function cal() with radio input - javascript

i created a form with cal() but im not able to make it work with radio input.
It worked with select and option, but now the value isnt taken.
here the code
<script>
function cal()
{
var pl=document.form1.template.value;
var resultat=pl;
document.form1.tresultat.value=resultat;
document.formfin.tresultatfin.value = calfin();
}
</script>
<form name="form1">
<label for="Template">Option 1 : Template</label>
<ul>
<li id="template"><label for="logo+texte">Logo et texte</label>
<input type="radio" id="test" name="template" value="500" onclick="cal()"></li>
<li><label for="base">Base</label>
<input type="radio" id="test" name="template" value="800" onclick="cal()"></li>
<li><label for="perso">Sur-Mesure</label>
<input type="radio" id="test" name="template" value="2900" onclick="cal()"></li></ul>
<input type="text" value="0" name="tresultat">
</form>
any idea to get the value in the text input when selected ?
thanks

Radio buttons are weird because there's a list of separate elements instead of just one. The simplest thing to do is to pass the element itself as a parameter:
function cal( button )
{
var pl = button.value;
var resultat=pl;
document.form1.tresultat.value=resultat;
document.formfin.tresultatfin.value = calfin();
}
and then change the radio buttons:
<input type="radio" id="test" name="template" value="800" onclick="cal( this )"></li>
passing this to the function.

Related

check one radio button with dynamic values

<input type="radio" on-click="checkDefaultLanguage" id="checkbox" >
[[names(name)]]
this is my custom input field for radio and has dynamic values in it. I am trying to select one radio at a time and deselect from the others. but I cannot find any information for this. The one I have found are either with name attribute or having static input fields.
my JS
private checkDefaultLanguage() {
const checkboxes = <HTMLInputElement>this.querySelector('#checkbox');
checkboxes.addEventListener('click', () => {
if (checkboxes.checked) {
//what is should I do inside of it to make sure only one is selected at a time.
}
});
}
Just use name on the input, all input will get assigned to 1 group
<form>
<fieldset>
<legend>Select a maintenance drone</legend>
<div>
<input type="radio" id="huey" name="drone" checked />
<label for="huey">Huey</label>
</div>
<div>
<input type="radio" id="dewey" name="drone" />
<label for="dewey">Dewey</label>
</div>
<div>
<input type="radio" id="louie" name="drone" />
<label for="louie">Louie</label>
</div>
</fieldset>
</form>
tbh i dont fully understand what you are trying to do but you could pass the button you just clicked to the function
<input type="radio" on-click="checkDefaultLanguage(this)" id="checkbox" >
In your function you could just uncheck every box no matter if it's checked or not.
After this for-loop just check the one you passed to the function.

Make check-boxes becoming one group of radio button

I cannot make the input name same or value same. The second and third inputs come from a loop using c# razor. I have 2 sets of radio inputs first one is one set and second and third are another set. Because the second and third have the same name, checking one makes the other unchecked. I want the same for all of them together so it would be like I have one set of 3 radio buttons. Like I said above I am not able to make the name or value same due to back-end data display issue. Here is my attempt below.
//first radio <br/>
<div class="radio">
<label>
<input id="dcenter-allradio" type="radio" value="0" />All
</label>
</div>
//this radio button is a loop <br>
<input type="radio" name="#Model.Facet.Key" value="#item.Key">tagitem.j
<div class="radio">
<label>
<input id="dcenter-listradio" type="radio" name="#Model.Facet.Key" value="#item.Key" />tagItem.Name
</label>
</div>
<script>
$(document).ready(function () {
if ($('#dcenter-listradio').prop("checked", true)) {
$('#dcenter-allradio').prop("checked", false);
}
if ($('#dcenter-allradio').prop("checked", true)) {
$('#dcenter-listradio').prop("checked", false);
}
});
</script>
If you can give them all the same class, then you can just use jQuery to detect when a change has occurred and then uncheck other items in the same class.
$(document).ready(function() {
var selector = ".groupTogether";
// or if you can't give same class, you could use "#unrelatedRadio, input[name='related']"
$(selector).change(function()
{
if(this.checked)
{
$(selector).not(this).prop('checked', false);
}
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<input id="unrelatedRadio" name="unrelated" type="radio" class="groupTogether">unrelated</input>
<input id="relatedA" name="related" type="radio" class="groupTogether">Related A</input>
<input id="relatedB" name="related" type="radio" class="groupTogether">Related B</input>
Or, if you can't give them the same class, just replace the selector with something that selects both sets (in my example, "#unrelatedRadio, input[name='related']")
let radios = document.querySelectorAll("input");
for (let i of radios){
i.name="same"
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
//first radio <br/>
<div class="radio">
<label>
<input id="dcenter-allradio" type="radio" value="0" />All
</label>
</div>
//this radio button is a loop <br>
<input type="radio" name="#Model.Facet.Key" value="#item.Key">tagitem.j
<div class="radio">
<label>
<input id="dcenter-listradio" type="radio" name="#Model.Facet.Key" value="#item.Key" />tagItem.Name
</label>
</div>

Get radio button value which is outside a form post

I have a form which has some radio buttons which is outside this form.The html is as follows
<input type="radio" id="radio1" name="radios" value="radio1" checked>
<label for="radio1">Credit Card</label>
<input type="radio" id="radio2" name="radios"value="radio2">
<label for="radio2">Debit Card</label>
<form method="post" action='./process.php'>
<label>name</label>
<input type="text"/>
<input type="submit" style="float:right" value="Pay Now"/>
</form>
When I press on the paynow button,i want to pass the value of button selected to the php of this form (process.php) .But I dont want to place the radio buttons inside the form.Is there any solution?
You could have a hidden value inside the form, onsubmit put the value of that radio button inside the hidden value
<input type="radio" name="test" value="a">a<br>
<input type="radio" name="test" value="b">b
<form>
<input type="hidden" name="test" id="hidden">
<submit onClick="transferData">
</form>
<script>
var transferData = function() {
var radioVal =$('input:radio[name=test]:checked').val()
$('#hidden').val(radioVal);
}
</script>
HTML5 supports an attribute called "form". You can use it to set the form for controls that are outside your form, like so:
<input type="radio" id="radio1" name="radios" value="radio1" checked>
<label form="myForm" for="radio1">Credit Card</label>
<input type="radio" id="radio2" name="radios"value="radio2">
<label form="myForm" for="radio2">Debit Card</label>
<form id="myForm" method="post" action='./process.php'>
<label>name</label>
<input type="text"/>
<input type="submit" style="float:right" value="Pay Now"/>
</form>
Note how id="myForm" is added to the form and form="myForm" is added to the radio-buttons. Hope that helped you.
Yeah, you could add a reference to jQuery, before the </body>. Then, using JQuery, you could select the checked radio button as follows:
var selected = $("input[type='radio']:checked");
if (selected.length > 0) {
selectedVal = selected.val();
}
The selectedVal parameter will hold the value you want.
The selection of the selected radio button should be done on the click event of submit button.
That could be done as follows:
$("input[type='submit']").click(function(){
// code goes here.
});
You must have a onsubmit attribute on your form, and inside, assign to a hidden field the selected radio button value.
Like this:
<form id='myForm' method="post" action='./process.php' onsubmit='getRadioButtonValue()'>
...
<input type="hidden" name="selectedRadioValue" />
</form>
function getRadioButtonValue(){
var radioValue = $('input[name=radios]:checked', '#myForm').val();
$('input[name='selectedRadioValue']').val(radioValue);
}
Put everything in the form. If you want to send all values. Add required attibute to your tags.
Other wise use jquery
<form id="test" method="POST">
<input type="text" id="name" required minlength="5" name="name"/>
<input type="password" id="pw" required name="pw"/>
<input id ="sub" type="submit"/>
</form>
<ul id="answer"></ul>
</body>
<script>
$("#sub").click(function(event){
event.preventDefault();
query = $.post({
url : 'check_ajax.php',
data : {'name': $('input[name=name]').val(), 'pw': $('#pw').val()},
});
query.done(function(response){
$('#answer').html(response);
});
});
</script>
All you need to do is to add the value of the option/input outside the form in the data
Use this onsubmit event!
$('input[name=radios]:checked').val()
Check the example

how to get the value of the hidden fields in here after the radio button is clicked

Am trying to get the value of the hidden input fields on every click of a radio button. I have just posted a single div. I have a multiple div with same structure. I have successfully obtained the value of radio button but I want to get the value of hidden input now.
<div class="QA">
<h1> First Question</h1>
<input type="radio" id="check" name="q" value="A">Options 1</input>
<input type="radio" id="check" name="q" value="B">Options 2</input>
<input type="radio" id="check" name="q" value="C">Options 3</input>
<input type="radio" id="check" name="q" value="D">Options 4</input>
<input type="hidden" id="result" value="B" />
<br/>
<div id="result"></div>
</div>
<script>
$(document).ready(function() {
$("input:radio").change(function() {
checkResult(this);
});
});
function checkResult(el)
{
$this=$(el).parent("div.QA");
$this.slideUp();
}
</script>
Maybe you could try removing the hidden input entirely and indicate the correct answer using a data-* attribute. Something like:
<div class="QA" data-answer="B">
Then in your checkResult function you could retrieve this value using
function checkResult(el)
{
$this=$(el).parent("div.QA");
var answer = $this.data("answer");
$this.slideUp();
}
function checkResult(el)
{
$this = $(el).parents("div.QA");
$this.slideUp();
var x = $this.find('#result').val(); //find value of hidden field in parent div
}
Change your markup
multiple id's should not be used. Use class instead.
<input type="radio" id="check" name="q" value="A">Options 1</input>
to
<input type="radio" class="check" name="q" value="A">Options 1</input>
var $hidden=$(el).siblings("input[type='hidden']");
BTW you have lot of elements with same ID, not good
You can get the value of the hidden element by it's id.
var hiddenValue = $("#result").val();
You can use this in hidden function
function checkResult(el)
{
var hiddenValue = $("#result").val();
alert(hiddenValue);
}

jQuery Radio Button function not working properly

I have a form with two radio buttons and a submit button which leads to a specific form based upon the user's selection.
I wanted to use jQuery to change between the two buttons but have gotten myself a bit lost.
Here is my javascript from another file in the proj:
function goTo()
{
var yesButton = $('#yesRad');
var noButton = $('#noRad');
if (yesButton[0].checked)
{
submitForm('yesForm') && noButton.Checked==false;
}
else (noButton[1].checked)
{
submitForm('noForm') && yesButton.Checked==false;
}
Inside the jsp I have the following code:
<form:form action="interested" commandName="user" name="yesForm" id="yesForm">
<input type="hidden" name="state" value="<c:out value="${requestScope.state}"/>" />
<input type="hidden" id="address" name="address" value="${user.address}" />
<input type="hidden" name="mode" value="1" />
<input type="radio" name ="radio"id="yesRad" value="yesForm" checked="checked" />Yes<br>
</form:form>
<form:form action="notinterested" commandName="user" name="noForm" id="noForm">
<input type="hidden" name="state" value="<c:out value="${requestScope.state}"/>" />
<input type="hidden" id="address" name="address" value="${user.address}" />
<input type="hidden" name="mode" value="1" />
<input type="radio" name="radio" id="noRad" value="noForm" />No<br>
</form:form>
Submit
<script>
$("#yesRad").change(function(){
var $input = $("#yesRad");
var $inputb = $("#noRad");
if($inputb.is(':checked'))
$("#yesRad").prop("checked", false);
else if($input.is(':checked'))
$("#yesRad").prop("checked",true) && $("#noRad").prop("checked",false);
});
</script>
I have gotten some functionality out of my jQuery but it's definitely far from correct..
I hope I was clear and thorough in my question. Thanks in advance!!
To begin with, don't use prop, use attr. prop is slower.
You've defined variables so let's not look them up again. In your if/else statement just use the variables.
I'm not entirely sure what you're trying to do with the &&. I suspect you're trying to set the value of the two inputs. If so, they should be separate statements. If inputb is checked there is no reason to set it to checked, so we can remove that piece.
You probably want this change to fire on both inputs.
$("#yesRad, #noRad").change(function(){
var $input = $("#yesRad");
var $inputb = $("#noRad");
if($inputb.is(':checked')){
$input.attr("checked", false);
} else if($input.is(':checked')){
$inputb.attr("checked",false);
}
});
Solved: Using javascript and taking the radio buttons out of the separate form elements.
First let's take a look at the JSP form elements involved:
<form:form action="interested" commandName="user" name="yesForm" id="yesForm">
<input type="hidden" name="state" value="<c:out value="${requestScope.state}"/>" />
<input type="hidden" id="address" name="address" value="${user.address}" />
</form:form>
<form:form action="notinterested" commandName="user" name="noForm" id="noForm">
<input type="hidden" name="state" value="<c:out value="${requestScope.state}"/>" />
<input type="hidden" id="address" name="address" value="${user.address}" />
</form:form>
<input name="radio" type="radio" id="Yes" value="yes" />Yes<br>
<input name="radio" type="radio" id="No" value="no"/>No<br>
What I did here was simply take the radio buttons out of the separate forms and grouped them together...pretty obvious; now let's look at the javascript file.
function goHere()
{
var yesButton = $('#Yes');
var noButton = $('#No');
var str ="Please select an option first then press the 'Submit' button";
if (yesButton[0].checked)
{
submitForm('yesForm');
}
else if (noButton[0].checked)
{
submitForm('noForm');
}
else
{
document.write(str.fontcolor.font("red"));
}
}
As you can see the function 'goHere();' is going to tell the submit button in the following code where we want to go based on the user's selection on our radio buttons.
Here's the call from our javascript function in a submit button on the form...
<div class="button-panel" id="Submit"><span class="buttons buttons-left"></span>
<button type="button" class="buttons buttons-middle" name="submitBtn" onClick="goHere();">Submit</button>
<span class="buttons buttons-right"></span>
That's it!! Simply put; sometimes, while it's invaluable to learn something new, if it's not broke--etc. Hope this helps someone later on down the line!

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