I have a link:
<a class="tag" wi_id="3042" wl_id="3693" for_user_id="441" href="#a">
which triggers an ajax call
$(".tag").click(function() {
var for_user_id = $(this).attr("for_user_id");
var wl_id = $(this).attr("wl_id");
var wi_id = $(this).attr("wi_id");
$.ajax({
type: "POST",
url: "/ajax/actions/tag.php",
data: {
'for_user_id': 'for_user_id',
'wl_id': 'wl_id',
'wi_id': 'wi_id'
},
success: function(data){
$(this).text("You've tagged this");
$(this).closest('.gl_buttons_holder').toggleClass('gl_buttons_holder gl_buttons_holder_tagged');
$(this).closest('.gl_buttons').addClass('tagged');
}
});
return false;
});
But in the console I see the following:
TypeError: e is undefined
The ajax file gets processed but the POST data is blank, and the success actions do not happen, so it gets posted with zeros and classes are not changed
I have stared and stared... anything obvious?
this is not passed automatically to the AJAX callback function. You can use the context: parameter to tell jQuery to pass it:
$.ajax({
type: "POST",
url: "/ajax/actions/tag.php",
data: {
'for_user_id': for_user_id,
'wl_id': wl_id,
'wi_id': wi_id
},
context: this,
success: function(data){
$(this).text("You've tagged this");
$(this).closest('.gl_buttons_holder').toggleClass('gl_buttons_holder gl_buttons_holder_tagged');
$(this).closest('.gl_buttons').addClass('tagged');
}
});
You're sending your data wrong, don't call your variables inside single quotes.
$(".tag").click(function() {
var for_user_id = $(this).attr("for_user_id");
var wl_id = $(this).attr("wl_id");
var wi_id = $(this).attr("wi_id");
$.ajax({
type: "POST",
url: "/ajax/actions/tag.php",
data: {
'for_user_id': for_user_id,
'wl_id': wl_id,
'wi_id': wi_id
},
success: function(data){
$(this).text("You've tagged this");
$(this).closest('.gl_buttons_holder').toggleClass('gl_buttons_holder gl_buttons_holder_tagged');
$(this).closest('.gl_buttons').addClass('tagged');
}
});
return false;
});
Related
I have two tables in a database , when pressing the submit button I want to insert new trader into trader table and get id using laravel 5.2 by using post ajax under condition ,then execute another post ajax for invoice insert , but the problem in this case is when I press the submit it execute second ajax before the first ajax .. why?
$(document).ready(function(e) {
$('#invoiceForm').validate({
//rules: itemRules,
errorPlacement: function (element) {
return false;
},
submitHandler: function (event) {
//event.preventDefault();
// $('#selectedTraderName').valid();
var allItems = [];
$('tr.inputsItem').each(function () {
rowData = $(this).children('td').find('.form-control').map(function () {
return $(this).val();
}).get();
rowData.push(parseInt($(this).children('td').find('strong#autoTotal').text().trim()));
if($('select[id=selectedTraderName]').val() <= lastTraderID) {
rowData.push($('select[id=selectedTraderName]').val());
}
else{
newTrader = [];
newTrader.push($('#name').val());
newTrader.push($('#traderMail').val());
newTrader.push($('#mobileNumber').val());
newTrader.push($('#address').val());
$.ajax({
type: 'POST',
url: insertNewTrader,
data:{_token:token, trader:newTrader}
}).done(function (msg) {
rowData.push(msg['id']);
});
}
alert(rowData[6]);
allItems.push(rowData);
$.ajax({
type: 'POST',
url: insertNewItem,
data:{_token:token, items:allItems}
}).done(function () {
alert('done');
});
});
}
});
Of course, you can't nest ajax calls because of the if/else statement instead you can use a Deferred object like this:
rowData.push(parseInt($(this).children('td').find('strong#autoTotal').text().trim()));
// Create a new Deferred object
var deferred = $.Deferred();
if ($('select[id=selectedTraderName]').val() <= lastTraderID) {
rowData.push($('select[id=selectedTraderName]').val());
//Nothing to wait just resolve the deferred
deferred.resolve();
} else {
newTrader = [];
newTrader.push($('#name').val());
newTrader.push($('#traderMail').val());
newTrader.push($('#mobileNumber').val());
newTrader.push($('#address').val());
$.ajax({
type: 'POST',
url: insertNewTrader,
data: {
_token: token,
trader: newTrader
}
}).done(function(msg) {
rowData.push(msg['id']);
//Resolve the deferred
deferred.resolve();
});
}
//When the deferred resolved then execute your next ajax request
deferred.then(function() {
allItems.push(rowData);
$.ajax({
type: 'POST',
url: insertNewItem,
data: {
_token: token,
items: allItems
}
}).done(function() {
alert('done');
});
});
I hope thsi will help you.
Check the 2nd ajax request condition and call 2nd ajax function on 1st ajax function complete section/success section.
$.ajax({
type: 'POST',
url: insertNewItem,
data:{_token:token, items:allItems},
complete : function(){
//call ur 2nd ajax request here
},
success : function(data){
console.log(data);
//call ur 2nd ajax request here
}
});
I have two buttons that both performs AJAX call:
$("#save").click(function() {
$.ajax({
type: "POST",
url: saveEntryURL,
data: { id: $("#id").val() },
success: function(r) {
...
},
error: function(r) {
...
}
})
})
$("#tag-as-final").click(function() {
$.ajax({
type: "POST",
url: finalizeEntryURL,
data: { id: $("#id").val() },
success: function(r) {
...
},
error: function(r) {
...
}
})
})
The requirement is that when the user click the finalize button, the system will first perform a save before actually tagging it as final. To reuse the code attached to the save button, I call the onclick listener of the save button before the actual AJAX call like this:
$("#tag-as-final").click(function() {
$("#save").click()
^^^^^^^^^^^^^^^^^^
$.ajax({
type: "POST",
url: finalizeEntryURL,
But it will not do "save-and-finalize-after" behavior since both AJAX calls are asynchronous. I need to run one after another, but cannot afford to make the AJAX call of the save button synchronous (I'm doing also a lot of other things while the tagging occurs occurs). I know this would be silly but I'm thinking something similar to...
$("#tag-as-final").click(function() {
$("#save").click().peformAsyc()
^^^^^^^^^^^^
$.ajax({
type: "POST",
url: finalizeEntryURL,
...that will force it to finish performing first the chained function before continuing, but I know that is not available. Is there any way to do this? My current work-around is placing the same save AJAX function inside the finalize AJAX function, though it doesn't allow me to code DRY (Don't Repeat Yourself):
$("#tag-as-final").click(function() {
$.ajax({
type: "POST",
url: saveEntryURL,
data: { id: $("#id").val() },
success: function(r) {
...
$.ajax({
type: "POST",
url: finalizeEntryURL,
data: { id: $("#id").val() },
success: function(r) {
...
},
error: function(r) {
...
}
})
},
error: function(r) {
...
}
})
})
It's pretty simple, you are better using jquery "promises". Like so:
var generalSettings = { }; //Settings for AJAX call.
var jqXHR = $.ajax(generalSettings); //Do AJAX call.
generalSettings.data = 'newdata'; //update generalSettings
jqXHR.done(function(data){
$.ajax(generalSettings); //New Petition with updated settings.
});
This is using ES6 promises and jQuery promises:
function doAjaxAsPromise(settings){
return new Promise(function(resolve){
var jqXHR = $.ajax(settings);
jqXHR.done(function(data){
resolve(data);
});
});
}
var settings = { };
var petition = doAjaxAsPromise(settings);
var secondpetition = petition.then(function(data){
//work with data
//new settings
var settings = { };
return doAjaxAsPromise(settings);
});
var thirdpetition = secondpetition.then(function(data){
//work with data
//new settings
var settings = { };
return doAjaxAsPromise(settings);
});
//If needed to reuse settings object outside promise scope:
//var settings = Object.create(settings);
Some other nice thing you can do for code reuse:
function save(settings) {
var prom = doAjaxAsPromise(settings);
return prom.then(function(data){
//do something with your data.
});
}
function tagAsFinal(savedPromise, settings){
return savedPromised.then(function(){
var prom = doAjaxAsPromise(settings);
return prom.then(function(data){
//work with data;
});
});
}
$('save').on('click', function(){
save(settings); //settings = $.ajax settings.
});
$('tagAsFinal').on('click', function(){
var generalSettings = { };
var settingsone = Object.create(generalSettings);
var settingstwo = Object.create(generalSettings);
var saved = save(settingsone); //$.ajax settings.
tagAsFinal(saved, settingstwo);
});
//Can still be reduced.
I have seen several examples and can't seem to get the hang of passing more than one variable to mysql using jquery. Here is my situation:
I have a page with 2 cascading drop downs,( they work great using jquery to update second drop down based on the first drop down.)
when the first drop down is selected jquery updates the second drop down AND passes the customer id to a php script that creates a new record in the tblinvoice table (this also works great no problems.)
when the second drop down is selected I need to pass that value along with the invoice number to my php script so I can update the record with the instid.(this is the part that don't work)
If I only pass the instid and manually put the invoice number in the where clause of the query all works fine. If I omit the where clause all records are updated as expected. I need to know what I am doing wrong or what is missing.
I will try to post the code here
jquery code
$(document).ready(function() {
$("select#cust").change(function() {
var cust_id = $("select#cust option:selected").attr(
'value');
var test = $("#test").val();
var din = $("#idate").val();
$("#inst").html("");
if (cust_id.length > 0) {
$.ajax({
type: "POST",
url: "fetch_inst.php",
data: "cust_id=" + cust_id,
cache: false,
beforeSend: function() {
$('#inst').html(
'<img src="loader.gif" alt="" width="24" height="24">'
);
},
success: function(html) {
$("#inst").html(html);
}
});
if (test == 0) {
$.ajax({
type: "POST",
url: "wo_start.php",
data: "cust_id=" + cust_id,
cache: false,
beforeSend: function() {
},
success: function(html) {
$("#invoice").html(html);
$("#test").val(1);
var inum = $("#inv").val();
$("#invnum").val(din +
"-" + inum);
}
});
}
}
});
$("select#inst").change(function() {
var inst_id = $("select#inst option:selected").attr(
'value');
var custid = $("select#cust option:selected").attr(
'value');
var invid = # ("#inv").val()
if (inst_id.length > 0) {
$.ajax({
type: "POST",
url: "wo_start.php",
data: {
inst_id: inst_id,
}
cache: false,
beforeSend: function() {
},
success: function() {
}
});
}
});
});
I have tried using data: {inst_id:inst_id,custid:custid,invid:invid,} (no update to the table like this)
I also tried data: "inst_id="+inst_id+"&custid="+custid+"&invid="+invid,(this also gives no results.)
Can someone PLEASE look at this jquery and see if I am making a simple error?
Try this format:
data: { inst_id: inst_id, custid: custid, invid: invid },
You can post a JSON object to the server so long as you serialize it and then let the server know the data type.
First you need to define your JSON object:
var postData = { inst_id: inst_id, custid: custid, invid: invid };
Then update your ajax to use the serialized version of that object and let the server know the data type:
$.ajax({
type: "POST",
url: "fetch_inst.php",
data: JSON.stringify(postData),
contentType: "application/json",
..continue the rest of your ajax....
I'm using jQuery ajax call to post process a form.
I want to display a loading message or image while the form is processed and when the action is completed to display a complete message.
How can I do it?
This is my jQuery code.
$s('body').on('click', '#group-update', function() {
var formInputs = $s('input').serializeArray();
var groupId = $s(this).data('group');
var error = $s('#modal .info');
var tr = $s('#dataT-attrgroup').find('tr.on_update');
formInputs.push({
name: 'id',
value: groupId
});
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
success: function(data) {
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
}
});
});
Before ajax function display your loader and inside the success function from your ajax hide it.
As you can see in my example i inserted $('.loader').show(); and $('.loader').hide();
$('.loader').show();
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
success: function(data) {
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
$('.loader').hide();
}
});
According to the PHP docs:
The upload progress will be available in the $_SESSION superglobal when an upload is in progress, and when POSTing a variable of the same name as the session.upload_progress.name INI setting is set to. When PHP detects such POST requests, it will populate an array in the $_SESSION, where the index is a concatenated value of the session.upload_progress.prefix and session.upload_progress.name INI options. The key is typically retrieved by reading these INI settings, i.e.
You should take a look at : https://github.com/blueimp/jQuery-File-Upload/wiki/PHP-Session-Upload-Progress
I think this will definitely help you out!
Display your message just before launching $.ajax();
And close it in the success (and error) callback functions.
example :
$s('body').on('click', '#group-update', function() {
var formInputs = $s('input').serializeArray();
var groupId = $s(this).data('group');
var error = $s('#modal .info');
var tr = $s('#dataT-attrgroup').find('tr.on_update');
formInputs.push({
name: 'id',
value: groupId
});
var dlg = $s('<div/>').text('your message').dialog();
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
error:function() {
dlg.dialog('close');
},
success: function(data) {
dlg.dialog('close');
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
}
});
});
If you go through ajax section of jquery documentation you will notice some more method like success ie error, beforesend, complete etc. Here is the code snippet.
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
beforeSend : function(){
// load message or image
},
success: function(data) {
// write code as per requirement
},
complete : function(){
// load complete message where you previously added the message or image, as a result previous one will be overwritten
}
});
I have an MVC application with a controller named Angular (I use AngularJS as well), which has an action called GetQuestion. That action returns a JsonResult which looks like this (grabbed from Chrome):
{"game":{"Title":"Diablo III","ImgPaths":["d31.jpg","d32.jpg"]},"Answers":["Diablo III","World of Tanks","Need for Speed"]}
My JS function is like this:
var request = $.ajax({
url: "/Angular/GetQuestion",
dataType: "json",
type: "post",
success: (function (data) { alert(data); })
});
But instead of the Json I wrote above, alert window only says [object Object]
Update
Ok, that was fixed, thaks. However as you may suspect, my goal is not to present this data in alert box, but use it somehow. So here's my controller in Angular
function QuestionCtrl($scope) {
var request = $.ajax({
url: "/Angular/GetQuestion",
dataType: "json",
type: "post",
success: function (data) {
$scope.answers = JSON.stringify(data.Answers);
$scope.imgPath = JSON.stringify(data.game.ImgPaths[0]);
}
});
}
And then the view:
<div ng-controller="QuestionCtrl">
<img class="quizImage" src="~/Gallery/{{imgPath}}"/>
#using (Html.BeginForm("Answer", "Angular", FormMethod.Post))
{
<p ng-repeat="answer in answers"><input type="radio" name="game" value="{{answer}}"/> {{answer}}</p>
<p><input type="submit" value="Answer"/></p>
}
</div>
And I don't have neither image or the questions. If I hardcode them in controller then it's ok.
An alert will show that, i would suggest using console.log(data)
var request = $.ajax({
url: "/Angular/GetQuestion",
dataType: "json",
type: "post",
success: (function (data) { console.log(data); })
});
or as the comments states:
var request = $.ajax({
url: "/Angular/GetQuestion",
dataType: "json",
type: "post",
success: (function (data) { alert(JSON.stringify(data)); })
});
I resolved my second problem like this:
function QuestionCtrl($scope, $http) {
$http.post('/Angular/GetQuestion',null).success(function(data) {
$scope.answers = data.Answers;
$scope.imgPath = data.game.ImgPaths[0];
//console.log($scope.answers);
//console.log($scope.imgPath);
});
}
Note that it's AngularJS.
The reason it's happening is because JSON is an Object in JavaScript. When you type
alert(data);
It will attempt to cast the object to a string which in this case will only output that fact that it's an Object.
To view the contents of an object you can write a simple function to use with an alert or console.log.
function outputProperties(anObject) {
var props = '';
for (var prop in anObject) {
props += '\n' + prop + ' value: ' + anObject[prop];
}
return props;
}
And use it like this
alert(outputProperties(data));
For starters... when ever you are dynamically building the src url for an image (using the {{expression}} syntax from Angular) you need to not use the "src" attribute and use the "ng-src" angular directive. It allows angular time to process your url before the image is loaded.