of each parent, so i tried to fadeIn ".plink" but its doing the same function for all the divs of "plink"
<script>
$(document).ready(function(){
$('.plink').hide();
$('.project').mouseover(function(){
$(this).next('.plink').fadeIn(400);
});
$('.project').mouseleave(function(){
$(this).next('.plink').fadeOut(200);
});
});
</script>
<div class="project">
<div class="plink">
<div class="go"></div>
<div class="goplus"><img src="images/more.png" border="0"/></div>
</div>
<div class="pic"><img src="images/portfolio_pic2.png" border="0" alt="projectname"/></div>
<div class="title">Test1</div>
</div>
<div class="spacer_project"></div>
<div class="project">
<div class="plink">
<div class="go"></div>
<div class="goplus"><img src="images/more.png" border="0"/></div>
</div>
<div class="pic"><img src="images/portfolio_pic.png" border="0" alt="projectname"/></div>
<div class="title">test2</div>
</div>
You can use find() instead of next()...
$(this).find('.plink').fadeIn(400);
because this is your .project div then you need to "find" the child elements that you are looking for. Using next() means you will get the very next element if it matches the selector (i.e. it is check to see if the next .project div matches the .plink selector)
I would go the FIND route like musefan suggested. Here is the solution code:
http://jsfiddle.net/bx7YC/
<div class="project">
<div class="plink">
<div class="go">go</div>
<div class="goplus">goplus</div>
</div>
<div class="pic">pic</div>
<div class="title">Test1</div>
</div>
<div class="spacer_project"></div>
<div class="project">
<div class="plink">
<div class="go">go</div>
<div class="goplus">goplus</div>
</div>
<div class="pic">pic</div>
<div class="title">Test2</div>
</div>
$('.plink').hide();
$('.project').mouseover(function(){
$(this).find('.plink').fadeIn(400);
});
$('.project').mouseleave(function(){
$(this).find('.plink').fadeOut(200);
});
I replaced the broken img links with simple text for the jsfiddle.
<div id="wrapper">
<div class="accordionButton">Personal Information</div>
<div class="accordionContent">
Personal text
</div>
<div class="accordionButton">Experience</div>
<div class="accordionContent">
Experience information
</div>
<div class="accordionButton">Training</div>
<div class="accordionContent">
No skills
<div class="accordionButton">Career</div>
<div class="accordionContent">
Never had a job
</div>
<div class="accordionButton">Referers</div>
<div class="accordionContent">
None.
</div>
</div>
This code works how i want it to. It is a horizontal accordion. However, when it is loaded on my webpage, they content divs have to be hidden for my jquery to work.
Jquery:
$(document).ready(function() {
// When div is clicked, hidden content divs will slide out
$('div.accordionButton').click(function() {
$('div.accordionContent').slideUp('normal');
$(this).next().slideDown('normal');
});
// Close all divs on load page
$("div.accordionContent").hide();
});
If i don't hide the divs, all the divs display. Is there any way to display the 1st page without changing too much of my jquery or would i have to set different class names for the button and the content so that when a specified button is clicked, the affiliated content will slide out for that button div?
You can use jquery selector for first div and set it as show(). Something like :
$('div.accordionContent:first').show();
I think you have to try this:-
<script type="text/javascript">
$.fn.accordion = function(settings) {
accordion = $(this);
}
$(document).ready(function($) {
$('div.accordionContent').click(function() {
if($(this).next().is(":visible")) {
$(this).next().slideDown();
}
$('div.accordionContent').filter(':visible').slideUp();
$(this).next().slideDown();
return false;
});
});
</script>
Why not use slideToggle() instead of IF statements....
Try this very simple solution
HTML
<div class="accordion-container">
<div class="accordion-content">
<div class="accordion-title">Title</div>
<div class="accordion-toggle">Toggle content</div>
</div>
<div class="accordion-content">
<div class="accordion-title">Title</div>
<div class="accordion-toggle">Toggle content</div>
</div>
<div class="accordion-content">
<div class="accordion-title">Title</div>
<div class="accordion-toggle">Toggle content</div>
</div>
</div>
jQuery
$('.accordion-content .accordion-title').on('click', function(){
$(this).toggleClass('active');
$('.accordion-title').not($(this)).removeClass('active');
$(this).next().slideToggle();
$(".accordion-toggle").not($(this).next()).slideUp();
});
Ive made a fiddle of my problem here.
http://jsfiddle.net/E9cUS/1/
JavaScript:
$('.top').click(function () {
var thisPage = $(this).closest('.yesNoItem');
$('.yesNoTick').stop().animate({"opacity" : 1},400, function () {
thisPage.find('.no .top').stop().animate({"opacity" : 0},400, function () {
$(this).css("display", "none");
});
});
});
$('.yesNoNext').click(function () {
$(this).closest('.yesNoItem').stop().animate({"opacity" : 0},400, function () {
//This isnt working? Please advise?
$(this).next('.yesNoItem').stop().animate({"opacity" : 1},400);
});
});
HTML:
<div id="stage">
<div class="yesNoOuter">
<div class="yesNoItem" style="opacity:1;">
<div class="yesNoContainer yes">
<div class="top">
<div class="yesNoTick"></div>
</div>
<div class="bottom">
</div>
</div>
<div class="yesNoContainer no">
<div class="top">
<div class="yesNoTick"></div>
</div>
<div class="bottom">
<p>Text 1</p>
<div class="yesNoNext">More</span>
</div>
</div>
</div>
<div class="yesNoItem">
<div class="yesNoContainer yes">
<div class="top">
<div class="yesNoTick"></div>
</div>
<div class="bottom">
</div>
</div>
<div class="yesNoContainer no">
<div class="top">
<div class="yesNoTick"></div>
</div>
<div class="bottom">
<p>Text 2</p>
<div class="yesNoNext">More</span>
</div>
</div>
</div>
</div>
</div>
I've also put the line of code thats not working.
Bascially it is hiding the element that I want, but not fading the next one in...
Can any one advise based upon my code? Many thanks!
You had an error in your markup
<div class="yesNoNext">More</span>
if you correct that, next() works http://jsfiddle.net/E9cUS/2/
I think your HTML got messed up. The second .yesNoItem element is not a sibling but a child of the first .yesNoItem element (right click -> inspect element).
Probably because of <div class="yesNoNext">More</span> (opening div, closing span). The browser will attempt to correct this automatically and just ignore the closing span tag (at least this seems to be the case if you inspect the DOM).
If you correct your HTML it should work (at least it should select the right element).
If they are actually supposed to be nested, then .next() is the wrong method anyways.